Line spectrum : particle nature of electron (Part - 16) - Structure of Atom, Class 11 Video Lecture

hello friends this video on structure of
atom part 16 is brought to you by exam
fear calm no more fear from exam before
watching this video please make sure
that you have watched part 1 two parts
of teen the last thing I told was a line
spectrum which also shows the particle
nature lines vector as we discussed the
way it works is you take any gas or any
metal you excited heated whatever the
Rays come out that is electro vanity
Ray's comes out you pass that through
the prism and you see these kind of
spectrum where we have this kind of ice
and that clearly see is that these guys
are the electromagnet Aries has some
particle nature correct same as ever
here to produce the electromagnetic
spectrum we supply the energy to a
sample by heating it and then radiation
is emitted and then we observe this
radiation using prism the conclusion we
have is the light has a dual nature dual
behavior if you see it it B is like a
wave also it behaves like a particle
also right where B is like ball will
bounce back correct also microscopic
particles such as electrons also behave
wave particle with the electrons also
have dual nature electrons also have
well and this is something which will
help us in fun in the quantum model
please remember electron also have
village we'll take some example some
let's take some examples on
electromagnetic waves first we have to
calculate the energy of one mole of
photon whose frequency is 5 into 10 to
the power 14 Hertz so we have frequency
given this is the frequency and we
defined that energy of one mole energy
of one molecule is we know that how much
we have the formula HP this is for one
molecule right so let's put the values
here what is the value of H
H is flying
this constant six five six to 6 into 10
to the power minus 34 joule-seconds into
frequency is 5 into 10 to power my do a
plus 40 first that is nothing word per
second so if you multiply you get value
as 3 point 3 1 3 into 10 to the power
minus 90 June so this is my energy of
one molecule I want to find energy of
one mole so energy one more is nothing
but one mole has we know that six point
zero 2 3 into 10 to the power 23
molecules so this into energy of one
molecule
I hope this UNICEF this formula energy
of one mole is nothing but energy this
number because this number is nothing
but one mole has many molecules into
energy of one molecules energy of one
molecules we have already found will
just put the value six point zero 2 3
into 10 to the power 23 into 3 point 3 1
3 8 to 10 to the power minus 90 and the
whole thing will become juice site per
mole actually because this is one mole
so if you solve this you get 1 99.5 one
kilo Joule well and that is my answer
let's take for example a bulb of 100
watt emits monochromatic light of
wavelength 400 nanometer if you
calculate the number of photons emitted
per second by them so we have 100 watt
bulb that emits a light of this
wavelength we define the number of
photons emitted by bulb per second so it
is a 100 watt this I say power is 100
god this means what that means hundred
joules per second is my part correct
so in once again this much energy is
given from the bulb now this much energy
is coming from some n photons right and
each photon will give some energy and
their energy will be h mu o HC by lamda
because we have given lambda C this is
the whole power of the bulb power of
bulb that is 100 Joule per second and
this power comes from n photons and n
photons each photon will have energy of
su / lambda book understand this so what
you get is hundred jewel in once again
if you take is nothing but n which is
the number of photons do HC by lambda H
is 6 point 6 - 6 into 10 to the power
minus 34 joule-seconds see speed of
light 3 into 10 to the power 8 meter per
second please note every the units I am
putting everything in meter seconds
jewels and then I have lambda lambda is
400 nanometer so I will convert this
into meter so 1 nanometer is going to 1
nanometer is equal to n is equal to 10
to power 9 meter so I say 4 nanometers
nothing but for it to go - I meet up
correct so if you solve this now to get
the value of n you will find n s 20 into
10 to the power 19
I like photons and since we're doing 4
per second this these are the my this
many photons will be per second emitted
okay these are my photons emitted hope
you understand this what we are done we
had a bulb which was which was power of
the common water this Honey Joule per
second
and this the whole energy was coming
from some n number of photons each
photon has energy HC by lambda we want
the number of thank you visit exam
viacom to watch free educational videos
try free online tests get the best
quality study materials study from the
best tutors and mentors and much more
thanks again