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All questions of Single-Phase AC Circuits for Electrical Engineering (EE) Exam
Find the value of the instantaneous voltage if the resistance is 2 ohm and the instantaneous current in the circuit is 5A.- a)5V
- b)2V
- c)10V
- d)2.5V
Correct answer is option 'C'. Can you explain this answer?
Find the value of the instantaneous voltage if the resistance is 2 ohm and the instantaneous current in the circuit is 5A.
a)
5V
b)
2V
c)
10V
d)
2.5V
 | Yash Patel answered |
We know that,
v=iR, substituting the given values from the question, we get v=10V.
v=iR, substituting the given values from the question, we get v=10V.
A 30 microF capacitor is connected across a 400V, 50Hz supply. Calculate the current.- a)6.67A
- b)3.77A
- c)5.65A
- d)2.33A
Correct answer is option 'B'. Can you explain this answer?
A 30 microF capacitor is connected across a 400V, 50Hz supply. Calculate the current.
a)
6.67A
b)
3.77A
c)
5.65A
d)
2.33A
 | Ravi Singh answered |
We know that: Xc=1/(2*f*pi*C).
Substituting the values from the given question, we get Xc= 106.2 ohm.
I=V/Xc, hence I= 3.77A.
Substituting the values from the given question, we get Xc= 106.2 ohm.
I=V/Xc, hence I= 3.77A.
If the resonant frequency in a series RLC circuit is 50kHz along with a bandwidth of 1kHz, find the quality factor.- a)5
- b)50
- c)100
- d)500
Correct answer is option 'B'. Can you explain this answer?
If the resonant frequency in a series RLC circuit is 50kHz along with a bandwidth of 1kHz, find the quality factor.
a)
5
b)
50
c)
100
d)
500
 | Zoya Sharma answered |
We know that Quality factor is equal to the resonant frequency divided by the bandwidth. Substituting the values from the given question, we get Q=50.
A 30 microF capacitor is connected across a 400V, 50Hz supply. Calculate the capacitive reac-tance.- a)102 ohm
- b)123.4 ohm
- c)106.2 ohm
- d)143.2 ohm
Correct answer is option 'C'. Can you explain this answer?
A 30 microF capacitor is connected across a 400V, 50Hz supply. Calculate the capacitive reac-tance.
a)
102 ohm
b)
123.4 ohm
c)
106.2 ohm
d)
143.2 ohm
| | Yash Patel answered |
We know that: Xc=1/(2*f*pi*C).
Substituting the values from the given question, we get Xc= 106.2 ohm.
Substituting the values from the given question, we get Xc= 106.2 ohm.
At resonance, the capacitive energy is ___________ inductive energy.- a)Greater than
- b)Less than
- c)Equal to
- d)Depends on the circuit
Correct answer is option 'C'. Can you explain this answer?
At resonance, the capacitive energy is ___________ inductive energy.
a)
Greater than
b)
Less than
c)
Equal to
d)
Depends on the circuit
 | Sanya Agarwal answered |
At resonance, the capacitive energy is equal to the inductive energy and the circuit appears to be resistive in nature.
In a series RLC circuit, the phase difference between the current in the circuit and the voltage across the inductor is?- a)0 degrees
- b)90 degrees
- c)180 degrees
- d)360 degrees
Correct answer is option 'B'. Can you explain this answer?
In a series RLC circuit, the phase difference between the current in the circuit and the voltage across the inductor is?
a)
0 degrees
b)
90 degrees
c)
180 degrees
d)
360 degrees
| | Ravi Singh answered |
In a series RLC circuit, the phase difference between the voltage across the inductor and the current in the circuit is 90 degrees.
In a series RLC circuit, the phase difference between the current in the inductor and the current in the resistor is?- a)0 degrees
- b)90 degrees
- c)180 degrees
- d)360 degrees
Correct answer is option 'A'. Can you explain this answer?
In a series RLC circuit, the phase difference between the current in the inductor and the current in the resistor is?
a)
0 degrees
b)
90 degrees
c)
180 degrees
d)
360 degrees
| | Rhea Reddy answered |
In a series RLC circuit, the phase difference between the current in the inductor and the current in the resistor is 0 degrees because the same current flows in the inductor as well as the resistor.
Find the time taken for the current in an inductor to change to 2A from 0A if the power in the inductor is 5W. The value of inductance is 10H.- a)1s
- b)2s
- c)3s
- d)4s
Correct answer is option 'D'. Can you explain this answer?
Find the time taken for the current in an inductor to change to 2A from 0A if the power in the inductor is 5W. The value of inductance is 10H.
a)
1s
b)
2s
c)
3s
d)
4s
 | Kajal Mukherjee answered |
The expression for power in an inductive circuit is:
P= LI2/2
Substituting the values from the given question, we get t=4s.
P= LI2/2
Substituting the values from the given question, we get t=4s.
What happens to the quality factor when resonant frequency increases?- a)Increases
- b)Decreases
- c)Remains the same
- d)Becomes zero
Correct answer is option 'A'. Can you explain this answer?
What happens to the quality factor when resonant frequency increases?
a)
Increases
b)
Decreases
c)
Remains the same
d)
Becomes zero
 | Lavanya Menon answered |
We know that Quality factor is equal to the resonant frequency divided by the bandwidth. Hence as the resonant frequency increases, quality factor also increases.
Find the value of Q if the reactive power is 10W and the average power is 5W.- a)10
- b)5
- c)2
- d)1
Correct answer is option 'C'. Can you explain this answer?
Find the value of Q if the reactive power is 10W and the average power is 5W.
a)
10
b)
5
c)
2
d)
1
 | Srestha Kumar answered |
Q is the ratio of the reactive power to the average power.
Substituting the given values from the question, we get Q=2.
Substituting the given values from the question, we get Q=2.
Find the reactive power when the average power is 5W and Q=2.- a)10W
- b)5W
- c)2W
- d)1W
Correct answer is option 'A'. Can you explain this answer?
Find the reactive power when the average power is 5W and Q=2.
a)
10W
b)
5W
c)
2W
d)
1W
 | Nitya Chopra answered |
Q is the ratio of the reactive power to the average power.
Substituting the given values from the question, we get reactive power= 10W.
Substituting the given values from the question, we get reactive power= 10W.
As the impedance increases, the admittance ____________- a)Increases
- b)Decreases
- c)Remains the same
- d)Becomes zero
Correct answer is option 'B'. Can you explain this answer?
As the impedance increases, the admittance ____________
a)
Increases
b)
Decreases
c)
Remains the same
d)
Becomes zero
| | Sanya Agarwal answered |
As the impedance increases, the admittance decreases because admittance is equal to 1/impedance.
What happens to the voltage across the inductor when the Q factor decreases?- a)Increases
- b)Decreases
- c)Remains the same
- d)Becomes zero
Correct answer is option 'B'. Can you explain this answer?
What happens to the voltage across the inductor when the Q factor decreases?
a)
Increases
b)
Decreases
c)
Remains the same
d)
Becomes zero
| | Sanya Agarwal answered |
We know that voltage across the inductor in resonance condition is equal to Q times the source voltage. Hence as the Q factor decreases, the voltage across the inductor also decreases.
If the resonant frequency in a series RLC circuit is 50kHz along with a bandwidth of 1kHz, find the quality factor.- a)5
- b)50
- c)100
- d)500
Correct answer is option 'B'. Can you explain this answer?
If the resonant frequency in a series RLC circuit is 50kHz along with a bandwidth of 1kHz, find the quality factor.
a)
5
b)
50
c)
100
d)
500
| | Srestha Kumar answered |
Calculation of Quality Factor
To calculate the quality factor (Q) of an RLC circuit, we use the formula:
Q = Resonant Frequency / Bandwidth
Given values:
Resonant Frequency (f) = 50 kHz
Bandwidth (Δf) = 1 kHz
Calculation:
Q = 50 kHz / 1 kHz
Q = 50
Therefore, the quality factor of the series RLC circuit is 50.
This value indicates the sharpness of the resonance peak in the circuit. A higher quality factor signifies a more selective circuit with a narrow bandwidth around the resonant frequency.
What is the power factor of a series RLC circuit under resonance condition?- a)0
- b)1
- c)Infinity
- d)100
Correct answer is option 'B'. Can you explain this answer?
What is the power factor of a series RLC circuit under resonance condition?
a)
0
b)
1
c)
Infinity
d)
100
| | Yash Patel answered |
The power factor for a series RLC circuit in resonance condition is always 1 because the current is in phase with the voltage under resonance condition.
Can ohm’s law be applied in an ac circuit?- a)Yes
- b)No
- c)Depends on the rms current
- d)Depends on the rms voltage
Correct answer is option 'A'. Can you explain this answer?
Can ohm’s law be applied in an ac circuit?
a)
Yes
b)
No
c)
Depends on the rms current
d)
Depends on the rms voltage
 | Hrishikesh Yadav answered |
's law be applied to AC circuits?
Yes, Ohm's law can be applied to AC circuits, but it needs to be modified to account for the varying voltage and current values in an alternating current circuit. In AC circuits, the relationship between voltage, current, and resistance is given by the impedance formula, which includes a complex term incorporating frequency and reactance.
Yes, Ohm's law can be applied to AC circuits, but it needs to be modified to account for the varying voltage and current values in an alternating current circuit. In AC circuits, the relationship between voltage, current, and resistance is given by the impedance formula, which includes a complex term incorporating frequency and reactance.
Find the average current in an inductor if the total current in the inductor is 30A.- a)10A
- b)26A
- c)15A
- d)5A
Correct answer is option 'C'. Can you explain this answer?
Find the average current in an inductor if the total current in the inductor is 30A.
a)
10A
b)
26A
c)
15A
d)
5A
 | Alok Khanna answered |
Average current= I/2.
Substituting the value of I from the equation, average current= 13A.
Substituting the value of I from the equation, average current= 13A.
What is the correct formula for quality factor?- a)Q=BW*fr
- b)Q=BW/fr
- c)Q=fr/BW
- d)Q=fr2
Correct answer is option 'C'. Can you explain this answer?
What is the correct formula for quality factor?
a)
Q=BW*fr
b)
Q=BW/fr
c)
Q=fr/BW
d)
Q=fr2
| | Lavanya Menon answered |
The correct formula for quality factor is Q=fr/BW, where fr is the resonant frequency, BW is the bandwidth frequency and Q is the quality factor.
When is tanφ positive?- a)When inductive reactance is greater than capacitive reactance
- b)When inductive reactance is less than capacitive reactance
- c)When inductive reactance is equal to capacitive reactance
- d)When inductive reactance is zero
Correct answer is option 'A'. Can you explain this answer?
When is tanφ positive?
a)
When inductive reactance is greater than capacitive reactance
b)
When inductive reactance is less than capacitive reactance
c)
When inductive reactance is equal to capacitive reactance
d)
When inductive reactance is zero
| | Yash Patel answered |
tanφ is positive when inductive reactance is greater than capacitive reactance because current will lag the voltage.
The energy stored in the capacitor is of _________ nature.- a)Electrostatic
- b)Magnetic
- c)Neither electrostatic nor magnetic
- d)Either electrostatic or magnetic
Correct answer is option 'A'. Can you explain this answer?
The energy stored in the capacitor is of _________ nature.
a)
Electrostatic
b)
Magnetic
c)
Neither electrostatic nor magnetic
d)
Either electrostatic or magnetic
| | Zoya Sharma answered |
The energy stored in a capacitor is in the form of electrostatic energy whereas the energy stored in the inductor is in the form of magnetic energy.
The current leads the supply voltage in a series RLC circuit has its frequency _________ the resonant frequency.- a)Above
- b)Below
- c)Equal to
- d)Cannot be determined
Correct answer is option 'B'. Can you explain this answer?
The current leads the supply voltage in a series RLC circuit has its frequency _________ the resonant frequency.
a)
Above
b)
Below
c)
Equal to
d)
Cannot be determined
| | Zoya Sharma answered |
The current leads the voltage in a series RLC circuit when the supply voltage is less than the resonant voltage.
In a series RLC circuit, the phase difference between the voltage across the inductor and the voltage across the resistor is?- a)0 degrees
- b)90 degrees
- c)180 degrees
- d)360 degrees
Correct answer is option 'B'. Can you explain this answer?
In a series RLC circuit, the phase difference between the voltage across the inductor and the voltage across the resistor is?
a)
0 degrees
b)
90 degrees
c)
180 degrees
d)
360 degrees
| | Yash Patel answered |
In a series RLC circuit, the phase difference between the voltage across the inductor and the voltage across the resistor is 90 degrees.
The energy stored in the inductor is of _________ nature.- a)Electrostatic
- b)Magnetic
- c)Neither electrostatic nor magnetic
- d)Either electrostatic or magnetic
Correct answer is option 'B'. Can you explain this answer?
The energy stored in the inductor is of _________ nature.
a)
Electrostatic
b)
Magnetic
c)
Neither electrostatic nor magnetic
d)
Either electrostatic or magnetic
 | Sarthak Yadav answered |
The energy stored in a capacitor is in the form of electrostatic energy whereas the energy stored in the inductor is in the form of magnetic energy.
If two bulbs are connected in parallel and one bulb blows out, what happens to the other bulb?- a)The other bulb blows out as well
- b)The other bulb continues to glow with the same brightness
- c)The other bulb glows with increased brightness
- d)The other bulb stops glowing
Correct answer is option 'B'. Can you explain this answer?
If two bulbs are connected in parallel and one bulb blows out, what happens to the other bulb?
a)
The other bulb blows out as well
b)
The other bulb continues to glow with the same brightness
c)
The other bulb glows with increased brightness
d)
The other bulb stops glowing
| | Sanya Agarwal answered |
In a parallel circuit, if one bulb blows out, it acts as an open circuit. Current does not flow in that branch but it continues to flow in the other branch hence the bulb continues to glow.
What happens to the current flow in a fully charged capacitor?- a)Current flow stops
- b)Current flow doubles
- c)Current flow becomes half its original value
- d)Current flow becomes one-fourth its original value
Correct answer is option 'A'. Can you explain this answer?
What happens to the current flow in a fully charged capacitor?
a)
Current flow stops
b)
Current flow doubles
c)
Current flow becomes half its original value
d)
Current flow becomes one-fourth its original value
 | Rahul Banerjee answered |
When a capacitor is fully charged, it does not store any more charge. There is no change in charge with time. Current is the rate of change of charge, hence it becomes zero, or stops.
The power for a purely resistive circuit is zero when?- a)Either current or voltage is zero
- b)Both current and voltage are zero
- c)Voltage is zero
- d)Current is zero
Correct answer is option 'A'. Can you explain this answer?
The power for a purely resistive circuit is zero when?
a)
Either current or voltage is zero
b)
Both current and voltage are zero
c)
Voltage is zero
d)
Current is zero
| | Sanya Agarwal answered |
P=VIcosϕ Power in a circuit is the product of voltage, current and the cosine of the phase angle. Phase angle is 00 for purely resistive circuit so, P=VI. Hence if either voltage or current is zero, the power is zero.
The power for a purely resistive circuit is zero when?- a)Current is zero
- b)Voltage is zero
- c)Both current and voltage are zero
- d)Either current or voltage is zero
Correct answer is option 'D'. Can you explain this answer?
The power for a purely resistive circuit is zero when?
a)
Current is zero
b)
Voltage is zero
c)
Both current and voltage are zero
d)
Either current or voltage is zero
 | Nandita Bajaj answered |
The power in a resistive circuit is the product of the voltage, current and the cosine of the phase angle. Hence if either voltage or current is zero, the power is zero.
Calculate the capacitance of a capacitor that stores 80microC of charge and has a voltage of 4V.- a)20F
- b)20microF
- c)10F
- d)10microF
Correct answer is option 'B'. Can you explain this answer?
Calculate the capacitance of a capacitor that stores 80microC of charge and has a voltage of 4V.
a)
20F
b)
20microF
c)
10F
d)
10microF
| | Sanvi Kapoor answered |
Q is directly proportional to V. The constant of proportionality in this case is C, that is, the capacitance. Hence C=Q/V.
C=80microC/4V=20microF.
C=80microC/4V=20microF.
What happens to the quality factor when the bandwidth increases?- a)Increases
- b)Decreases
- c)Remains the same
- d)Becomes zero
Correct answer is option 'B'. Can you explain this answer?
What happens to the quality factor when the bandwidth increases?
a)
Increases
b)
Decreases
c)
Remains the same
d)
Becomes zero
| | Lavanya Menon answered |
We know that Quality factor is equal to the resonant frequency divided by the bandwidth. Hence as the bandwidth increases, quality factor decreases.
In case of Inductive circuit, Frequency is ______________ to the current.- a)Directly proportional
- b)Inversely proportional
- c)Unrelated
- d)Much greater than
Correct answer is option 'B'. Can you explain this answer?
In case of Inductive circuit, Frequency is ______________ to the current.
a)
Directly proportional
b)
Inversely proportional
c)
Unrelated
d)
Much greater than
| | Ravi Singh answered |
Inductance is inversely proportional to current since, as the inductance increases, current decreases.
Quality factor is also known as _________- a)Voltage magnification
- b)Current magnification
- c)Resistance magnification
- d)Impedance magnification
Correct answer is option 'A'. Can you explain this answer?
Quality factor is also known as _________
a)
Voltage magnification
b)
Current magnification
c)
Resistance magnification
d)
Impedance magnification
| | Krish Saini answered |
Quality factor is also known as Voltage magnification because it represents the ratio of the voltage across a reactive component (such as an inductor or capacitor) to the applied voltage. In other words, it quantifies the amplification of voltage across the reactive component in a resonant circuit.
The quality factor (Q) is a dimensionless parameter that is defined as the ratio of the reactance of the reactive component to the resistance of the circuit. It is given by the formula:
Q = X/R
where X is the reactance of the component and R is the resistance of the circuit. The reactance is the opposition offered by the component to the flow of alternating current and is dependent on the frequency of the signal.
The quality factor is a measure of the selectivity or sharpness of resonance in a circuit. A higher quality factor indicates a circuit with a narrow bandwidth and a sharper resonance peak, while a lower quality factor indicates a circuit with a wider bandwidth and a broader resonance peak.
The voltage magnification in a resonant circuit is directly related to the quality factor. A higher quality factor implies a higher voltage magnification, meaning that the voltage across the reactive component is amplified compared to the applied voltage. This is because a higher quality factor indicates a lower resistance in the circuit, which allows more energy to be stored in the reactive component and results in a higher voltage across it.
On the other hand, a lower quality factor implies a lower voltage magnification, meaning that the voltage across the reactive component is attenuated compared to the applied voltage. This is because a lower quality factor indicates a higher resistance in the circuit, which dissipates more energy and results in a lower voltage across the reactive component.
In summary, the quality factor is also known as voltage magnification because it represents the amplification or attenuation of voltage across a reactive component in a resonant circuit. It is directly related to the ratio of the reactance to the resistance in the circuit and determines the selectivity and sharpness of resonance.
The quality factor (Q) is a dimensionless parameter that is defined as the ratio of the reactance of the reactive component to the resistance of the circuit. It is given by the formula:
Q = X/R
where X is the reactance of the component and R is the resistance of the circuit. The reactance is the opposition offered by the component to the flow of alternating current and is dependent on the frequency of the signal.
The quality factor is a measure of the selectivity or sharpness of resonance in a circuit. A higher quality factor indicates a circuit with a narrow bandwidth and a sharper resonance peak, while a lower quality factor indicates a circuit with a wider bandwidth and a broader resonance peak.
The voltage magnification in a resonant circuit is directly related to the quality factor. A higher quality factor implies a higher voltage magnification, meaning that the voltage across the reactive component is amplified compared to the applied voltage. This is because a higher quality factor indicates a lower resistance in the circuit, which allows more energy to be stored in the reactive component and results in a higher voltage across it.
On the other hand, a lower quality factor implies a lower voltage magnification, meaning that the voltage across the reactive component is attenuated compared to the applied voltage. This is because a lower quality factor indicates a higher resistance in the circuit, which dissipates more energy and results in a lower voltage across the reactive component.
In summary, the quality factor is also known as voltage magnification because it represents the amplification or attenuation of voltage across a reactive component in a resonant circuit. It is directly related to the ratio of the reactance to the resistance in the circuit and determines the selectivity and sharpness of resonance.
In a parallel circuit, we consider _____________ instead of impedance.- a)Resistance
- b)Capacitance
- c)Inductance
- d)Admittance
Correct answer is option 'D'. Can you explain this answer?
In a parallel circuit, we consider _____________ instead of impedance.
a)
Resistance
b)
Capacitance
c)
Inductance
d)
Admittance
 | Bijoy Mehta answered |
In a parallel circuit, we consider admittance instead of impedance, where admittance is the reciprocal of impedance.
If the current and voltage are 90 degree out of phase, the power factor will be?- a)0
- b)Infinity
- c)1
- d)Insufficient information provided
Correct answer is option 'A'. Can you explain this answer?
If the current and voltage are 90 degree out of phase, the power factor will be?
a)
0
b)
Infinity
c)
1
d)
Insufficient information provided
 | Kiran Iyer answered |
The power factor is the cosine of the angle in between the voltage and the current. If the angle between the voltage and current is 90, then cos90=0. Hence, the power factor is zero.
At resonance, bandwidth includes the frequency range that allows _____ percent of the maximum voltage to flow.- a)33.33
- b)66.67
- c)50
- d)70.7
Correct answer is option 'D'. Can you explain this answer?
At resonance, bandwidth includes the frequency range that allows _____ percent of the maximum voltage to flow.
a)
33.33
b)
66.67
c)
50
d)
70.7
| | Zoya Sharma answered |
At resonance, bandwidth includes the frequency range that allows 70.2 percent of the maximum voltage to flow. This is because at the bandwidth frequency range, the value of the voltage is equal to the maximum value of voltage divided by √2.
If a 2F capacitor has 1C charge, calculate the voltage across its terminals.- a)0.5V
- b)2V
- c)1.5V
- d)1V
Correct answer is option 'B'. Can you explain this answer?
If a 2F capacitor has 1C charge, calculate the voltage across its terminals.
a)
0.5V
b)
2V
c)
1.5V
d)
1V
| | Nayanika Kaur answered |
Q is directly proportional to V. The constant of proportionality in this case is C, that is, the capacitance.
Hence Q ∝ V
i.e. Q = VC
then V = Q/C
V=2/1=2V.
What is the voltage across a capacitor at the time of switching, that is, when t=0?- a)Infinity
- b)0V
- c)Cannot be determined
- d)1V
Correct answer is option 'B'. Can you explain this answer?
What is the voltage across a capacitor at the time of switching, that is, when t=0?
a)
Infinity
b)
0V
c)
Cannot be determined
d)
1V
| | Sanchita Sharma answered |
Explanation:
When a switch is closed or opened in a circuit containing a capacitor, the voltage across the capacitor at the instant of switching is determined by the initial conditions of the circuit.
Initial Conditions:
Before the switch is closed or opened, the capacitor is assumed to be fully charged or discharged. This means that the voltage across the capacitor is either the maximum voltage or zero voltage, depending on its initial state.
Switching at t=0:
At the instant of switching (t=0), the behavior of the capacitor depends on its initial conditions.
If the capacitor is fully charged before switching, it will try to maintain the voltage across its terminals. Therefore, the voltage across the capacitor at t=0 will be zero. This is because the capacitor resists sudden changes in voltage and will discharge through the circuit.
If the capacitor is initially discharged (voltage=0), it will try to prevent any change in voltage across its terminals. Therefore, the voltage across the capacitor at t=0 will be the maximum voltage. This is because the capacitor will charge up rapidly to its maximum voltage as the circuit seeks to establish equilibrium.
Answer:
In the given question, the voltage across the capacitor at the time of switching (t=0) is 0V. This implies that the capacitor is either fully charged or discharged before the switch is closed or opened.
When a switch is closed or opened in a circuit containing a capacitor, the voltage across the capacitor at the instant of switching is determined by the initial conditions of the circuit.
Initial Conditions:
Before the switch is closed or opened, the capacitor is assumed to be fully charged or discharged. This means that the voltage across the capacitor is either the maximum voltage or zero voltage, depending on its initial state.
Switching at t=0:
At the instant of switching (t=0), the behavior of the capacitor depends on its initial conditions.
If the capacitor is fully charged before switching, it will try to maintain the voltage across its terminals. Therefore, the voltage across the capacitor at t=0 will be zero. This is because the capacitor resists sudden changes in voltage and will discharge through the circuit.
If the capacitor is initially discharged (voltage=0), it will try to prevent any change in voltage across its terminals. Therefore, the voltage across the capacitor at t=0 will be the maximum voltage. This is because the capacitor will charge up rapidly to its maximum voltage as the circuit seeks to establish equilibrium.
Answer:
In the given question, the voltage across the capacitor at the time of switching (t=0) is 0V. This implies that the capacitor is either fully charged or discharged before the switch is closed or opened.
Find the value of current when the maximum value of current is 50A in the bandwidth range.- a)56.65A
- b)35.36A
- c)45.34A
- d)78.76A
Correct answer is option 'B'. Can you explain this answer?
Find the value of current when the maximum value of current is 50A in the bandwidth range.
a)
56.65A
b)
35.36A
c)
45.34A
d)
78.76A
| | Yash Patel answered |
At the bandwidth frequency range, the value of the current is equal to the maximum value of current divided by √2. Hence I =50/√2= 35.36A.
if the impedance of a system is 4 ohm, calculate its admittance.- a)0.25 ohm-1
- b)4 ohm-1
- c)25 ohm-1
- d)0.4 ohm-1
Correct answer is option 'A'. Can you explain this answer?
if the impedance of a system is 4 ohm, calculate its admittance.
a)
0.25 ohm-1
b)
4 ohm-1
c)
25 ohm-1
d)
0.4 ohm-1
| | Prasad Saini answered |
We know that: Y=1/Z.
Substituting the value of Z from the question, we get Y= 0.25 ohm-1.
Substituting the value of Z from the question, we get Y= 0.25 ohm-1.
Find the source voltage when the voltage across the inductor is 2000V and the Q factor is 20.- a)10V
- b)200V
- c)100V
- d)90V
Correct answer is option 'C'. Can you explain this answer?
Find the source voltage when the voltage across the inductor is 2000V and the Q factor is 20.
a)
10V
b)
200V
c)
100V
d)
90V
| | Zoya Sharma answered |
We know that voltage across the inductor in resonance condition is equal to Q times the source voltage. VL=QV. Substituting the values from the given question, we get V=100V.
What is the frequency in resonance condition?- a)Minimum
- b)Maximum
- c)Cannot be determined
- d)Zero
Correct answer is option 'B'. Can you explain this answer?
What is the frequency in resonance condition?
a)
Minimum
b)
Maximum
c)
Cannot be determined
d)
Zero
| | Pallavi Nair answered |
At resonance condition, the frequency is maximum since the inductive reactance is equal to the capacitive reactance and the voltage and current are in phase.
If the current in a coil having a constant inductance of L henrys grows at a uniform rate, what is the value of the average current?- a)I
- b)I/2
- c)I/4
- d)0
Correct answer is option 'B'. Can you explain this answer?
If the current in a coil having a constant inductance of L henrys grows at a uniform rate, what is the value of the average current?
a)
I
b)
I/2
c)
I/4
d)
0
 | Palak Verma answered |
The average current is the average of the current which flows in the inductor. Hence it is I/2.
When voltage across a capacitor increases, what happens to the charge stored in it?- a)Increases
- b)Decreases
- c)Becomes zero
- d)Cannot be determined
Correct answer is option 'A'. Can you explain this answer?
When voltage across a capacitor increases, what happens to the charge stored in it?
a)
Increases
b)
Decreases
c)
Becomes zero
d)
Cannot be determined
| | Raghav Majumdar answered |
When voltage across a capacitor increases, the charge stored in it also increases be-cause charge is directly proportional to voltage, capacitance being the constant of proportionality.
An induced emf is said to be ___________- a)Inductive
- b)Capacitive
- c)Resistive
- d)Cannot be determined
Correct answer is option 'A'. Can you explain this answer?
An induced emf is said to be ___________
a)
Inductive
b)
Capacitive
c)
Resistive
d)
Cannot be determined
| | Rhea Reddy answered |
Any circuit in which a change of current is accompanied by a change of flux, and therefore by an induced emf, is said to be inductive.
The instantaneous voltage is a product of the resistance and the _____________ current in a resistive circuit.- a)Instantaneous
- b)Average
- c)RMS
- d)Peak
Correct answer is option 'A'. Can you explain this answer?
The instantaneous voltage is a product of the resistance and the _____________ current in a resistive circuit.
a)
Instantaneous
b)
Average
c)
RMS
d)
Peak
| | Vaibhav Joshi answered |
The instantaneous voltage is a product of the instantaneous current and the resistance in the circuit.
A resistance of 7 ohm is connected in series with an inductance of 31.8mH. The circuit is connected to a 100V 50Hz sinusoidal supply. Calculate the phase difference.- a)-55.1
- b)55.1
- c)66.1
- d)-66.1
Correct answer is option 'A'. Can you explain this answer?
A resistance of 7 ohm is connected in series with an inductance of 31.8mH. The circuit is connected to a 100V 50Hz sinusoidal supply. Calculate the phase difference.
a)
-55.1
b)
55.1
c)
66.1
d)
-66.1
| | Sanaya Basu answered |
φ=tan-1(XL/R)=55.1
Since this is an inductive circuit, the current will lag, hence φ= -55.1.
Since this is an inductive circuit, the current will lag, hence φ= -55.1.
A resistance of 7 ohm is connected in series with an inductance of 31.8mH. The circuit is connected to a x V 50Hz sinusoidal supply. The current in the circuit is 8.2A. Calculate the value of x.- a)10V
- b)50V
- c)100V
- d)120V
Correct answer is option 'C'. Can you explain this answer?
A resistance of 7 ohm is connected in series with an inductance of 31.8mH. The circuit is connected to a x V 50Hz sinusoidal supply. The current in the circuit is 8.2A. Calculate the value of x.
a)
10V
b)
50V
c)
100V
d)
120V
| | Vaishnavi Nair answered |
XL=2*pi*f*L= 10ohm. Therefore the total impedance =sqrt(R2+XL2)=12.2ohm.
V=IZ, Therefore V=12.2*8.2=100V.
V=IZ, Therefore V=12.2*8.2=100V.
In an RLC circuit, which of the following is always used as a vector reference?- a)Voltage
- b)Resistance
- c)Impedance
- d)Current
Correct answer is option 'A'. Can you explain this answer?
In an RLC circuit, which of the following is always used as a vector reference?
a)
Voltage
b)
Resistance
c)
Impedance
d)
Current
| | Rahul Banerjee answered |
In an RLC circuit, the voltage is always used as a reference and according to the phase of the voltage, the phase of the other parameters is decided.
Find the Q factor when the voltage across the capacitor is 1000V and the source voltage is 100V.- a)10
- b)20
- c)30
- d)40
Correct answer is option 'A'. Can you explain this answer?
Find the Q factor when the voltage across the capacitor is 1000V and the source voltage is 100V.
a)
10
b)
20
c)
30
d)
40
| | Tanvi Rane answered |
We know that voltage across the capacitor in resonance condition is equal to Q times the source voltage. Vc=QV. Substituting the values from the given question, we get Q=10.
For an RC circuit, the phase angle is always ________- a)Positive
- b)Negative
- c)0
- d)90
Correct answer is option 'A'. Can you explain this answer?
For an RC circuit, the phase angle is always ________
a)
Positive
b)
Negative
c)
0
d)
90
| | Avik Saha answered |
For a series resistance and capacitance circuit, the phase angle is always a positive value because the current will always leads the voltage.
What is the effective value of current?- a)RMS current
- b)Average current
- c)Instantaneous current
- d)Total current
Correct answer is option 'A'. Can you explain this answer?
What is the effective value of current?
a)
RMS current
b)
Average current
c)
Instantaneous current
d)
Total current
| | Gargi Mishra answered |
Effective current is also known as the effective current. RMS stands for Root Mean Square. This value of current is obtained by squaring all the current values, finding the average and then finding the square root.
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