Given:
- Trader bought two horses for 19,500.
- One horse was sold at a loss of 20%.
- The other horse was sold at a profit of 15%.
- The selling price of each horse is the same.
To find:
The cost prices of the horses.
Solution:
Let's assume the cost price of the first horse is "x" and the cost price of the second horse is "y".
Step 1: Formulate equations based on the given information.
- The sum of the cost prices of the two horses is 19,500.
x + y = 19,500 --(1)
- The selling price of each horse is the same.
Selling price of first horse = Selling price of second horse
- Selling price = Cost price + Profit
(x - 20% of x) = (y + 15% of y)
Step 2: Simplify the equation.
- x - 0.2x = y + 0.15y
- 0.8x = 1.15y --(2)
Now, we have two equations (1) and (2) with two variables x and y. We can solve these equations to find the values of x and y.
Step 3: Solve the equations.
From equation (1), we can write x in terms of y.
x = 19,500 - y
Substitute the value of x in equation (2).
0.8(19,500 - y) = 1.15y
Simplify the equation.
15,600 - 0.8y = 1.15y
Combine like terms.
15,600 = 1.95y
Divide both sides by 1.95.
y = 15,600 / 1.95
y = 8,000
Step 4: Substitute the value of y in equation (1) to find x.
x + 8,000 = 19,500
x = 19,500 - 8,000
x = 11,500
Answer:
The cost prices of the two horses are 11,500 and 8,000, respectively. Therefore, option B is the correct answer.