JEE Exam  >  JEE Videos  >  Mathematics (Maths) Class 12  >  Equation of a Plane in Normal Form, Equation of a Plane Perpendicular to a given Vector

Equation of a Plane in Normal Form, Equation of a Plane Perpendicular to a given Vector Video Lecture | Mathematics (Maths) Class 12 - JEE

204 videos|288 docs|139 tests

FAQs on Equation of a Plane in Normal Form, Equation of a Plane Perpendicular to a given Vector Video Lecture - Mathematics (Maths) Class 12 - JEE

1. What is the equation of a plane in normal form?
Ans. The equation of a plane in normal form is given by Ax + By + Cz = D, where A, B, and C are the components of the normal vector to the plane and D is a constant.
2. How can I find the equation of a plane perpendicular to a given vector?
Ans. To find the equation of a plane perpendicular to a given vector, you can use the normal form equation. The components of the given vector will be A, B, and C in the equation, and you can choose any value for D.
3. What does the normal vector represent in the equation of a plane?
Ans. The normal vector in the equation of a plane represents the direction perpendicular to the plane. It is the vector that is orthogonal to all vectors lying in the plane.
4. Can the equation of a plane have negative coefficients?
Ans. Yes, the equation of a plane can have negative coefficients. The signs of the coefficients determine the direction of the normal vector, but they do not affect the position or orientation of the plane itself.
5. Is it possible to write the equation of a plane in point-normal form?
Ans. Yes, it is possible to write the equation of a plane in point-normal form. This form is given by (x - x0)A + (y - y0)B + (z - z0)C = 0, where (x0, y0, z0) is a point on the plane and A, B, and C are the components of the normal vector.
204 videos|288 docs|139 tests
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