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The sum of four numbers is 48. When 5 and 1 are added to the first two; and 3 & 7 are subtracted from the 3rd & 4th, the numbers will be equal. The numbers are        (SSC CGL 1st Sit. 2015)
  • a)
    4, 12, 12, 20
  • b)
    5, 11, 13, 19
  • c)
    6, 10, 14, 18
  • d)
    9, 7, 15, 17
Correct answer is option 'C'. Can you explain this answer?

Malavika Rane answered
Given Information:
The sum of four numbers is 48. When 5 and 1 are added to the first two; and 3 & 7 are subtracted from the 3rd & 4th, the numbers will be equal.

Let's solve the problem step by step:

Step 1: Formulate the Equations
Let the four numbers be a, b, c, and d.
According to the given information, we have:
a + b + c + d = 48
(a + 5) + (b + 1) = (c - 3) + (d - 7)

Step 2: Simplify the Equations
From the second equation, we get:
a + b + 6 = c + d - 10
a + b = c + d - 16
Substitute the value of a + b from the second equation into the first equation:
c + d - 16 + c + d = 48
2c + 2d - 16 = 48
2c + 2d = 64
c + d = 32

Step 3: Find the Numbers
Now, we have:
a + b = 32
a + b + 6 = 32
a + b = 26
Let's check the options:
a = 6, b = 10, c = 14, d = 18
6 + 10 + 14 + 18 = 48
(6 + 5) + (10 + 1) = (14 - 3) + (18 - 7)
11 + 11 = 11 + 11
Therefore, the numbers are 6, 10, 14, and 18, which satisfy all the conditions given in the problem.
Thus, the correct answer is option 'C' (6, 10, 14, 18).

What is the value of: (9 ÷ 30)2 × 2.4 + 0.3 o f 12 × (1 – 0.3)2 + 9 × (0.3)2 = ?         (SSC MTS 2018)
  • a)
    3.43
  • b)
    3.69
  • c)
    2.79
  • d)
    2.17
Correct answer is option 'C'. Can you explain this answer?

Anjana Singh answered
(9 ÷ 30)2 × 2.4 + 0.3 of 12 × (1 – 0.3)2 + 9 × (0.3)2 = ?
⇒ (0.3)2 × 2.4 + 3.6 × (0.7)2 + 9 × (0.09)
⇒ (0.09) × 2.4 + 1.764 + 9 × (0.09)
⇒ 1.98 + 0.81
⇒ 2.79

What is the simplified value of (2 + 1) (22 + 1) (24 + 1) (28 +1)?       (SSC Sub. Ins. 2017)
  • a)
    28 – 1
  • b)
    216– 1
  • c)
    232 – 1
  • d)
    264 – 1
Correct answer is option 'B'. Can you explain this answer?

Mira Sharma answered
According to question.
(2 + 1) (22 + 1) (24 + 1) (28 + 1) = ?
⇒ (2 + 1) (28 + 1) (22+ 1) (24 + 1)
⇒ (29 + 2 + 28 + 1) (26 + 22 + 24 + 1)
⇒ (215 + 214 + 213 + 212 + 211 + 210 + 29 + 28 + 27 + 26 + 25 + 24 + 23 + 22 + 2) + 1
Here, a = 2, n = 15 r = 2


⇒ (216 – 2)
∴(216 – 2) + 1 = (216 – 1)
∴ (2 + 1) (22 + 1) (24 + 1) (28 + 1) = (216 – 1)

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