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All questions of Directions & Distances for Bank Exams Exam

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Ayush starts from his house and moves towards South. He walks 100m, then turns left and walks 200m, turns right and walks 500m. How far is he from his house?
  • a)
    400 √5m                                                 
  • b)
    800m      
  • c)
    200 √10m                                               
  • d)
    200 √2m           
Correct answer is option 'C'. Can you explain this answer?

Arya Roy answered
We can solve this problem using the Pythagorean theorem.

First, let's break down Ayush's movements:
1. He walks 100m south.
2. He turns left (which means he is now facing east) and walks 200m.
3. He turns right (which means he is now facing south again) and walks 500m.

Now, let's determine his horizontal (east-west) and vertical (north-south) displacements.

Horizontal displacement:
Ayush only moved horizontally during step 2, where he walked 200m east. Therefore, his total horizontal displacement is 200m.

Vertical displacement:
Ayush moved vertically during steps 1 and 3. In step 1, he walked 100m south, and in step 3, he walked 500m south. Therefore, his total vertical displacement is 100m + 500m = 600m.

Now we can use the Pythagorean theorem to calculate the distance between his starting point (his house) and his final position:

Distance = √(horizontal displacement^2 + vertical displacement^2)
Distance = √(200m^2 + 600m^2)
Distance = √(40,000m^2 + 360,000m^2)
Distance = √(400,000m^2)
Distance = 200√10m

So the correct answer is 3 (200√10m).

Tanuj started walking from a point ‘P’ towards South. After walking 40 metres he took a left turn. He then walked 30 metres and reached a point Q.  What is the straight distance between P and Q and Q is towards in which direction with reference to point P?          
  • a)
    60 metres, South-East         
  • b)
    50 metres, South-West               
  • c)
    50 metres, South-East                   
  • d)
    Data Inadequate           
Correct answer is option 'C'. Can you explain this answer?

Aryan Goyal answered
Given: Tanuj started walking from a point P towards South. After walking 40 metres he took a left turn. He then walked 30 metres and reached a point Q.

To find: The straight distance between P and Q and Q is towards in which direction with reference to point P.

Solution:

Let us draw a diagram to understand the situation better.

From the diagram, we can see that:

- Tanuj starts walking from point P towards South.
- After walking 40 metres, he takes a left turn and walks 30 metres to reach point Q.
- The straight distance between P and Q is the hypotenuse of the right-angled triangle formed by P, Q and the point where Tanuj took the left turn.
- Using Pythagoras theorem, we can calculate the straight distance between P and Q as:

Straight distance between P and Q = √(40² + 30²) = √2500 = 50 metres

- To find the direction of Q with reference to point P, we need to find the angle between the line joining P and Q and the line pointing towards North.

- Let us draw a line from P pointing towards North.

- Let us draw a line joining P and Q.

- The angle between the line joining P and Q and the line pointing towards North is the angle marked in red in the diagram.

- To find this angle, we can use trigonometry. The tangent of this angle is given by:

tanθ = perpendicular/base = 30/40 = 0.75

θ = tan⁻¹(0.75) = 36.87°

- Therefore, the direction of Q with reference to point P is South-East.

Hence, the correct answer is option (c) 50 metres, South-East.

Shehnaz wants to go to the market. She started from her home which is in North and comes to a crossing. The road to her left ends in a park and straight ahead is the office complex. In which direction is the market from crossing?
  • a)
    East                   
  • b)
    West
  • c)
    North                          
  • d)
    South
Correct answer is option 'B'. Can you explain this answer?

Avantika Chakraborty answered
From the Fig, it is clear that Anoop starts his journey from point A and finishes his journey at point B. It can be seen that point B is at a distance of 10 m from point A and in the From the Fig, it is clear that Anoop starts his journey from point A and finishes his journey at point B. It can be seen that point B is at a distance of 10 m from point A and in the East direction.

From her house, Avantika went 15 km to the North, then, she turned West and covered 10 km. Then, she turned South and covered 5 km. Finally, turning to East, she covered 10 km. In which direction is she from her house?
  • a)
    East                   
  • b)
    West
  • c)
    North                          
  • d)
    South
Correct answer is option 'C'. Can you explain this answer?

Dia Mehta answered
i) Avantika went 15 km to the North.
ii) Then she turned west and covered 10 km.
iii) Then, she turned south and covered 5 km.
iv) Finally turning to east, she covered 10 km
Drawing the Diagram as per the given information:
Therefore, it is clear that She is in the North from his house.

One morning after sunrise, Sunil was standing facing a pole. The shadow of the pole fell exactly to his right, which direction was he facing?
  • a)
    East                    
  • b)
    South
  • c)
    North                            
  • d)
    Data inadequate
Correct answer is option 'B'. Can you explain this answer?

Saptarshi Chauhan answered
Explanation:

To solve this question, we need to understand the direction of the shadow during sunrise.

- During sunrise, the sun rises in the east and casts a shadow towards the west.
- Therefore, if Sunil's shadow is falling exactly to his right, then he must be facing towards the south.

Hence, the correct answer is option B, South.

In summary:

- During sunrise, the sun rises in the east and casts a shadow towards the west.
- If the shadow falls exactly to the right, then the person must be facing towards the south.
- Therefore, Sunil was facing towards the south.

Two buses start from the opposite points of a main road, 150 km apart. The first bus runs for 25 km and takes a right turn and then runs for 15 km. It then turns left and runs for another 25 km and takes the direction back to reach the main road. In the meantime, due to a minor breakdown, the other bus has run only 35 km along the main road. What would be the distance between the two buses at this point ? 
  • a)
    65 km           
  • b)
    75 km
  • c)
    80 km           
  • d)
    85 km
Correct answer is option 'A'. Can you explain this answer?

Priyanka Menon answered
Given information:
- Two buses start from opposite points of a main road, 150 kms apart.
- The first bus runs for 25kms and takes a right turn and then runs for 15 kms.
- It then turns left and runs for another 25 kms and takes the direction back to reach the main road.
- The other bus has run only 35 kms along the main road.

To find:
- The distance between the two buses at this point.

Explanation:
Let's assume that the two buses meet at point X on the main road.

- The first bus travels a total distance of 25 + 15 + 25 = 65 kms before reaching point X.
- The second bus travels a total distance of 35 kms before reaching point X.
- Therefore, the distance between the two buses at point X is 150 - (65 + 35) = 50 kms.

Now, we need to find the distance between the two buses at the point where the first bus reaches the main road again.

- The first bus has covered a total distance of 2 * 25 + 15 = 65 kms from its starting point to reach the main road again.
- The second bus has covered a total distance of 35 + 25 = 60 kms from its starting point to reach the point where the first bus reached the main road again.
- Therefore, the distance between the two buses at this point is 150 - (65 + 60) = 25 kms.

Therefore, the distance between the two buses at the point where the first bus reaches the main road again is 25 kms.

Answer: Option A) 65 kms.

Mohan was facing east. he walked 4 km forward and then after turning to his right walked 3 km. Again he turned to his right and walked 4 km. After this he turned back. Which direction, was he facing at that time?
  • a)
    East
  • b)
    West
  • c)
    North
  • d)
    South
Correct answer is option 'A'. Can you explain this answer?

Kiran Reddy answered
According to given data let's make Mohan walking route direction;
Before turning back his face was in West direction.
After turned back his face should be in 'East' direction.
Hence, the correct answer is "East".

A man walks in straight 100 m and turns his right and walk 75 m. Again he turns his right and walk 100 m. And last he turn his left and walk 25m. If now he is walking in north di- rection. Then find from which direction he started?
  • a)
    West
  • b)
    East
  • c)
    North 
  • d)
    South
Correct answer is option 'A'. Can you explain this answer?

Maitri Chavan answered
To solve this problem, we can break down Kewal's movements into a grid and calculate the distance from his starting point.

**Step-by-step solution:**

1. Start by drawing a grid. Assume Kewal's starting point is at the origin (0,0).

2. Kewal moves southeast a distance of 14m. This means he moves 14 units to the right (east) and 14 units down (south). So his new position is (14,-14).

3. Next, Kewal moves west a distance of 28m. Since he is moving west, his x-coordinate decreases by 28. So his new position is (-14,-14).

4. Kewal then moves northwest a distance of 14m. This means he moves 14 units to the left (west) and 14 units up (north). So his new position is (-28,0).

5. Finally, Kewal moves east a distance of 8m. Since he is moving east, his x-coordinate increases by 8. So his final position is (-20,0).

6. To find the distance between Kewal's final position and the origin (starting point), we can use the distance formula: distance = sqrt((x2-x1)^2 + (y2-y1)^2)

- Substitute the values into the formula: distance = sqrt((-20-0)^2 + (0-0)^2)
- Simplify: distance = sqrt((-20)^2 + 0^2)
- Calculate: distance = sqrt(400 + 0)
- Final answer: distance = sqrt(400) = 20

Therefore, Kewal is 20 meters away from his starting point. Hence, the correct answer is option A) 20m.

Namratha walks 14 metres towards west, then turns to her right and walks 14 meters and then turns to her left and walks 10 metres. Again turning to her left she walks 14 metres. What is the shortest distance (in metres) between her starting point and her present position?  
  • a)
    38m
  • b)
    28m
  • c)
    24m
  • d)
    10m
  • e)
    None of these
Correct answer is option 'C'. Can you explain this answer?

Hridoy Das answered
Let's break down Namratha's movements step by step:
  1. First Movement: She walks 14 meters west.
  2. Second Movement: She turns right and walks 14 meters north.
  3. Third Movement: She turns left and walks 10 meters west.
  4. Fourth Movement: She turns left again and walks 14 meters south.
Now, let's analyze her position.
  • After the first movement, she's 14 meters west of the starting point.
  • After the second movement, she's 14 meters west and 14 meters north of the starting point.
  • After the third movement, she's 24 meters west and 14 meters north of the starting point.
  • After the fourth movement, she moves 14 meters south, so she's now 24 meters west and at the same latitude as her starting point (because the south movement cancels out the north movement).
To find the shortest distance between her starting point and her present position, we just need to calculate the straight-line distance (which is the horizontal distance since her vertical displacement is zero).
Since she is 24 meters west of her starting point, the shortest distance is:
Distance=24 meters\text{Distance} = 24 \text{ meters}Distance=24 meters
So the correct answer is 24 meters (Option 3).
 

A man is performing yoga with his head down and legs up. His face is towards the West. In which direction, will his left hand be?
  • a)
    North                          
  • b)
    South
  • c)
    East                   
  • d)
    West
Correct answer is option 'A'. Can you explain this answer?

Avantika Chakraborty answered
 If you face towards west your left hand will be pointing towards the south when held straight side ways horizontally, now the person is upside down so obviously the direction of the left hand will be opposite, so it will be facing north direction.

Facing North, Ramesh walks 20 m, then he turns left and walks 30m, then again he turns left and walks 20 m. Then, he turns right and walks 10 m. How far is he now from his starting position?
  • a)
    30 m                           
  • b)
    25 m
  • c)
    40 m                           
  • d)
    45 m
Correct answer is option 'C'. Can you explain this answer?

Ishita Choudhury answered
To solve this problem, we need to visualize Ramesh's movements and calculate the distance between his final position and his starting position.

Let's break down Ramesh's movements step by step:

1. Ramesh walks 20 m facing North.
2. He turns left and walks 30 m.
3. He turns left again and walks 20 m.
4. He turns right and walks 10 m.

Calculating the North-South and East-West distances separately will help us determine the final position.

North-South Distance:
- Ramesh initially walks 20 m facing North.
- Then he turns left and walks 30 m, which means he moves 30 m towards the West.
- Finally, he turns left again and walks 20 m, which means he moves 20 m towards the South.

So, the total North-South distance covered by Ramesh is 20 m (North) - 20 m (South) = 0 m.

East-West Distance:
- Ramesh initially walks 20 m facing North.
- Then he turns left and walks 30 m, which means he moves 30 m towards the West.
- Finally, he turns left again and walks 20 m, which means he moves 20 m towards the South.
- After that, he turns right and walks 10 m, which means he moves 10 m towards the East.

So, the total East-West distance covered by Ramesh is 20 m (West) + 10 m (East) = 30 m.

Using the Pythagorean theorem, we can calculate the distance between Ramesh's final position and his starting position:

Distance = √((North-South Distance)^2 + (East-West Distance)^2)
= √((0 m)^2 + (30 m)^2)
= √(0 + 900)
= √900
= 30 m

Therefore, Ramesh is 30 m away from his starting position. The correct answer is option (a) 30 m.

Hemant started from his house and walked 3km eastward, then he turned right and walked 2km, then again he turned left and walked 1 km, then turned right and walked 2 km. He turned right again and walked 1 km and reached his school. What is the minimum distance between Hemant’s house and his school?
  • a)
    12 km
  • b)
    9km
  • c)
    6 km
  • d)
    5 km
Correct answer is option 'D'. Can you explain this answer?

Shama rane answered
's house and his school?

To find the minimum distance between Hemant's house and school, we can draw a diagram:

H --- 3km ---> A --- 2km ---> B
| |
1km 2km
| |
C <--- 1km="" ---="">

H: Hemant's house
A, B, C, D: points on the path he took
We can see that Hemant walked in a rectangular path, and his school is at point D.

To find the minimum distance, we can use the Pythagorean theorem to find the diagonal distance between H and D:

HD = sqrt((HC + CD)^2 + 3^2)
= sqrt((1 + 1)^2 + 9)
= sqrt(22)
≈ 4.69 km

Therefore, the minimum distance between Hemant's house and school is approximately 4.69 km.

X and Y started from a fixed point. X moves towards North and after walking 3 km turns to his right and covers 4 km. Y moves towards West and walks 5 km and then turns to his right and walks 3 km. How far X and Y are from each other?
  • a)
    5km                    
  • b)
    9km
  • c)
    6km                    
  • d)
    10km
Correct answer is option 'B'. Can you explain this answer?

Sahana Nair answered
To find out how far X and Y are from each other, we can plot their movements on a coordinate plane.

Let's assume the starting point as the origin (0,0). X moves towards the North, which means it moves along the positive y-axis. After walking 3 km, X turns to its right (clockwise) and covers 4 km. This means X moves 4 km along the positive x-axis. So, the final position of X is (4,3).

Y moves towards the West, which means it moves along the negative x-axis. After walking 5 km, Y turns to its right and covers 3 km. This means Y moves 3 km along the negative y-axis. So, the final position of Y is (-5,-3).

Using the distance formula, we can calculate the distance between the final positions of X and Y:

Distance = √((x2 - x1)^2 + (y2 - y1)^2)

Plugging in the values:
Distance = √((4 - (-5))^2 + (3 - (-3))^2)
= √(9^2 + 6^2)
= √(81 + 36)
= √117
≈ 10.82

Rounding off to the nearest whole number, the distance between X and Y is approximately 11 km.

Therefore, the correct answer is option 'B' - 9 km.

Jenny walked 2.5 km towards North and turned towards West. After covering 2 km’s he turned to South and walked 1.5 km’s. He then turned to East and covered 2 km’s. How far is Jenny from original point?
  • a)
    5 km                                                       
  • b)
    2.5 km              
  • c)
    1.5 km                                                    
  • d)
    1 km
Correct answer is option 'D'. Can you explain this answer?

Gowri Yadav answered
Towards West, she turned towards South and walked for 3 km. How far is she from her starting point and in which direction?

Jenny walked 2.5 km towards North and then 2 km towards West. This creates a right-angled triangle with the hypotenuse being the distance she has covered so far. Using Pythagoras' theorem, we can find the length of the hypotenuse:

hypotenuse = √(2.5^2 + 2^2) = √(6.25 + 4) = √10.25 km

Now, Jenny has walked 3 km towards South. This creates another right-angled triangle, with the hypotenuse being the distance she has covered in total. We can use Pythagoras' theorem again to find the length of the hypotenuse:

hypotenuse = √(√10.25^2 + 3^2) = √(10.25 + 9) = √19.25 km ≈ 4.38 km

Therefore, Jenny is approximately 4.38 km away from her starting point, and the direction is South-West.

A starts from his house and moves towards B’s house which is 4km North.  After walking for three-fourth of the distance he finds B coming towards him along with C, who is A’s enemy. Wanting to avoid him, A takes a left turn and runs for a distance of 2kms.Now, if from this point (say ‘P’) he decides to go to B’s house, how much distance would he need to cover?
  • a)
    3km                                                        
  • b)
    Ö5km                                
  • c)
    1km                                                        
  • d)
    Ö3km                                
Correct answer is option 'B'. Can you explain this answer?

Sreemoyee Dey answered
However, I can suggest that the distance between A and B, the mode of transportation used by A, and the time taken to reach B would all be important factors in understanding this scenario.

One morning after sunrise, Bikram and Shailash were standing in a town with their backs towards each other. Bikram’s shadow fell exactly towards left hand side. Which direction was Shailash facing?
  • a)
    East                    
  • b)
    West
  • c)
    North                            
  • d)
    South
Correct answer is option 'D'. Can you explain this answer?

Nandini Gupta answered
Sun rises in the East. It is given that "one morning after sunrise", therefore, we will mark Sun in the East direction in the below diagram.
When Sun is in the East direction, shadow of an object falls in the West. 
It is given that Bikram's shadow falls towards left hand side. This means Bikram's left hand side should be West direction.
In the question above pattern followed is,

Therefore the correct answer is Option D South.

Rohan walked 40 metres towards North, took a left turn and walked 20 metres. He again took a left turn and walked 40 metres. The distance and the direction in which he is from the starting point is
  • a)
    20 metres East
  • b)
    20 metres North
  • c)
    20 metres West
  • d)
    100 metres South
Correct answer is option 'C'. Can you explain this answer?

EduRev GATE answered
Given
1. Rohan walked 40 metres towards North, took a left turn and walked 20 metres.
2. He again took a left turn and walked 40 metres.
According to the given information, we get the following figure,

Therefore, above figure clearly shows the distance from B to A is 20 metres
The direction of B with respect to A is West.
Hence, "20 metres West" is the correct answer.

Chapter doubts & questions for Directions &amp; Distances - IBPS PO Prelims & Mains Preparation 2024 is part of Bank Exams exam preparation. The chapters have been prepared according to the Bank Exams exam syllabus. The Chapter doubts & questions, notes, tests & MCQs are made for Bank Exams 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests here.

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