Commerce Exam > Commerce Videos > Applied Mathematics for Class 12 > Basic Concept and Problems on Mixture and Alligation (Part - 4)
Basic Concept and Problems on Mixture and Alligation (Part - 4) Video Lecture | Applied Mathematics for Class 12 - Commerce
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FAQs on Basic Concept and Problems on Mixture and Alligation (Part - 4) Video Lecture - Applied Mathematics for Class 12 - Commerce
| 1. What is the basic concept of mixture and alligation? |  |
Ans. The basic concept of mixture and alligation involves finding the ratio in which two or more ingredients or components of different strengths or prices are mixed to obtain a desired strength or price. It helps in solving problems related to the mixture of different substances.
| 2. What are the common problems on mixture and alligation? | |
Ans. The common problems on mixture and alligation include finding the ratio of two or more ingredients, calculating the quantity of each ingredient in the mixture, determining the average price or strength of the mixture, and finding the amount of one ingredient to be added to an existing mixture to achieve a desired ratio or strength.
| 3. How do you solve mixture and alligation problems? | |
Ans. To solve mixture and alligation problems, you can follow these steps:
1. Understand the problem and identify the given information.
2. Determine the components or ingredients involved in the mixture and their individual strengths or prices.
3. Set up a table or diagram to represent the given information and the unknowns.
4. Use the concept of alligation to find the ratios and proportions of the ingredients.
5. Use the ratios to calculate the quantities or prices of the ingredients.
6. Verify the solution by checking if the given conditions are satisfied.
| 4. Can you provide an example of a mixture and alligation problem? | |
Ans. Sure! Here's an example:
A chemist has two solutions of alcohol, one containing 40% alcohol and the other containing 70% alcohol. How much of each solution should be mixed to obtain 10 liters of a solution containing 50% alcohol?
Solution:
Let x liters of the 40% alcohol solution be mixed with (10 - x) liters of the 70% alcohol solution.
The equation can be set up as: 40x + 70(10 - x) = 50 * 10
Simplifying the equation, we get: 40x + 700 - 70x = 500
Rearranging terms, we get: 30x = 200
Solving for x, we find: x = 6.67 liters (approximately)
Therefore, 6.67 liters of the 40% alcohol solution should be mixed with (10 - 6.67) = 3.33 liters of the 70% alcohol solution to obtain 10 liters of a solution containing 50% alcohol.
| 5. How can mixture and alligation be applied in real-life scenarios? | |
Ans. Mixture and alligation concepts can be applied in various real-life scenarios. For example:
- In cooking, it helps in determining the quantities of different ingredients needed to achieve a desired taste or consistency.
- In manufacturing industries, it is used to calculate the proportions of different materials required to produce a specific product.
- In finance, it can be used to calculate the average return on investment when different assets are combined in a portfolio.
- In pharmacy, it helps in determining the quantities of different drugs and their strengths needed to prepare a specific medication.
- In agriculture, it can be used to calculate the amount of different fertilizers or pesticides required to achieve a desired nutrient balance or pest control.
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Dec 04, 2024 Last updated |
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