Balance Oxidation number method Numericals (Part - 15) - Redox Reaction,

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reaction part 15 is brought to you by
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the co shell says but magnet iron reacts
with bromide or in base medium please
note the medium is based to give Magnus
dioxide in Froemming
I let us write the reaction first the
reaction is mno4 - yes well bromide ion
we are - to give manganese dioxide mno2
plus vomit I be are over three miles
correct so let's write the memory -
first the membrane tip is ox consume
water that is su right interval first
balance oxidation number so let's write
the oxidation number fast so we'll apply
the formula the formula we have our
oxidation number is free image of human
face the memory type if you don't
remember it in you can watch the free
previous video can you explain this free
image we can't use free free state we
can't use ions if oxygen you can use so
we begin again make it - - this will
come out in few if you give it X X minus
2 into 4 minus 8 is equal to minus 1
this becomes plus and this is minus 1
this is also this becomes minus 2
oxygens you see come out to be plus 4
right this is minus 2 so X into minus 2
into 3 is X minus 6 is equal to minus 1
X comes out with plus 5 so we have the
oxidation states defined clear correct
so let's see this is from 7 to 4 that is
change is minus 3 and this is from minus
1 to plus 5 so change is plus 6 write
this is minus 1 plus ty please note it
is not 1 to 5
it is minus 1/2 plus Phi changes Phi
minus minus 1 that is 6 so you see here
the changes of 6 units here the change
of 3 units so what we can do is we can
multiply this with 2 correct
so we have to multiply this with 2
because the first says if the balance
oxidation number right so let's multiply
this guy with two both side this is 2
and this is 2 right so I have minus
reaction this is my current reversed the
next is what balance charge right so
we'll see balance charge so in this case
what we do is the same reaction and see
the LHS charge LHS charge is what light
in line 2 into minus 1 plus 1 into minus
1 total charge is what minus 3/4 right
hand side if you see charge that is 0
charge here into 0 and 1 charge here
right the charge is not balanced so we
have to add we have to balance the
charge right so it says it's the basic
mediums we can add h minus sign so we
get me out of h minus n if you add row H
minus then what will happen in LHS the
charge will increase more it will become
minus 4 y is 5 like that
if you add in RHS yes it will become
minus 1 minus 2 minus 3 right we add
version as so we can add to wash iron
right here and - oh Sh - on it
so with this the charge will become what
minus 3 right so in the right hand side
we have to add 2 OS - ions just to
balance the charge so with this charge
is balanced
- my charge is balanced okay the next
step is what balance hydrogen so let's
see how to do so hydrogen if you see in
LHS how many hydrogen's zero in our
ashes how many hydrogen - how can you
balance you can balance by adding one
water molecule here we had one water
molecule here this becomes 2 right
because 2 hydrogen form is so let's add
one higher water molecule here only one
right so with this both are balanced so
water is also balanced the next is
oxygen bridges to validate this validate
oxygen so let's see in LHS and RHS what
is the oxygen form LHS oxygen counter is
what 4 into 2 8 plus 1 right that is my
knowledge is how many 2 into 2 4 plus 3
from this plus 2 from Oh H minus 4 plus
3 7 plus 2 my if you see both are knife
that means oxygen is balanced that means
we are correct - this is my balanced
reaction want I can write here in black
- mno4 minus plus vr plus h2o gives t m2
plus v r3 minus plus halogens
this is my balance flow let's take some
more examples you have to balance this
reaction and this is a basic medium
correct
so our step is ox consumed bottom
right this is the memory tip so the
first is balance
o X so let's find the oxidation state
for all the rule we have is 3 image of
human face
right so with this free we cannot apply
ion we can apply oxygen we can apply
this is minus 2 this will become plus 7
right here this is minus 2 this becomes
plus 4 this is zero so if you see here
it is plus 7/2 plus 4 change of minus 3
here in this case it is minus 1 to 0 the
change is for 1 correct so what we'll do
here we'll multiply this thing with 3
we'll multiply this guy whole thing with
3 so if you see now this is 3 and this
is 3 so what we will do we will make it
3 here and we'll make it 3 by 2 there so
let us write this reaction because the
scanning little clumsy
this is mno4 minus plus 3i minus gives
you MN or 2 plus 3 by 2
I
right and with this my oxidation states
are balanced now I have to balance
charge so let's see balance charge let
me do a different color so in this case
LHS what is the charge minus 1 and minus
3 minus 1 plus minus 3 that is minus 4
in right hand side what is the charge
zero and zero zero charge so I have to
make it - for both side so basic so I
can add H - Meghan I add which - I can't
add in LH is because it will make it
more negative so I can add 4h - here in
RHS right so this becomes minus 1 it is
all balanced let us talk about charges
done hydrogen balance let's balance
hydrogen so let me again balance
hydrogen so in LHS how many hydrogen's 0
in right hand side how many hydrogen's
four I have to balance it what I can do
is I can add to what the molecules here
we are - what your volume is e so in
this case it also has now for correct so
hydrogen is balanced what is the next
step I have to just validate for oxygen
Alex let's see in LHS how many oxygen 4
+ 2 that is 6 notches harmony 2
plus four that is six you see both are
saying that means I'm done correct
this is my balanced reaction okay so
first you have to balance oxidation
number then charge the hydrogen and then
validate for oxygen valence thank you
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