SSC CGL Exam > SSC CGL Videos > Quantitative Aptitude for SSC CGL > Probability: Three Colour Balls
Probability: Three Colour Balls Video Lecture | Quantitative Aptitude for SSC CGL
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314 videos|170 docs|185 tests
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FAQs on Probability: Three Colour Balls Video Lecture - Quantitative Aptitude for SSC CGL
| 1. What is the probability of selecting a red ball from the three color balls? |  |
Ans. The probability of selecting a red ball from the three color balls can be calculated by dividing the number of red balls by the total number of balls. If there are, for example, 2 red balls out of 6 total balls, the probability would be 2/6 or 1/3, which is approximately 0.3333.
| 2. What is the probability of selecting a green ball if there are 4 green balls in the set? | |
Ans. The probability of selecting a green ball can be determined by dividing the number of green balls by the total number of balls. If there are 4 green balls out of a total of 10 balls, the probability would be 4/10 or 2/5, which is equal to 0.4 or 40%.
| 3. If there are 3 red balls, 2 green balls, and 1 blue ball, what is the probability of selecting a blue ball? | |
Ans. The probability of selecting a blue ball can be calculated by dividing the number of blue balls by the total number of balls. In this case, since there is only 1 blue ball out of a total of 6 balls, the probability would be 1/6, which is approximately 0.1667 or 16.67%.
| 4. How many different combinations of color balls can be selected from the set of 3 red balls, 2 green balls, and 1 blue ball? | |
Ans. The number of different combinations of color balls can be calculated using the concept of combinations. In this case, we have 3 red balls, 2 green balls, and 1 blue ball. The total number of combinations can be found using the formula C(n, r) = n! / (r!(n-r)!), where n is the total number of balls and r is the number of balls to be selected. So, the number of combinations would be C(6, 3) = 6! / (3!(6-3)!) = 20.
| 5. What is the probability of not selecting a red ball if there are 3 red balls, 2 green balls, and 1 blue ball? | |
Ans. The probability of not selecting a red ball can be calculated by subtracting the probability of selecting a red ball from 1. In this case, the probability of selecting a red ball is 3/6 or 1/2. Therefore, the probability of not selecting a red ball would be 1 - 1/2 = 1/2 or 0.5, which is equal to 50%.
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Dec 23, 2024 Last updated |
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