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All questions of Electromagnetic Waves for NEET Exam
Green-house effect is the heating up of earth's atmosphere due to [2002]- a)green plants
- b)infra-red rays
- c)X-rays
- d)ultraviolet rays
Correct answer is option 'B'. Can you explain this answer?
Green-house effect is the heating up of earth's atmosphere due to [2002]
a)
green plants
b)
infra-red rays
c)
X-rays
d)
ultraviolet rays
 | Aniket Chawla answered |
Infrared rays is the cause of Green house effect. The glass transmits visible light and short infrared rays which are absorbed by plants. Then it emits long infrared rays, which are reflected back by glass.
Which of the following statement is false for theproperties of electromagnetic waves? [2010]- a)Both electric and magnetic field vectorsattain the maxima and minima at the sameplace and same time.
- b)The energy in electromagnetic wave isdivided equally between electric andmagnetic vectors
- c)Both electric and magnetic field vectors areparallel to each other and perpendicular tothe direction of propagation of wave
- d)These waves do not require any materialmedium for propagation.
Correct answer is option 'C'. Can you explain this answer?
Which of the following statement is false for theproperties of electromagnetic waves? [2010]
a)
Both electric and magnetic field vectorsattain the maxima and minima at the sameplace and same time.
b)
The energy in electromagnetic wave isdivided equally between electric andmagnetic vectors
c)
Both electric and magnetic field vectors areparallel to each other and perpendicular tothe direction of propagation of wave
d)
These waves do not require any materialmedium for propagation.
 | Krish Patel answered |
Electromagnetic waves are the combination of mutually perpendicular electric and magnetic fields. So, option (c) is false.
We consider the radiation emitted by the humanbody. Which of the following statements is true? [2003]- a)the radiation emitted lies in the ultravioletregion and hence is not visible.
- b)the radiation emitted is in the infra-redregion.
- c)the radiation is emitted only during the day.
- d)the radiation is emitted during the summersand absorbed during the winters.
Correct answer is option 'B'. Can you explain this answer?
We consider the radiation emitted by the humanbody. Which of the following statements is true? [2003]
a)
the radiation emitted lies in the ultravioletregion and hence is not visible.
b)
the radiation emitted is in the infra-redregion.
c)
the radiation is emitted only during the day.
d)
the radiation is emitted during the summersand absorbed during the winters.
 | Jatin Chakraborty answered |
Depends on the magnitude of frequency
The electric and magnetic field of an electromagneticwave are [2007]- a)in opposite phase and perpendicular to eachother
- b)in opposite phase and parallel to each other
- c)in phase and perpendicular to each other
- d)in phase and parallel to each other.
Correct answer is option 'C'. Can you explain this answer?
The electric and magnetic field of an electromagneticwave are [2007]
a)
in opposite phase and perpendicular to eachother
b)
in opposite phase and parallel to each other
c)
in phase and perpendicular to each other
d)
in phase and parallel to each other.
 | Sarthak Saini answered |
Variation in magnetic field causes electric field and vice-versa.
In electromagnetic waves,
.
Both
and 
are in the same phase.
In electromagnetic waves
E = E0 sin(ωt - kx)
B = B0 sin(ωt - kx)
The electromagnetic waves travel in the
direction of
In electromagnetic waves,
.Both
and are in the same phase.In electromagnetic waves
E = E0 sin(ωt - kx)
B = B0 sin(ωt - kx)
The electromagnetic waves travel in the
direction of
The velocity of electromagnetic radiation in a medium of permittivity ∈0 and permeability μ0 is given by [2008]- a)
- b)
- c)
- d)
Correct answer is option 'C'. Can you explain this answer?
The velocity of electromagnetic radiation in a medium of permittivity ∈0 and permeability μ0 is given by [2008]
a)
b)
c)
d)
 | Sushant Goyal answered |
The velocity of electromagnetic radiation
in a medium of permittivity ∈0 and
permeability μ0 is equal to
in a medium of permittivity ∈0 and
permeability μ0 is equal to
The frequencies of X-rays, γ-rays and ultravioletrays are respectively a, b, and c. Then [2000]- a)a < b, b < c
- b)a < b, b > c
- c)a > b, b > c
- d)a > b, b < c
Correct answer is option 'B'. Can you explain this answer?
The frequencies of X-rays, γ-rays and ultravioletrays are respectively a, b, and c. Then [2000]
a)
a < b, b < c
b)
a < b, b > c
c)
a > b, b > c
d)
a > b, b < c
 | Krish Khanna answered |
γ rays has lowest wavelength and highest frequency among them while ultraviolet ray has highest wavelength and lowest frequency.
Order of frequency : b > a > c
Order of frequency : b > a > c
The electromagnetic radiations are caused by [1999]- a)a stationary charge
- b)uniformly moving charges
- c)accelerated charges
- d)all of above
Correct answer is option 'C'. Can you explain this answer?
The electromagnetic radiations are caused by [1999]
a)
a stationary charge
b)
uniformly moving charges
c)
accelerated charges
d)
all of above
 | Vaibhav Basu answered |
A stationary charge produces electric field only; an uniformly moving charge produces localised electromagnetic field; an accelerated charge produces electromagnetic radiations.
An electromagnetic wave of frequency v = 3.0MHz passes from vacuum into a dielectricmedium with relative permittivity ε = 4.0. Then[NEET Kar. 2013]- a)wavelength is doubled and frequency isunchanged
- b)wavelength is doubled and frequencybecomes half
- c)wavelength is halved and frequencyremains unchanged
- d)wavelength and frequency both remainunchanged
Correct answer is option 'C'. Can you explain this answer?
An electromagnetic wave of frequency v = 3.0MHz passes from vacuum into a dielectricmedium with relative permittivity ε = 4.0. Then[NEET Kar. 2013]
a)
wavelength is doubled and frequency isunchanged
b)
wavelength is doubled and frequencybecomes half
c)
wavelength is halved and frequencyremains unchanged
d)
wavelength and frequency both remainunchanged
 | Ayush Sengupta answered |
Given: frequency f = 2MHz, relative
permittivity ∈r= 4
permittivity ∈r= 4
From formula,
velocity 
[Since frequency remains unchanged]
The decreasing order of wavelength of infrared,microwave, ultraviolet and gamma rays is [2011]- a)microwave, infrared, ultraviolet, gamma rays
- b)gamma rays, ultraviolet, infrared, microwaves
- c)microwaves, gamma rays, infrared,ultraviolet
- d)infrared, microwave, ultraviolet, gamma rays
Correct answer is option 'A'. Can you explain this answer?
The decreasing order of wavelength of infrared,microwave, ultraviolet and gamma rays is [2011]
a)
microwave, infrared, ultraviolet, gamma rays
b)
gamma rays, ultraviolet, infrared, microwaves
c)
microwaves, gamma rays, infrared,ultraviolet
d)
infrared, microwave, ultraviolet, gamma rays
 | Soumya Ahuja answered |
The decreasing order of the wavelengths is as given below :
microwave, infrared, ultraviolet, gamma
rays.
microwave, infrared, ultraviolet, gamma
rays.
The oscillating electric and magnetic field vectorsof electromagnetic wave are oriented along [1994]- a)the same direction and in phase
- b)the same direction but have a phasedifference of 90º
- c)mutually perpendicular directions and arein phase
- d)mutually perpendicular directions but has aphase difference of 90º
Correct answer is option 'C'. Can you explain this answer?
The oscillating electric and magnetic field vectorsof electromagnetic wave are oriented along [1994]
a)
the same direction and in phase
b)
the same direction but have a phasedifference of 90º
c)
mutually perpendicular directions and arein phase
d)
mutually perpendicular directions but has aphase difference of 90º
 | Akshat Chavan answered |
The direction of oscillations of E and B fields are perpendicular to each other as well as to the direction of propagation. So, electromagnetic waves are transverse in nature. The electric and magnetic fields oscillate in same phase.
The ratio of amplitude of magnetic field to theamplitude of electric field for an electromagneticwave propagating in vacuum is equal to : [2012M]- a)the speed of light in vacuum
- b)reciprocal of speed of light in vacuum
- c)the ratio of magnetic permeability to theelectric susceptibility of vacuum
- d)unity
Correct answer is option 'B'. Can you explain this answer?
The ratio of amplitude of magnetic field to theamplitude of electric field for an electromagneticwave propagating in vacuum is equal to : [2012M]
a)
the speed of light in vacuum
b)
reciprocal of speed of light in vacuum
c)
the ratio of magnetic permeability to theelectric susceptibility of vacuum
d)
unity
| | Rocky Handsome answered |
Correct option (b) reciprocal of speed of light in vacuum Explanation: The amplitude of magnetic field and electric field for an electromagnetic wave propagating in vacuum are related as E0 = B0c where c is the speed of light in vacuum. • B0 /E0 =1/C
The electric field part of an electromagnetic wave in a medium is represented by Ex=0;
Ez = 0. The wave is : [2009]- a)moving along x direction with frequency 106Hz and wave length 100 m.
- b)moving along x direction with frequency106 Hz and wave length 200 m.
- c)moving along – x direction with frequency106 Hz and wave length 200 m.
- d)moving along y direction with frequency2π × 106 Hz and wave length 200 m.
Correct answer is option 'B'. Can you explain this answer?
The electric field part of an electromagnetic wave in a medium is represented by Ex=0;
Ez = 0. The wave is : [2009]a)
moving along x direction with frequency 106Hz and wave length 100 m.
b)
moving along x direction with frequency106 Hz and wave length 200 m.
c)
moving along – x direction with frequency106 Hz and wave length 200 m.
d)
moving along y direction with frequency2π × 106 Hz and wave length 200 m.
 | Naveen Menon answered |
Comparing with the equation of wave
The electric field associated with an e.m. wave in vacuum is given by 
cos (kz – 6 ×108t), where E, z and t are in volt/m, meter and seconds respectively. The value of wave vector k is : [2012]- a)2 m–1
- b)0.5 m–1
- c)6 m–1
- d)3 m–1
Correct answer is option 'A'. Can you explain this answer?
The electric field associated with an e.m. wave in vacuum is given by cos (kz – 6 ×108t), where E, z and t are in volt/m, meter and seconds respectively. The value of wave vector k is : [2012]
cos (kz – 6 ×108t), where E, z and t are in volt/m, meter and seconds respectively. The value of wave vector k is : [2012]a)
2 m–1
b)
0.5 m–1
c)
6 m–1
d)
3 m–1
 | Mehul Iyer answered |
On comparing the given equation to
if 
represent electric and magnetic field vectors of the electromagnetic waves, then the direction of propagation of the waves will be along- a)
- b)
- c)
- d)
Correct answer is option 'D'. Can you explain this answer?
if represent electric and magnetic field vectors of the electromagnetic waves, then the direction of propagation of the waves will be along
represent electric and magnetic field vectors of the electromagnetic waves, then the direction of propagation of the waves will be alonga)
b)
c)
d)
 | Mahesh Saini answered |
Direction of propagation of electro-magnetic waves is perpendicular to Electric field and Magnetic field. Hence, direction is given by
In a circuit, inductance L and capacitance C are connected as shown in the figure. A1 and A2 
are ammeters. When key K is pressed to complete the circuit, then just after closing key (K), the readings of A1 and A2 will be [1999]- a)zero in both A1 and A2
- b)maximum in both A1 and A2
- c)zero in A1 and maximum in A2
- d)maximum in A1 and zero in A2
Correct answer is option 'D'. Can you explain this answer?
In a circuit, inductance L and capacitance C are connected as shown in the figure. A1 and A2
are ammeters. When key K is pressed to complete the circuit, then just after closing key (K), the readings of A1 and A2 will be [1999]
a)
zero in both A1 and A2
b)
maximum in both A1 and A2
c)
zero in A1 and maximum in A2
d)
maximum in A1 and zero in A2
 | Prisha Singh answered |
Initially there is no D.C. current in inductive circuit and maximum D.C. current is in capacitive current. Hence, the current is zero in A2 and maximum in A1.
The electric and the magnetic field associated with an E.M. wave, propagating along the +z-axis, can be represented by [2011]- a)
- b)
- c)
- d)
Correct answer is option 'A'. Can you explain this answer?
The electric and the magnetic field associated with an E.M. wave, propagating along the +z-axis, can be represented by [2011]
a)
b)
c)
d)
| | Krish Khanna answered |
E.M. wave always propagates in a direction perpendicular to both electric and magnetic fields. So, electric and magnetic fields should be along + X– and + Y–directions respectively. Therefore, option (a) is the correct option.
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