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A train 300 m long crossed a platform 900 m long in 1 minute 12 seconds. The speed of the train in km/hr was:- a)45
- b)50
- c)54
- d)60
Correct answer is option 'D'. Can you explain this answer?
A train 300 m long crossed a platform 900 m long in 1 minute 12 seconds. The speed of the train in km/hr was:
a)
45
b)
50
c)
54
d)
60
|
Pk Academy answered |
Distance covered in 72 sec = (300+900)m
Speed = (1200/72)m/sec
=(50/3) m/sec
= (50/3 × 18/5) km/hr = 60 km/hr
Speed = (1200/72)m/sec
=(50/3) m/sec
= (50/3 × 18/5) km/hr = 60 km/hr
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If two mixers and one T.V cost Rs. 7000. While two T.V s and one mixer cost Rs. 9800. The value of one T.V is:- a)Rs. 2800
- b)Rs. 2100
- c)Rs. 4200
- d)Rs. 8400
Correct answer is option 'C'. Can you explain this answer?
If two mixers and one T.V cost Rs. 7000. While two T.V s and one mixer cost Rs. 9800. The value of one T.V is:
a)
Rs. 2800
b)
Rs. 2100
c)
Rs. 4200
d)
Rs. 8400
|
Nidhi Chakraborty answered |
Explanation:
Let the cost of one mixer be x and the cost of one TV be y.
- From the given information, we have:
2x + y = 7000 ...(i) (Two mixers and one TV cost Rs. 7000)
2y + x = 9800 ...(ii) (Two TVs and one mixer cost Rs. 9800)
Solving the above two equations:
- Multiplying equation (i) by 2, we get:
4x + 2y = 14000
- Subtracting equation (ii) from the above equation, we get:
3x = 4200
- Dividing by 3 on both sides, we get:
x = 1400
- Substituting the value of x in equation (i), we get:
2(1400) + y = 7000
2800 + y = 7000
y = 7000 - 2800
y = 4200
Hence, the cost of one TV is Rs. 4200. Option C is correct.
Let the cost of one mixer be x and the cost of one TV be y.
- From the given information, we have:
2x + y = 7000 ...(i) (Two mixers and one TV cost Rs. 7000)
2y + x = 9800 ...(ii) (Two TVs and one mixer cost Rs. 9800)
Solving the above two equations:
- Multiplying equation (i) by 2, we get:
4x + 2y = 14000
- Subtracting equation (ii) from the above equation, we get:
3x = 4200
- Dividing by 3 on both sides, we get:
x = 1400
- Substituting the value of x in equation (i), we get:
2(1400) + y = 7000
2800 + y = 7000
y = 7000 - 2800
y = 4200
Hence, the cost of one TV is Rs. 4200. Option C is correct.
Amit starts from a point A and walks to another point B and then returns from B to A by his car and thus takes a total time of 6h and 45 min, if he had driven both ways in his car, then he would have taken 2hless.How long would it take for him to walk both ways?- a)7h 45 min
- b)8h 15 min
- c)8h 30 min
- d)8h 45min
Correct answer is option 'D'. Can you explain this answer?
Amit starts from a point A and walks to another point B and then returns from B to A by his car and thus takes a total time of 6h and 45 min, if he had driven both ways in his car, then he would have taken 2hless.How long would it take for him to walk both ways?
a)
7h 45 min
b)
8h 15 min
c)
8h 30 min
d)
8h 45min
|
Codebreakers answered |
Let w be the time taken in one way by walking and C be the time taken in one way By car.
A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?- a)10/21
- b)11/21
- c)2/7
- d)5/7
Correct answer is option 'A'. Can you explain this answer?
A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?
a)
10/21
b)
11/21
c)
2/7
d)
5/7
|
Keerthana Khanna answered |
Understanding the problem:
In this problem, we have a bag containing 2 red, 3 green, and 2 blue balls. We need to find the probability that none of the balls drawn is blue when two balls are drawn at random.
Solution:
Total number of ways to draw 2 balls out of 7:
Total balls = 2 red + 3 green + 2 blue = 7
Number of ways to draw 2 balls out of 7 = 7C2 = 21
Number of ways to draw 2 balls that are not blue:
Since we do not want any blue balls, we will only consider red and green balls.
Number of red balls = 2
Number of green balls = 3
Number of ways to draw 2 balls (red or green) = 2C2 + 3C1*2C1 = 1 + 6 = 7
Probability of drawing 2 balls that are not blue:
Probability = Number of ways to draw 2 balls that are not blue / Total number of ways to draw 2 balls
Probability = 7 / 21 = 1 / 3 = 10 / 21
Therefore, the probability that none of the balls drawn is blue is 10/21, which corresponds to option 'A'.
In this problem, we have a bag containing 2 red, 3 green, and 2 blue balls. We need to find the probability that none of the balls drawn is blue when two balls are drawn at random.
Solution:
Total number of ways to draw 2 balls out of 7:
Total balls = 2 red + 3 green + 2 blue = 7
Number of ways to draw 2 balls out of 7 = 7C2 = 21
Number of ways to draw 2 balls that are not blue:
Since we do not want any blue balls, we will only consider red and green balls.
Number of red balls = 2
Number of green balls = 3
Number of ways to draw 2 balls (red or green) = 2C2 + 3C1*2C1 = 1 + 6 = 7
Probability of drawing 2 balls that are not blue:
Probability = Number of ways to draw 2 balls that are not blue / Total number of ways to draw 2 balls
Probability = 7 / 21 = 1 / 3 = 10 / 21
Therefore, the probability that none of the balls drawn is blue is 10/21, which corresponds to option 'A'.
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:- a)39, 30
- b)41, 32
- c)42, 33
- d)43, 34
Correct answer is option 'C'. Can you explain this answer?
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
a)
39, 30
b)
41, 32
c)
42, 33
d)
43, 34
|
Ayush Yadav answered |
Given information:
- One student scored 9 marks more than the other
- The marks of one student is 56% of the sum of their marks
Let the marks obtained by the two students be x and y.
Forming equations:
1. x = y + 9 (One student scored 9 marks more than the other)
2. x = 0.56(x + y) (The marks of one student is 56% of the sum of their marks)
Solving the equations:
Substitute equation 1 into equation 2:
y + 9 = 0.56(y + y + 9)
y + 9 = 1.12y + 5.04
0.12y = 3.96
y = 33
Substitute y back into equation 1:
x = 33 + 9
x = 42
Therefore, the marks obtained by the two students are 42 and 33.
The correct answer is option C.
- One student scored 9 marks more than the other
- The marks of one student is 56% of the sum of their marks
Let the marks obtained by the two students be x and y.
Forming equations:
1. x = y + 9 (One student scored 9 marks more than the other)
2. x = 0.56(x + y) (The marks of one student is 56% of the sum of their marks)
Solving the equations:
Substitute equation 1 into equation 2:
y + 9 = 0.56(y + y + 9)
y + 9 = 1.12y + 5.04
0.12y = 3.96
y = 33
Substitute y back into equation 1:
x = 33 + 9
x = 42
Therefore, the marks obtained by the two students are 42 and 33.
The correct answer is option C.
Anubhav Gokhale, is a B.Sc. with Computer Science passed in second class with 58% marks. He had passed HSC in first class with 76% marks. He has completed 25 years of age in December 2007.- a)if the case is to be referred to Executive Head.
- b)if the case is to be referred to Vice President.
- c)if the candidate is to be selected.
- d)if the information is inadequate to take a decision.
- e)if the candidate is not to be selected
Correct answer is option 'B'. Can you explain this answer?
Anubhav Gokhale, is a B.Sc. with Computer Science passed in second class with 58% marks. He had passed HSC in first class with 76% marks. He has completed 25 years of age in December 2007.
a)
if the case is to be referred to Executive Head.
b)
if the case is to be referred to Vice President.
c)
if the candidate is to be selected.
d)
if the information is inadequate to take a decision.
e)
if the candidate is not to be selected
|
Gitanjali Khanna answered |
Reasoning for selecting Vice President:
- Anubhav Gokhale has a B.Sc. in Computer Science with 58% marks, which is a decent academic qualification.
- He passed his HSC with 76% marks, indicating strong academic performance in the past.
- He has completed 25 years of age, showing a good level of maturity.
- Referring the case to the Vice President would be appropriate as this position typically deals with mid-level candidates who have a decent educational background and experience.
- The Vice President can further evaluate Anubhav Gokhale's qualifications and potential for the job role.
- Anubhav Gokhale has a B.Sc. in Computer Science with 58% marks, which is a decent academic qualification.
- He passed his HSC with 76% marks, indicating strong academic performance in the past.
- He has completed 25 years of age, showing a good level of maturity.
- Referring the case to the Vice President would be appropriate as this position typically deals with mid-level candidates who have a decent educational background and experience.
- The Vice President can further evaluate Anubhav Gokhale's qualifications and potential for the job role.
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