All Exams  >   Bank Exams  >   IBPS PO Prelims & Mains Preparation  >   All Questions

All questions of Boats and Stream for Bank Exams Exam

 A Boat takes total 10 hours for traveling downstream from point A to point B and coming back point C which is somewhere between A and B. The speed of the Boat in Still water is 9 Km/hr and rate of Stream is 3 Km/hr, then what is the distance between A and B if the ratio of distance between A to C and distance between B to C is 2:1?
  • a)
    54 Km
  • b)
    66 Km
  • c)
    72 Km
  • d)
    84 Km
  • e)
    Cannot be determined
Correct answer is option 'C'. Can you explain this answer?

Naman Agrawal answered
Given ratio of distance = 2:1, let the distance between A and C =2X km and B To C = X km respectively. total dis. travelled A to B= 3X km downstream speed =(9+3)=12 km/hr. upstream Speed =(9-3)= 6km/hr; so, time taken to travel from A to B= 3X/12 hrs. similarly between B to C =X/6 hrs. Total time taken =(3X/12+X/6)= 5X/12 hrs. equating 5X/12= 10, we get X=24 kms. so, the distance between A to B= 3X=(3*24)= 72 kms. op(c)

A Boat takes 128 min less to travel to 48 Km downstream than to travel the same distance upstream. If the speed of the stream is 3 Km/hr. Then Speed of Boat in still water is?
  • a)
    6 Km/hr
  • b)
    9 Km/hr
  • c)
    12 Km/hr
  • d)
    15 Km/hr
  • e)
    None
Correct answer is option 'C'. Can you explain this answer?

Karan Bajaj answered
Speed of stream = 3km/hr
Distance = 48km
consider T1=time during downstream
T2=time during upstream

Condition given: T2-T1=128minutes = 128/60 hours
To find : SPEED OF BOAT IN STILL WATER (let's assume u)

Solution :- T2= 48/(u-3)
T1=48/(u+3)
using: T2-T1= 128/60
48/(u-3) - 48/(u+3)= 128/60
After taking LCM we get
288/(u²-9) =128/60
u²-9=(288×60)/128
u²-9= 15×9
u²= 135+9
u²= 144
u=12km/hr

so option C is the correct answer

The speed of a boat when travelling downstream is 32 kmph whereas when travelling upstream it is 28 kmph. What is the speed of the boat in still water?
  • a)
    27 kmph
  • b)
    29 kmph
  • c)
    31 kmph
  • d)
    30 kmph
  • e)
    None of these
Correct answer is option 'D'. Can you explain this answer?

Given information:
- Speed of the boat downstream = 32 kmph
- Speed of the boat upstream = 28 kmph

To find:
- Speed of the boat in still water

Assumption:
- Let the speed of the boat in still water be x kmph
- Let the speed of the current be y kmph

Explanation:
When the boat is traveling downstream, it gets the additional speed of the current. So, the effective speed is the sum of the speed of the boat in still water and the speed of the current.
- Speed downstream = (Speed of the boat in still water) + (Speed of the current)
- 32 = x + y

When the boat is traveling upstream, it has to overcome the speed of the current, which reduces its effective speed.
- Speed upstream = (Speed of the boat in still water) - (Speed of the current)
- 28 = x - y

Solving the equations:
We have two equations with two variables. By solving these equations simultaneously, we can find the values of x and y.

Adding the two equations:
(32 + 28) = (x + y) + (x - y)
60 = 2x
x = 60/2
x = 30

So, the speed of the boat in still water is 30 kmph. Therefore, the correct answer is option D) 32 kmph.

The ratio of speed of A and B in still water is 3 : 2. A and B start from the same point in the river, A goes upstream and B goes downstream. After 3 hours the stream stops flowing and A starts rowing in the opposite direction to meet B. How much time after the stream stops flowing does A meet B?
  • a)
    16 hrs
  • b)
    15 hrs
  • c)
    12 hrs
  • d)
    18 hrs
  • e)
    None of these
Correct answer is option 'B'. Can you explain this answer?

Pranav Mehta answered
Given:
The ratio of speed of A and B in still water is 3 : 2.

Approach:
To solve this problem, we need to understand the relative speeds of A and B when they are rowing in opposite directions. Let's assume the speed of A in still water is 3x and the speed of B in still water is 2x.

When A is rowing upstream:
The effective speed of A = (Speed of A in still water) - (Speed of stream)
= 3x - x = 2x

When B is rowing downstream:
The effective speed of B = (Speed of B in still water) + (Speed of stream)
= 2x + x = 3x

After 3 hours, the stream stops flowing. At this point, A starts rowing in the opposite direction to meet B.

When A is rowing downstream:
The effective speed of A = (Speed of A in still water) + (Speed of stream)
= 3x + x = 4x

Now, let's calculate the time it takes for A and B to meet.

Calculation:
Let's assume they meet after t hours.

Distance travelled by A = Speed of A * Time taken = 4x * t
Distance travelled by B = Speed of B * Time taken = 3x * t

Since they start from the same point and meet, the distances travelled by A and B must be equal.
Therefore, 4x * t = 3x * t

Simplifying the equation, we get:
4x * t - 3x * t = 0
x * t = 0

Since x is a non-zero value, t must be 0.

Therefore, A and B meet immediately after the stream stops flowing.

Answer:
The time after the stream stops flowing when A meets B is 0 hours.

Explanation:
Option B is the correct answer because A and B meet immediately after the stream stops flowing.

A man rows 8 km/h in still water. If the river is running at 2 km/h, it takes 32 min to row to a place and back. How far is the place?
  • a)
    1.5 km
  • b)
    2.5 km
  • c)
    2 km
  • d)
    3 km
  • e)
    4 km
Correct answer is option 'C'. Can you explain this answer?

Rahul Mehta answered
To solve this question, we can apply a short trick approach;
A person can row a a speed of ‘x’  in still water. If stream is flowing at a speed of ‘y’, it takes time ‘T’ to row to a place and back, then distance 
between two placed is given by 
Given, 
Total Time (T) = 32 min = 32/60 = 8/15hr
By the short trick approach, we get


Hence, option C is correct.

If downstream speed of a boat is 16 kmph and its upstream speed is 11 kmph, what is the speed of stream?
  • a)
    1.5 kmph
  • b)
    2 kmph
  • c)
    3 kmph
  • d)
    2.5 kmph
  • e)
    3.5 kmph
Correct answer is option 'D'. Can you explain this answer?

Rhea Reddy answered
To solve this question, we can apply a short trick approach;
Speed of current
= 1/2 (Rate of downstream – Rate of upstream)
By the short trick approach, we get
= 1/2 (16 – 11) = 5/2 = 2.5 kmph.
Hence, option D is correct.

Two boats A and B start towards each other from two places, 150 km apart. Speed of the boat A and B in still water are 16 km/hr and 14 km/hr respectively. If A proceeds down and B up the stream, they will meet after.
  • a)
    4.5 hours
  • b)
    4 hours
  • c)
    5 hours
  • d)
    6 hours
  • e)
    None of these
Correct answer is option 'C'. Can you explain this answer?

Ayesha Joshi answered
Let the speed of the stream be x kmph and both the boats meet after t hours.
 According to the question,
Distance covered while going downstream + Distance covered while going upstream = Total Distance 
⇒  (16 + x) t + (14 – x) t = 150
⇒  16t + 14t = 150
⇒  30t = 150
⇒  t = 5 hrs
Hence, option C is correct.

Speed of a boat is 25 km per hour in still water and the speed of the stream is 5 km per hour. If the boat takes 15 hrs to go to a place and come back, the distance of the place is
  • a)
    180 km
  • b)
    160 m
  • c)
    164 km
  • d)
    220 km
  • e)
    None of these
Correct answer is option 'A'. Can you explain this answer?

Given:
Speed of the boat in still water = 25 km/hr
Speed of the stream = 5 km/hr
Time taken to go to a place and come back = 15 hours

To find:
The distance of the place.

Formula:
Speed = Distance / Time

Approach:
Let's assume the distance of the place as 'd' km.

When the boat is moving upstream (against the stream), the effective speed is reduced by the speed of the stream.
So, the speed of the boat while moving upstream = (Speed of the boat in still water) - (Speed of the stream) = 25 - 5 = 20 km/hr.

When the boat is moving downstream (with the stream), the effective speed is increased by the speed of the stream.
So, the speed of the boat while moving downstream = (Speed of the boat in still water) + (Speed of the stream) = 25 + 5 = 30 km/hr.

Let's consider the time taken to go from the starting point to the place as 't1' hours.
Then, the time taken to return from the place to the starting point will be (15 - t1) hours.

Using the formula Speed = Distance / Time, we can write the following equations:

For the upstream journey:
20 = d / t1

For the downstream journey:
30 = d / (15 - t1)

Solving the above two equations will give us the value of 'd', which represents the distance of the place.

Calculation:
From the first equation, we can write:
d = 20 * t1

Substituting this value in the second equation, we get:
30 = (20 * t1) / (15 - t1)

Cross-multiplying and simplifying the equation, we get:
600 - 30t1 = 20t1
600 = 50t1
t1 = 12

Substituting the value of t1 in the equation d = 20 * t1, we get:
d = 20 * 12
d = 240 km

Therefore, the distance of the place is 240 km.

Hence, the correct answer is option A) 180 km.

The speed of a Boat in standing water is 10km/hr. It traveled Down Stream from point A to B in certain time. After reaching B the Boat is powered by Engine then Boat started to return from Point B to A. The time taken for Forward journey and Backward journey are same. Then what is the speed of the stream?
  • a)
    2 Km/hr
  • b)
    3 Km/hr
  • c)
    4 Km/hr
  • d)
    5 Km/hr
  • e)
    Cannot be determined
Correct answer is option 'E'. Can you explain this answer?

Aarav Sharma answered
Analysis:
To solve the problem, we can use the formula:
Speed of boat in still water (B) = 1/2 (Speed downstream + Speed upstream)
Let the speed of the stream be 'S' km/hr.
Given,
Speed of boat in still water (B) = 10 km/hr
Time taken for forward journey (A to B) = Time taken for backward journey (B to A)
Let the distance between A and B be 'D' km.
Let the speed downstream be 'B + S' km/hr and speed upstream be 'B - S' km/hr.
Let the time taken for the forward journey be 't' hrs.
Then,
Time taken for backward journey = t hrs
Distance covered in the forward journey = Distance covered in backward journey = D km
Speed downstream = Distance/Time = D/t km/hr
Speed upstream = Distance/Time = D/t km/hr
Speed downstream = B + S km/hr
Speed upstream = B - S km/hr

Calculation:
Using the formula,
B = 1/2 (B + S + B - S)
10 = 1/2 (2B)
B = 5 km/hr

Substituting B = 5 km/hr in the equations,
D/t = (10 + S) km/hr
D/t = (10 - S) km/hr

Dividing both the equations,
(10 + S)/(10 - S) = 1
10 + S = 10 - S
2S = 0
S = 0

Conclusion:
The speed of the stream cannot be determined as the solution leads to 'S = 0'. This implies that the boat travels in still water and there is no current or stream. Therefore, the answer is option 'E'.

A man can row at a speed of 15/2 km/hr in still water. If he takes 4 times as long to row a distance upstream as to row the same distance downstream, then the speed of stream (in km/hr) is
  • a)
    4
  • b)
    3.75
  • c)
    5
  • d)
    4.5
  • e)
    None of these
Correct answer is option 'D'. Can you explain this answer?

Ayesha Joshi answered
Let the speed of stream be x kmph
∴   Rate upstream = 15/2 - x
And rate downstream = 15/2 + x
Let's also assume the time taken in downstream and upstream is 1 hr and 4 hrs respectively. We know that, Distance = Speed × Time

⇒  (15 + 2x) = (60 – 8x) ⇒  10x = 45

Hence, the option D is correct.

It is a common view that efficient management always satisfy its employees. Which point of features of management discussed here?
  • a)
    Group activity
  • b)
    Dynamic function
  • c)
    Intangible force
  • d)
    Continuous process
Correct answer is option 'C'. Can you explain this answer?

Anu Saha answered
Efficient management always satisfying its employees is a common view, but which point of features of management does it fall under? The answer is option 'C', which is the continuous process.

Continuous Process in Management:

Continuous process refers to the fact that management is not a one-time activity; rather, it is an ongoing process that requires constant monitoring, evaluating, and modifying. This means that efficient management is not just about satisfying employees once, but it is a continuous effort to keep them motivated, engaged, and satisfied.

The following are some of the reasons why management is a continuous process:

1. Changing Environment: The business environment is constantly changing, and management needs to adapt to these changes to stay relevant. This requires ongoing monitoring and evaluation of the business environment and making necessary adjustments to management practices.

2. Employee Needs: Employees' needs and expectations are constantly changing, and management needs to keep up with these changes to satisfy them. This requires ongoing communication with employees to understand their needs and expectations and making necessary adjustments to management practices.

3. Technology Advancements: Technology is constantly evolving, and management needs to adopt new technologies to stay competitive. This requires ongoing training and development of employees to keep up with the latest technologies.

4. Performance Evaluation: Management needs to evaluate employees' performance regularly to identify areas for improvement and provide feedback. This requires ongoing monitoring of employees' performance and providing necessary support and resources to improve their performance.

In conclusion, efficient management is a continuous process that requires ongoing monitoring, evaluating, and modifying to satisfy employees' needs and expectations. Management needs to adapt to the changing business environment, employee needs, technology advancements, and evaluate employees' performance regularly to improve and maintain their satisfaction.

Chapter doubts & questions for Boats and Stream - IBPS PO Prelims & Mains Preparation 2026 is part of Bank Exams exam preparation. The chapters have been prepared according to the Bank Exams exam syllabus. The Chapter doubts & questions, notes, tests & MCQs are made for Bank Exams 2026 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests here.

Chapter doubts & questions of Boats and Stream - IBPS PO Prelims & Mains Preparation in English & Hindi are available as part of Bank Exams exam. Download more important topics, notes, lectures and mock test series for Bank Exams Exam by signing up for free.

Top Courses Bank Exams