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All questions of Factorisation of Algebraic expressions for Class 8 Exam
Factorise: x2+ 8x + 16- a)(x+ 3)2
- b)(x+ 2)2
- c)(x+ 4)2
- d)(x+ 5)2
Correct answer is option 'C'. Can you explain this answer?
Factorise: x2+ 8x + 16
a)
(x+ 3)2
b)
(x+ 2)2
c)
(x+ 4)2
d)
(x+ 5)2
 | Geetika Shah answered |
C ) (x2 +8x +16)
= (x2 + 4x + 4x + 16)
= ( x2 + 4x ) + (4x + 16 )
= x(x + 4 ) +4(x + 4 )
=(x + 4)(x + 4)
=(x + 4)2
= (x2 + 4x + 4x + 16)
= ( x2 + 4x ) + (4x + 16 )
= x(x + 4 ) +4(x + 4 )
=(x + 4)(x + 4)
=(x + 4)2
Solve: 7x2y2z2÷14xyza)(1/2)xyzb)(3/2)xyzc)(3/4)xyzd)(2/1)xyzCorrect answer is option 'A'. Can you explain this answer?
 | Target Study Academy answered |
7x²y²z²÷14xyz
=(7/14)(x²/x)(y²/y)(z²/z)
=1/2(x)(y)(z)
=1/2xyz.
=(7/14)(x²/x)(y²/y)(z²/z)
=1/2(x)(y)(z)
=1/2xyz.
Factorise: x2+x y+ 8x+ 8y- a)(x + 8) (x + y)
- b)(x + y)
- c)(x + 8)
- d)(x + 9) (x – y)
Correct answer is option 'A'. Can you explain this answer?
Factorise: x2+x y+ 8x+ 8y
a)
(x + 8) (x + y)
b)
(x + y)
c)
(x + 8)
d)
(x + 9) (x – y)
 | Aditi Saxena answered |
x^2 + xy + 8x + 8y = x[x + y] + 8[x + y]
= (x + y)(x + 8)
Divide the given polynomial by the given monomial: (x3+ 2x2+ 3x) ÷ 2x- a)1/2 (x2+2x+3)
- b)1/2
- c)(x2+2x+3)
- d)none of these
Correct answer is option 'A'. Can you explain this answer?
Divide the given polynomial by the given monomial: (x3+ 2x2+ 3x) ÷ 2x
a)
1/2 (x2+2x+3)
b)
1/2
c)
(x2+2x+3)
d)
none of these
| | Ananya Das answered |
(x3+2x2+3x)/2x
=x(x2+2x+3)/2x
=(x2+2x+3)/2
=x(x2+2x+3)/2x
=(x2+2x+3)/2
Find the common factors of 2y, 22xy.- a)2y
- b)2
- c)22
- d)y
Correct answer is option 'A'. Can you explain this answer?
Find the common factors of 2y, 22xy.
a)
2y
b)
2
c)
22
d)
y
| | Amit Sharma answered |
Only 2y is common in both the terms
Factorize x² + 8x + 12- a)(x + 2)(x + 6)
- b)(x + 3)(x + 4)
- c)3x + 12
- d)3x - 12
Correct answer is option 'A'. Can you explain this answer?
Factorize x² + 8x + 12
a)
(x + 2)(x + 6)
b)
(x + 3)(x + 4)
c)
3x + 12
d)
3x - 12
 | Kaavya Saha answered |
x² + 8x + 12
two no whose product is 12 and sum is 8
ie. 2 and 6 so;
x2+2x+6x+12
x(x+2)+6(x+2)
(x+2)(x+6)
two no whose product is 12 and sum is 8
ie. 2 and 6 so;
x2+2x+6x+12
x(x+2)+6(x+2)
(x+2)(x+6)
Which of the following is quotient obtained on dividing –18 xyz2 by –3 xz?- a)6 Yz
- b)–6 yz
- c)6 xy2
- d)6 xy
Correct answer is option 'A'. Can you explain this answer?
Which of the following is quotient obtained on dividing –18 xyz2 by –3 xz?
a)
6 Yz
b)
–6 yz
c)
6 xy2
d)
6 xy
| | Geetika Shah answered |
–18 xyz2/–3 xz x and x gets cancelled,-18 gets divided by -3 .and z2 gets divided by z so only one z remain in numerator So the quotient obtained is 6yz
Can you explain the answer of this question below:Divide as directed: 26xy (x + 5) (y – 4) ÷ 13x (y – 4)
- A:
2y (x + 5)
- B:
(x + 5)
- C:
2y
- D:
None of these
The answer is A.
Divide as directed: 26xy (x + 5) (y – 4) ÷ 13x (y – 4)
2y (x + 5)
(x + 5)
2y
None of these
 | Kavya Saxena answered |
26xy(x + 5) (y - 4) / 13x(y - 4)
Cancelling 13x(y-4)
=2y(x+5)
Cancelling 13x(y-4)
=2y(x+5)
Factorise: p4– 81- a)(p – 3) (p + 3) (p2+ 9)
- b)(p + 3) (p2+ 9)
- c)(p – 3) (p + 3)
- d)none of these
Correct answer is option 'A'. Can you explain this answer?
Factorise: p4– 81
a)
(p – 3) (p + 3) (p2+ 9)
b)
(p + 3) (p2+ 9)
c)
(p – 3) (p + 3)
d)
none of these
 | Malavika Basu answered |
We have p4 - 81 = (p2)2 - (9)2
Now using a2 - b2 = (a + b)(a - b), we have
(p2)2 - (9)2 = (p2 + 9)(p2 -9)
We can factorise p2 - 9 further as
p2 - 9 = (p)2 - (3)2
= (p + 3)(p - 3)
∴ p4 - 81 = (p + 3)(p - 3)(p2 + 9)
Can you explain the answer of this question below:Factorise: 4y2−12y+ 9
- A:
(7y− 5)2
- B:
(5y− 3)2
- C:
(2y− 5)2
- D:
(2y− 3)2
The answer is D.
Factorise: 4y2−12y+ 9
(7y− 5)2
(5y− 3)2
(2y− 5)2
(2y− 3)2
| | Kavya Saxena answered |
We have 4y2 - 12y+9. comparing the equation with (a-b)2=a2-2ab+b2,gives us a2=(2y)2,2ab=2*3*2y and b2=(3)2.Hence the answer is (2y-3)2.
Factorise: 10x2 − 18x3 + 14x4- a)2x2
- b)2x2(9x2−5x+7)
- c)(7x2−9x+5)
- d) 2x2(7x2−9x+5)
Correct answer is option 'D'. Can you explain this answer?
Factorise: 10x2 − 18x3 + 14x4
a)
2x2
b)
2x2(9x2−5x+7)
c)
(7x2−9x+5)
d)
2x2(7x2−9x+5)
 | Baishali Mehta answered |
10x2 − 18x3 + 14x4 = 2x(5x− 9x2 + 7x3) = 2x2(5− 9x + 7x2)
When we factorise an expression, we write it as a ________ of factors.- a)product
- b)difference
- c)sum
- d)none of these
Correct answer is option 'A'. Can you explain this answer?
When we factorise an expression, we write it as a ________ of factors.
a)
product
b)
difference
c)
sum
d)
none of these
| | Aditya Shah answered |
When we factorise an algebraic expression, we write it as a product of factors. These factors may be numbers, algebraic variables or algebraic expressions.
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