CBSE Class 12 > Class 12 Videos > Problem: Wheatstone Bridge Numericals (Part - 22) - Capacitor & Capacitance, Physics, Class 12
Problem Wheatstone Bridge Numericals (Part - 22) - Capacitor & Capacitance,
FAQs on Problem: Wheatstone Bridge Numericals (Part - 22) - Capacitor & Capacitance, Physics, Class 12
| 1. What is a Wheatstone Bridge? |  |
Ans. A Wheatstone Bridge is a circuit used to measure unknown resistance by using a known resistance and a variable resistance. It is based on the principle of null deflection, where the bridge is balanced when the ratio of the resistances in the arms of the bridge is equal.
| 2. How does a Wheatstone Bridge work? | |
Ans. A Wheatstone Bridge works by comparing the ratio of the resistances in two arms of the bridge circuit. When the bridge is balanced, the potential difference across the galvanometer becomes zero, indicating that the ratio of the resistances is equal. This balance condition is used to determine the value of an unknown resistance.
| 3. What is the role of a capacitor in a Wheatstone Bridge? | |
Ans. In a Wheatstone Bridge, a capacitor is used to introduce capacitance into the circuit. It helps in balancing the bridge by compensating for the resistance of the arms. The capacitance value can be adjusted to achieve a balanced condition in the bridge.
| 4. How is capacitance calculated in a Wheatstone Bridge? | |
Ans. The capacitance in a Wheatstone Bridge can be calculated using the formula: C = (R2/R1) * C1 Where C is the unknown capacitance, R1 and R2 are the known resistances in the bridge arms, and C1 is the value of the known capacitance.
| 5. What are the applications of a Wheatstone Bridge in capacitance measurements? | |
Ans. Wheatstone Bridge is widely used in capacitance measurements. Some of its applications include: - Capacitor testing: It can be used to determine the capacitance value of an unknown capacitor. - Quality control: It is used in industries to ensure the quality and accuracy of manufactured capacitors. - Calibration: Wheatstone Bridge is used to calibrate capacitance meters and instruments. - Research and development: It is used in scientific research to study the characteristics of capacitors. - Circuit design: Wheatstone Bridge is used to optimize and design circuits involving capacitors.
Text Transcript from Video
hello friends this video on capacitors
and capacitance part 22 is brought to
you by exam feel calm
no more fear from exam please make sure
that you have watched all the videos
toolbar 21 before going ahead with part
22 now we have concluded the lesson I
have covered almost all the topics not
almost in fact I have covered all the
topics related to capacitors I have also
explained you how to solve circuits to
calculate equivalent capacitance and to
solve problems on energy stored in a
capacitor now it's time that we discuss
certain concepts to show on some more
problems in capacitors because sometimes
it happens that the circuit looks so
very complicated with so many capacitors
that it becomes very tedious to
calculate the equivalent capacitance in
a normal day so there are certain
methods which are often used to follow
such complicated circuits so now we will
discuss some of those methods and I will
also solve one or two problems of each
method so let us start with the one
problem
thank when discuss Falk talks about
beeps tone reach wheatstonebridge please
have certain kind of seconds which looks
somewhat like this what is a Wheatstone
bridge first to see this let us suppose
that you have a circuit which looks
somewhat like this now if you look at
this circuit if I ask you calculate the
equivalent capacitance of this circuit
do you think it is very easy to find it
out no because this is the circuit looks
so messed up so you have to apply two
bunch of planes to see which is in
series with God and which is a parallel
with one right look at the circuit very
carefully so that might give confusion
to your mind sweep stone bridge is a
method for such circuits it sees that if
you have a circuit like this and if C 1
by C 2
is equal to C 3 by C 4 then we say that
the brinch is a balanced bridge okay so
if C 1 by C 2 is equal to C 3 by C 4 we
call this bridge as a balanced bridge
and act then at that situation we see
that the potential at this point is
equal to the potential at this point let
us call this point a and call this point
B then we say that potential at ay is
equal to potential at P so if if you
have a circuit like this and C 1 by C 2
is equal to C 3 by C 4 before you see
that the bridge is balanced so under
that situation the potential at Point a
is equal to the potential at point B so
now if potential at Point a is equal to
potential of point B then what will
happen since there is no potential
difference between a and B that means
there will be no charge flowing through
this capacitor C 5 right because a
capacitor and stores charge only if
there is a finite potential difference
across it because if there is no
potential difference across it if both
the plates of the capacitor have the
same are at the same potential then
there is no scope of storing charge
right so this capacitor C 5 becomes a
dead capacitor so now if I ask you to
calculate the equivalent capacitance of
this circuit you can simply ignore the
capacitor C 5 so you can just draw the
circuit like this so now it is very easy
for you to calculate the equivalent
capacitance between points P and Q
because this circuit is equivalent to
this one
right but this is C 1 this is C 2 this
is C 3 this is C 4 so that means C 1 and
C 2 are in series c3 and c4 are in
series so that means C 1 C 2 ad in
series similarly C 3 C 4
I am series right so let us suppose the
equivalent capacitance of C 1 and C 2
years C - and the C 3 and C 4 is C
double - so what will happen we can
substitute it like this let us call this
C - it is called the C double - and then
C - and C double - are in parallel C
equivalent will be equal to C - the C
double - so this would be the equivalent
capacitance of the circuit so mainly
times you will come across questions
where you will have exactly similar
second which I have drawn now but it
which is similar to this so for such
circuits it is always advisable to
quickly calculate C 1 by C 2 and C 3 by
C 4 they are equal then the bridge is
balanced and then you can very easily
consider this capacitor C 5 as dead
capacitor and then you are set it
becomes really simple now what will
happen if C 1 by C 2 is not equal to C
equals 0 in that case we cannot apply
this rule right so if C 1 by C 2 is not
equal to C 3 by C 4 then we will apply
the other methods which mean I will be
discussing here after so before that let
us quickly solve a problem on no stone
bridge look at this question find the
equivalent capacitance between points P
and Q given the values of C 1 C 2 C 3 C
4 and C 5 so C the bridge which I drew
in the last page is not exactly looking
similar to this one but this also is the
same is of the same pattern so see you
have to judge the pattern yourself for
example you draw this at your own
convenience point B Point Q draw it in
the same manner
as I taught you so from point P it is
going to C 1 and C key so from point B
it is going to C 1 and C 3 so this is C
1 and this is C 3 similarly from point Q
it is going to C 2 and C 4 so this is
going C 2 and C 4 okay then what is
happening C 2 is getting connected to C
1 right so C 2 is getting connected C 1
now if you so C 2 and C 1 is then what
about C 3 C 3 is getting connected C 4
so C 3 is getting connected to C 4 what
about C 5 C 5 is getting connected to
these two points the point which is
connecting C 1 and C 2 that is the point
which is connecting C 1 and C 2 is this
and the point which is connecting C 3
and C 4 that is this so C 1 is located
midway between these two points right so
now this it resemble the last circuit
which I deal with the last page okay so
this is a pitch this looks like a
Wheatstone bridge now let us calculate C
1 by C what is C 1 by C 2 here C 1 and C
2 are all for my program
so C 1 by C 2 is 1 let us calculate C 3
by C 4 C 3 by C 4 is also all Row 4 so
this is also 1 therefore therefore we
can see that C 5 ends up dead capacitor
so we can draw the circuit like this C 1
C 2 C 3 C 4 this is C 1 this is C 2 this
is C 3 and this is C 4 so let us look at
calculates in C - that is the series
combination of C 1 and C key so what
will you see that 1 by C dash is equal
to 1 by C 1 plus 1 by C 2 so 1 by C 1 is
1 by 4 plus 1 by C 2 is 1 by 4 so this
is equal to 1 by 2 dr. C dash
two microphones similarly let us
calculate Z double - that is the
equivalent capacitance of series
formulation of seeking xe4 so that will
be 1 by C double dash is equal to 1 by C
3 plus 1 by C food that will also be 1
by thing C double dash will also be
equal to 2 micro farad's so what would
be the equivalent capacitance of the
circuit that will be C dash + C Double
Dash in fact less than the C dash plus C
Double Dash so that is 2 plus 2 which is
equal to 4 micro farad this would be the
equivalent capacitance of this second so
this is how you approach problems on
Wheatstone bridge
thank you please visit exam viacom to
watch free educational videos drive free
online tests get the best quality study
materials
study from the best tutors and mentors
and much moon thank you once again
and capacitance part 22 is brought to
you by exam feel calm
no more fear from exam please make sure
that you have watched all the videos
toolbar 21 before going ahead with part
22 now we have concluded the lesson I
have covered almost all the topics not
almost in fact I have covered all the
topics related to capacitors I have also
explained you how to solve circuits to
calculate equivalent capacitance and to
solve problems on energy stored in a
capacitor now it's time that we discuss
certain concepts to show on some more
problems in capacitors because sometimes
it happens that the circuit looks so
very complicated with so many capacitors
that it becomes very tedious to
calculate the equivalent capacitance in
a normal day so there are certain
methods which are often used to follow
such complicated circuits so now we will
discuss some of those methods and I will
also solve one or two problems of each
method so let us start with the one
problem
thank when discuss Falk talks about
beeps tone reach wheatstonebridge please
have certain kind of seconds which looks
somewhat like this what is a Wheatstone
bridge first to see this let us suppose
that you have a circuit which looks
somewhat like this now if you look at
this circuit if I ask you calculate the
equivalent capacitance of this circuit
do you think it is very easy to find it
out no because this is the circuit looks
so messed up so you have to apply two
bunch of planes to see which is in
series with God and which is a parallel
with one right look at the circuit very
carefully so that might give confusion
to your mind sweep stone bridge is a
method for such circuits it sees that if
you have a circuit like this and if C 1
by C 2
is equal to C 3 by C 4 then we say that
the brinch is a balanced bridge okay so
if C 1 by C 2 is equal to C 3 by C 4 we
call this bridge as a balanced bridge
and act then at that situation we see
that the potential at this point is
equal to the potential at this point let
us call this point a and call this point
B then we say that potential at ay is
equal to potential at P so if if you
have a circuit like this and C 1 by C 2
is equal to C 3 by C 4 before you see
that the bridge is balanced so under
that situation the potential at Point a
is equal to the potential at point B so
now if potential at Point a is equal to
potential of point B then what will
happen since there is no potential
difference between a and B that means
there will be no charge flowing through
this capacitor C 5 right because a
capacitor and stores charge only if
there is a finite potential difference
across it because if there is no
potential difference across it if both
the plates of the capacitor have the
same are at the same potential then
there is no scope of storing charge
right so this capacitor C 5 becomes a
dead capacitor so now if I ask you to
calculate the equivalent capacitance of
this circuit you can simply ignore the
capacitor C 5 so you can just draw the
circuit like this so now it is very easy
for you to calculate the equivalent
capacitance between points P and Q
because this circuit is equivalent to
this one
right but this is C 1 this is C 2 this
is C 3 this is C 4 so that means C 1 and
C 2 are in series c3 and c4 are in
series so that means C 1 C 2 ad in
series similarly C 3 C 4
I am series right so let us suppose the
equivalent capacitance of C 1 and C 2
years C - and the C 3 and C 4 is C
double - so what will happen we can
substitute it like this let us call this
C - it is called the C double - and then
C - and C double - are in parallel C
equivalent will be equal to C - the C
double - so this would be the equivalent
capacitance of the circuit so mainly
times you will come across questions
where you will have exactly similar
second which I have drawn now but it
which is similar to this so for such
circuits it is always advisable to
quickly calculate C 1 by C 2 and C 3 by
C 4 they are equal then the bridge is
balanced and then you can very easily
consider this capacitor C 5 as dead
capacitor and then you are set it
becomes really simple now what will
happen if C 1 by C 2 is not equal to C
equals 0 in that case we cannot apply
this rule right so if C 1 by C 2 is not
equal to C 3 by C 4 then we will apply
the other methods which mean I will be
discussing here after so before that let
us quickly solve a problem on no stone
bridge look at this question find the
equivalent capacitance between points P
and Q given the values of C 1 C 2 C 3 C
4 and C 5 so C the bridge which I drew
in the last page is not exactly looking
similar to this one but this also is the
same is of the same pattern so see you
have to judge the pattern yourself for
example you draw this at your own
convenience point B Point Q draw it in
the same manner
as I taught you so from point P it is
going to C 1 and C key so from point B
it is going to C 1 and C 3 so this is C
1 and this is C 3 similarly from point Q
it is going to C 2 and C 4 so this is
going C 2 and C 4 okay then what is
happening C 2 is getting connected to C
1 right so C 2 is getting connected C 1
now if you so C 2 and C 1 is then what
about C 3 C 3 is getting connected C 4
so C 3 is getting connected to C 4 what
about C 5 C 5 is getting connected to
these two points the point which is
connecting C 1 and C 2 that is the point
which is connecting C 1 and C 2 is this
and the point which is connecting C 3
and C 4 that is this so C 1 is located
midway between these two points right so
now this it resemble the last circuit
which I deal with the last page okay so
this is a pitch this looks like a
Wheatstone bridge now let us calculate C
1 by C what is C 1 by C 2 here C 1 and C
2 are all for my program
so C 1 by C 2 is 1 let us calculate C 3
by C 4 C 3 by C 4 is also all Row 4 so
this is also 1 therefore therefore we
can see that C 5 ends up dead capacitor
so we can draw the circuit like this C 1
C 2 C 3 C 4 this is C 1 this is C 2 this
is C 3 and this is C 4 so let us look at
calculates in C - that is the series
combination of C 1 and C key so what
will you see that 1 by C dash is equal
to 1 by C 1 plus 1 by C 2 so 1 by C 1 is
1 by 4 plus 1 by C 2 is 1 by 4 so this
is equal to 1 by 2 dr. C dash
two microphones similarly let us
calculate Z double - that is the
equivalent capacitance of series
formulation of seeking xe4 so that will
be 1 by C double dash is equal to 1 by C
3 plus 1 by C food that will also be 1
by thing C double dash will also be
equal to 2 micro farad's so what would
be the equivalent capacitance of the
circuit that will be C dash + C Double
Dash in fact less than the C dash plus C
Double Dash so that is 2 plus 2 which is
equal to 4 micro farad this would be the
equivalent capacitance of this second so
this is how you approach problems on
Wheatstone bridge
thank you please visit exam viacom to
watch free educational videos drive free
online tests get the best quality study
materials
study from the best tutors and mentors
and much moon thank you once again
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