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Test: Reduction Of A Simple Distributed Loading - Mechanical Engineering MCQ


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14 Questions MCQ Test - Test: Reduction Of A Simple Distributed Loading

Test: Reduction Of A Simple Distributed Loading for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Test: Reduction Of A Simple Distributed Loading questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The Test: Reduction Of A Simple Distributed Loading MCQs are made for Mechanical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Reduction Of A Simple Distributed Loading below.
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Test: Reduction Of A Simple Distributed Loading - Question 1

The uniformly distributed load is having two different values of load per unit length on the ends of the distribution.

Detailed Solution for Test: Reduction Of A Simple Distributed Loading - Question 1

The answer is no. The uniform distributed load is not having two different values of the load per unit meter on the corner. Rather the distribution is uniform. That is it is having the same value of the same on both of the corners.

Test: Reduction Of A Simple Distributed Loading - Question 2

There are two types of loading. The uniformly distributed and the non-uniformly distributed that is the one having two different values at corners.

Detailed Solution for Test: Reduction Of A Simple Distributed Loading - Question 2

The two forms of the loading are the uniformly distributed and the non-uniformly distributed that is the one having two different values at corners. The uniform distributed load is not having two different values of the load per unit meter on the corner.

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Test: Reduction Of A Simple Distributed Loading - Question 3

The type of reduction of the loading is different for the uniformly distributed and the non-uniformly.

Detailed Solution for Test: Reduction Of A Simple Distributed Loading - Question 3

The methods for the reduction of the loadings is different for both uniformly distributed and the non-uniformly. In the latter the simplification uses the quadratic equation. The latter also uses the integration for the same purpose.

Test: Reduction Of A Simple Distributed Loading - Question 4

Determine the magnitude of the resultant force acting on the shaft shown from left.

Detailed Solution for Test: Reduction Of A Simple Distributed Loading - Question 4

The net force will act at the centroid of the parabola. Whether it be a parabola or the cubic curve the centroid is the only point at which the net force act. Force can’t be acted horizontally if the loading is vertical. Hence whatever be the shape of the loading, the centroid is the point of action of net force.

Test: Reduction Of A Simple Distributed Loading - Question 5

In the simplification of the loading system the net force acts at the ___________ of the loading body.

Detailed Solution for Test: Reduction Of A Simple Distributed Loading - Question 5

In the simplification of the loading system the net force acts at the centroid of the loading body. That is if the loading system is in the form of the triangle then the at the distance 2 by 3 of the base the net force of the loading will act. And the load will be half the area of the loading.

Test: Reduction Of A Simple Distributed Loading - Question 6

In triangle distributed loading, the loading at any distance can be easily found by using which of the following trigonometry function?

Detailed Solution for Test: Reduction Of A Simple Distributed Loading - Question 6

In triangle distributed loading, the loading at any distance can be easily found by using Tangent trigonometry function. That is because the linear distance only determines the vertical loading. That is the loading is uniform along the linear distance. Is the linear distance is more the loading is more.

Test: Reduction Of A Simple Distributed Loading - Question 7

Determine the magnitude of the resultant force acting on the shaft shown. The length is 2m.

Detailed Solution for Test: Reduction Of A Simple Distributed Loading - Question 7

The net force will act at the centroid of the parabola. Whether it be a parabola or the cubic curve the centroid is the only point at which the net force act. Force can’t be acted horizontally if the loading is vertical. Hence whatever be the shape of the loading, the centroid is the point of action of net force.

Test: Reduction Of A Simple Distributed Loading - Question 8

If the non-Uniform loading is of the type of parabola then?

Detailed Solution for Test: Reduction Of A Simple Distributed Loading - Question 8

The net force will act at the centroid of the parabola. Whether it be a parabola or the cubic curve the centroid is the only point at which the net force act. Force can’t be acted horizontally if the loading is vertical. Hence whatever be the shape of the loading, the centroid is the point of action of net force.

Test: Reduction Of A Simple Distributed Loading - Question 9

If any external force also is applied on the distributed loading then?

Detailed Solution for Test: Reduction Of A Simple Distributed Loading - Question 9

The external forces are treated differently. They are not added by the force of the distributed loading. That is the force not only acts at the centroid always. It can be shifted also. Depending on the external forces.

Test: Reduction Of A Simple Distributed Loading - Question 10

The resultant force acting, of the uniformly distributed loading is dependent on:

Detailed Solution for Test: Reduction Of A Simple Distributed Loading - Question 10

The resultant force acting, of the uniformly distributed loading is dependent on the area that the distribution is covering. The more the area the more is the force. That is the more is the tension created over the structure on which loading is kept. Hence the answer.

Test: Reduction Of A Simple Distributed Loading - Question 11

The difference between the two types of loading namely uniformly distributed and the non-uniformly distributed loading is that:

Detailed Solution for Test: Reduction Of A Simple Distributed Loading - Question 11

The non-uniformly distributed loading is using the integration for getting the net force given by it. And the former only need the area or the linear distance of the loading. That is when the distance is multiplied by the uniformly distributed load the net force is obtained. But that is not so with the non-uniform one.

Test: Reduction Of A Simple Distributed Loading - Question 12

Determine the location of the resultant force acting on the shaft shown from left. The length is 2m.

Detailed Solution for Test: Reduction Of A Simple Distributed Loading - Question 12

The net force will act at the centroid of the parabola. Whether it be a parabola or the cubic curve the centroid is the only point at which the net force act. Force can’t be acted horizontally if the loading is vertical. Hence whatever be the shape of the loading, the centroid is the point of action of net force.

Test: Reduction Of A Simple Distributed Loading - Question 13

Determine the location of the resultant force acting on the shaft shown from left.

Detailed Solution for Test: Reduction Of A Simple Distributed Loading - Question 13

The net force will act at the centroid of the parabola. Whether it be a parabola or the cubic curve the centroid is the only point at which the net force act. Force can’t be acted horizontally if the loading is vertical. Hence whatever be the shape of the loading, the centroid is the point of action of net force.

Test: Reduction Of A Simple Distributed Loading - Question 14

Determine the magnitude of the resultant force acting on the shaft shown from left.

Detailed Solution for Test: Reduction Of A Simple Distributed Loading - Question 14

The net force will act at the centroid of the parabola. Whether it be a parabola or the cubic curve the centroid is the only point at which the net force act. Force can’t be acted horizontally if the loading is vertical. Hence whatever be the shape of the loading, the centroid is the point of action of net force.

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