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All questions of Simple Interest and Compound Interest for GMAT Exam
Find the sum of money when increases 1/10 of itself every year amount to Rs. 600 in 5 years.- a)Rs. 380
- b)Rs. 280
- c)Rs. 480
- d)None
- e)All of the above
Correct answer is option 'D'. Can you explain this answer?
Find the sum of money when increases 1/10 of itself every year amount to Rs. 600 in 5 years.
a)
Rs. 380
b)
Rs. 280
c)
Rs. 480
d)
None
e)
All of the above
 | Ishani Rane answered |
This is an example of an exponential growth problem. Exponential growth can be modeled by the equation P = a(r)t, where a is the initial amount, t is the time that has passed, P is the amount after time t, and r is the rate of growth.
For your problem, t = 5 years and P = 600. The money increases by 1/10 = 10% each year, so each year, the amount of money is 110% of the previous year. That's a rate of growth of r = 1.1. So:
600 = a(1.1)5
600 = 1.61051a
372.55 = a
The sum was initially Rs. 372.55.
Find the Compound Interest on Rs. 12500 at 8% per annum for 9 months compounded quarterly.- a)Rs.1020
- b)Rs. 1428
- c)Rs. 510
- d)765.1
- e)All of the above
Correct answer is option 'D'. Can you explain this answer?
Find the Compound Interest on Rs. 12500 at 8% per annum for 9 months compounded quarterly.
a)
Rs.1020
b)
Rs. 1428
c)
Rs. 510
d)
765.1
e)
All of the above
 | EduRev CLAT answered |
The correct is D as
n=9 months
=3 quaterly
A=125000×(1+2/100)3^=125000×(1+2/100)^3
=125000×51/50×51/50×51/50=125000×51/50×51/50×51/50
=Rs.132651
CI=A−P
=132651−125000
=Rs.765.1
n=9 months
=3 quaterly
A=125000×(1+2/100)3^=125000×(1+2/100)^3
=125000×51/50×51/50×51/50=125000×51/50×51/50×51/50
=Rs.132651
CI=A−P
=132651−125000
=Rs.765.1
A father left a will of Rs.5 lakhs between his two daughters aged 10 and 15 such that they may get equal amounts when each of them reach the age of 21 years. The original amount of Rs.5 lakhs has been instructed to be invested at 10% p.a. simple interest. How much did the elder daughter get at the time of the will?- a)Rs.2,04,797
- b)Rs.3,05,890
- c)Rs.1,90,00
- d)Rs.4,00,700
- e)Rs.2,46,870
Correct answer is option 'A'. Can you explain this answer?
A father left a will of Rs.5 lakhs between his two daughters aged 10 and 15 such that they may get equal amounts when each of them reach the age of 21 years. The original amount of Rs.5 lakhs has been instructed to be invested at 10% p.a. simple interest. How much did the elder daughter get at the time of the will?
a)
Rs.2,04,797
b)
Rs.3,05,890
c)
Rs.1,90,00
d)
Rs.4,00,700
e)
Rs.2,46,870
 | Akash Pandey answered |
Answer – A.Rs.2,04,797 Explanation : Let Rs.x be the amount that the elder daughter got at the time of the will. Therefore, the younger daughter got (5,00,000 – x).
The elder daughter’s money earns interest for (21 – 15) = 6 years @ 10% p.a simple interest The younger daughter’s money earns interest for (21 – 10) = 11 years @ 10% p.a simple interest.
As the sum of money that each of the daughters get when they are 21 is the same, x + (6*10*x/100)= (5,00,000 – x) +(11*10*[5,00,000-x]/100) 100x+60x = (5,00,000-x)+(55,000,000-110x) 160x =55,500,000-111x 271x = 55,500,000 X = 2,04,797
The elder daughter’s money earns interest for (21 – 15) = 6 years @ 10% p.a simple interest The younger daughter’s money earns interest for (21 – 10) = 11 years @ 10% p.a simple interest.
As the sum of money that each of the daughters get when they are 21 is the same, x + (6*10*x/100)= (5,00,000 – x) +(11*10*[5,00,000-x]/100) 100x+60x = (5,00,000-x)+(55,000,000-110x) 160x =55,500,000-111x 271x = 55,500,000 X = 2,04,797
A sum of rupees 3200 is compounded annually at the rate of 25 paise per rupee per annum. Find the compound interest payable after 2 years.- a)1200
- b)1600
- c)1800
- d)2000
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
A sum of rupees 3200 is compounded annually at the rate of 25 paise per rupee per annum. Find the compound interest payable after 2 years.
a)
1200
b)
1600
c)
1800
d)
2000
e)
None of these
 | Anaya Patel answered |
Rate of interest is 25 paise per rupee per annum.
So for 100 rupees it is 2500 paise i.e. 25 percent
Now, CI = 3200(1+25/100)2 – 3200 = 1800
So for 100 rupees it is 2500 paise i.e. 25 percent
Now, CI = 3200(1+25/100)2 – 3200 = 1800
At the start of 2015, Jane opened two new accounts – X and Y – to invest her total savings of $1000. She invested p percent of her savings in account X, which yielded a simple interest of 8 percent per annum, and the rest of the savings in account Y, which yielded a simple interest of 6 percent per annum. Was the amount of interest earned by account X greater than the amount of interest earned by account Y during the year 2015?(1) The value of p was between 25 and 30, inclusive
(2) The total interest earned by the two accounts during 2015 was $66- a)Statement (1) ALONE is sufficient, but statement (2) alone is
not sufficient to answer the question asked. - b)Statement (2) ALONE is sufficient, but statement (1) alone is
not sufficient to answer the question asked - c)BOTH statements (1) and (2) TOGETHER are sufficient to
answer the question asked, but NEITHER statement ALONE
is sufficient to answer the question asked. - d)EACH statement ALONE is sufficient to answer the question
asked. - e)Statements (1) and (2) TOGETHER are NOT sufficient to
answer the question asked, and additional data specific to the
problem are needed.
Correct answer is option 'D'. Can you explain this answer?
At the start of 2015, Jane opened two new accounts – X and Y – to invest her total savings of $1000. She invested p percent of her savings in account X, which yielded a simple interest of 8 percent per annum, and the rest of the savings in account Y, which yielded a simple interest of 6 percent per annum. Was the amount of interest earned by account X greater than the amount of interest earned by account Y during the year 2015?
(1) The value of p was between 25 and 30, inclusive
(2) The total interest earned by the two accounts during 2015 was $66
(2) The total interest earned by the two accounts during 2015 was $66
a)
Statement (1) ALONE is sufficient, but statement (2) alone is
not sufficient to answer the question asked.
not sufficient to answer the question asked.
b)
Statement (2) ALONE is sufficient, but statement (1) alone is
not sufficient to answer the question asked
not sufficient to answer the question asked
c)
BOTH statements (1) and (2) TOGETHER are sufficient to
answer the question asked, but NEITHER statement ALONE
is sufficient to answer the question asked.
answer the question asked, but NEITHER statement ALONE
is sufficient to answer the question asked.
d)
EACH statement ALONE is sufficient to answer the question
asked.
asked.
e)
Statements (1) and (2) TOGETHER are NOT sufficient to
answer the question asked, and additional data specific to the
problem are needed.
answer the question asked, and additional data specific to the
problem are needed.
| | Anaya Patel answered |
Step 1 & 2: Understand Question and Draw Inference
Step 3 : Analyze Statement 1 independent
Statement 1 says that ‘The value of p was between 25 and 30, inclusive’
- So, the answer to the question ‘Is p > 43?’ is NO
Since Statement 1 leads to a unique answer to the question, it is sufficient
Step 4 : Analyze Statement 2 independent
Statement 2 says that ‘The total interest earned by the two accounts during 2015 was $66’
- (Interest earned by Account X) + (Interest earned by Account Y) = 66
- This is a linear equation with only 1 unknown, p. So, by solving this equation, we will be able to find the value of p
- Once we know the value of p, we can answer the question ‘Is p > 43?’
- So, Statement 2 also is sufficient to answer the question
Step 5: Analyze Both Statements Together (if needed)
Since we’ve already arrived at a unique answer in Steps 3 and 4, this step is not required
Answer: Option D
Answer: Option D
In what time Rs. 2600 amount to Rs. 3055 at the rate of 3 ½ % per annum.- a)2½ years
- b)5 years
- c)3 years
- d)None
- e)All of the above
Correct answer is option 'B'. Can you explain this answer?
In what time Rs. 2600 amount to Rs. 3055 at the rate of 3 ½ % per annum.
a)
2½ years
b)
5 years
c)
3 years
d)
None
e)
All of the above
 | Faizan Khan answered |
The correct option is B.
Principal amount=2600
Rate=3 1/2%pa=7/2
Time = T
SI=3055-2600=455
SI=PRT/100
455=2600×7×T/100×2,
T=5yrs.
Principal amount=2600
Rate=3 1/2%pa=7/2
Time = T
SI=3055-2600=455
SI=PRT/100
455=2600×7×T/100×2,
T=5yrs.
Raghu lends Rs 50,000 of two of his friends. He gives Rs 30,000 to the first at 6% p.a. simple interest. He wants to make a profit of 10% on the whole. The simple interest rate at which he should lend the remaining sum of money to the second friend is- a)8%
- b)16%
- c)11%
- d)17%
- e)19%
Correct answer is option 'B'. Can you explain this answer?
Raghu lends Rs 50,000 of two of his friends. He gives Rs 30,000 to the first at 6% p.a. simple interest. He wants to make a profit of 10% on the whole. The simple interest rate at which he should lend the remaining sum of money to the second friend is
a)
8%
b)
16%
c)
11%
d)
17%
e)
19%
 | Target Study Academy answered |
Answer –B.16% Explanation : S.I. on Rs 30000 =(30000×6×1)/100 = Rs. 1800 Profit to made on Rs 50000 = 50000×10/100=Rs 5000 S.I.on Rs.20000 = 5000-1800 = Rs.3200 Rate=(S.I.* 100)/(P * T)=(3200×100)/20000 =16% per annum
Shortcut: 6……………………x ………..10…………….
3………………………2
4/(x-10)=2/3 x=16
Shortcut: 6……………………x ………..10…………….
3………………………2
4/(x-10)=2/3 x=16
An amount of money grows upto Rs. 4000 in 2 years and up to Rs. 8000 in 3 years on compound interest. What is the sum?- a)Rs. 1600
- b)Rs. 1000
- c)Rs. 1200
- d)Rs. 2400
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
An amount of money grows upto Rs. 4000 in 2 years and up to Rs. 8000 in 3 years on compound interest. What is the sum?
a)
Rs. 1600
b)
Rs. 1000
c)
Rs. 1200
d)
Rs. 2400
e)
None of these
| | Aarav Sharma answered |
Solution:
Let the principal be Rs. x.
Given, the principal amount grows up to Rs. 4000 in 2 years and up to Rs. 8000 in 3 years on compound interest.
Calculation:
Using the formula for compound interest,
Amount after 2 years = x(1 + r/100)²
Amount after 3 years = x(1 + r/100)³
Given, amount after 2 years = Rs. 4000 and amount after 3 years = Rs. 8000
So, we have two equations as below:
x(1 + r/100)² = 4000
x(1 + r/100)³ = 8000
Dividing the second equation by the first equation, we get:
(1 + r/100) = 2
r/100 = 1
r = 100
Substituting the value of r in any of the equations above, we get:
x = 1000
Therefore, the sum is Rs. 1000.
Hence, option (b) is the correct answer.
Let the principal be Rs. x.
Given, the principal amount grows up to Rs. 4000 in 2 years and up to Rs. 8000 in 3 years on compound interest.
Calculation:
Using the formula for compound interest,
Amount after 2 years = x(1 + r/100)²
Amount after 3 years = x(1 + r/100)³
Given, amount after 2 years = Rs. 4000 and amount after 3 years = Rs. 8000
So, we have two equations as below:
x(1 + r/100)² = 4000
x(1 + r/100)³ = 8000
Dividing the second equation by the first equation, we get:
(1 + r/100) = 2
r/100 = 1
r = 100
Substituting the value of r in any of the equations above, we get:
x = 1000
Therefore, the sum is Rs. 1000.
Hence, option (b) is the correct answer.
A $200 investment at x percent per annum and a $500 investment at y percent per annum have a combined yearly return of 10 percent of the total of the two investments. If $400 is invested at x percent and $600 is invested at y percent per annum to give a combined yearly return of 9.2 percent of the total of the two investments, what will be the combined percentage yearly return of the total investment if $100 each is invested at x percent per annum and y percent per annum respectively?- a)5%
- b)7.5%
- c)8.5%
- d)10%
- e)17%
Correct answer is option 'C'. Can you explain this answer?
A $200 investment at x percent per annum and a $500 investment at y percent per annum have a combined yearly return of 10 percent of the total of the two investments. If $400 is invested at x percent and $600 is invested at y percent per annum to give a combined yearly return of 9.2 percent of the total of the two investments, what will be the combined percentage yearly return of the total investment if $100 each is invested at x percent per annum and y percent per annum respectively?
a)
5%
b)
7.5%
c)
8.5%
d)
10%
e)
17%
| | Anaya Patel answered |
Given:
- Case-I
- Principal , P = $200
- Rate of interest = x% p.a.
- Principal, P = $500
- Rate of Interest = y% p.a.
- Combined yearly return = 10%
- Principal , P = $200
- Case-II
- Principal, P = $400
- Rate of interest = x% p.a.
- Principal, P = $600
- Rate of Interest = y% p.a.
- Combined yearly return = 9.2%
- Principal, P = $400
To Find: Combined yearly return if $100 each is invested at x% p.a. and y% p.a.?
- Let the combined yearly return be R%
- So, Return on $200 invested at R% p.a. = Return on $100 at x% p.a. + Return on $100 at y% p.a.
Approach:
- For finding the value of R, we need to find the value of x and y.
- We are given two cases in which the principals are invested at x% and y% per annum and we are also given the combined yearly return for both the cases
- The combined yearly return is equal to the sum of the returns of the individual investments
- Writing the combined yearly return equations for each of the case will give us an equation in x and y
- We will solve both the equations to get the value of x and y, which will be used to calculate the yearly return on $100 each invested at x% and y% p.a.
Working out:
- Case-I
- As the combined yearly return is equal to the sum of the returns of individual investments, we can write the following equation
- 2x +5y = 70……………..(1)
2. Case-II
- As the combined yearly return is equal to the sum of the returns of individual investments, we can write the following equation
3. Solving (1) and (2), we have y = 12 and x = 5
4. Hence, combined yearly return on investment of $100 each at x% and y% can be calculated as
4. Hence, combined yearly return on investment of $100 each at x% and y% can be calculated as
Answer : C
Out of Rs. 50,000 that a man has, he lends Rs. 8,000 at 11/2 % per annum simple interest and Rs. 24,000 at 6% per annum simple interest. He lends the remaining money at a certain rate of interest so that he gets total annual interest of Rs. 3,680. The rate of interest per annum, at which the remaining money is lent, is ?- a)5%
- b)7%
- c)10%
- d)12%
- e)None of the Above
Correct answer is option 'C'. Can you explain this answer?
Out of Rs. 50,000 that a man has, he lends Rs. 8,000 at 11/2 % per annum simple interest and Rs. 24,000 at 6% per annum simple interest. He lends the remaining money at a certain rate of interest so that he gets total annual interest of Rs. 3,680. The rate of interest per annum, at which the remaining money is lent, is ?
a)
5%
b)
7%
c)
10%
d)
12%
e)
None of the Above
 | Dinesh Murugesan answered |
10%
A person earns an interest of 240 on investing certain amount at Simple interest for 2 years at 5 percent amount. If the rate of interest is compounded annually then how much more interest will be gain by the person at same rate of interest and on the same sum.- a)6
- b)8
- c)12
- d)10
- e)None of these
Correct answer is option 'A'. Can you explain this answer?
A person earns an interest of 240 on investing certain amount at Simple interest for 2 years at 5 percent amount. If the rate of interest is compounded annually then how much more interest will be gain by the person at same rate of interest and on the same sum.
a)
6
b)
8
c)
12
d)
10
e)
None of these
 | Preeti Khanna answered |
240 = P*(5/100)*2, P = 2400
CI = 2400(1+5/100)2 – 2400 = 246
So, 246 – 240 = 6
CI = 2400(1+5/100)2 – 2400 = 246
So, 246 – 240 = 6
A sum was put at simple interest at a certain rate for 2 years. Had it been put at 4% higher rate, it would have fetched Rs. 112 more. The sum is:- a)1120
- b)1400
- c)1200
- d)8000
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
A sum was put at simple interest at a certain rate for 2 years. Had it been put at 4% higher rate, it would have fetched Rs. 112 more. The sum is:
a)
1120
b)
1400
c)
1200
d)
8000
e)
None of these
| | Anaya Patel answered |
The correct answer is C as let principle be p , rate be r , si be x . Also t = 2yrs.
so , x = (p*r*2)/100
x = 2pr/100 _____(1)
If rate = r+4 , si = x+112 then
x+112 = (p*(r+4)*2)/100
x+112 = 2p(r+4)/100
2pr/100+112 = (2pr+8p)/100 (using eq(1))
(2pr+11200)/100 = (2pr+8p)/100
2pr+11200 = 2pr+8p
11200 = 8p
p = 1400
Correct ans is b) 1400
so , x = (p*r*2)/100
x = 2pr/100 _____(1)
If rate = r+4 , si = x+112 then
x+112 = (p*(r+4)*2)/100
x+112 = 2p(r+4)/100
2pr/100+112 = (2pr+8p)/100 (using eq(1))
(2pr+11200)/100 = (2pr+8p)/100
2pr+11200 = 2pr+8p
11200 = 8p
p = 1400
Correct ans is b) 1400
Tarun invested an amount of Rs. 10000 at the simple interest rate of 8% per annum and another amount at the simple interest rate of 20% per annum. The total interest earned at the end of one year on the total amount invested became 12% per annum. Find the total amount invested.- a)Rs.12,000
- b)Rs.15000
- c)Rs.5,000
- d)Rs.10,000
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
Tarun invested an amount of Rs. 10000 at the simple interest rate of 8% per annum and another amount at the simple interest rate of 20% per annum. The total interest earned at the end of one year on the total amount invested became 12% per annum. Find the total amount invested.
a)
Rs.12,000
b)
Rs.15000
c)
Rs.5,000
d)
Rs.10,000
e)
None of these
 | Future Foundation Institute answered |
Answer – B.Rs.15000 Explanation : SI1= 10000*8*1/100 = 800
SI2 = x*20*1/100 = x/5 800+(x/5) = (10000+x)*12*1/100 80000+20x = 1,20,000+12x 8x = 40,000 X = 5000
Total= 10000+5000 = 15000
SI2 = x*20*1/100 = x/5 800+(x/5) = (10000+x)*12*1/100 80000+20x = 1,20,000+12x 8x = 40,000 X = 5000
Total= 10000+5000 = 15000
Two equal some of money were invested at an annual rate of 10%, One sum at simple interest and other at compound interest, If the difference between the interest after 2 years was Rs.100, What were the sum invested ?- a)25,000
- b)100000
- c)20,000
- d)10,000
- e)50,000
Correct answer is option 'D'. Can you explain this answer?
Two equal some of money were invested at an annual rate of 10%, One sum at simple interest and other at compound interest, If the difference between the interest after 2 years was Rs.100, What were the sum invested ?
a)
25,000
b)
100000
c)
20,000
d)
10,000
e)
50,000
| | Target Study Academy answered |
Correct Answer :- d
Explanation : Assume X = 100
SI = 120
CI = 121
100 mean difference is 1
200 mean difference is 2
Therefore, 10000 mean difference is 100.
The simple interest on a certain sum of money for 4 years at 15 percent per annum is 600. Find the compound interest in the same sum at 10 percent interest for 2 years- a)220
- b)200
- c)210
- d)120
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
The simple interest on a certain sum of money for 4 years at 15 percent per annum is 600. Find the compound interest in the same sum at 10 percent interest for 2 years
a)
220
b)
200
c)
210
d)
120
e)
None of these
 | Ravi Singh answered |
600 = p*4*(15/100), P = 1000
CI = 1000(1+10/100)2 – 1000 = 210
CI = 1000(1+10/100)2 – 1000 = 210
Hari took an educational loan from a nationalized bank for his 2 years course of MBA. He took the loan of Rs.5 lakh such that he would be charged at 7% p.a. at CI during his course and at 9% CI after the completion of the course. He returned half of the amount which he had to be paid on the completion of his studies and remaining after 2 years. What is the total amount returned by Hari?- a)Rs. 626255
- b)Rs. 626277
- c)Rs. 616266
- d)Rs. 626288
- e)None of these
Correct answer is option 'D'. Can you explain this answer?
Hari took an educational loan from a nationalized bank for his 2 years course of MBA. He took the loan of Rs.5 lakh such that he would be charged at 7% p.a. at CI during his course and at 9% CI after the completion of the course. He returned half of the amount which he had to be paid on the completion of his studies and remaining after 2 years. What is the total amount returned by Hari?
a)
Rs. 626255
b)
Rs. 626277
c)
Rs. 616266
d)
Rs. 626288
e)
None of these
 | Naroj Boda answered |
5,00,000 * (1.07)² = 572450
Returned amount = 286225
After two years = 286225 * (1.09)² = 340063
Total amount = 286225 + 340063 = 626288
Returned amount = 286225
After two years = 286225 * (1.09)² = 340063
Total amount = 286225 + 340063 = 626288
A sum of 3000 becomes 3600 in 3 years at 15 percent per annum. What will be the sum at the same rate after 9 years.- a)5124
- b)5184
- c)5186
- d)5192
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
A sum of 3000 becomes 3600 in 3 years at 15 percent per annum. What will be the sum at the same rate after 9 years.
a)
5124
b)
5184
c)
5186
d)
5192
e)
None of these
 | Divey Sethi answered |
3600 = 3000*(1+15/100)3
(1+15/100)3 = 6/5
Amount = 3000*[(1+15/100)3]3
Amount = 3000*(6/5)3 = 5184
(1+15/100)3 = 6/5
Amount = 3000*[(1+15/100)3]3
Amount = 3000*(6/5)3 = 5184
A sum was put at simple interest at a certain rate for 5 years. had it been put at 5% higher rate, it would have fetched Rs. 500 more. What is the sum?- a)Rs. 2000
- b)Rs. 2400
- c)Rs. 2500
- d)Rs. 3200
- e)Rs. 4400
Correct answer is option 'A'. Can you explain this answer?
A sum was put at simple interest at a certain rate for 5 years. had it been put at 5% higher rate, it would have fetched Rs. 500 more. What is the sum?
a)
Rs. 2000
b)
Rs. 2400
c)
Rs. 2500
d)
Rs. 3200
e)
Rs. 4400
 | Notes Wala answered |
The correct answer is A
let principle be p , rate be r , si be x . Also t = 5 yrs.
so , x = (p*r*5)/100
x = 5pr/100 _____(1)
If rate = r+5 , si = x+500 then
x+500 = (p*(r+5)*5)/100
x+500 = 5p(r+5)/100
5pr/100+500 = (5pr+25p)/100 (using eq(1))
(5pr+50000)/100 = (5pr+25p)/100
5pr+50000 = 5pr+25p
50000 = 25p
p = 2000
let principle be p , rate be r , si be x . Also t = 5 yrs.
so , x = (p*r*5)/100
x = 5pr/100 _____(1)
If rate = r+5 , si = x+500 then
x+500 = (p*(r+5)*5)/100
x+500 = 5p(r+5)/100
5pr/100+500 = (5pr+25p)/100 (using eq(1))
(5pr+50000)/100 = (5pr+25p)/100
5pr+50000 = 5pr+25p
50000 = 25p
p = 2000
A man had Rs. 5800 a part of which he lent at 4% and rest at 6%. The whole annual interest received was Rs. 292. The money lent at 4% was ……?- a)Rs. 3000
- b)Rs. 2600
- c)Rs. 2700
- d)None
- e)All of the above
Correct answer is option 'D'. Can you explain this answer?
A man had Rs. 5800 a part of which he lent at 4% and rest at 6%. The whole annual interest received was Rs. 292. The money lent at 4% was ……?
a)
Rs. 3000
b)
Rs. 2600
c)
Rs. 2700
d)
None
e)
All of the above
| | Anaya Patel answered |
The correct option is D as Let the part lent at 4% be x then , rest will be (5800-x) .
(x*4*1)/100 + { (5800-x)*6*1 } / 100 = 292
4x/100 + { 34800 - 6x }/100 = 292
4x + 34800 - 6x = 29200
2x = 5600
x = 2800 so , d is correct option.
(x*4*1)/100 + { (5800-x)*6*1 } / 100 = 292
4x/100 + { 34800 - 6x }/100 = 292
4x + 34800 - 6x = 29200
2x = 5600
x = 2800 so , d is correct option.
What is the difference between the compound interest and the simple interest for the sum Rs. 16000 at 5% p.a. for 2 years?- a)Rs. 80
- b)Rs. 60
- c)Rs. 54
- d)Rs. 40
- e)Rs. 35
Correct answer is option 'A'. Can you explain this answer?
What is the difference between the compound interest and the simple interest for the sum Rs. 16000 at 5% p.a. for 2 years?
a)
Rs. 80
b)
Rs. 60
c)
Rs. 54
d)
Rs. 40
e)
Rs. 35
| | Dia Mehta answered |
Option ( A) 40 is the correct answer.
Explanation:- Given, P = 16000₹
R = 5% , T = 2 years
A = P (1 + R /100) ^n
= 16000 * ( 1+5/100) ^2
= 16000 * ( 105 / 100) ^2
A = 17,640₹
C. I = A- P
= 17,640 - 16,000
= 1,640
S. I = PTR / 100
= 16000 * 2 * 5/ 100
= 1,600
Difference CI - SI ;
= 1640 - 1600
= 40 ₹
Ravi borrowed some money at the rate of 4 pcpa for the first three years, at the rate of 8 pcpa for the next two years and at the rate of 9 pcpa for the period beyond 5 years. If he pays a total simple interest of Rs. 19550 at the end of 7 years, how much money did he borrow?- a)Rs. 39,500
- b)Rs. 42,500
- c)Rs. 41,900
- d)Rs. 43,000
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
Ravi borrowed some money at the rate of 4 pcpa for the first three years, at the rate of 8 pcpa for the next two years and at the rate of 9 pcpa for the period beyond 5 years. If he pays a total simple interest of Rs. 19550 at the end of 7 years, how much money did he borrow?
a)
Rs. 39,500
b)
Rs. 42,500
c)
Rs. 41,900
d)
Rs. 43,000
e)
None of these
 | Aspire Academy answered |
The correct answer is B .as f the amount borrowed be Rs.x, then
x×4×6
100
+
x×8×2
100
+
x×9×2
100
x×4×6100+x×8×2100+x×9×2100 = Rs.19550Th
=>
12x100+16x100+18x10012x100+16x100+18x100 = 19550
=> 12x+16x+18x
= 1955000
=> 46x = 1955000
=> x = 19550000
46
1955000046
= Rs.42500
x×4×6
100
+
x×8×2
100
+
x×9×2
100
x×4×6100+x×8×2100+x×9×2100 = Rs.19550Th
=>
12x100+16x100+18x10012x100+16x100+18x100 = 19550
=> 12x+16x+18x
= 1955000
=> 46x = 1955000
=> x = 19550000
46
1955000046
= Rs.42500
Vikram lends Rs 30,000 of two of his friends. He gives Rs 15,000 to the first at 6% p.a. simple interest. He wants to make a profit of 10% on the whole. The simple interest rate at which he should lend the remaining sum of money to the second friend is- a)8%
- b)16%
- c)12%
- d)14%
- e)None of the Above
Correct answer is option 'D'. Can you explain this answer?
Vikram lends Rs 30,000 of two of his friends. He gives Rs 15,000 to the first at 6% p.a. simple interest. He wants to make a profit of 10% on the whole. The simple interest rate at which he should lend the remaining sum of money to the second friend is
a)
8%
b)
16%
c)
12%
d)
14%
e)
None of the Above
| | Alok Verma answered |
D. 14%
Explanation: S.I. on Rs 15000 =(15000×6×1)/100 = Rs. 900 Profit to made on Rs 30000 = 30000×10/100=Rs 3000 S.I.on Rs.15000 = 3000-900 = Rs.2100 Rate=(S.I.* 100)/(P * T)=(2100×100)/15000 =14% per annum
Explanation: S.I. on Rs 15000 =(15000×6×1)/100 = Rs. 900 Profit to made on Rs 30000 = 30000×10/100=Rs 3000 S.I.on Rs.15000 = 3000-900 = Rs.2100 Rate=(S.I.* 100)/(P * T)=(2100×100)/15000 =14% per annum
.)In what time Rs. 540 at 5 percent per annum will produce the same Interest as Rs. 1800 in 5 years at 6 percent per annum.- a)10 years
- b)30 years
- c)25 years
- d)None
- e)All of the above
Correct answer is option 'D'. Can you explain this answer?
.)In what time Rs. 540 at 5 percent per annum will produce the same Interest as Rs. 1800 in 5 years at 6 percent per annum.
a)
10 years
b)
30 years
c)
25 years
d)
None
e)
All of the above
 | Bank Exams India answered |
Using the simple interest formula I = PRT, we set the interests equal: 540 * 0.05 * T = 1800 * 0.06 * 5. 27T = 540. T = 20 years. Since 20 isn't an option, the answer is D.
A sum of Rs. 8400 was taken as loan. This is to be paid in two equal annual installments. If the rate of interest be 20% compounded annually, then the value of each installment is- a)5400
- b)5700
- c)5100
- d)5200
- e)None of these
Correct answer is option 'A'. Can you explain this answer?
A sum of Rs. 8400 was taken as loan. This is to be paid in two equal annual installments. If the rate of interest be 20% compounded annually, then the value of each installment is
a)
5400
b)
5700
c)
5100
d)
5200
e)
None of these
 | Yash Patel answered |
Let value of each installment be X.
X/(1 + 20/100) + X/(1 + 20/100)² = 8400
⇒ X(5/6 + 25/36) = 8400
⇒ X(56/36) = 8400
X = 5400
X/(1 + 20/100) + X/(1 + 20/100)² = 8400
⇒ X(5/6 + 25/36) = 8400
⇒ X(56/36) = 8400
X = 5400
A man borrows 10000 rupees at 20 % compound interest for 3 years. If every year he pays 2000 rupees as repayment. How much amount is still left to be paid by the man?- a)5000
- b)7000
- c)9000
- d)10000
- e)None of these
Correct answer is option 'D'. Can you explain this answer?
A man borrows 10000 rupees at 20 % compound interest for 3 years. If every year he pays 2000 rupees as repayment. How much amount is still left to be paid by the man?
a)
5000
b)
7000
c)
9000
d)
10000
e)
None of these
| | Aisha Gupta answered |
Amount to be paid at the end of three years = 10000*(1+20/100)3 = 17280
Amount paid as instalment by the man = 2000*(1+20/100)2 + 2000*(1+20/100) + 2000 = 7280
So remaining amount = 10000
Amount paid as instalment by the man = 2000*(1+20/100)2 + 2000*(1+20/100) + 2000 = 7280
So remaining amount = 10000
The simple interest accrued on a sum of certain principal is Rs. 6500/- in eight years at the rate of 13 p.c.p.a. What would be the compound interest accrued on that principal at the rate of 8 p.c.p.a. in 2 years?- a)Rs. 1040/-
- b)Rs. 1020/-
- c)Rs. 1060/-
- d)Rs. 1200/-
- e)None of these
Correct answer is option 'A'. Can you explain this answer?
The simple interest accrued on a sum of certain principal is Rs. 6500/- in eight years at the rate of 13 p.c.p.a. What would be the compound interest accrued on that principal at the rate of 8 p.c.p.a. in 2 years?
a)
Rs. 1040/-
b)
Rs. 1020/-
c)
Rs. 1060/-
d)
Rs. 1200/-
e)
None of these
| | Anaya Patel answered |
The corect option is A by using compound formulae the amount comes to be 1040.
The compound interest on a certain sum for 2 years is Rs. 786 and S.I. is Rs. 750. If the sum is invested such that the S.I. is Rs. 1296 and the number of years is equal to the rate per cent per annum, Find the rate of interest?- a)4%
- b)5%
- c)6%
- d)8%
- e)2%
Correct answer is option 'C'. Can you explain this answer?
The compound interest on a certain sum for 2 years is Rs. 786 and S.I. is Rs. 750. If the sum is invested such that the S.I. is Rs. 1296 and the number of years is equal to the rate per cent per annum, Find the rate of interest?
a)
4%
b)
5%
c)
6%
d)
8%
e)
2%
 | Vikas Kumar answered |
CI for 2 years = Rs. 786
SI for 2 years = Rs. 750
36/360 * 100 = 10%
P for first year = 3600
P*x*x/100 = 1296
x = 6%
P is going to pay Rs.700 to Q, 7 months later at 6% annual simple interest, Q isgoing to pay Rs.550 to P, 12 months later at 8% annual simple interest, if theydecide to settle the debts, who will pay what amount to whom ?- a)A, Rs.149
- b)B,Rs.167
- c)A, Rs.155
- d)B, Rs.197
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
P is going to pay Rs.700 to Q, 7 months later at 6% annual simple interest, Q isgoing to pay Rs.550 to P, 12 months later at 8% annual simple interest, if theydecide to settle the debts, who will pay what amount to whom ?
a)
A, Rs.149
b)
B,Rs.167
c)
A, Rs.155
d)
B, Rs.197
e)
None of these
| | Aisha Gupta answered |
Answer – B.B,Rs.167
Explanation :
For P:
P+ (p*6*7/12*100) = 700
1200p+42P = 700*1200
P = 676.33
For Q:
P+ (p*8*12/12*100) = 550
1200P+96P = 550*1200
P =509.26
Q =676-509 = 167
Explanation :
For P:
P+ (p*6*7/12*100) = 700
1200p+42P = 700*1200
P = 676.33
For Q:
P+ (p*8*12/12*100) = 550
1200P+96P = 550*1200
P =509.26
Q =676-509 = 167
Suresh lends 40% of his money at 15% per annum, 50% of the rest at 10% per annum and the rest at 18% per annum rate of interest. What would be the annual rate of interest, if the interest is calculated on the whole sum?- a)18.5%
- b)14.4%
- c)16.5%
- d)19.5%
- e)None of the Above
Correct answer is option 'B'. Can you explain this answer?
Suresh lends 40% of his money at 15% per annum, 50% of the rest at 10% per annum and the rest at 18% per annum rate of interest. What would be the annual rate of interest, if the interest is calculated on the whole sum?
a)
18.5%
b)
14.4%
c)
16.5%
d)
19.5%
e)
None of the Above
| | Preeti Khanna answered |
B. 14.4%
Explanation: x – (40/100)*x = 60x/100 40/100 at 15% p.a = 40/100 * 15/100 = 60x/1000 50/100*60x/100 = 30x/100 at 10% p.a = 30x/100 * 10/100 = 30x/1000 Balance amount = x – 40x/100 – 30x/100 = 30x/100 at 18% p.a = 18/100 * 30x/100 = 54x/1000 R = [(144x/1000)/x] * 100 = 14.4%
Explanation: x – (40/100)*x = 60x/100 40/100 at 15% p.a = 40/100 * 15/100 = 60x/1000 50/100*60x/100 = 30x/100 at 10% p.a = 30x/100 * 10/100 = 30x/1000 Balance amount = x – 40x/100 – 30x/100 = 30x/100 at 18% p.a = 18/100 * 30x/100 = 54x/1000 R = [(144x/1000)/x] * 100 = 14.4%
Venkat and Vidhya have to clear their respective loans by paying 2 equal annual instalments of Rs.30000 each. Venkat pays at 10% pa of SI and Vidhyapays at 10% CI pa. What is the difference in their payments ?- a)200
- b)300
- c)400
- d)500
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
Venkat and Vidhya have to clear their respective loans by paying 2 equal annual instalments of Rs.30000 each. Venkat pays at 10% pa of SI and Vidhyapays at 10% CI pa. What is the difference in their payments ?
a)
200
b)
300
c)
400
d)
500
e)
None of these
| | Bank Exams India answered |
D =[(30,000 *110/100*110/100) – 30,000] – 30,000 *10*2/100
=[36300-30000]- 6000
=6300 – 6000
D = 300
=[36300-30000]- 6000
=6300 – 6000
D = 300
During the first year the population of a village is increased by 5% and the second year it is diminished by 5%. At the end of the second year its population was 31500. What was the population at the beginning of the first year?- a)35500
- b)31578
- c)33500
- d)33000
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
During the first year the population of a village is increased by 5% and the second year it is diminished by 5%. At the end of the second year its population was 31500. What was the population at the beginning of the first year?
a)
35500
b)
31578
c)
33500
d)
33000
e)
None of these
| | Preeti Khanna answered |
x * 105/100 * 95/100 = 31500
x = 31500 * 100/105 * 100/95
D = 31578
x = 31500 * 100/105 * 100/95
D = 31578
A sum of money becomes Rs 35,280 after 2 years and Rs 37,044 after 3 years when lent on compound interest. Find the principal amount.- a)2800
- b)3000
- c)3200
- d)4000
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
A sum of money becomes Rs 35,280 after 2 years and Rs 37,044 after 3 years when lent on compound interest. Find the principal amount.
a)
2800
b)
3000
c)
3200
d)
4000
e)
None of these
| | Bank Exams India answered |
37044 = p*(1 +r/100)3
35280 = p*(1 + r/100)2
Divide both equations to get the value of r and then substitute in any equation to get P
35280 = p*(1 + r/100)2
Divide both equations to get the value of r and then substitute in any equation to get P
The difference between interest received by Vivek and Vimal is Rs.405 on Rs.4500 for 3 years. What is the difference in rate of interest ?- a)1.5%
- b)2%
- c)3%
- d)2.7%
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
The difference between interest received by Vivek and Vimal is Rs.405 on Rs.4500 for 3 years. What is the difference in rate of interest ?
a)
1.5%
b)
2%
c)
3%
d)
2.7%
e)
None of these
| | Faizan Khan answered |
4500*3/100(R1-R2) = 405
R1-R2 = 405*100/13500 = 3%
R1-R2 = 405*100/13500 = 3%
Priya saves an amount of 500 every year and then lent that amount at an interest of 10 percent compounded annually. Find the amount after 3 years.- a)1820.5
- b)1840.5
- c)1920.5
- d)1940.5
- e)None of these
Correct answer is option 'A'. Can you explain this answer?
Priya saves an amount of 500 every year and then lent that amount at an interest of 10 percent compounded annually. Find the amount after 3 years.
a)
1820.5
b)
1840.5
c)
1920.5
d)
1940.5
e)
None of these
| | Bank Exams India answered |
Total amount = 500*(1+10/100)3 + 500*(1+10/100)2 + 500*(1+10/100)
= 1820.5
= 1820.5
Ajay borrows Rs 1000 at the rate of 12% per annum simple interest and Babu borrows Rs 1050 at the rate of 10% per annum simple interest. In how many years will their amounts of debts be equal?- a)18/5
- b)10/3
- c)22/3
- d)10/5
- e)None of the Above
Correct answer is option 'B'. Can you explain this answer?
Ajay borrows Rs 1000 at the rate of 12% per annum simple interest and Babu borrows Rs 1050 at the rate of 10% per annum simple interest. In how many years will their amounts of debts be equal?
a)
18/5
b)
10/3
c)
22/3
d)
10/5
e)
None of the Above
| | Anaya Patel answered |
B. 10/3
Explanation: Let Time = x years Then, [1000+(1000*12*x)/100] = [1050+(1050*10*x)/100] => 1000 + 120x = 1050 + 105x => 15x = 50 ⇒ x = 10/3 years
Explanation: Let Time = x years Then, [1000+(1000*12*x)/100] = [1050+(1050*10*x)/100] => 1000 + 120x = 1050 + 105x => 15x = 50 ⇒ x = 10/3 years
The compound interest accrued on an amount of the end of two years @ 12 p.c.p.a. is Rs. 2862/- What is the amount?- a)Rs. 11,250/-
- b)Rs. 12,200/-
- c)Rs. 13,500/-
- d)Rs. 10,000
- e)None of these
Correct answer is option 'A'. Can you explain this answer?
The compound interest accrued on an amount of the end of two years @ 12 p.c.p.a. is Rs. 2862/- What is the amount?
a)
Rs. 11,250/-
b)
Rs. 12,200/-
c)
Rs. 13,500/-
d)
Rs. 10,000
e)
None of these
 | Glance Learning Institute answered |
The correct answer is A as
CI = P((1+R/100)^n - 1)
2862 = P(( 1+12/100)^2-1)
2862 = P((1+144/10000 + 24/100) -1)
2862 = P (144/10000+24/100)
2862 = P (2544/10000)
P = 11,250
CI = P((1+R/100)^n - 1)
2862 = P(( 1+12/100)^2-1)
2862 = P((1+144/10000 + 24/100) -1)
2862 = P (144/10000+24/100)
2862 = P (2544/10000)
P = 11,250
Vivek invests Rs 15000 as fixed deposit at a bank at the rate of 10% per annum SI. But due to some pressing needs he has to withdraw the entire money after 5 years, for which the bank allowed him a lower rate of interest. If he gets Rs 8250 less than what he would have got at the end of 10 years, the rate of interest allowed by the bank is- a)8%
- b)8.5%
- c)9%
- d)9.5%
- e)10%
Correct answer is option 'C'. Can you explain this answer?
Vivek invests Rs 15000 as fixed deposit at a bank at the rate of 10% per annum SI. But due to some pressing needs he has to withdraw the entire money after 5 years, for which the bank allowed him a lower rate of interest. If he gets Rs 8250 less than what he would have got at the end of 10 years, the rate of interest allowed by the bank is
a)
8%
b)
8.5%
c)
9%
d)
9.5%
e)
10%
| | Faizan Khan answered |
Answer –C.9% Explanation : P=15000, T1=10 years, T2=5 years, R1=10%, R2=? [(15000*10*10)/100 – (15000*R2*5)/100] = 8250
15000 – 750R2 = 8250
R2 = 9%
15000 – 750R2 = 8250
R2 = 9%
Roger distributed a total investment of $1000 between mutual funds A and B and received a combined yearly return of 10 percent. How much did he invest in mutual fund A?(1) Had he increased the share of mutual fund A in his total investment by 50 percent, he would have received a combined yearly return of 11 percent
(2) He received a return of 8 percent from mutual fund B- a)Statement (1) ALONE is sufficient, but statement (2) alone is
not sufficient to answer the question asked - b)Statement (2) ALONE is sufficient, but statement (1) alone is
not sufficient to answer the question asked. - c)BOTH statements (1) and (2) TOGETHER are sufficient to
answer the question asked, but NEITHER statement ALONE
is sufficient to answer the question asked. - d)EACH statement ALONE is sufficient to answer the question
asked. - e)Statements (1) and (2) TOGETHER are NOT sufficient to
answer the question asked, and additional data specific to the
problem are needed.
Correct answer is option 'E'. Can you explain this answer?
Roger distributed a total investment of $1000 between mutual funds A and B and received a combined yearly return of 10 percent. How much did he invest in mutual fund A?
(1) Had he increased the share of mutual fund A in his total investment by 50 percent, he would have received a combined yearly return of 11 percent
(2) He received a return of 8 percent from mutual fund B
(2) He received a return of 8 percent from mutual fund B
a)
Statement (1) ALONE is sufficient, but statement (2) alone is
not sufficient to answer the question asked
not sufficient to answer the question asked
b)
Statement (2) ALONE is sufficient, but statement (1) alone is
not sufficient to answer the question asked.
not sufficient to answer the question asked.
c)
BOTH statements (1) and (2) TOGETHER are sufficient to
answer the question asked, but NEITHER statement ALONE
is sufficient to answer the question asked.
answer the question asked, but NEITHER statement ALONE
is sufficient to answer the question asked.
d)
EACH statement ALONE is sufficient to answer the question
asked.
asked.
e)
Statements (1) and (2) TOGETHER are NOT sufficient to
answer the question asked, and additional data specific to the
problem are needed.
answer the question asked, and additional data specific to the
problem are needed.
| | Anaya Patel answered |
Step 1 & 2: Understand Question and Draw Inference
Given:
- Total investment = $1000
- Let investment in A = a dollars
- So, investment in B = 1000 – a dollars
- Total interest earned = 10% per annum
- = 10% of 1000 = $100 per annum
To find :a = ?
- Let Investment A give a return of x percent and Investment B give a return of y percent.
- Since Total interest earned = $100, we can write:
- Interest earned from Investment A + Interest earned from Investment B = 100
- Thus, in order to know the value of a, we need to know the value of x and y.
Step 3 : Analyze Statement 1 independent
(1) Had he increased the share of mutual fund A in his total investment by 50 percent, he would have received a combined yearly return of 11 percent
- Note that the amount of total investment still remains $1000 only. Only the allocation of this amount between investments A and B has changed
- So, new investment in A = 1.5a
- New investment in B = 1000 – 1.5a
- Given: Combined yearly return = 11% of $1000 = $110
- (Return from Investment A) + (Return from Investment B) = 110
- This equation has 3 unknowns. Therefore, it is not sufficient to determine a unique value of a
Step 4 : Analyze Statement 2 independent
2) He received a return of 8 percent from mutual fund B
This equation has 2 unknowns. Not sufficient to find a unique value of x.
Step 5: Analyze Both Statements Together (if needed)
- Substituting y = 8 in (III) we get:
- ax - 8a = 2000
- This is the same as Equation (IV)
So, even after both statements together, we cannot find a unique value of a.
Answer: Option E
A man invests Rs.8000 for 5 years at 5% p.a. Simple Interest interest reckoned yearly. Income tax at the rate of 20% on the interest earned is deducted at the end of each year. Find the amount at the end of the fifth year.- a)Rs.11,500
- b)Rs.10,500
- c)Rs.9,600
- d)Rs.10,000
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
A man invests Rs.8000 for 5 years at 5% p.a. Simple Interest interest reckoned yearly. Income tax at the rate of 20% on the interest earned is deducted at the end of each year. Find the amount at the end of the fifth year.
a)
Rs.11,500
b)
Rs.10,500
c)
Rs.9,600
d)
Rs.10,000
e)
None of these
| | Yash Patel answered |
Answer – C.Rs.9,600 Explanation : 5% is the rate of interest. 20% deducted mean rate of Interest 4% SI = 8000*4*5/100=1600
The amount at the end of 5 years = 8000 + 1600 = 9600
The amount at the end of 5 years = 8000 + 1600 = 9600
Amit lent a part of Rs. 15900 to Raju at 6% SI. Rest to Anil at 5% SI. After 4 years he got an amount of Rs 19376 in total. Then what is the amount paid by Anil in total?- a)Rs. 9176
- b)Rs. 9847
- c)Rs. 10200
- d)Rs. 11200
- e)None
Correct answer is option 'C'. Can you explain this answer?
Amit lent a part of Rs. 15900 to Raju at 6% SI. Rest to Anil at 5% SI. After 4 years he got an amount of Rs 19376 in total. Then what is the amount paid by Anil in total?
a)
Rs. 9176
b)
Rs. 9847
c)
Rs. 10200
d)
Rs. 11200
e)
None
| | Naroj Boda answered |
Answer – 3.Rs. 10200Explanation : 3476 = x*6*4/100 + (15900-x)*5*4/100 x =7400 Anil = 8500+8500*4*5/100 = 10200
Leela takes a loan of Rs. 8400 at 10% p.a. compounded annually which is to be repaid in two equal annual installments. One at the end of one year and the other at the end of the second year. The value of each installment is?- a)4200
- b)4140
- c)4840
- d)5640
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
Leela takes a loan of Rs. 8400 at 10% p.a. compounded annually which is to be repaid in two equal annual installments. One at the end of one year and the other at the end of the second year. The value of each installment is?
a)
4200
b)
4140
c)
4840
d)
5640
e)
None of these
 | Cstoppers Instructors answered |
8400 = x*(210/121) ⇒ 4840
A man invests Rs. 124000 for 9 years at 5% SI. Income tax at the rate of 19% is deducted from interest earned at the end of every year. Find the amount at the end of the 9th year?- a)Rs. 169198
- b)RS. 169918
- c)Rs. 196918
- d)Rs. 199698
- e)None
Correct answer is option 'A'. Can you explain this answer?
A man invests Rs. 124000 for 9 years at 5% SI. Income tax at the rate of 19% is deducted from interest earned at the end of every year. Find the amount at the end of the 9th year?
a)
Rs. 169198
b)
RS. 169918
c)
Rs. 196918
d)
Rs. 199698
e)
None
 | KS Coaching Center answered |
Answer – 1.Rs. 169198 Explanation : for one year = 124000*5/100 = 6200 income tax = 6200*81/100 = 5022 for 9 years = 45198 Amount = 124000+45198 = 169198
Vithya gave Rs.20000/- to Priya for 5 years and Rs.30000/- to Vijay for 2 years. If the rate of interests is the same and she received Rs.12800- as SI from both. What is the rate of interest?- a)8%
- b)7%
- c)9%
- d)11%
- e)None of these
Correct answer is option 'A'. Can you explain this answer?
Vithya gave Rs.20000/- to Priya for 5 years and Rs.30000/- to Vijay for 2 years. If the rate of interests is the same and she received Rs.12800- as SI from both. What is the rate of interest?
a)
8%
b)
7%
c)
9%
d)
11%
e)
None of these
| | Aisha Gupta answered |
A)8% Explanation : 20000*5*R/100 + 30000*2*R/100 = 12800 1600R = 12800 R = 12800/1600 = 8
What is the sum of amount which gives Rs. 6300 as interest @ 7% per annum of simple interest in 7*1/2years?- a)36000
- b)24000
- c)63000
- d)12000
- e)None of these
Correct answer is option 'D'. Can you explain this answer?
What is the sum of amount which gives Rs. 6300 as interest @ 7% per annum of simple interest in 7*1/2years?
a)
36000
b)
24000
c)
63000
d)
12000
e)
None of these
 | Sachin Salaria answered |
S.I=6300,R=7%,T=7*1/2=15/2 YEARS
Formula
SI= P×R×T/100
6300 =P×7×15/100×2
6300=P×7×3/20×2
6300×40=P×7×3
6300×40/7×3=P
300×40=P
12000= P answer is D
Formula
SI= P×R×T/100
6300 =P×7×15/100×2
6300=P×7×3/20×2
6300×40=P×7×3
6300×40/7×3=P
300×40=P
12000= P answer is D
Find the least number of years in which the sum put at 25% rate of interest will be more than doubled.- a)2 years
- b)3 years
- c)4 years
- d)5 years
- e)None of these
Correct answer is option 'D'. Can you explain this answer?
Find the least number of years in which the sum put at 25% rate of interest will be more than doubled.
a)
2 years
b)
3 years
c)
4 years
d)
5 years
e)
None of these
| | Target Study Academy answered |
Amount > = P*(1+25/100)n
Amount = p*(5/4)n
For n = 4, (625/256) which is greater than 2.
Amount = p*(5/4)n
For n = 4, (625/256) which is greater than 2.
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