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Example and Summary - Arithmetic Progression Video Lecture - Class 10
FAQs on Example and Summary - Arithmetic Progression Video Lecture - Class 10
| 1. What is an arithmetic progression? |  |
An arithmetic progression is a sequence of numbers in which the difference between any two consecutive terms is always the same. This difference is called the common difference.
| 2. How can we find the nth term of an arithmetic progression? | |
To find the nth term of an arithmetic progression, we can use the formula: nth term = first term + (n - 1) * common difference. Here, the first term refers to the initial term of the progression, n represents the position of the term, and the common difference is the fixed value between the terms.
| 3. Can an arithmetic progression have negative terms? | |
Yes, an arithmetic progression can have negative terms. The common difference can be positive, negative, or zero, which determines the direction of the progression. For example, an arithmetic progression with a common difference of -2 would have negative terms.
| 4. How can we find the sum of the first 'n' terms of an arithmetic progression? | |
The sum of the first 'n' terms of an arithmetic progression can be calculated using the formula: sum = (n/2) * (first term + last term). Here, the first term is the initial term of the progression, and the last term can be found using the formula: last term = first term + (n - 1) * common difference.
| 5. Can an arithmetic progression have a common difference of zero? | |
Yes, an arithmetic progression can have a common difference of zero. In this case, all the terms of the progression would be the same. For example, if the first term is 5 and the common difference is 0, then all the terms of the progression would be 5.
Text Transcript from Video
hello friends this video on arithmetic
progressions part 13 is brought to you
by exam viacom no more fear from exam
before watching this video please make
sure that you have watched part 1 to
part 12 let's take for example 200 logs
are stacked in the following way
painting logs in the bottom then 19 then
18 like that right and we don't know the
last how many are total cement walls are
200 this is also a B 20 19 18 17 desert
s where a is equal to 200 and D is good
- sum is given servants 200 correct so
SN is nothing but and by doing T wave
thus in -1 be correct so 200 is nothing
but n is equal to we don't know n by 2
into a is 20 plus n minus 1 into minus 1
correct so what we get the fish me God
is this becomes 400 over hundred is
equal to n into n sorry this is 40 minus
n plus 1 correct
this is 1 this is 1 this is nothing but
n into or T 1 minus I so what equation I
got is n square minus 4 T 1 n plus 400
is equal to 0 or factorize this n square
minus 16 and minus 25 n plus 400 is
equal to 0 or you can see this is
nothing but n into n minus 16 minus 25
is 14-0 so n is equal to 25 or 16
correct now if you have to find
a 16 or a 25 thank you fine let's fight
the number of we have to find the number
of log which in the top so if n is equal
to 25 a 25 nothing but a this 20 plus n
minus 1 is 24 D is minus 1 that come out
to be minus 1 that is not possible
negative number is not possible for the
number of law so 25 is not a valuable
illusion a 2016 aramide is nothing worth
20 plus n minus 1 in the spring 16-1 15
e 2 minus 1 that is this is the forcing
number so the top one has 5 logs right
the top has five dogs the total number
of rows we get is 16 that is that 25 is
not possible because if we consider 25
is option the top row should have minus
4 log which is not possible so the top
or have 16 dots correct so what we have
done here we saw that the number of
losses 20 19 18 17 like that way so you
see this is nothing but a ap where the
first time is 20 and the common defense
is minus 1 we found the total term we
got a quiet equation you solve it we got
n is about 25 or 16 and then we found
that 25 is unpossible so n is equal to
60 let's do a quick little summary
automatic probation is the list of
number where each term is obtained by
adding a fixed number to the preceding
down right so that sequences a a plus da
plus 2 D equal to B form also a given
list of number a 1 a 2 a 3 a 3
the difference is constant this a 2 -
even if we - little everything is
constant and the difference is common
difference in terms of a P is nothing
but en is value a plus n minus 1 D the
sum of form of a P is n by 2 into VA
plus n minus 1 D is very efficient
formula also if you know the last term
in first term the sum is also called and
bytom into a plus n thank you visit exam
viacom to watch free education videos
try free online tests in the best
quality study materials study from the
best shooters
mentors and much more thanks again
progressions part 13 is brought to you
by exam viacom no more fear from exam
before watching this video please make
sure that you have watched part 1 to
part 12 let's take for example 200 logs
are stacked in the following way
painting logs in the bottom then 19 then
18 like that right and we don't know the
last how many are total cement walls are
200 this is also a B 20 19 18 17 desert
s where a is equal to 200 and D is good
- sum is given servants 200 correct so
SN is nothing but and by doing T wave
thus in -1 be correct so 200 is nothing
but n is equal to we don't know n by 2
into a is 20 plus n minus 1 into minus 1
correct so what we get the fish me God
is this becomes 400 over hundred is
equal to n into n sorry this is 40 minus
n plus 1 correct
this is 1 this is 1 this is nothing but
n into or T 1 minus I so what equation I
got is n square minus 4 T 1 n plus 400
is equal to 0 or factorize this n square
minus 16 and minus 25 n plus 400 is
equal to 0 or you can see this is
nothing but n into n minus 16 minus 25
is 14-0 so n is equal to 25 or 16
correct now if you have to find
a 16 or a 25 thank you fine let's fight
the number of we have to find the number
of log which in the top so if n is equal
to 25 a 25 nothing but a this 20 plus n
minus 1 is 24 D is minus 1 that come out
to be minus 1 that is not possible
negative number is not possible for the
number of law so 25 is not a valuable
illusion a 2016 aramide is nothing worth
20 plus n minus 1 in the spring 16-1 15
e 2 minus 1 that is this is the forcing
number so the top one has 5 logs right
the top has five dogs the total number
of rows we get is 16 that is that 25 is
not possible because if we consider 25
is option the top row should have minus
4 log which is not possible so the top
or have 16 dots correct so what we have
done here we saw that the number of
losses 20 19 18 17 like that way so you
see this is nothing but a ap where the
first time is 20 and the common defense
is minus 1 we found the total term we
got a quiet equation you solve it we got
n is about 25 or 16 and then we found
that 25 is unpossible so n is equal to
60 let's do a quick little summary
automatic probation is the list of
number where each term is obtained by
adding a fixed number to the preceding
down right so that sequences a a plus da
plus 2 D equal to B form also a given
list of number a 1 a 2 a 3 a 3
the difference is constant this a 2 -
even if we - little everything is
constant and the difference is common
difference in terms of a P is nothing
but en is value a plus n minus 1 D the
sum of form of a P is n by 2 into VA
plus n minus 1 D is very efficient
formula also if you know the last term
in first term the sum is also called and
bytom into a plus n thank you visit exam
viacom to watch free education videos
try free online tests in the best
quality study materials study from the
best shooters
mentors and much more thanks again
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Nov 23, 2024 Last updated |
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