All questions of Active Filters for Electrical Engineering (EE) Exam

The output waveform of CLC filter is superimposed by a waveform referred to as_________
  • a)
    Square wave
  • b)
    Triangular wave
  • c)
    Saw tooth wave
  • d)
    Sine wave
Correct answer is option 'C'. Can you explain this answer?

Moumita Chopra answered
Since the rectifier conducts current only in the forward direction, any energy discharged by the capacitor will flow into the load. This result in a DC voltage upon which is superimposed a waveform referred to as a saw tooth wave.

The advantages of a pi-filter is_________
  • a)
    low output voltage
  • b)
    low PIV
  • c)
    low ripple factor
  • d)
    high voltage regulation
Correct answer is option 'C'. Can you explain this answer?

Mihir Chawla answered
Advantages of a Pi-Filter

A Pi-filter is a type of LC filter commonly used in power supply circuits to reduce ripple voltage. It consists of two capacitors and one inductor arranged in the shape of a Pi symbol. The Pi-filter is designed to provide a low ripple factor, which is one of its major advantages. In this answer, we will discuss the advantages of a Pi-filter in detail.

1. Low Ripple Factor:
- The primary advantage of a Pi-filter is its ability to reduce the ripple voltage in a power supply circuit.
- Ripple voltage is the small AC component present on the DC output voltage of a power supply. It is typically caused by the switching action of the rectifier or other sources of noise in the circuit.
- The Pi-filter is specifically designed to attenuate this ripple voltage and provide a smooth and stable DC output.
- The arrangement of the capacitors and inductor in the Pi-filter allows it to effectively filter out the high-frequency components of the ripple voltage, resulting in a low ripple factor.
- A low ripple factor indicates that the power supply is providing a more stable and clean DC output, which is desirable for many electronic devices.

2. Improved Voltage Regulation:
- Another advantage of a Pi-filter is its ability to improve voltage regulation in a power supply circuit.
- Voltage regulation refers to the ability of a power supply to maintain a stable output voltage despite changes in input voltage or load conditions.
- The Pi-filter helps in regulating the output voltage by smoothing out any fluctuations or variations caused by changes in load current or input voltage.
- The inductor in the Pi-filter provides a high impedance to high-frequency components, preventing them from affecting the output voltage.
- This high impedance effectively isolates the load from any fluctuations in the input voltage, resulting in improved voltage regulation.

3. Lower PIV (Peak Inverse Voltage):
- The Pi-filter also offers the advantage of reducing the Peak Inverse Voltage (PIV) across the rectifier diodes.
- PIV is the maximum voltage that a diode must withstand in the reverse-bias direction when it is not conducting.
- In a power supply circuit, the diodes are subjected to high PIV values due to the presence of ripple voltage.
- By reducing the ripple voltage using a Pi-filter, the PIV across the diodes is also reduced, increasing their reliability and lifespan.

In conclusion, the advantages of a Pi-filter include low ripple factor, improved voltage regulation, and lower PIV. These features make it a suitable choice for power supply circuits, where stable and clean DC output is required. The Pi-filter effectively filters out high-frequency components, resulting in a smooth and regulated output voltage.

The inductor filter should be used when RL is consistently small because_________
  • a)
    Effective filtering takes place when load current is high
  • b)
    Effective filtering takes place when load current is low
  • c)
    Current lags behind voltage
  • d)
    Current leads voltage
Correct answer is option 'A'. Can you explain this answer?

Reasons for using inductor filter when RL is consistently small:
Inductor filter should be used when RL is consistently small because of the following reasons:
- Effective filtering takes place when load current is high: In an inductor filter, the inductor offers high impedance to high-frequency noise, allowing it to filter out unwanted high-frequency components effectively when the load current is high. This helps in reducing the ripple voltage and achieving a smoother output voltage.
- Current lags behind voltage: In an RL circuit, the current flowing through the inductor lags behind the applied voltage due to the inductive reactance. This phase shift between current and voltage helps in filtering out high-frequency noise components, as the inductor tends to oppose sudden changes in current.
Therefore, when RL is consistently small, the inductor filter is more effective in filtering out noise and providing a stable output voltage. It is important to consider the load current and the phase relationship between current and voltage when choosing the appropriate filter for a given circuit.

The voltage in case of a full wave rectifier in a CLC filter is_________
  • a)
    Vϒ = IDC/2fC
  • b)
     Vϒ = IDC fC
  • c)
    Vϒ = IDC/fC
  • d)
    Vϒ = 2IDCfC
Correct answer is option 'A'. Can you explain this answer?

Sahil Datta answered
Understanding Full Wave Rectifier with CLC Filter
In a full wave rectifier circuit equipped with a CLC (Capacitor-Filter-Capacitor) filter, the output voltage can be derived from the relationship between the DC output current, frequency, and capacitance.
Voltage Equation
The equation for the output voltage (V) across the load can be expressed as:
V ≈ IDC / (2fC)
Where:
- IDC = DC output current
- f = frequency of the rectified signal
- C = capacitance of the filter
This indicates that the output voltage is directly proportional to the DC current and inversely proportional to both the frequency and capacitance.
Why Option A is Correct
- Rectifier Output: In a full wave rectifier, the output frequency doubles, which is a critical factor in the equation.
- Capacitance Role: The capacitors in the CLC filter smooth the rectified voltage, and their value directly affects the output voltage. A larger capacitance results in a higher voltage across the load.
- Frequency Impact: Increasing the frequency reduces the output voltage, as the rectifier charges and discharges the capacitors more quickly.
Conclusion
Thus, the correct expression for the output voltage in a full wave rectifier with a CLC filter is indeed:
V = IDC / (2fC), which corresponds to option 'A'. This relationship helps in designing efficient rectifier circuits by understanding the impact of load, frequency, and capacitance on the output voltage.

The rectifier current is a short duration pulses which cause the diode to act as a_________
  • a)
    Voltage regulator
  • b)
    Mixer
  • c)
    Switch
  • d)
    Oscillator
Correct answer is option 'C'. Can you explain this answer?

 The diode permits charge to flow in capacitor when the transformer voltage exceeds the capacitor voltage. It disconnects the power source when the transformer voltage falls below that of a capacitor.

 In a choke l section filter_______
  • a)
    the inductor and capacitor are connected across the load
  • b)
    the inductor is connected in series and capacitor is connected across the load
  • c)
    the inductor is connected across and capacitor is connected in series to the load
  • d)
    the inductor and capacitor are connected in series
Correct answer is option 'B'. Can you explain this answer?

The choke filter is sometimes also called as L section filter because the inductor and capacitor are connected in the shape ’L’ or inverted manner. But several sections of this choke filter are employed to smooth the output curve and make it free from ripples.

What causes to decrease the sudden rise in the current for a rectifier?
  • a)
    the electrical energy
  • b)
    The ripple factor
  • c)
    The magnetic energy
  • d)
    Infinite resistance
Correct answer is option 'C'. Can you explain this answer?

Bhaskar Unni answered
When the output current of a rectifier increases above a certain value, magnetic energy is stored in the inductor. This energy tends to decrease the sudden rise in the current. This also helps to prevent the current to fall down too much.

What makes the load in a choke filter to bypass harmonic components?
  • a)
    capacitor
  • b)
    inductor
  • c)
    resistor
  • d)
    diodes
Correct answer is option 'A'. Can you explain this answer?

Niharika Basu answered
Choke Filter and its Purpose:

A choke filter is a type of electronic filter that is used to remove or minimize harmonic components from a signal. It consists of a coil of wire wound around a magnetic core. The purpose of a choke filter is to provide a high impedance to the undesired harmonic frequencies and allow only the desired fundamental frequency to pass through.

Role of Capacitor in Choke Filter:

A choke filter consists of a series combination of an inductor and a capacitor. The load in a choke filter is connected across the capacitor. The capacitor plays a crucial role in bypassing the harmonic components and allowing the fundamental frequency to reach the load.

Explanation:

1. Reactive Impedance of Capacitor:

- The reactance of a capacitor is given by the formula Xc = 1/(2πfC), where Xc is the capacitive reactance, f is the frequency, and C is the capacitance.
- At lower frequencies, the capacitive reactance is higher, which means that the capacitor offers high impedance to low-frequency signals.
- As the frequency increases, the capacitive reactance decreases, resulting in lower impedance to high-frequency signals.

2. Filtering Action of Capacitor:

- In a choke filter, the inductor provides a high impedance to the harmonic frequencies, while the capacitor bypasses these frequencies to the load.
- The capacitor acts as a short circuit for the harmonic frequencies, allowing them to flow through it and preventing them from reaching the load.
- At the same time, the capacitor offers high impedance to the fundamental frequency, preventing it from being bypassed.
- As a result, the harmonic frequencies are diverted away from the load, while the fundamental frequency is allowed to pass through and reach the load.

Conclusion:

In summary, the load in a choke filter is bypassed by harmonic components by using a capacitor. The capacitor provides a low impedance path for the harmonic frequencies, allowing them to flow through it and preventing them from reaching the load. On the other hand, the capacitor offers high impedance to the fundamental frequency, allowing it to pass through and reach the load. This filtering action of the capacitor helps in removing or minimizing harmonic components from the signal and ensuring that only the desired fundamental frequency is delivered to the load.

The cut-in point of a capacitor filter is_________
  • a)
    The instant at which the conduction starts
  • b)
    The instant at which the conduction stops
  • c)
    The time after which the output is not filtered
  • d)
    The time during which the output is perfectly filtered
Correct answer is option 'A'. Can you explain this answer?

Avik Chaudhary answered
The capacitor charges when the diode is in ON state and discharges during the OFF state of the diode. The instant at which the conduction starts is called cut-in point. The instant at which the conduction stops is called cut-out point.

A single phase full wave rectifier makes use of pi section filter with 10µF capacitors and a choke of 10henry. The secondary voltage is 280V and the load current is 100mA. Determine the dc output voltage when f=50Hz.
  • a)
    345V
  • b)
    521V
  • c)
    243V
  • d)
    346V
Correct answer is option 'D'. Can you explain this answer?

Parth Ghoshal answered
The pi section filter in a single phase full wave rectifier is used to smoothen the pulsating DC output voltage by reducing the ripple voltage.

The 10 in your question is incomplete, but assuming it refers to a value for one of the components in the pi section filter, it could be the value of the capacitance or inductance used in the filter. These values are typically chosen based on the desired ripple voltage reduction and load requirements.

The rms value of ripple current for an L section filter is_______
  • a)
     IRMS=√2/3*XL*VDC
  • b)
    IRMS=√2/3*XL*VDC
  • c)
     IRMS=√2/3*X*VDC
  • d)
    none
Correct answer is option 'A'. Can you explain this answer?

The ac current through L is determined primarily by XL=2ωL. It is directly proportional to voltage produced and indirectly proportional to the reactance.

The inductor filter gives a smooth output because_________
  • a)
    It offers infinite resistance to ac components
  • b)
    It offers infinite resistance to dc components
  • c)
    Pulsating dc signal is allowed
  • d)
    The ac signal is amplified
Correct answer is option 'A'. Can you explain this answer?

Inductor Filter and Its Characteristics

Introduction:
An inductor filter is a circuit that uses an inductor (a passive two-terminal electrical component that stores energy in a magnetic field) to smoothen the output of a rectifier circuit. It is commonly used in power supply applications to reduce the ripple voltage and provide a steady DC voltage output.

Working Principle:
When an alternating current (AC) signal passes through an inductor, it induces a magnetic field around it. This magnetic field opposes any changes in the current flowing through it. As a result, the inductor offers high resistance to AC components or high-frequency variations in the current.

Infinitely High Resistance to AC Components:
The inductor filter gives a smooth output because it offers infinite resistance to AC components. This means that the inductor effectively blocks high-frequency variations or ripple present in the input signal. The inductor's high reactance at higher frequencies attenuates the AC components, allowing only the DC component to pass through. This results in a smoother output waveform.

Impedance of an Inductor:
The impedance of an inductor, denoted by 'ZL', is given by the equation ZL = jωL, where ω is the angular frequency of the AC signal and L is the inductance of the inductor. As the frequency increases, the reactance of the inductor also increases, causing the impedance to rise. Therefore, at higher frequencies, the inductor acts as a high-pass filter, allowing only the DC component to pass through.

Effect on Ripple Voltage:
In a rectifier circuit, the output is a pulsating DC signal with a superimposed ripple voltage due to the AC input. The inductor filter is placed after the rectifier to reduce this ripple voltage. By offering infinite resistance to the AC components, the inductor effectively smoothens the output waveform by attenuating the ripple voltage. As a result, the output becomes closer to a pure DC signal.

Advantages of Inductor Filter:
- Provides a smoother DC output by reducing ripple voltage.
- Increases the stability and reliability of the power supply.
- Reduces noise and interference in the output signal.
- Helps in maintaining a constant voltage level for sensitive electronic devices.

Conclusion:
The inductor filter offers infinite resistance to AC components, attenuating high-frequency variations or ripple present in the input signal. This results in a smoother output waveform by reducing the ripple voltage. By understanding the working principle and characteristics of the inductor filter, electrical engineers can design and implement efficient power supply circuits for various applications.

The condition for the regulation curve in a choke filter is_________
  • a)
    LC≥RL/3ω
  • b)
    LC≤RL/3ω
  • c)
    L≥RL/3ω
  • d)
    LC≥RL
Correct answer is option 'A'. Can you explain this answer?

Explanation of the answer:

Condition for the regulation curve in a choke filter:
- The condition for the regulation curve in a choke filter is given by the formula: LC ≥ RL/3ω.
- Where L represents the inductance of the choke, C represents the capacitance of the filter capacitor, R is the load resistance, and ω is the angular frequency of the input signal.
- This condition ensures that the choke filter is effective in smoothing out the ripples in the output voltage and providing a stable DC output.
- If the value of LC is greater than or equal to RL/3ω, it indicates that the choke filter is capable of providing adequate filtering and regulation for the circuit.
Therefore, the correct answer is option 'A': LC ≥ RL/3ω. This condition is essential to ensure proper functioning of the choke filter in maintaining a stable output voltage.

The ripple to heavy loads by a capacitor is_______
  • a)
    high
  • b)
    depends on temperature
  • c)
    low
  • d)
    no ripple at all
Correct answer is option 'C'. Can you explain this answer?

Rahul Sen answered
Ripple factor is inversely proportional to load resistance for a capacitor filter.
So, the ripples that are produced are low when the load is high.

What is the relation between time constant and load resistance?
  • a)
    They don’t depend on each other
  • b)
    They are directly proportional
  • c)
    They are inversely proportional
  • d)
    Cannot be predicted
Correct answer is option 'C'. Can you explain this answer?

Avik Chaudhary answered
 If the load resistance value is large, the discharge time constant will be of a high value. Thus the capacitors time to discharge will get over soon. This lowers the amount of ripples in the output and increases the output voltage. If the load resistance is small, the discharge time constant will be more with decrease in output voltage.

The value of inductance at which the current in a choke filter does not fall to zero is_________
  • a)
    peak inductance
  • b)
    cut-in inductance
  • c)
    critical inductance
  • d)
    damping inductance
Correct answer is option 'C'. Can you explain this answer?

Manisha Chavan answered
When the value of inductance is increased, a value is reached where the diodes supplies current continuously. This value of inductance is called critical inductance.

The output dc voltage of an LC filter is_______
  • a)
    VDC=2Vm/π + IDCR
  • b)
    VDC=Vm/π – IDCR
  • c)
    VDC=2Vm/π – 2IDCR
  • d)
    VDC=2Vm/π – IDCR
Correct answer is option 'D'. Can you explain this answer?

The value for VDC is same as that of inductor filter. If inductor has no dc resistance, then VDC=2Vm/π. If R is the series resistance of transformer, then VDC=2Vm/π – IDCR.

The rms ripple voltage (Vrms) of a shunt filter is_________
  • a)
    IDC/2√3
  • b)
    IDC2√3
  • c)
    IDC/√3
  • d)
     IDC√3
Correct answer is option 'A'. Can you explain this answer?

Devanshi Iyer answered
The ripple waveform will be triangular in nature. The rms value of this wave is independent of slopes or lengths of straight lines. It depends only on the peak value.

At f=50Hz, the ripple factor of CLC filter is_________
  • a)
    ϒ=5700RL / (LC1C2)
  • b)
    ϒ=5700/ (LC1C2RL)
  • c)
    ϒ=5700LC1/ (C2RL)
  • d)
    ϒ=5700C1C2/ (LRL)
Correct answer is option 'B'. Can you explain this answer?

Neha Basak answered
The ripple factor of a rectifier is the measure of disturbances produced in the output. It’s the effectiveness of a power supply filter to reduce the ripple voltage. The ratio of ripple voltage to DC output voltage is ripple factor which is 5700 / (LC1C2RL) at 50Hz.

The ripple factor for an l section filter is_______
  • a)
    ϒ= 1/6√2ω2LC
  • b)
    ϒ= 6√2ω2LC
  • c)
    ϒ= 6√3ω2LC
  • d)
    ϒ= 1/6√3ω2LC
Correct answer is option 'A'. Can you explain this answer?

Saptarshi Nair answered
The ripple factor is the ratio of root mean square (rms) value of ripple voltage to absolute value of dc component. It can also be expressed as the peak to peak value.

The output voltage VDC for a rectifier with inductor filter is given by_________
  • a)
    (2Vm/π)-IDCR
  • b)
    (2Vm/π)+IDCR
  • c)
    (2Vmπ)-IDCR
  • d)
    (2Vmπ)+IDCR
Correct answer is option 'A'. Can you explain this answer?

Sagnik Sen answered
The inductor with high resistance can cause poor voltage regulation. The choke resistance, the resistance of half of transformer secondary is not negligible.

What is the number of capacitors and inductors used in a CLC filter?
  • a)
    1, 2 respectively
  • b)
    2, 1 respectively
  • c)
    1, 1 respectively
  • d)
    2, 2 respectively
Correct answer is option 'B'. Can you explain this answer?

Milan Saha answered
A very smooth output can be obtained by a filter consisting of one inductor and two capacitors connected across each other. They are arranged in the form of letter ‘pi’. So, these are also called as pi filters.

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