Mechanical Engineering Exam > Mechanical Engineering Videos > Topper Handwritten Notes & Videos for GATE ME > Heat Exchange Between Non Black Bodies Shield Concept HMT Tutorial- 28, Heat and Mass Transfer, GATE
Heat Exchange Between Non Black Bodies Shield Concept HMT Tutorial- 28, Heat and Mass Transfer, GATE Video Lecture | Topper Handwritten Notes & Videos for GATE ME - Mechanical Engineering
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FAQs on Heat Exchange Between Non Black Bodies Shield Concept HMT Tutorial- 28, Heat and Mass Transfer, GATE Video Lecture - Topper Handwritten Notes & Videos for GATE ME - Mechanical Engineering
| 1. What is heat exchange between non-black bodies? |  |
Ans. Heat exchange between non-black bodies refers to the transfer of thermal energy between objects that do not absorb or emit radiation equally at all wavelengths. Unlike black bodies, which absorb and emit radiation perfectly, non-black bodies have a selective absorption and emission spectrum, resulting in different heat exchange characteristics.
| 2. What is the shield concept in heat exchange? | |
Ans. The shield concept in heat exchange involves the use of a barrier or shield between two objects to minimize the heat transfer between them. The shield acts as a thermal insulator, reducing the conduction, convection, and radiation heat transfer. It helps to maintain temperature differences and control the heat flow between the objects.
| 3. How is the heat exchange between non-black bodies different from black bodies? | |
Ans. Heat exchange between non-black bodies differs from black bodies in terms of their radiation properties. Non-black bodies have selective absorption and emission characteristics, meaning they absorb and emit radiation at specific wavelengths. In contrast, black bodies absorb and emit radiation equally at all wavelengths. This difference in absorption and emission properties affects the heat exchange behavior.
| 4. What are some factors that affect heat exchange between non-black bodies? | |
Ans. Several factors influence heat exchange between non-black bodies, including surface emissivity, temperature difference, surface area, distance between objects, and the presence of any shielding materials. These factors determine the rate and direction of heat transfer, and understanding their impact is crucial for analyzing and designing heat exchange systems.
| 5. Can the shield concept be applied to all heat exchange scenarios? | |
Ans. The shield concept can be applied to many heat exchange scenarios, but its effectiveness depends on the specific conditions and requirements of the system. In some cases, a shield may not be suitable or practical due to space limitations, cost constraints, or other factors. It is important to evaluate the feasibility and benefits of using a shield based on the specific heat exchange requirements and constraints of the system.
Text Transcript from Video
all right my dear so today in this video
I'm going to share with you non black
okay I'm going to share with you
heat accents between two non black
bodies when there is it external
elements is inserted that is shield okay
so basically what happened what happen
if you were talking about you know
cylinder or concentric cylinder doesn't
click cylinder when we are having two
cylinders or two concentric cylinders in
that case we are having different
formula to find out heat transfer rate
that is cube and that should be in fuel
per second or what we are having
different formula okay now in case of
shield and conceptive cylinder we are
having different formulas also but here
it truly in get 2003 get 2003 they have
asked the question there is room and
there is a you know there is a plate
play this hanging inside the room plate
is having some area as well as row with
room is having some area so this is
suppose at a one this suppose that a
tools if in this type of numerical
problem will face in case of radiation
and ejections between two non black
bodies then what would be the formula to
find out numerical problem were to find
out required things what we need to find
out in that problem what should be the
formula for that so for this Q is equal
to we are having a formula Sigma a 1 T 1
to the power 4 minus T 2 to the power 4
1 by epsilon 1 a1 by a2 1 by epsilon 2
minus 1 you can also write like this
Sigma T 1 to the power 4 T 2 to the
power 4 1 by epsilon 1 a1 1 minus
epsilon 2 a 2 xn to both the same which
will simplify this above equation but
definitely we are going to get this
value so this is a formula for Q okay
now if we if we will solve that
numerical problem which has
being asked in gate 2003 then definitely
you are going to so I mean we're going
to get the approach to solve problems if
you get such type of things it's not a
case on it's not only case or per room
as well as a clearly you can see if they
are you sitting there is a you know we
can say there is a play there is a
cylinder in the in a cylinder
there is something we are putting but
suppose that if there is a room and the
wall is having wood in between two walls
suppose that this is a wall okay this is
the first part of a wall and this is the
second part of the wall in between this
one we are putting different material
different material okay at this type of
things we generally do in case of in
case we are building something in the
desert okay for for decreasing heat
transfer rate that's why inside the room
who is leaving will not feel that much
hot as compared to the surrounding okay
so this is all about that what I wanted
to share with you but the most important
thing is this is how to sort numerical
problem which has been asking gate once
you will come to know how to solve the
problem then my purpose of making this
video will be fulfilled
okay I hope you wanted to learn
numerical problems not theoretical but
theory is good but once you will build
up approach to solve numerical problem
then that becomes quite interesting for
everybody those are preparing for
complete examination just like create as
a CJ okay so this is a this is the
question has right now in front of you I
hope you can read the question that's
why I've written in that way okay so I
don't want to read the question you can
read this question after pausing the
video okay so what happens actually how
we can solve the question okay once you
got the question in gate well so in that
case how you should solve the question
that is important right I'll share with
you the exactly so first of all find out
what you need to find out in the problem
once you will come to know what you need
to find out in the problem then your
problem solved because you can write
down the formula for finding out the
thing
you need to find out okay so in this
case what we need to find the heat loss
from two surfaces of the plate okay
so once you will come to know one queue
you can multiple without depth you with
two that definitely you can find out too
because there they did not share with
you anything about the wall in this
problem okay so we are we are just
considering both the wall having similar
values okay so suppose that we are
having this and now area of inside
hanging a plate area is 10 centimeter
square so area of the plate is 10
centimeter square therefore this will
become 10 to the power minus 4 meter
square I am converting all even seen to
SI unit so 10 to the power minus 3 meter
square right
after conversion what we call and the
room the area of the room is 100 meter
square okay now let me write down the
formula first Q is equal to what we
write we have dignity 1 Sigma T 1 to the
power 4 minus T 2 to the power 4 1 by
epsilon 1 a1 by a2 1 by epsilon 2 minus
1 okay so this is the formula now till
now what we got values a1 and a2 we got
these two values now we have to find out
T 1 and T 2 and Sigma all to given T 1
okay this one is this one for epsilon 2
is here T 2 is here and epsilon 1 is
here and T 1 is here okay so this is all
values we required to find out the value
of Q heat transfer rate so just what if
we need to do we need to put all values
right away and in this case once will
come to know how to solve the quotient
don't be hesitate or don't get
distracted from the question just keep
your concentration on the top that's why
will not mix mistake at this point if we
make mistake then what's the use of
understanding the question and knowing
all formulas nothing so remember my dear
friend once will come to know how to
solve the question then come eat
and solve the question right there so I
will get the right answer
alright so a 1 is how much we have given
10 to the power minus 3 Sigma 5 into 10
to the power minus 6 sorry first 10 5 to
the power 5 5 point 6 7 into 10 to the
power minus 8 t 1 is 800 so 800 to the
power 4 T 2 is here 300 differ for now 1
by epsilon 1 epsilon 1 is 0.6 okay II 1
10 to the power minus 3 a 200 1 by
epsilon 2 point 3 minus 1 they can see
your point 3 right so all values we have
written right now and all these things
it's just in front of you for your
better understanding now what right now
we required the most can amazing my dear
can tell me what do we required right
now I know you are thinking about
calculated that's right we need
calculator to solve the problem without
calculator at this point it would be
difficult for us right so let's go for
the calculator so here we got the
calculator and what we call first we
need to solve this lower part so first
1/3 divide - 1 is into 10 to the power
minus 3 divided by 800 okay that's okay
okay we got this now plus 1 divided by
0.6 so this is how much we are getting
here one point six six six nine okay so
always take up to four decimal values
there so I will avoid error okay now we
have to solve this one so 800 to the
power 4 minus 300 to the power 4 so how
much this is okay into 10 to the power
minus 3 multiple 5 point 6 7 into 10 to
the power minus 8 okay always try to
come come to know how to solve how we
use calculator and of course you need to
you need to learn how to use calculator
online calculator because indeed you are
not going to get this one okay
cause dude is gone when he can use this
calculator okay now I am sharing with
you that how to stall how to practice
okay well I will definitely recommend
you to do one thing put eyes at your
home
that's why by using all in callable
that's why i will not face problem
directly whenever you will see it or
write the gate examination right so how
much we are getting here 22 points 7 6 5
0 5 ok now divide this value with 1
point 3 / 6 line how much we are getting
here 13 13 point 6 5 7
okay that's Q that means what okay so I
am it will be you need to be in what so
what we got 13 point 6 but most
important fact here you are going to
make mistake you will just do one thing
what he'll just you will just mark the
right answer maybe thirteen point six
seven oh this one you don't do this if
we do this then definitely you are
making mistake and I mean knowing even
knowing after the problem will you will
make mistake because total heat loss so
there's a room and there is a plate so
heat loss must be from both the side so
you have to multiple the answer with two
so what we got exactly here thirteen
point six five seven multiple two so
twenty seven point three one twenty
seven point three one so B is the right
answer
I hope you understand the problem okay
so be calm and be happy
thanks for watching see you soon in my
next video bye bye
I'm going to share with you non black
okay I'm going to share with you
heat accents between two non black
bodies when there is it external
elements is inserted that is shield okay
so basically what happened what happen
if you were talking about you know
cylinder or concentric cylinder doesn't
click cylinder when we are having two
cylinders or two concentric cylinders in
that case we are having different
formula to find out heat transfer rate
that is cube and that should be in fuel
per second or what we are having
different formula okay now in case of
shield and conceptive cylinder we are
having different formulas also but here
it truly in get 2003 get 2003 they have
asked the question there is room and
there is a you know there is a plate
play this hanging inside the room plate
is having some area as well as row with
room is having some area so this is
suppose at a one this suppose that a
tools if in this type of numerical
problem will face in case of radiation
and ejections between two non black
bodies then what would be the formula to
find out numerical problem were to find
out required things what we need to find
out in that problem what should be the
formula for that so for this Q is equal
to we are having a formula Sigma a 1 T 1
to the power 4 minus T 2 to the power 4
1 by epsilon 1 a1 by a2 1 by epsilon 2
minus 1 you can also write like this
Sigma T 1 to the power 4 T 2 to the
power 4 1 by epsilon 1 a1 1 minus
epsilon 2 a 2 xn to both the same which
will simplify this above equation but
definitely we are going to get this
value so this is a formula for Q okay
now if we if we will solve that
numerical problem which has
being asked in gate 2003 then definitely
you are going to so I mean we're going
to get the approach to solve problems if
you get such type of things it's not a
case on it's not only case or per room
as well as a clearly you can see if they
are you sitting there is a you know we
can say there is a play there is a
cylinder in the in a cylinder
there is something we are putting but
suppose that if there is a room and the
wall is having wood in between two walls
suppose that this is a wall okay this is
the first part of a wall and this is the
second part of the wall in between this
one we are putting different material
different material okay at this type of
things we generally do in case of in
case we are building something in the
desert okay for for decreasing heat
transfer rate that's why inside the room
who is leaving will not feel that much
hot as compared to the surrounding okay
so this is all about that what I wanted
to share with you but the most important
thing is this is how to sort numerical
problem which has been asking gate once
you will come to know how to solve the
problem then my purpose of making this
video will be fulfilled
okay I hope you wanted to learn
numerical problems not theoretical but
theory is good but once you will build
up approach to solve numerical problem
then that becomes quite interesting for
everybody those are preparing for
complete examination just like create as
a CJ okay so this is a this is the
question has right now in front of you I
hope you can read the question that's
why I've written in that way okay so I
don't want to read the question you can
read this question after pausing the
video okay so what happens actually how
we can solve the question okay once you
got the question in gate well so in that
case how you should solve the question
that is important right I'll share with
you the exactly so first of all find out
what you need to find out in the problem
once you will come to know what you need
to find out in the problem then your
problem solved because you can write
down the formula for finding out the
thing
you need to find out okay so in this
case what we need to find the heat loss
from two surfaces of the plate okay
so once you will come to know one queue
you can multiple without depth you with
two that definitely you can find out too
because there they did not share with
you anything about the wall in this
problem okay so we are we are just
considering both the wall having similar
values okay so suppose that we are
having this and now area of inside
hanging a plate area is 10 centimeter
square so area of the plate is 10
centimeter square therefore this will
become 10 to the power minus 4 meter
square I am converting all even seen to
SI unit so 10 to the power minus 3 meter
square right
after conversion what we call and the
room the area of the room is 100 meter
square okay now let me write down the
formula first Q is equal to what we
write we have dignity 1 Sigma T 1 to the
power 4 minus T 2 to the power 4 1 by
epsilon 1 a1 by a2 1 by epsilon 2 minus
1 okay so this is the formula now till
now what we got values a1 and a2 we got
these two values now we have to find out
T 1 and T 2 and Sigma all to given T 1
okay this one is this one for epsilon 2
is here T 2 is here and epsilon 1 is
here and T 1 is here okay so this is all
values we required to find out the value
of Q heat transfer rate so just what if
we need to do we need to put all values
right away and in this case once will
come to know how to solve the quotient
don't be hesitate or don't get
distracted from the question just keep
your concentration on the top that's why
will not mix mistake at this point if we
make mistake then what's the use of
understanding the question and knowing
all formulas nothing so remember my dear
friend once will come to know how to
solve the question then come eat
and solve the question right there so I
will get the right answer
alright so a 1 is how much we have given
10 to the power minus 3 Sigma 5 into 10
to the power minus 6 sorry first 10 5 to
the power 5 5 point 6 7 into 10 to the
power minus 8 t 1 is 800 so 800 to the
power 4 T 2 is here 300 differ for now 1
by epsilon 1 epsilon 1 is 0.6 okay II 1
10 to the power minus 3 a 200 1 by
epsilon 2 point 3 minus 1 they can see
your point 3 right so all values we have
written right now and all these things
it's just in front of you for your
better understanding now what right now
we required the most can amazing my dear
can tell me what do we required right
now I know you are thinking about
calculated that's right we need
calculator to solve the problem without
calculator at this point it would be
difficult for us right so let's go for
the calculator so here we got the
calculator and what we call first we
need to solve this lower part so first
1/3 divide - 1 is into 10 to the power
minus 3 divided by 800 okay that's okay
okay we got this now plus 1 divided by
0.6 so this is how much we are getting
here one point six six six nine okay so
always take up to four decimal values
there so I will avoid error okay now we
have to solve this one so 800 to the
power 4 minus 300 to the power 4 so how
much this is okay into 10 to the power
minus 3 multiple 5 point 6 7 into 10 to
the power minus 8 okay always try to
come come to know how to solve how we
use calculator and of course you need to
you need to learn how to use calculator
online calculator because indeed you are
not going to get this one okay
cause dude is gone when he can use this
calculator okay now I am sharing with
you that how to stall how to practice
okay well I will definitely recommend
you to do one thing put eyes at your
home
that's why by using all in callable
that's why i will not face problem
directly whenever you will see it or
write the gate examination right so how
much we are getting here 22 points 7 6 5
0 5 ok now divide this value with 1
point 3 / 6 line how much we are getting
here 13 13 point 6 5 7
okay that's Q that means what okay so I
am it will be you need to be in what so
what we got 13 point 6 but most
important fact here you are going to
make mistake you will just do one thing
what he'll just you will just mark the
right answer maybe thirteen point six
seven oh this one you don't do this if
we do this then definitely you are
making mistake and I mean knowing even
knowing after the problem will you will
make mistake because total heat loss so
there's a room and there is a plate so
heat loss must be from both the side so
you have to multiple the answer with two
so what we got exactly here thirteen
point six five seven multiple two so
twenty seven point three one twenty
seven point three one so B is the right
answer
I hope you understand the problem okay
so be calm and be happy
thanks for watching see you soon in my
next video bye bye
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Nov 22, 2024 Last updated |
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