Class 7 Exam > Class 7 Videos > Examples: Solving by Transposing
Examples: Solving by Transposing Video Lecture - Class 7
FAQs on Examples: Solving by Transposing Video Lecture - Class 7
| 1. What is transposing in mathematics? |  |
Ans. Transposing in mathematics refers to the process of rearranging an equation to isolate a particular variable on one side of the equation. This is done by performing the inverse operation on both sides of the equation.
| 2. Why is transposing used in solving equations? | |
Ans. Transposing is used in solving equations to make it easier to find the value of a specific variable. By rearranging the equation and isolating the variable, we can simplify the problem and solve for the unknown value.
| 3. Can transposing be used in all types of equations? | |
Ans. Yes, transposing can be used in all types of equations, including linear equations, quadratic equations, and simultaneous equations. It is a versatile technique that helps in solving various mathematical problems.
| 4. What are the steps involved in transposing an equation? | |
Ans. The steps involved in transposing an equation are as follows:
1. Identify the variable you want to isolate.
2. Perform the inverse operation on both sides of the equation to move all terms except the one with the variable to the other side.
3. Simplify the equation by combining like terms, if necessary.
4. Check your solution by substituting the value of the variable back into the original equation.
| 5. Are there any limitations or restrictions when transposing an equation? | |
Ans. While transposing an equation, it is important to note that any operation performed on one side of the equation must also be performed on the other side to maintain equality. Additionally, dividing or multiplying by variables requires caution as it may introduce extraneous solutions. It is crucial to check the validity of the solution obtained by substituting it back into the original equation.
Text Transcript from Video
hello friends this video on simple
equations part eight is brought to you
by exam fee or comm know about fear from
exam question number eight 3 minus 2
into 2 minus y is equal to 7 so in this
case which is the term that you will
shift the first that is nothing but this
3 so let us first move 3 to right hand
side so what will happen it will become
minus 2 into 2 minus y is equal to 7
minus 3 so this is nothing but minus 2
into 2 minus y is equal to 4 right so
now here one very interesting thing that
we will observe is the next thing that
we are going to shift is this minus 2
now how is this my wish to present on
the left hand side this is something you
need to understand now when we say minus
2 into 2 minus y what does this mean
this basically means that minus 2 is a
number which is getting multiplied to 2
minus 5 so therefore when this minus 2
shifts to the other side what is going
to happen it is going to become divided
by minus 2
now many a times students get confused
they feel that okay they say we have
minus 2 so when this term goes to the
other side it will become plus 2 no
that's because whatever whenever
transposing is happening there is
reversal of the operation so if a number
is getting added on them to inside in
that case when it is transposed to the
number gets subtracted on the right hand
side similarly if a now it is getting
multiplied on the right hand side the my
clique number will get divided on the
left hand side so that is the thing that
we follow so in this case this 2 is not
getting subtracted from any number minus
2 basically is a negative number which
is getting multiplied to another number
so basically the operation is
multiplication so this is a number so
minus 2 is
but as a whole and here - - is getting
multiplied therefore the moment it gets
shifted to the other side the number
will remain - - but this time it will
get divided so that's one important
thing to understand so that you do not
get confused so in this case we are
going to shift - to here so what will
happen this side will be 2 - y and this
same it would be 4 divided by minus 2
the four divided by minus 2 is equal to
minus 2 so now - y is equal to minus 2
now we will also shift this to the
center this time the 2 is actively
getting added to the snuper's therefore
when it comes to this side it becomes
minus 2 so therefore minus y is equal to
minus 4 so both sides you have - - which
tells that y is equal to 4 why do we
like why did we write like this that's
because if you multiply minus 1 on both
sides what will happen this side will
become wild this side will become 4 so
we can say that Y is equal to 4 is a
solution of this equation question
number 9 34 minus 5 into P minus 1 is
equal to 4 so in this case also first of
all we will shift this constant term so
it becomes minus 5 P minus 1 is equal to
4 minus 34 so this can be written as
minus 5 into P minus 1 is equal to minus
30 now this in turn calculated as P
minus 1 is equal to minus 30 divided by
minus 5 thats because here it was minus
5 into this down so when - fire gets
shifted to the side it becomes divided
by so 5 6 to 30 and minus - gives plus
therefore you get 5 P minus 1 is equal
to 6 therefore P is equal to 6 plus 1
which is equal to 7 therefore P is equal
to 7 is the solution for this equation
question number 10 0 is equal to 16 plus
4 into M
six so here also the same thing we will
have to bring all the variables on one
side so let us try to bring the
variables on the left-hand side and the
constants on the right hand side so how
can we do that let's see how do we do
that
so for now let us first shift the
constants
let's bring the constants in this side
so this becomes minus 16 is equal to 4
into M minus 6 now if you write minus 16
is equal to 4 into M minus 6 if you
shift this if you want you can like the
entire left hand side as right hand side
and the entire right hand side is left
hand side but this you can only do when
you are taking the entire left hand side
and writing it into the right hand side
and vice versa so this can be written as
4 into M minus 6 is equal to -16 do they
mean the same thing then so this from
here now we will shift to the 4 so this
becomes M minus 6 is equal to minus 16
divided by 4 so for force is 16 so we
get M minus 6 is equal to minus 4 or you
can see M is equal to minus 4 plus 6
which is equal to 2 therefore M is equal
to 2 is a solution for this equation
thank you please visit exampie or come
for free quality education you can learn
with a simple four-step learning process
wherein you can watch video lessons you
can ask your questions you can refer
notes and you can take a free online
test we have content for class 6 to 12
on physics chemistry mathematics and
biology along with practical videos so
please subscribe to our channel for
daily updates thank you
equations part eight is brought to you
by exam fee or comm know about fear from
exam question number eight 3 minus 2
into 2 minus y is equal to 7 so in this
case which is the term that you will
shift the first that is nothing but this
3 so let us first move 3 to right hand
side so what will happen it will become
minus 2 into 2 minus y is equal to 7
minus 3 so this is nothing but minus 2
into 2 minus y is equal to 4 right so
now here one very interesting thing that
we will observe is the next thing that
we are going to shift is this minus 2
now how is this my wish to present on
the left hand side this is something you
need to understand now when we say minus
2 into 2 minus y what does this mean
this basically means that minus 2 is a
number which is getting multiplied to 2
minus 5 so therefore when this minus 2
shifts to the other side what is going
to happen it is going to become divided
by minus 2
now many a times students get confused
they feel that okay they say we have
minus 2 so when this term goes to the
other side it will become plus 2 no
that's because whatever whenever
transposing is happening there is
reversal of the operation so if a number
is getting added on them to inside in
that case when it is transposed to the
number gets subtracted on the right hand
side similarly if a now it is getting
multiplied on the right hand side the my
clique number will get divided on the
left hand side so that is the thing that
we follow so in this case this 2 is not
getting subtracted from any number minus
2 basically is a negative number which
is getting multiplied to another number
so basically the operation is
multiplication so this is a number so
minus 2 is
but as a whole and here - - is getting
multiplied therefore the moment it gets
shifted to the other side the number
will remain - - but this time it will
get divided so that's one important
thing to understand so that you do not
get confused so in this case we are
going to shift - to here so what will
happen this side will be 2 - y and this
same it would be 4 divided by minus 2
the four divided by minus 2 is equal to
minus 2 so now - y is equal to minus 2
now we will also shift this to the
center this time the 2 is actively
getting added to the snuper's therefore
when it comes to this side it becomes
minus 2 so therefore minus y is equal to
minus 4 so both sides you have - - which
tells that y is equal to 4 why do we
like why did we write like this that's
because if you multiply minus 1 on both
sides what will happen this side will
become wild this side will become 4 so
we can say that Y is equal to 4 is a
solution of this equation question
number 9 34 minus 5 into P minus 1 is
equal to 4 so in this case also first of
all we will shift this constant term so
it becomes minus 5 P minus 1 is equal to
4 minus 34 so this can be written as
minus 5 into P minus 1 is equal to minus
30 now this in turn calculated as P
minus 1 is equal to minus 30 divided by
minus 5 thats because here it was minus
5 into this down so when - fire gets
shifted to the side it becomes divided
by so 5 6 to 30 and minus - gives plus
therefore you get 5 P minus 1 is equal
to 6 therefore P is equal to 6 plus 1
which is equal to 7 therefore P is equal
to 7 is the solution for this equation
question number 10 0 is equal to 16 plus
4 into M
six so here also the same thing we will
have to bring all the variables on one
side so let us try to bring the
variables on the left-hand side and the
constants on the right hand side so how
can we do that let's see how do we do
that
so for now let us first shift the
constants
let's bring the constants in this side
so this becomes minus 16 is equal to 4
into M minus 6 now if you write minus 16
is equal to 4 into M minus 6 if you
shift this if you want you can like the
entire left hand side as right hand side
and the entire right hand side is left
hand side but this you can only do when
you are taking the entire left hand side
and writing it into the right hand side
and vice versa so this can be written as
4 into M minus 6 is equal to -16 do they
mean the same thing then so this from
here now we will shift to the 4 so this
becomes M minus 6 is equal to minus 16
divided by 4 so for force is 16 so we
get M minus 6 is equal to minus 4 or you
can see M is equal to minus 4 plus 6
which is equal to 2 therefore M is equal
to 2 is a solution for this equation
thank you please visit exampie or come
for free quality education you can learn
with a simple four-step learning process
wherein you can watch video lessons you
can ask your questions you can refer
notes and you can take a free online
test we have content for class 6 to 12
on physics chemistry mathematics and
biology along with practical videos so
please subscribe to our channel for
daily updates thank you
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Nov 15, 2024 Last updated |
Examples: Solving by Transposing for Class 72024 is part of Class 7 preparation. The notes and questions for Examples: Solving by Transposing
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