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Test: Fracture Mechanics & Thermal Stresses - Mechanical Engineering MCQ


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10 Questions MCQ Test - Test: Fracture Mechanics & Thermal Stresses

Test: Fracture Mechanics & Thermal Stresses for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Test: Fracture Mechanics & Thermal Stresses questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The Test: Fracture Mechanics & Thermal Stresses MCQs are made for Mechanical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Fracture Mechanics & Thermal Stresses below.
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Test: Fracture Mechanics & Thermal Stresses - Question 1

The critical value at which crack extension occurs is called

Detailed Solution for Test: Fracture Mechanics & Thermal Stresses - Question 1

Explanation: Fracture toughness is the critical value of stress intensity at which crack extension occurs.

Test: Fracture Mechanics & Thermal Stresses - Question 2

Stress intensity factor is the critical value of stress at which crack extension occurs.

Detailed Solution for Test: Fracture Mechanics & Thermal Stresses - Question 2

Explanation: Stress intensity specifies the stress intensity at the tip of the crack.

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Test: Fracture Mechanics & Thermal Stresses - Question 3

The critical value at which crack extension occurs is called

Detailed Solution for Test: Fracture Mechanics & Thermal Stresses - Question 3

Explanation: Fracture toughness is the critical value of stress intensity at which crack extension occurs.

Test: Fracture Mechanics & Thermal Stresses - Question 4

Fracture toughness does not depend upon geometry of the part containing crack

Detailed Solution for Test: Fracture Mechanics & Thermal Stresses - Question 4

Explanation: Fracture toughness is directly proportional to a factor Y that depends upon geometry of the part having crack.

Test: Fracture Mechanics & Thermal Stresses - Question 5

How many modes are there for crack propagation?

Detailed Solution for Test: Fracture Mechanics & Thermal Stresses - Question 5

Explanation: Opening, sliding and tearing are the 3 modes.

Test: Fracture Mechanics & Thermal Stresses - Question 6

A curved beam has neutral axis is curved while loaded and straight when unloaded. 

Detailed Solution for Test: Fracture Mechanics & Thermal Stresses - Question 6

Explanation: Curved beam’s neutral axis is always curved irrespective of the loading.

Test: Fracture Mechanics & Thermal Stresses - Question 7

A curved beam with eccentricity 0.02D is loaded with 1kN.Centroidal radius=4D and inner and outer radii are 3.5D and 4.5D respectively. Area of cross section is 0.8D². Find the dimension D if allowable stress is 110N/mm².Considering only bending stress.

Detailed Solution for Test: Fracture Mechanics & Thermal Stresses - Question 7

Explanation: σ(b)=Mh/ AeR or σ(b)=1000x4Dx(4D-0.2D-3.5D)/ 0.8D²x0.02Dx3.5D , σ(b)=21428.6/D²
21428.6/D² = 110 or D=13.95mm.

Test: Fracture Mechanics & Thermal Stresses - Question 8

A curved beam with eccentricity 0.02D is loaded with 1kN.Centroidal radius=4D and inner and outer radii are 3.5D and 4.5D respectively. Area of cross section is 0.8D². Find the dimension D if allowable stress is 110N/mm² and considering only direct tensile stress.

Detailed Solution for Test: Fracture Mechanics & Thermal Stresses - Question 8

Explanation: Direct Tensile Stress=1000/0.8D² or σ (t) =1250/D²
1250/D²=110 or D=3.4mm.

Test: Fracture Mechanics & Thermal Stresses - Question 9

The bending stress in a straight beam varies linearly with the distance from neural axis like that in a curved beam.

Detailed Solution for Test: Fracture Mechanics & Thermal Stresses - Question 9

Explanation: Bending stress in a curved beam varies hyperbolically with the distance from neutral axis.

Test: Fracture Mechanics & Thermal Stresses - Question 10

A curved beam with eccentricity 0.02D is loaded with 1kN.Centroidal radius=4D and inner and outer radii are 3.5D and 4.5D respectively. Area of cross section is 0.8D². Find the dimension D if allowable stress is 110N/mm² and considering combined effect of direct stress and bending stress.

Detailed Solution for Test: Fracture Mechanics & Thermal Stresses - Question 10

Explanation: σ(b)=Mh/ AeR or σ(b)=1000x4Dx(4D-0.2D-3.5D)/ 0.8D²x0.02Dx3.5D , σ(b)=21428.6/D²
DirectTensile Stress=1000/0.8D² or σ (t) =1250/D²
Total stress=22678.6/D² N/mm²= 110 or D=14.35mm.

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