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All questions of Permutation and Combination for Bank Exams Exam
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In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there?- a)159
- b)194
- c)205
- d)209
- e)None of these
Correct answer is option 'D'. Can you explain this answer?
In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there?
a)
159
b)
194
c)
205
d)
209
e)
None of these
|
Krishna P answered |
Since there should be at least one boy in the selection, the ways by which 4 children can be selected become 6C1*4C3, 6C2*4C2, 6C3*4C1, 6C4*4C0.
total selection becomes the sum of the above four combinations. ie, 24+90+80+15=209
total selection becomes the sum of the above four combinations. ie, 24+90+80+15=209
In how many different ways can the letters of the word ‘MATHEMATICS’ be arranged so that the vowels always come together?- a)10080
- b)4989600
- c)120960
- d)None of these
Correct answer is option 'C'. Can you explain this answer?
In how many different ways can the letters of the word ‘MATHEMATICS’ be arranged so that the vowels always come together?
a)
10080
b)
4989600
c)
120960
d)
None of these
|
Sagar Sharma answered |
"WORD" be arranged?
The word "WORD" has 4 letters. Therefore, there are 4 different positions for the first letter, 3 different positions for the second letter, 2 different positions for the third letter, and 1 different position for the last letter.
The total number of ways to arrange the letters is given by 4 x 3 x 2 x 1 = 24.
Therefore, there are 24 different ways to arrange the letters of the word "WORD".
The word "WORD" has 4 letters. Therefore, there are 4 different positions for the first letter, 3 different positions for the second letter, 2 different positions for the third letter, and 1 different position for the last letter.
The total number of ways to arrange the letters is given by 4 x 3 x 2 x 1 = 24.
Therefore, there are 24 different ways to arrange the letters of the word "WORD".
How many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9, which are divisible by 5 and none of the digits is repeated?- a)5
- b)10
- c)15
- d)20
Correct answer is option 'D'. Can you explain this answer?
How many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9, which are divisible by 5 and none of the digits is repeated?
a)
5
b)
10
c)
15
d)
20
|
Faizan Khan answered |
Since each desired number is divisible by 5, so we must have 5 at the unit place. So, there is 1 way of doing it.
The tens place can now be filled by any of the remaining 5 digits (2, 3, 6, 7, 9). So, there are 5 ways of filling the tens place.
The hundreds place can now be filled by any of the remaining 4 digits. So, there are 4 ways of filling it.
∴ Required number of numbers = (1 x 5 x 4) = 20.
In how many different ways can the letters of the word ‘LEADING’ be arranged in such a way that the vowels always come together?- a)360
- b)480
- c)720
- d)5040
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
In how many different ways can the letters of the word ‘LEADING’ be arranged in such a way that the vowels always come together?
a)
360
b)
480
c)
720
d)
5040
e)
None of these
|
Anaya Patel answered |
The word ‘LEADING’ has 7 different letters.
When the vowels EAI are always together, they can be supposed to form one letter.
Then, we have to arrange the letters LNDG (EAI).
Now, 5 (4 + 1 = 5) letters can be arranged in 5! = 120 ways.
The vowels (EAI) can be arranged among themselves in 3! = 6 ways.
∴ Required number of ways = (120 x 6) = 720.
How many 4-letter words with or without meaning, can be formed out of the letters of the word, ‘LOGARITHMS’, if repetition of letters is not allowed?- a)40
- b)400
- c)5040
- d)2520
Correct answer is option 'C'. Can you explain this answer?
How many 4-letter words with or without meaning, can be formed out of the letters of the word, ‘LOGARITHMS’, if repetition of letters is not allowed?
a)
40
b)
400
c)
5040
d)
2520
|
|
Aarav Sharma answered |
'LOGARITHMS' contains 10 different letters.
Required number of words = Number of arrangements of 10 letters, taking 4 at a time.
= 10P4
= 5040.
Chapter doubts & questions for Permutation and Combination - NABARD Grade A & Grade B Preparation 2024 is part of Bank Exams exam preparation. The chapters have been prepared according to the Bank Exams exam syllabus. The Chapter doubts & questions, notes, tests & MCQs are made for Bank Exams 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests here.
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