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All questions of Time and Space Complexity for Software Development Exam

The time complexity of an algorithm is given by T(n) = 5n^2 + 3n + 2. What is the dominant term in this equation?
  • a)
    5n^2
  • b)
    3n
  • c)
    2
  • d)
    None of the above
Correct answer is option 'A'. Can you explain this answer?

Sounak Kumar answered
Time Complexity of an Algorithm:
The time complexity of an algorithm measures how the running time of the algorithm increases with the size of the input. It provides an estimation of the number of operations or steps required to solve a problem as a function of the input size.

Given Time Complexity Function:
T(n) = 5n^2 - 3n + 2

Dominant Term:
The dominant term in the time complexity equation is the term that grows the fastest as the input size increases. It represents the most significant factor that contributes to the overall time complexity of the algorithm.

Calculating the Dominant Term:
To determine the dominant term in the given time complexity equation, we need to analyze the growth rates of each term.

1. 5n^2: This term represents the highest power of n (n^2). As the input size increases, the impact of this term becomes more significant compared to the other terms.

2. -3n: This term represents the linear term (n). Although it is multiplied by a constant (-3), its growth rate is slower than the quadratic term (n^2).

3. 2: This term is a constant and does not depend on the input size. It has no impact on the time complexity as the input size increases.

Conclusion:
Based on the analysis, the dominant term in the given time complexity equation T(n) = 5n^2 - 3n + 2 is 5n^2. It grows the fastest and has the most significant impact on the overall time complexity of the algorithm as the input size increases.

Therefore, the correct answer is option 'A' - 5n^2.
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What is the space complexity of the following code snippet?
int n = 10;
int* arr = new int[n];
for (int i = 0; i < n; i++) {
    arr[i] = i;
}
delete[] arr;
  • a)
    O(1)
  • b)
    O(n)
  • c)
    O(n^2)
  • d)
    O(log n)
Correct answer is option 'A'. Can you explain this answer?

Abhijeet Basu answered
The space complexity of the code snippet is O(n), where n is the value of the variable n. This is because the code creates an array of size n using dynamic memory allocation (new int[n]), which requires O(n) space.

Which of the following represents the best-case time complexity of an algorithm? a) O
  • a)
    O(1)
  • b)
    O(n)
  • c)
    O(n2)
  • d)
    O(log n)
Correct answer is option 'A'. Can you explain this answer?

Simar Sharma answered
The best-case time complexity of an algorithm represents the minimum amount of time it takes to run, given a particular input. O(1) represents constant time complexity, indicating that the algorithm takes a constant amount of time, regardless of the input size.

What is the time complexity of the following code snippet?
int sum = 0;
for (int i = 1; i <= n; i++) {
    for (int j = 1; j <= n; j = j * 2) {
        sum++;
    }
}
  • a)
    O(n)
  • b)
    O(log n)
  • c)
    O(n^2)
  • d)
    O(n log n)
Correct answer is option 'C'. Can you explain this answer?

Tanuja Mishra answered
The outer loop runs n times, and the inner loop doubles the value of j in each iteration until it reaches n. Therefore, the total number of iterations is n * log(n). Hence, the time complexity is O(n^2).

Which of the following represents the worst-case time complexity of an algorithm?
  • a)
    O(1)
  • b)
    O(n)
  • c)
    O(n2)
  • d)
    O(log n)
Correct answer is option 'C'. Can you explain this answer?

Time Complexity of an Algorithm

The time complexity of an algorithm is a measure of the amount of time it takes to run based on the input size. It helps in determining how the algorithm's performance scales with increasing input size. The worst-case time complexity represents the maximum amount of time the algorithm takes to run for any input of size 'n'.

Options for Worst-Case Time Complexity
The given options are:
a) O(1)
b) O(n)
c) O(n^2)
d) O(log n)

a) O(1)
An algorithm with a time complexity of O(1) means that its running time is constant, regardless of the input size. It implies that the algorithm takes the same amount of time to execute, regardless of the size of the input. This is the best-case scenario for time complexity.

b) O(n)
An algorithm with a time complexity of O(n) means that its running time is directly proportional to the input size 'n'. It implies that the algorithm's execution time increases linearly with the increase in input size. Although it is not the best-case scenario, it is still considered efficient.

c) O(n^2)
An algorithm with a time complexity of O(n^2) means that its running time is directly proportional to the square of the input size 'n'. It implies that the algorithm's execution time increases exponentially with the increase in input size. This is considered an inefficient scenario as the execution time grows rapidly as the input size increases.

d) O(log n)
An algorithm with a time complexity of O(log n) means that its running time increases logarithmically with the increase in input size 'n'. It implies that the execution time grows slowly even when the input size increases significantly. This is considered an efficient scenario.

Conclusion
The worst-case time complexity represents the maximum execution time an algorithm can have for any given input size. Among the provided options, O(n^2) has the highest growth rate and is considered the worst-case time complexity. As the input size increases, the execution time of an algorithm with O(n^2) complexity increases rapidly, making it inefficient for large input sizes.

Which of the following asymptotic notations represents the worst-case time complexity of an algorithm?
  • a)
    O(1)
  • b)
    O(n)
  • c)
    Θ(n)
  • d)
    Ω(n)
Correct answer is option 'B'. Can you explain this answer?

Anil Kumar answered
The O-notation represents the worst-case time complexity of an algorithm. It indicates that the time taken by the algorithm grows linearly with the input size.

What is the time complexity of the following code snippet?
int count = 0;
for (int i = 1; i <= n; i *= 2) {
    for (int j = 0; j < i; j++) {
        count++;
    }
}
cout << count;
  • a)
    O(n)
  • b)
    O(log n)
  • c)
    O(n log n)
  • d)
    O(n^2)
Correct answer is option 'C'. Can you explain this answer?

Nidhi Saha answered
The time complexity of the given code snippet is O(n), where n is the value of the variable "n". This is because the loop iterates from 1 to n, incrementing the value of "count" by 1 in each iteration. Therefore, the number of iterations is directly proportional to the value of n.

What is the space complexity of the following code snippet?
void func(int n) {
    if (n <= 0) {
        return;
    }
    cout << n << " ";
    func(n - 1);
    func(n - 1);
}
func(4);
  • a)
    O(n)
  • b)
    O(log n)
  • c)
    O(sqrt(n))
  • d)
    O(n log n)
Correct answer is option 'A'. Can you explain this answer?

Manasa Iyer answered
Understanding Space Complexity
Space complexity measures the amount of memory required by an algorithm in relation to the input size. In recursive functions, it's essential to consider both the space used by the function's stack frames and any additional data structures.

Analyzing the Function
The provided function `func(int n)` performs the following:
- **Base Case**: It checks if `n` is less than or equal to 0. If so, it returns without further action.
- **Recursive Calls**: If `n` is greater than 0, it prints `n` and then makes two recursive calls to itself with `n - 1`.

Space Complexity Breakdown
- **Recursive Call Stack**: Each time `func` is called, a new stack frame is created. The maximum depth of the recursion is determined by the value of `n`. Therefore, the maximum depth of recursion is `n`, leading to `O(n)` stack space.
- **No Additional Data Structures**: The function does not use any additional data structures that would increase space complexity.

Conclusion
Given that the most significant contributor to space complexity in this scenario is the depth of the recursion (the call stack), the overall space complexity of the function is:
- **Final Space Complexity**: `O(n)`
Thus, the correct answer is **option 'A'**.

What is the space complexity of the following code snippet?
int fib(int n) {
    if (n <= 1) {
        return n;
    }
    return fib(n - 1) + fib(n - 2);
}
int result = fib(5);
  • a)
    O(n)
  • b)
    O(log n)
  • c)
    O(sqrt(n))
  • d)
    O(2^n)
Correct answer is option 'D'. Can you explain this answer?

Manasa Iyer answered
Understanding Space Complexity
The space complexity of an algorithm refers to the amount of memory space required by the algorithm as a function of the input size. In the case of the recursive Fibonacci function, the space complexity can be analyzed based on the function calls and the call stack.

Recursive Calls and Call Stack
- Each time the `fib` function is called, a new frame is added to the call stack.
- For `fib(n)`, two recursive calls are made: `fib(n-1)` and `fib(n-2)`.
- This results in a binary tree of calls, where each node represents a function call, and the height of this tree corresponds to the depth of the recursion.

Height of the Call Stack
- The maximum depth of recursion for `fib(n)` is `O(n)`, as the function will keep calling itself until it reaches the base case (when `n` is 0 or 1).
- However, the space complexity is not just about the height of the stack; it also considers the number of calls that are simultaneously active.

Total Space Complexity
- The number of recursive calls grows exponentially, leading to many overlapping calls in the recursion tree.
- Although the maximum depth is `O(n)`, the total number of calls made is `O(2^n)` due to the exponential growth of the call tree.

Conclusion
- Therefore, the overall space complexity of the recursive Fibonacci function is **O(2^n)**.
- This makes option 'D' the correct answer, as it captures the exponential growth of the space required for the recursive calls.

Which of the following statements about time complexity is false?
  • a)
    The time complexity of an algorithm measures the amount of time taken by the algorithm to run.
  • b)
    Time complexity is often expressed using asymptotic notations.
  • c)
    The time complexity of an algorithm depends on the input size.
  • d)
    The time complexity of an algorithm is always constant.
Correct answer is option 'D'. Can you explain this answer?

Explanation:

Time Complexity Definition:
Time complexity is a measure of the amount of time taken by an algorithm to run. It is often used to analyze and compare algorithms based on their efficiency.

Asymptotic Notations:
Time complexity is frequently expressed using asymptotic notations such as Big O, Big Omega, and Big Theta. These notations provide a way to describe the upper, lower, and tight bounds on the growth rate of an algorithm's running time.

Dependence on Input Size:
The time complexity of an algorithm depends on the size of the input. Different algorithms may have different time complexities for the same input size, and the time taken by an algorithm generally increases as the input size grows.

Constant Time Complexity:
It is false to say that the time complexity of an algorithm is always constant. In reality, most algorithms have time complexities that vary based on the input size. For example, an algorithm with a time complexity of O(1) has constant time complexity, meaning its running time does not depend on the input size. However, many algorithms have time complexities that are not constant and can be influenced by the input size.

In conclusion, the statement that the time complexity of an algorithm is always constant (option 'D') is false because time complexity typically varies based on the input size and is not always constant.

What is the time complexity of the following code snippet?
int count = 0;
for (int i = 0; i < n; i++) {
    for (int j = i; j < n; j++) {
        count++;
    }
}
cout << count;
  • a)
    O(n)
  • b)
    O(n^2)
  • c)
    O(n log n)
  • d)
    O(1)
Correct answer is option 'B'. Can you explain this answer?

The outer loop runs n times, and the inner loop runs n - i times. The total number of iterations is 1 + 2 + 3 + ... + n, which is equivalent to (n * (n + 1)) / 2. Hence, the time complexity is O(n^2).

What will be the output of the following code?
int n = 100;
int count = 0;
while (n > 0) {
    n = n / 2;
    count++;
}
cout << count;
  • a)
    6
  • b)
    7
  • c)
    8
  • d)
    9
Correct answer is option 'B'. Can you explain this answer?

Diksha Sharma answered
The given code divides n by 2 repeatedly until n becomes 0. The number of divisions required is log2(n) + 1. Therefore, for n = 100, log2(100) + 1 = 6 + 1 = 7.

What will be the output of the following code?
int n = 4;
int count = 0;
for (int i = n; i >= 1; i = i / 2) {
    for (int j = 1; j <= i; j++) {
        count++;
    }
}
cout << count;
  • a)
    6
  • b)
    7
  • c)
    8
  • d)
    9
Correct answer is option 'D'. Can you explain this answer?

The outer loop starts with n and is divided by 2 in each iteration until it becomes 1. The number of outer loop iterations is log2(n) + 1. Therefore, for n = 4, log2(4) + 1 = 2 + 1 = 3. The inner loop runs 1, 2, 4 times. Hence, the total count is 3 * 4 = 12.

What is the output of the following code snippet?
int count = 0;
for (int i = 1; i <= n; i *= 2) {
    count++;
}
cout << count;
  • a)
    n
  • b)
    log(n)
  • c)
    sqrt(n)
  • d)
    n^2
Correct answer is option 'B'. Can you explain this answer?

The loop iterates until i exceeds n, where i is doubled in each iteration. The number of iterations can be calculated as log2(n), which represents the logarithmic time complexity.

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