Electrical Engineering (EE) Exam  >  Electrical Engineering (EE) Tests  >  Test: Continuous Time Signals - Electrical Engineering (EE) MCQ

Test: Continuous Time Signals - Electrical Engineering (EE) MCQ


Test Description

10 Questions MCQ Test - Test: Continuous Time Signals

Test: Continuous Time Signals for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Test: Continuous Time Signals questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Continuous Time Signals MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Continuous Time Signals below.
Solutions of Test: Continuous Time Signals questions in English are available as part of our course for Electrical Engineering (EE) & Test: Continuous Time Signals solutions in Hindi for Electrical Engineering (EE) course. Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free. Attempt Test: Continuous Time Signals | 10 questions in 10 minutes | Mock test for Electrical Engineering (EE) preparation | Free important questions MCQ to study for Electrical Engineering (EE) Exam | Download free PDF with solutions
Test: Continuous Time Signals - Question 1

(Q.1-Q.2) The number of cars arriving at ICICI bank drive-in window during 10-min period is Poisson random variable X with b=2.1.

Q. The probability that more than 3 cars will arrive during any 10 min period is

Detailed Solution for Test: Continuous Time Signals - Question 1

Evaluate 1 – P(x = 0) – P(x = 1) – P(x = 2) – P(x = 3).

Test: Continuous Time Signals - Question 2

The probability that no car will arrive is

Detailed Solution for Test: Continuous Time Signals - Question 2

Evaluate P(x = 0).

1 Crore+ students have signed up on EduRev. Have you? Download the App
Test: Continuous Time Signals - Question 3

(Q.3-Q.5) Delhi averages three murder per week and their occurrences follow a Poisson distribution.3.

Q. The probability that there will be five or more murder in a given week is

Detailed Solution for Test: Continuous Time Signals - Question 3

P(5 or more) = 1 – P(0) – P(1) – P(2) – P(3) – P(4) = 0.1847.

Test: Continuous Time Signals - Question 4

On the average, how many weeks a year can Delhi expect to have no murders ?

Detailed Solution for Test: Continuous Time Signals - Question 4

P(0) = 0.0498. Hence average number of weeks per year with no murder is 52 x P(0) = 2.5889 week.

Test: Continuous Time Signals - Question 5

How many weeds per year (average) can the Delhi expect the number of murders per week to equal or exceed the average number per week?

Detailed Solution for Test: Continuous Time Signals - Question 5

P(3 or more) = 1 – P(0) – P (1) – P(2) = 0.5768. Therefore average number of weeks per year = 52 x 0.5768 or 29.994 weeks.

Test: Continuous Time Signals - Question 6

(Q.6-Q.8) The random variable X is defined by the density f(x) = 0.5u(x) e(0.5x)6.

Q. The expect value of g(x) = X3 is

Detailed Solution for Test: Continuous Time Signals - Question 6

Solve E[g(x)] = E[X3].

Test: Continuous Time Signals - Question 7

The mean of the random variable x is

Detailed Solution for Test: Continuous Time Signals - Question 7

Solve integral (x f(x) dx) from negative infinity to x.

Test: Continuous Time Signals - Question 8

The variance of the random variable x is

Detailed Solution for Test: Continuous Time Signals - Question 8

Variance is given by E[X230] – 1/16.

Test: Continuous Time Signals - Question 9

(Q.9-Q.10) A joint sample space for two random variable X and Y has four elements (1,1), (2,2), (3,3) and (4,4). Probabilities of these elements are 0.1, 0.35, 0.05 and 0.5 respectively.

Q. The probability of the event{X  2.5, Y  6} is

Detailed Solution for Test: Continuous Time Signals - Question 9

 The required answer is given by Fxy(2.5, 6.0) = 0.1 + 0.35 = 0.45.

Test: Continuous Time Signals - Question 10

The probability of the event that X is less than three is

Detailed Solution for Test: Continuous Time Signals - Question 10

The required answer is given by Fx(3.0) = Fxy(3.0, infinity) = 0.1 + 0.35 + 0.05 = 0.50.

Information about Test: Continuous Time Signals Page
In this test you can find the Exam questions for Test: Continuous Time Signals solved & explained in the simplest way possible. Besides giving Questions and answers for Test: Continuous Time Signals, EduRev gives you an ample number of Online tests for practice

Top Courses for Electrical Engineering (EE)

Download as PDF

Top Courses for Electrical Engineering (EE)