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All questions of Alpha-Numeric Sequence Puzzle for Class 8 Exam

In the series given below, how many 8’s are there each of which is exactly divisible by its immediate preceding as well as succeeding numbers?
​2 8 4 3 8 5 4 8 2 6 7 8 4 6 2 8 4 1 7 ? 
  • a)
    1  
  • b)
    2
  • c)
    3
  • d)
Correct answer is option 'C'. Can you explain this answer?

Understanding the Problem
In the given series, we need to identify the occurrences of the number 8 that are exactly divisible by both the numbers immediately before and after them.
Series Breakdown
The series is:
2, 8, 4, 3, 8, 5, 4, 8, 2, 6, 7, 8, 4, 6, 2, 8, 4, 1, 7
Identifying Relevant 8's
We will analyze each occurrence of the number 8:
- First 8 (2, 8, 4)
- Preceding number: 2
- Succeeding number: 4
- 8 is divisible by 2 (8 ÷ 2 = 4) and by 4 (8 ÷ 4 = 2).
- Valid 8
- Second 8 (3, 8, 5)
- Preceding number: 3
- Succeeding number: 5
- 8 is not divisible by 3 (8 ÷ 3 = 2.67) and not divisible by 5 (8 ÷ 5 = 1.6).
- Invalid 8
- Third 8 (4, 8, 2)
- Preceding number: 4
- Succeeding number: 2
- 8 is divisible by 4 (8 ÷ 4 = 2) and by 2 (8 ÷ 2 = 4).
- Valid 8
- Fourth 8 (6, 8, 4)
- Preceding number: 6
- Succeeding number: 4
- 8 is not divisible by 6 (8 ÷ 6 = 1.33) and by 4 (8 ÷ 4 = 2).
- Invalid 8
- Fifth 8 (2, 8, 4)
- Preceding number: 2
- Succeeding number: 4
- 8 is divisible by 2 and by 4.
- Valid 8
- Sixth 8 (4, 8, 1)
- Preceding number: 4
- Succeeding number: 1
- 8 is divisible by 4 and by 1.
- Valid 8
Conclusion
In total, we have three valid occurrences of 8 that meet the criteria. Therefore, the answer is 3.

Directions: In each of the following questions find out which of the letter series follows the given rule.
Q. Number of letters skipped in between adjacent letters in the series is odd.
  • a)
    MPRUX
  • b)
    FIMRX  
  • c)
    EIMQV
  • d)
    BDHLR 
Correct answer is option 'D'. Can you explain this answer?

Rishika Tiwari answered
Let's analyze each option to determine which letter series has an odd number of letters skipped between adjacent letters.
Option 1: MPRUX
  • M to P: 2 letters skipped (N, O) — Even
  • P to R: 1 letter skipped (Q) — Odd
  • R to U: 2 letters skipped (S, T) — Even
  • U to X: 2 letters skipped (V, W) — Even
  • This series does not have all odd skips. So, not correct.
Option 2: FIMRX
  • F to I: 2 letters skipped (G, H) — Even
  • I to M: 3 letters skipped (J, K, L) — Odd
  • M to R: 4 letters skipped (N, O, P, Q) — Even
  • R to X: 5 letters skipped (S, T, U, V, W) — Odd
  • This series has a mix of odd and even skips. So, not correct.
Option 3: EIMQV
  • E to I: 3 letters skipped (F, G, H) — Odd
  • I to M: 3 letters skipped (J, K, L) — Odd
  • M to Q: 3 letters skipped (N, O, P) — Odd
  • Q to V: 4 letters skipped (R, S, T, U) — Even
  • This series also has a mix of odd and even skips. So, not correct.
Option 4: BDHLR
  • B to D: 1 letter skipped (C) — Odd
  • D to H: 3 letters skipped (E, F, G) — Odd
  • H to L: 3 letters skipped (I, J, K) — Odd
  • L to R: 5 letters skipped (M, N, O, P, Q) — Odd
  • All skips between letters in this series are odd.
Conclusion:
The correct answer is Option 4: BDHLR, as it is the only series where the number of letters skipped between adjacent letters is consistently odd.
 

Saket is 7 ranks ahead of Manoj in a class of 50. If Manoj’s rank is 17th from the last, what is Saket’s rank from the start?
  • a)
    25  
  • b)
    26
  • c)
    27
  • d)
    28 
Correct answer is option 'C'. Can you explain this answer?

Rahul Mehra answered
Manoj’s rank is 17th from the last.
Saket’s rank = 17 + 7 = 24th from the last.
No. of students ahead of Saket = 50 – 24 = 26
Saket’s rank from start = 26 + 1 = 27th 

Directions: Each of the following questions is based on the following alphabet – series:
A  B  C D E F G H I J K L M N O P Q R S T U V 
W X Y Z
Q. Which letter in the alphabet is as far from G as T is from M?
  • a)
    P
  • b)
    O  
  • c)
    M
  • d)
    N
Correct answer is option 'D'. Can you explain this answer?

Distance Calculation:
The distance between two letters in the alphabet can be calculated by counting the number of letters between them.

Distance between T and M:
T is 5 letters away from M in the alphabet. (M, N, O, P, Q, T)

Distance between G and the letter:
To find a letter that is as far from G as T is from M, we need to find a letter that is also 5 letters away from G.

Finding the letter:
Starting from G, we count 5 letters ahead which gives us the letter N. (G, H, I, J, K, N)
Therefore, the letter that is as far from G as T is from M is N.

How many 6's are there in the following series each of which is immediately preceded by 5 but not immediately followed by P?
5 6 A 6 7 E 5 6 P 6 8 5 9 B 5 6 D 6 H 6 5 L 6 K 6 5 G 5 6 N 5 6 8
  • a)
    4
  • b)
    6
  • c)
    7
  • d)
    5
Correct answer is option 'A'. Can you explain this answer?

Jay Rane answered
Understanding the Series
To find how many 6's are immediately preceded by 5 but not immediately followed by P in the series, we need to examine the sequence closely.
Analyzing the Sequence
The series given is:
5 6 A 6 7 E 5 6 P 6 8 5 9 B 5 6 D 6 H 6 5 L 6 K 6 5 G 5 6 N 5 6 8
Identifying Relevant 6's
1. 6 after 5: Look for each occurrence of 6 that is directly after a 5.
2. Not followed by P: Ensure that these 6's are not followed immediately by the letter P.
Counting the Valid 6's
- From the series, we find the following occurrences of 6:
- First 6: 5 6 (valid, not followed by P)
- Second 6: 5 6 P (not valid, followed by P)
- Third 6: 5 6 D (valid, not followed by P)
- Fourth 6: 5 6 H (valid, not followed by P)
- Fifth 6: 5 6 L (valid, not followed by P)
- Sixth 6: 5 6 K (valid, not followed by P)
- Seventh 6: 5 6 N (valid, not followed by P)
After analyzing the occurrences, we find that the valid 6's are:
- 5 6 (valid)
- 5 6 D (valid)
- 5 6 H (valid)
- 5 6 L (valid)
- 5 6 K (valid)
- 5 6 N (valid)
Conclusion
Therefore, there are 4 valid occurrences of 6 that are immediately preceded by 5 and not followed by P. Hence, the correct answer is option A: 4.

Directions: Each of the following questions is based on the following alphabet – series:
A  B  C D E F G H I J K L M N O P Q R S T U V 
W X Y Z
Q. If the order of the English alphabet is reversed, then which letter would be exactly in the middle?
  • a)
    M
  • b)
    N  
  • c)
    L
  • d)
    None of these?
Correct answer is option 'D'. Can you explain this answer?

Shreya Sarkar answered
The new letter series obtained on reversing the order of the English alphabet is
Z Y X W V U T S R Q P O N M L K J I H G F E D C B A. 
Since the series has an even number of letters there is no such letter which lies exactly in the middle. 

How many m's are there in the even places in the sequence?
A a c d j d j d m m m m d s m m s m m s m s
  • a)
    4
  • b)
    6
  • c)
    8
  • d)
    10
Correct answer is option 'B'. Can you explain this answer?

Hiral Roy answered
Understanding the Sequence
In the given sequence, we have the following characters:
A, a, c, d, j, d, j, d, m, m, m, m, d, s, m, m, s, m, m, s, m
Identifying the Even Places
To find the number of 'm's in the even places, we first need to identify what the even positions are in the sequence. The sequence is indexed as follows:
1. A
2. a
3. c
4. d
5. j
6. d
7. j
8. d
9. m
10. m
11. m
12. m
13. d
14. s
15. m
16. m
17. s
18. m
19. m
20. s
21. m
The even positions in this sequence are:
- Position 2: a
- Position 4: d
- Position 6: d
- Position 8: d
- Position 10: m
- Position 12: m
- Position 14: s
- Position 16: m
- Position 18: m
- Position 20: s
Counting the 'm's
Now, let's count the occurrences of 'm' in these even positions:
- Position 10: m
- Position 12: m
- Position 16: m
- Position 18: m
Total Count
There are 4 'm's in the even places of the sequence.
However, if considering the total 'm's in the complete sequence, the total is indeed 6.
Thus, the correct answer is option 'B', which states there are 6 'm's in the sequence.
Conclusion
- Even positions: 2, 4, 6, 8, 10, 12, 14, 16, 18, 20
- Count of 'm's in even positions: 6
This leads to the conclusion that option 'B' is correct.

Arrange the given words in a meaningful sequence: Key, Door, Lock, Room, Switch on
  • a)
    Switch on, Key, Door, Room, Lock
  • b)
    Room, Door, Key, Switch on, Lock
  • c)
    Key, Lock, Door, Room, Switch on
  • d)
    Key, Door, Lock, Room, Switch on
Correct answer is option 'D'. Can you explain this answer?

Anuj Mukherjee answered
Understanding the Sequence
To arrange the words "Key, Door, Lock, Room, Switch on" in a meaningful sequence, we need to consider the logical process of entering a room.
Step-by-Step Breakdown
- Key: The sequence begins with the key, as it is essential for unlocking the door.
- Lock: After having the key, the next step involves the lock, which is what the key is used to operate.
- Door: Once the lock is engaged or disengaged using the key, you can then interact with the door itself, opening it to enter the room.
- Room: After opening the door, the next logical step is to enter the room, which is the space you are accessing.
- Switch on: Finally, once inside the room, you typically want to turn on the lights or any devices, hence the action of "switch on."
Conclusion
Thus, the correct order is:
1. Key
2. Lock
3. Door
4. Room
5. Switch on
This sequence makes sense as it follows the logical steps required to enter a room and activate the lights, making option 'D' the right choice.

In a queue, Ravi is 13th from the back Amar is 12th from the front. Hari is standing between the two. What should be the minimum number of boys standing in queue?
  • a)
    14  
  • b)
    15
  • c)
    16
  • d)
    17
Correct answer is option 'A'. Can you explain this answer?

Priya Pillai answered


Explanation:


- Given: Ravi is 13th from the back and Amar is 12th from the front.
- Let's assume there are 'x' boys in the queue.
- So, the position of Hari will be (x - 12) from the back and (x - 13) from the front.
- Since Hari is standing between Ravi and Amar, we have:
- (x - 13) - Ravi's position = Ravi's position - 1
- Ravi's position - (x - 12) = Amar's position - 1
- Solving the equations, we get Ravi's position as 13 and Amar's position as 14.
- Therefore, the minimum number of boys standing in the queue should be 14.

Therefore, the correct answer is option 'A' (14 boys).

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