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IUPAC nomenclature Practice - Organic Chemistry: Some Basic Principals & Techniques, Class 11 Video Lecture
FAQs on IUPAC nomenclature Practice - Organic Chemistry: Some Basic Principals & Techniques, Class 11 Video Lecture
| 1. What is the IUPAC nomenclature and why is it important in organic chemistry? |  |
Ans. The IUPAC nomenclature is a system of rules and guidelines used to name organic compounds. It is important in organic chemistry because it allows chemists to communicate and convey information about the structure and composition of a compound through its name. The IUPAC nomenclature ensures that each compound has a unique name and allows for easy identification and classification.
| 2. How do I name a compound using IUPAC nomenclature? | |
Ans. To name a compound using IUPAC nomenclature, you need to follow a set of rules. Start by identifying the longest continuous carbon chain in the compound, which becomes the parent chain. Number the parent chain to locate any substituents or functional groups. Name the substituents, indicating their position on the parent chain using the appropriate prefixes. Finally, assign a prefix or suffix to indicate any functional groups present. By following these rules, you can systematically name organic compounds using IUPAC nomenclature.
| 3. What are some common prefixes and suffixes used in IUPAC nomenclature? | |
Ans. Some common prefixes used in IUPAC nomenclature include methyl, ethyl, propyl, and butyl, which indicate the presence of substituents on the parent chain. Suffixes such as -ol, -al, and -one are used to indicate alcohols, aldehydes, and ketones, respectively. Other examples include -amine for amines, -oic acid for carboxylic acids, and -amide for amides. These prefixes and suffixes help in identifying and naming different functional groups in organic compounds.
| 4. Are there any exceptions or special cases in IUPAC nomenclature? | |
Ans. Yes, there are some exceptions and special cases in IUPAC nomenclature. For example, cyclic compounds have specific naming rules, where the prefix cyclo- is added to the parent chain's name. In cases of multiple substituents, the substituents are listed in alphabetical order, ignoring any prefixes like di- or tri-. Additionally, some common names are still widely used for certain compounds, even though they do not strictly follow IUPAC rules. It is important to learn and understand these exceptions to accurately name organic compounds.
| 5. How does IUPAC nomenclature help in understanding the properties and reactions of organic compounds? | |
Ans. IUPAC nomenclature plays a crucial role in understanding the properties and reactions of organic compounds. By knowing the systematic name of a compound, chemists can quickly identify its structure, functional groups, and substituents, which helps predict its chemical behavior. The name also provides information about the compound's physical properties, such as boiling point, melting point, and solubility. This knowledge aids in studying the reactivity and behavior of organic compounds, allowing for better analysis, synthesis, and manipulation in various chemical processes.
Text Transcript from Video
hello friends this video on organic UHD
basic part 2 L is brought to you by exam
figure no more fear from exam let's
do some more practice and try to name
these Ella cyclic compounds
this is benzene and 1 2 3 4 that is this
is provide right with it bro right one
one two three carbons profile and the
benzene this is very easy this is
profile bingeing correct so in benzene
you held up profile Alka I do let's take
this one so we have 1 2 3 4 carbon in
fact 5 carbon right so we have 5 carbon
here this is nitrile group so this will
be given priority 1 2 3 4 5 rate
function should be the lowest possible
number this chargin leaving from here so
this becomes at T we have methyl this is
3 methyl is the prefix I have 5 so I
spend all single bonds so in this
nitrile group so it's nitride this is
three methyl paint nitride let's see
this is 1 2 3 4 5 6 7 the longest chain
is 7 we can name in this fashion or in
this fashion let's try this this is 1 2
3 4 5 6 7 so you name in this fashion
becomes 2 plus 5 that is 7 if your name
in this fashion this becomes 1 2 3 1 5 6
3 plus 6 that is 9 right so in this case
it is 2 plus 5 seven other case it is 3
plus 6 that is - I will not take this
will take this only so this becomes at 2
and 5 we have methyl group so it is 2 2
5 dimethyl and you have seven so HEPT
all single bond in this is 2 5 dimethyl
15 correct now let's name this
this is one two three four five six
seven or you can name in this fashion
also but if you named in this fashion
you're the functional group gets a leave
the lower number actually right so this
is a better numbering so we have three
clover and three bromo Fishman come
first
bromo right because B comes before C
this is Momo this is cure so we will say
this has three bromo alphabetical order
three chloro and you have seven select
all single one in three Brahma three
chloro obtain let's take this for
example so we have cos group that is my
functional group so that will get the
higher priority right so this will
become 1 so 1 2 & 3 kind this is see
here carbon here so this will be 3
chloro is my prefix then I have 3 carbon
here so that becomes myth it flow and
all single gone and and this is aldehyde
so al so 3 chloro token null let's take
this guy see it or CN 2 CH ch2oh so let
me draw this this is one carbon one
chlorine one chlorine one hydrogen then
I have two hydrogen here and watch so
what is my functional group here alcohol
based on the priority with alcohol is
more is in the top priority then if you
compare with chlorine so this will be I
have to prefix and I will give this
number 1 this guy number two because I
want to minimize the alcohol group here
to chlorine attached to carbon 2's will
become
to die chloro then I have to carbon so
myth it all single-bond en and alcohol
well so it is to dichloro if not let's
do some more practice let's name this
compound so we have let's find the
longest chain longest chain will be this
guy this carbon to scum hominid carbon
one two three four five you can name
this from this side also this side also
its name both the side so let's leave
here one two three four five is one way
and its name another way also so here if
it will be in red one two three four
five correct so in both case my first is
my early high group that's okay now
let's see the alkene group so if I take
green alkene group come back to why take
red alkene group combi three so I will
not take red and then Greenough correct
see if I take red alkene goups comes in
to position
I take green the alkene group comes in
second position that is better so I will
take this scenario so this is my
numbering so I have five alcohol five
now carbon so there is no clicks here so
I start with penned and at second
position I have gone in soap end to e
and add one and five position I have two
aldehyde groups it will be one slice re
one and five I have two early IDEs would
die L this will be my name upon pen two
in one file die L let us name this
compound so let's find the longest chain
so I believe this is my longest chain o
carbon you can name from either side
doesn't matter let me name from this
side one two three four if your name
from this side also it's all same
because in both case one will be the
nitrile group and there is no double
bond here so let's name this one
there is no prefix here because there is
no branch so let's start with a four
carbon so it's Butte all single bond in
at the 104 I have my trying right so 1
and for Diane I try let's try to name is
compound let's find the longest chain of
carbon this is my longest chain of
carbon so I can name in this two fashion
1 2 3 4 or I can also name in the other
along that is 1 2 3 4 so if I take the
green ones so if I take the green ones
then my methyl group that is here extra
comes in do you take the red ones it
comes in three so green one is better
see in both the case at one position I
have my amine group right but if you
take this one the red ones the methyl
comes at 3 if you take green ones the
with high group comes in 2 so we take
this pattern norm so here we have a
prefix that is 2 methyl so it will be 2
methyl then we have 1 2 3 4 that is
Butte all single bond in and then I have
one at 4 I have amine so it's 1 comma 4
dye that is the name of this color
let's try to name this compound the
longest chain is my this is my longest
chain right it has all this groups now
this ketone is my primary one because it
has alcohol and ketone woods of Catan is
more priority so we will try to get the
minimum number to this so we have to
number in this pattern right we can't
number from left right because number 1
2 3 4 because that case we'd only get 3
numbers so we have to give the least
number so this is my best possible way
of numbering now let's start do they I
have a prefix yes
three I have a methyl group and also
three I have hydroxy group so at between
hydroxy and meth I which one comes first
that we see this ABCD EFG H comes first
so hydroxy will come faster so it will
be three hydroxy for this three methyl
is my prefix one two three four so
viewed all single gone in and at second
position I have ketone so that is my
name of this let's try to name this
compound the longest chain will be my
this straight chain I have two ways of
numbering it one two three four five
or I can number in this fashion one two
three four in both the cases if you see
I am getting the halogen functional
group at one at five position so in this
also one plus five is equal to six here
also my function is at five and one
position so it is five plus 1 is greater
than six so what do you know
so now I have a bromo and I do right we
should come first a B this is B this
come cause this has more variety so
growing gate glue should get lower
number so bromo group should get one
number that means this one is wrong
correct bromo get you should get lower
number so what is the number what is the
name of this it has to fix yes one
bromine is added so one remove it fifth
one iodine is added five I do and then
they are five carbon so pent all single
bond in this is the name of this let us
name this compound so the longest chain
is this guy so since aldehyde group and
I have
easy so I have our Lehigh group here
today this is more priety so this will
be number one this will be number two
and this will be number G so let me name
this so at two position I have methoxy
should we do then Toxie is my prefix
then one two three carbon that is flow
all single bond en and early hide so to
methoxy propanil is done let's try to
name this compound so this is my longest
chain with double bond and carboxylic
group also this li one two and three
why because skybox li group is the
highest priority it will be even one two
and three correct
so let me name this guy so this myth
hide first here this will be my child
and then we'll name this guy right this
poaching here he says in this chain I
have one methyl group so there will be
prefix here there is two methyl they are
three carbons Rob at second position I
have double bond to mean and since this
carboxylic it it will be wait right
methyl even methyl probe to e wait
correct
let's name this compound CBC is the
longest chain carvanha ham is a three
carboxylic acids group attached they're
very high priority so I can name them
one two three or one two three in this
fashion so let's see which one is better
so in this case both are exactly same
doesn't matter so let me take this guy
on it because in both case I get at 2h
Pro both are almost same doesn't matter
so let us take this guy so now if you
see at second I have hydroxy so it is
two hydroxy and then I have propane and
then I had three positions 1 2 & 3
I have what car box strike apostasy so
since it is carboxylic acid so I have D
right this in last two hydroxy was the
prefix this was the root this is the
suffix in hence the second a suffix
correctly thank you visit exam viacom to
watch free educational videos try free
online tests get the best quality study
materials study from the best tutors and
mentors and much more
thanks and serene
basic part 2 L is brought to you by exam
figure no more fear from exam let's
do some more practice and try to name
these Ella cyclic compounds
this is benzene and 1 2 3 4 that is this
is provide right with it bro right one
one two three carbons profile and the
benzene this is very easy this is
profile bingeing correct so in benzene
you held up profile Alka I do let's take
this one so we have 1 2 3 4 carbon in
fact 5 carbon right so we have 5 carbon
here this is nitrile group so this will
be given priority 1 2 3 4 5 rate
function should be the lowest possible
number this chargin leaving from here so
this becomes at T we have methyl this is
3 methyl is the prefix I have 5 so I
spend all single bonds so in this
nitrile group so it's nitride this is
three methyl paint nitride let's see
this is 1 2 3 4 5 6 7 the longest chain
is 7 we can name in this fashion or in
this fashion let's try this this is 1 2
3 4 5 6 7 so you name in this fashion
becomes 2 plus 5 that is 7 if your name
in this fashion this becomes 1 2 3 1 5 6
3 plus 6 that is 9 right so in this case
it is 2 plus 5 seven other case it is 3
plus 6 that is - I will not take this
will take this only so this becomes at 2
and 5 we have methyl group so it is 2 2
5 dimethyl and you have seven so HEPT
all single bond in this is 2 5 dimethyl
15 correct now let's name this
this is one two three four five six
seven or you can name in this fashion
also but if you named in this fashion
you're the functional group gets a leave
the lower number actually right so this
is a better numbering so we have three
clover and three bromo Fishman come
first
bromo right because B comes before C
this is Momo this is cure so we will say
this has three bromo alphabetical order
three chloro and you have seven select
all single one in three Brahma three
chloro obtain let's take this for
example so we have cos group that is my
functional group so that will get the
higher priority right so this will
become 1 so 1 2 & 3 kind this is see
here carbon here so this will be 3
chloro is my prefix then I have 3 carbon
here so that becomes myth it flow and
all single gone and and this is aldehyde
so al so 3 chloro token null let's take
this guy see it or CN 2 CH ch2oh so let
me draw this this is one carbon one
chlorine one chlorine one hydrogen then
I have two hydrogen here and watch so
what is my functional group here alcohol
based on the priority with alcohol is
more is in the top priority then if you
compare with chlorine so this will be I
have to prefix and I will give this
number 1 this guy number two because I
want to minimize the alcohol group here
to chlorine attached to carbon 2's will
become
to die chloro then I have to carbon so
myth it all single-bond en and alcohol
well so it is to dichloro if not let's
do some more practice let's name this
compound so we have let's find the
longest chain longest chain will be this
guy this carbon to scum hominid carbon
one two three four five you can name
this from this side also this side also
its name both the side so let's leave
here one two three four five is one way
and its name another way also so here if
it will be in red one two three four
five correct so in both case my first is
my early high group that's okay now
let's see the alkene group so if I take
green alkene group come back to why take
red alkene group combi three so I will
not take red and then Greenough correct
see if I take red alkene goups comes in
to position
I take green the alkene group comes in
second position that is better so I will
take this scenario so this is my
numbering so I have five alcohol five
now carbon so there is no clicks here so
I start with penned and at second
position I have gone in soap end to e
and add one and five position I have two
aldehyde groups it will be one slice re
one and five I have two early IDEs would
die L this will be my name upon pen two
in one file die L let us name this
compound so let's find the longest chain
so I believe this is my longest chain o
carbon you can name from either side
doesn't matter let me name from this
side one two three four if your name
from this side also it's all same
because in both case one will be the
nitrile group and there is no double
bond here so let's name this one
there is no prefix here because there is
no branch so let's start with a four
carbon so it's Butte all single bond in
at the 104 I have my trying right so 1
and for Diane I try let's try to name is
compound let's find the longest chain of
carbon this is my longest chain of
carbon so I can name in this two fashion
1 2 3 4 or I can also name in the other
along that is 1 2 3 4 so if I take the
green ones so if I take the green ones
then my methyl group that is here extra
comes in do you take the red ones it
comes in three so green one is better
see in both the case at one position I
have my amine group right but if you
take this one the red ones the methyl
comes at 3 if you take green ones the
with high group comes in 2 so we take
this pattern norm so here we have a
prefix that is 2 methyl so it will be 2
methyl then we have 1 2 3 4 that is
Butte all single bond in and then I have
one at 4 I have amine so it's 1 comma 4
dye that is the name of this color
let's try to name this compound the
longest chain is my this is my longest
chain right it has all this groups now
this ketone is my primary one because it
has alcohol and ketone woods of Catan is
more priority so we will try to get the
minimum number to this so we have to
number in this pattern right we can't
number from left right because number 1
2 3 4 because that case we'd only get 3
numbers so we have to give the least
number so this is my best possible way
of numbering now let's start do they I
have a prefix yes
three I have a methyl group and also
three I have hydroxy group so at between
hydroxy and meth I which one comes first
that we see this ABCD EFG H comes first
so hydroxy will come faster so it will
be three hydroxy for this three methyl
is my prefix one two three four so
viewed all single gone in and at second
position I have ketone so that is my
name of this let's try to name this
compound the longest chain will be my
this straight chain I have two ways of
numbering it one two three four five
or I can number in this fashion one two
three four in both the cases if you see
I am getting the halogen functional
group at one at five position so in this
also one plus five is equal to six here
also my function is at five and one
position so it is five plus 1 is greater
than six so what do you know
so now I have a bromo and I do right we
should come first a B this is B this
come cause this has more variety so
growing gate glue should get lower
number so bromo group should get one
number that means this one is wrong
correct bromo get you should get lower
number so what is the number what is the
name of this it has to fix yes one
bromine is added so one remove it fifth
one iodine is added five I do and then
they are five carbon so pent all single
bond in this is the name of this let us
name this compound so the longest chain
is this guy so since aldehyde group and
I have
easy so I have our Lehigh group here
today this is more priety so this will
be number one this will be number two
and this will be number G so let me name
this so at two position I have methoxy
should we do then Toxie is my prefix
then one two three carbon that is flow
all single bond en and early hide so to
methoxy propanil is done let's try to
name this compound so this is my longest
chain with double bond and carboxylic
group also this li one two and three
why because skybox li group is the
highest priority it will be even one two
and three correct
so let me name this guy so this myth
hide first here this will be my child
and then we'll name this guy right this
poaching here he says in this chain I
have one methyl group so there will be
prefix here there is two methyl they are
three carbons Rob at second position I
have double bond to mean and since this
carboxylic it it will be wait right
methyl even methyl probe to e wait
correct
let's name this compound CBC is the
longest chain carvanha ham is a three
carboxylic acids group attached they're
very high priority so I can name them
one two three or one two three in this
fashion so let's see which one is better
so in this case both are exactly same
doesn't matter so let me take this guy
on it because in both case I get at 2h
Pro both are almost same doesn't matter
so let us take this guy so now if you
see at second I have hydroxy so it is
two hydroxy and then I have propane and
then I had three positions 1 2 & 3
I have what car box strike apostasy so
since it is carboxylic acid so I have D
right this in last two hydroxy was the
prefix this was the root this is the
suffix in hence the second a suffix
correctly thank you visit exam viacom to
watch free educational videos try free
online tests get the best quality study
materials study from the best tutors and
mentors and much more
thanks and serene
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