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The line current in a three phase unbalanced load are Ia = 4 + j6, Ib = 2 - j2, Ic = -3 + j2, then zero sequence component of current will be
  • a)
    3 + j6
  • b)
    9 + j10
  • c)
    1 + j2
  • d)
    3 - j6
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
The line current in a three phase unbalanced load are Ia = 4 + j6, Ib ...
Concept:
The relation between the line currents in terms of the symmetrical components of currents is given below.
Ia0 = Zero Sequence Component of Current
Ia1 = Positive Sequence Component of Current
Ia2 = Negative Sequence Component of Current
a = 1∠120°, which represents the rotation of 120° in the clockwise direction.
a2 = 1∠-120° or 1∠240° in anticlockwise direction or clockwise direction, respectively.
1 + a + a2 = 0
Calculation:
Given that
Ia = 4 + j6, Ib = 2 - j2, Ic = -3 + j2
Zero sequence component of current,

∴ I0 = 1 + j2 A
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Community Answer
The line current in a three phase unbalanced load are Ia = 4 + j6, Ib ...
Zero Sequence Component of Current in Unbalanced Load

Given values:
Ia = 4 + j6
Ib = 2 - j2
Ic = -3 + j2

To find the zero sequence component of current, we need to calculate the average of the three phase currents.

Step 1: Calculate the average of the three phase currents
Iavg = (Ia + Ib + Ic) / 3
= (4 + j6 + 2 - j2 - 3 + j2) / 3
= (3 + j6) / 3
= 1 + j2

Step 2: The zero sequence component is given by the equation:
I0 = (Ia + Ib + Ic) / 3 - Iavg
= (4 + j6 + 2 - j2 - 3 + j2) / 3 - (1 + j2)
= (3 + j6) / 3 - (1 + j2)
= 3/3 + j6/3 - 1/3 - j2/3
= 1 + j2 - 1/3 - j2/3
= 1 - 1/3 + j2 - j2/3
= 2/3 + j4/3

Therefore, the zero sequence component of current is 2/3 + j4/3, which is expressed as 1 + j2 in rectangular form.

Hence, the correct answer is option 'C' - 1 + j2.
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