All Exams >
Software Development >
DSA in C++ >
All Questions
All questions of Searching and Sorting for Software Development Exam
The time complexity of binary search is:- a)O(log n)
- b)O(n)
- c)O(n2)
- d)O(1)
Correct answer is option 'A'. Can you explain this answer?
The time complexity of binary search is:
a)
O(log n)
b)
O(n)
c)
O(n2)
d)
O(1)
|
Simar Sharma answered |
Binary search has a time complexity of O(log n), where n is the number of elements in the sorted array.
| 1 Crore+ students have signed up on EduRev. Have you? Download the App |
Which of the following is an example of an in-place sorting algorithm?- a)Insertion sort
- b)Merge sort
- c)Quick sort
- d)Radix sort
Correct answer is option 'C'. Can you explain this answer?
Which of the following is an example of an in-place sorting algorithm?
a)
Insertion sort
b)
Merge sort
c)
Quick sort
d)
Radix sort
|
Codebreakers answered |
Quick sort is an in-place sorting algorithm, meaning it doesn't require additional memory to perform the sorting operation.
Which sorting algorithm has the worst-case time complexity of O(n^2)?- a)Merge sort
- b)Quick sort
- c)Insertion sort
- d)Heap sort
Correct answer is option 'C'. Can you explain this answer?
Which sorting algorithm has the worst-case time complexity of O(n^2)?
a)
Merge sort
b)
Quick sort
c)
Insertion sort
d)
Heap sort
|
Juhi Datta answered |
Explanation:
Insertion sort has the worst-case time complexity of O(n^2). Let's understand why.
Insertion Sort:
Insertion sort is a simple sorting algorithm that builds the final sorted array one item at a time. It is based on the idea that one element from the input elements is consumed in each iteration to find its correct position in the sorted array.
Worst Case:
The worst-case scenario occurs when the input array is in reverse order. In this case, for each element, the algorithm needs to compare it with all the previous elements in the sorted part of the array and shift them if they are greater, until it finds the correct position for the current element.
Key Steps:
The key steps involved in insertion sort are as follows:
1. Iterate through the array from the second element to the last element.
2. For each element, compare it with all the previous elements in the sorted part of the array.
3. If the current element is smaller than any of the previous elements, shift those elements to the right to create space for the current element.
4. Insert the current element at its correct position in the sorted part of the array.
Time Complexity Analysis:
To analyze the time complexity of insertion sort, we need to count the number of comparisons and shifts performed.
Comparisons:
In the worst-case scenario, for each element at index i, we need to compare it with all the previous elements in the sorted part of the array (from index 0 to i-1). So, the total number of comparisons can be calculated as follows:
n-1 + n-2 + n-3 + ... + 1 = (n-1) * n / 2 = (n^2 - n) / 2
Shifts:
In the worst-case scenario, for each element at index i, we may need to shift all the previous elements in the sorted part of the array (from index 0 to i-1) to the right. So, the total number of shifts can be calculated as follows:
n-1 + n-2 + n-3 + ... + 1 = (n-1) * n / 2 = (n^2 - n) / 2
Total Time Complexity:
The total number of comparisons and shifts can be calculated by summing up the above two expressions. Simplifying the expression, we get:
(n^2 - n) / 2 + (n^2 - n) / 2 = (2n^2 - 2n) / 2 = n^2 - n
Therefore, the worst-case time complexity of insertion sort is O(n^2).
Conclusion:
Among the given sorting algorithms, insertion sort has the worst-case time complexity of O(n^2). This means that as the size of the input array increases, the time taken by the algorithm to sort the array increases quadratically. It is not as efficient as other sorting algorithms like merge sort (O(nlogn)), quick sort (O(nlogn)), or heap sort (O(nlogn)) in terms of time complexity.
Insertion sort has the worst-case time complexity of O(n^2). Let's understand why.
Insertion Sort:
Insertion sort is a simple sorting algorithm that builds the final sorted array one item at a time. It is based on the idea that one element from the input elements is consumed in each iteration to find its correct position in the sorted array.
Worst Case:
The worst-case scenario occurs when the input array is in reverse order. In this case, for each element, the algorithm needs to compare it with all the previous elements in the sorted part of the array and shift them if they are greater, until it finds the correct position for the current element.
Key Steps:
The key steps involved in insertion sort are as follows:
1. Iterate through the array from the second element to the last element.
2. For each element, compare it with all the previous elements in the sorted part of the array.
3. If the current element is smaller than any of the previous elements, shift those elements to the right to create space for the current element.
4. Insert the current element at its correct position in the sorted part of the array.
Time Complexity Analysis:
To analyze the time complexity of insertion sort, we need to count the number of comparisons and shifts performed.
Comparisons:
In the worst-case scenario, for each element at index i, we need to compare it with all the previous elements in the sorted part of the array (from index 0 to i-1). So, the total number of comparisons can be calculated as follows:
n-1 + n-2 + n-3 + ... + 1 = (n-1) * n / 2 = (n^2 - n) / 2
Shifts:
In the worst-case scenario, for each element at index i, we may need to shift all the previous elements in the sorted part of the array (from index 0 to i-1) to the right. So, the total number of shifts can be calculated as follows:
n-1 + n-2 + n-3 + ... + 1 = (n-1) * n / 2 = (n^2 - n) / 2
Total Time Complexity:
The total number of comparisons and shifts can be calculated by summing up the above two expressions. Simplifying the expression, we get:
(n^2 - n) / 2 + (n^2 - n) / 2 = (2n^2 - 2n) / 2 = n^2 - n
Therefore, the worst-case time complexity of insertion sort is O(n^2).
Conclusion:
Among the given sorting algorithms, insertion sort has the worst-case time complexity of O(n^2). This means that as the size of the input array increases, the time taken by the algorithm to sort the array increases quadratically. It is not as efficient as other sorting algorithms like merge sort (O(nlogn)), quick sort (O(nlogn)), or heap sort (O(nlogn)) in terms of time complexity.
Which sorting algorithm is preferred when the data is already partially sorted?- a)Insertion sort
- b)Bubble sort
- c)Quick sort
- d)Selection sort
Correct answer is option 'A'. Can you explain this answer?
Which sorting algorithm is preferred when the data is already partially sorted?
a)
Insertion sort
b)
Bubble sort
c)
Quick sort
d)
Selection sort
|
Sonal Mehta answered |
Insertion sort is preferred when the data is already partially sorted because:
Efficiency:
- Insertion sort has a time complexity of O(n) for data that is almost sorted, making it efficient for partially sorted data.
- It is a simple sorting algorithm that works well with small datasets and is easy to implement.
Adaptability:
- Insertion sort is adaptive, meaning that it performs well when the input is almost sorted. It only requires a few comparisons and swaps to sort partially sorted data.
Stability:
- Insertion sort is stable, meaning that it preserves the relative order of equal elements. This property is beneficial when dealing with partially sorted data as it ensures the stability of the sorting process.
Space complexity:
- Insertion sort has a space complexity of O(1), meaning that it uses a constant amount of extra space. This makes it efficient in terms of memory usage, especially for partially sorted data.
In conclusion, insertion sort is the preferred sorting algorithm when dealing with partially sorted data due to its efficiency, adaptability, stability, and low space complexity.
Which of the following is an advantage of quick sort over merge sort?- a)Quick sort has better worst-case time complexity.
- b)Quick sort is stable.
- c)Quick sort requires less auxiliary space.
- d)Quick sort is more suitable for large data sets.
Correct answer is option 'C'. Can you explain this answer?
Which of the following is an advantage of quick sort over merge sort?
a)
Quick sort has better worst-case time complexity.
b)
Quick sort is stable.
c)
Quick sort requires less auxiliary space.
d)
Quick sort is more suitable for large data sets.
|
Pallavi Bose answered |
Advantage of Quick Sort over Merge Sort: Quick Sort requires less auxiliary space.
Explanation:
Quick Sort and Merge Sort are both popular sorting algorithms used in computer science. While both algorithms have their own advantages and disadvantages, Quick Sort has an advantage over Merge Sort in terms of auxiliary space usage.
Quick Sort:
Quick Sort is a divide-and-conquer algorithm that works by selecting a pivot element from the array and partitioning the other elements into two sub-arrays, according to whether they are less than or greater than the pivot. The sub-arrays are then recursively sorted. The key advantage of Quick Sort is its in-place sorting, meaning it does not require any additional memory to perform the sorting operation.
Merge Sort:
Merge Sort is also a divide-and-conquer algorithm that works by dividing the unsorted list into n sub-lists, each containing one element, and then repeatedly merging sub-lists to produce new sorted sub-lists until there is only one sub-list remaining. The key disadvantage of Merge Sort is its requirement of additional memory to perform the merging operation, as it needs to create temporary arrays to store the merged sub-lists.
Comparison:
Comparing Quick Sort and Merge Sort in terms of auxiliary space usage, Quick Sort requires less auxiliary space because it operates directly on the input array without the need for any additional memory allocation. In Quick Sort, the sorting is performed by swapping elements within the array itself, resulting in a space complexity of O(log n) on average.
On the other hand, Merge Sort requires additional memory space to store temporary arrays during the merging process. The space complexity of Merge Sort is usually O(n), which means it requires additional memory proportional to the size of the input array.
Conclusion:
In conclusion, the advantage of Quick Sort over Merge Sort is that Quick Sort requires less auxiliary space. This can be particularly beneficial when dealing with large data sets or situations where memory usage is a concern. However, it is important to note that Quick Sort has a worst-case time complexity of O(n^2) compared to Merge Sort's O(n log n) worst-case time complexity. Therefore, the choice between Quick Sort and Merge Sort depends on the specific requirements and constraints of the sorting problem at hand.
Explanation:
Quick Sort and Merge Sort are both popular sorting algorithms used in computer science. While both algorithms have their own advantages and disadvantages, Quick Sort has an advantage over Merge Sort in terms of auxiliary space usage.
Quick Sort:
Quick Sort is a divide-and-conquer algorithm that works by selecting a pivot element from the array and partitioning the other elements into two sub-arrays, according to whether they are less than or greater than the pivot. The sub-arrays are then recursively sorted. The key advantage of Quick Sort is its in-place sorting, meaning it does not require any additional memory to perform the sorting operation.
Merge Sort:
Merge Sort is also a divide-and-conquer algorithm that works by dividing the unsorted list into n sub-lists, each containing one element, and then repeatedly merging sub-lists to produce new sorted sub-lists until there is only one sub-list remaining. The key disadvantage of Merge Sort is its requirement of additional memory to perform the merging operation, as it needs to create temporary arrays to store the merged sub-lists.
Comparison:
Comparing Quick Sort and Merge Sort in terms of auxiliary space usage, Quick Sort requires less auxiliary space because it operates directly on the input array without the need for any additional memory allocation. In Quick Sort, the sorting is performed by swapping elements within the array itself, resulting in a space complexity of O(log n) on average.
On the other hand, Merge Sort requires additional memory space to store temporary arrays during the merging process. The space complexity of Merge Sort is usually O(n), which means it requires additional memory proportional to the size of the input array.
Conclusion:
In conclusion, the advantage of Quick Sort over Merge Sort is that Quick Sort requires less auxiliary space. This can be particularly beneficial when dealing with large data sets or situations where memory usage is a concern. However, it is important to note that Quick Sort has a worst-case time complexity of O(n^2) compared to Merge Sort's O(n log n) worst-case time complexity. Therefore, the choice between Quick Sort and Merge Sort depends on the specific requirements and constraints of the sorting problem at hand.
Which sorting algorithm has the best average-case time complexity?- a)Bubble sort
- b)Insertion sort
- c)Merge sort
- d)Selection sort
Correct answer is option 'C'. Can you explain this answer?
Which sorting algorithm has the best average-case time complexity?
a)
Bubble sort
b)
Insertion sort
c)
Merge sort
d)
Selection sort
|
|
Codebreakers answered |
Merge sort has a time complexity of O(n log n) in the average case, making it more efficient than other sorting algorithms.
What will be the output of the following code snippet?
#include <iostream>
using namespace std;void insertionSort(int arr[], int size) {
for (int i = 1; i < size; i++) {
int key = arr[i];
int j = i - 1; while (j >= 0 && arr[j] > key) {
arr[j + 1] = arr[j];
j = j - 1;
}
arr[j + 1] = key;
}
}int main() {
int arr[] = {7, 3, 9, 2, 5};
int size = sizeof(arr) / sizeof(arr[0]); insertionSort(arr, size); for (int i = 0; i < size; i++) {
cout << arr[i] << " ";
}
return 0;
}- a)2 3 5 7 9
- b)7 3 9 2 5
- c)5 2 9 3 7
- d)9 7 5 3 2
Correct answer is option 'A'. Can you explain this answer?
What will be the output of the following code snippet?
#include <iostream>
using namespace std;
#include <iostream>
using namespace std;
void insertionSort(int arr[], int size) {
for (int i = 1; i < size; i++) {
int key = arr[i];
int j = i - 1;
for (int i = 1; i < size; i++) {
int key = arr[i];
int j = i - 1;
while (j >= 0 && arr[j] > key) {
arr[j + 1] = arr[j];
j = j - 1;
}
arr[j + 1] = key;
}
}
arr[j + 1] = arr[j];
j = j - 1;
}
arr[j + 1] = key;
}
}
int main() {
int arr[] = {7, 3, 9, 2, 5};
int size = sizeof(arr) / sizeof(arr[0]);
int arr[] = {7, 3, 9, 2, 5};
int size = sizeof(arr) / sizeof(arr[0]);
insertionSort(arr, size);
for (int i = 0; i < size; i++) {
cout << arr[i] << " ";
}
return 0;
}
cout << arr[i] << " ";
}
return 0;
}
a)
2 3 5 7 9
b)
7 3 9 2 5
c)
5 2 9 3 7
d)
9 7 5 3 2
|
Vikram Singh Baghel answered |
The code implements the insertion sort algorithm to sort the given array. The sorted array will be {2, 3, 5, 7, 9}.
Which sorting algorithm is the most suitable for sorting a large collection of elements with a small range of values?- a)Merge sort
- b)Quick sort
- c)Counting sort
- d)Heap sort
Correct answer is option 'C'. Can you explain this answer?
Which sorting algorithm is the most suitable for sorting a large collection of elements with a small range of values?
a)
Merge sort
b)
Quick sort
c)
Counting sort
d)
Heap sort
|
Anil Kumar answered |
Counting sort is most suitable for sorting a large collection of elements with a small range of values because it operates by counting the occurrences of each element and then using that information to determine the sorted order.
What will be the output of the following code?
#include <iostream>
using namespace std;void insertionSort(int arr[], int n) {
for (int i = 1; i < n; i++) {
int key = arr[i];
int j = i - 1;
while (j >= 0 && arr[j] > key) {
arr[j + 1] = arr[j];
j--;
}
arr[j + 1] = key;
}
}int main() {
int arr[] = {5, 2, 4, 6, 1, 3};
int n = sizeof(arr) / sizeof(arr[0]);
insertionSort(arr, n);
for (int i = 0; i < n; i++) {
cout << arr[i] << " ";
}
return 0;
}- a)1 2 3 4 5 6
- b)6 5 4 3 2 1
- c)5 2 4 6 1 3
- d)1 6 2 5 3 4
Correct answer is option 'A'. Can you explain this answer?
What will be the output of the following code?
#include <iostream>
using namespace std;
#include <iostream>
using namespace std;
void insertionSort(int arr[], int n) {
for (int i = 1; i < n; i++) {
int key = arr[i];
int j = i - 1;
while (j >= 0 && arr[j] > key) {
arr[j + 1] = arr[j];
j--;
}
arr[j + 1] = key;
}
}
for (int i = 1; i < n; i++) {
int key = arr[i];
int j = i - 1;
while (j >= 0 && arr[j] > key) {
arr[j + 1] = arr[j];
j--;
}
arr[j + 1] = key;
}
}
int main() {
int arr[] = {5, 2, 4, 6, 1, 3};
int n = sizeof(arr) / sizeof(arr[0]);
insertionSort(arr, n);
for (int i = 0; i < n; i++) {
cout << arr[i] << " ";
}
return 0;
}
int arr[] = {5, 2, 4, 6, 1, 3};
int n = sizeof(arr) / sizeof(arr[0]);
insertionSort(arr, n);
for (int i = 0; i < n; i++) {
cout << arr[i] << " ";
}
return 0;
}
a)
1 2 3 4 5 6
b)
6 5 4 3 2 1
c)
5 2 4 6 1 3
d)
1 6 2 5 3 4
|
|
Vikram Singh Baghel answered |
The code implements the insertion sort algorithm, which sorts the array in ascending order. The sorted array will be {1, 2, 3, 4, 5, 6}.
Which search algorithm has a time complexity of O(log n)?- a)Linear search
- b)Binary search
- c)Depth-first search
- d)Breadth-first search
Correct answer is option 'B'. Can you explain this answer?
Which search algorithm has a time complexity of O(log n)?
a)
Linear search
b)
Binary search
c)
Depth-first search
d)
Breadth-first search
|
Neeraj Singh Kushwah answered |
Binary search has a time complexity of O(log n), where n is the size of the sorted input array. It repeatedly divides the search space in half, reducing the search space in each iteration.
What will be the output of the following code snippet?
#include <iostream>
using namespace std;int binarySearch(int arr[], int low, int high, int target) {
while (low <= high) {
int mid = low + (high - low) / 2; if (arr[mid] == target) {
return mid;
} if (arr[mid] < target) {
low = mid + 1;
} else {
high = mid - 1;
}
}
return -1;
}int main() {
int arr[] = {2, 5, 8, 12, 16};
int size = sizeof(arr) / sizeof(arr[0]);
int target = 8; int index = binarySearch(arr, 0, size - 1, target); cout << "Element found at index: " << index; return 0;
}- a)Element found at index: 2
- b)Element found at index: 1
- c)Element found at index: 3
- d)Element found at index: -1
Correct answer is option 'C'. Can you explain this answer?
What will be the output of the following code snippet?
#include <iostream>
using namespace std;
#include <iostream>
using namespace std;
int binarySearch(int arr[], int low, int high, int target) {
while (low <= high) {
int mid = low + (high - low) / 2;
while (low <= high) {
int mid = low + (high - low) / 2;
if (arr[mid] == target) {
return mid;
}
return mid;
}
if (arr[mid] < target) {
low = mid + 1;
} else {
high = mid - 1;
}
}
return -1;
}
low = mid + 1;
} else {
high = mid - 1;
}
}
return -1;
}
int main() {
int arr[] = {2, 5, 8, 12, 16};
int size = sizeof(arr) / sizeof(arr[0]);
int target = 8;
int arr[] = {2, 5, 8, 12, 16};
int size = sizeof(arr) / sizeof(arr[0]);
int target = 8;
int index = binarySearch(arr, 0, size - 1, target);
cout << "Element found at index: " << index;
return 0;
}
}
a)
Element found at index: 2
b)
Element found at index: 1
c)
Element found at index: 3
d)
Element found at index: -1
|
|
Vikram Singh Baghel answered |
The code implements the binary search algorithm to find the target element in the given sorted array. The target element 8 is found at index 3.
Which of the following is an example of a linear search algorithm?- a)Binary search
- b)Hashing
- c)Sequential search
- d)Interpolation search
Correct answer is option 'C'. Can you explain this answer?
Which of the following is an example of a linear search algorithm?
a)
Binary search
b)
Hashing
c)
Sequential search
d)
Interpolation search
|
Tanuj Arora answered |
Linear search, also known as sequential search, checks each element of the list one by one until the target element is found or the end of the list is reached.
What will be the output of the following code snippet?
#include <iostream>
using namespace std;int linearSearch(int arr[], int size, int target) {
for (int i = 0; i < size; i++) {
if (arr[i] == target) {
return i;
}
}
return -1;
}int main() {
int arr[] = {4, 9, 2, 7, 5};
int size = sizeof(arr) / sizeof(arr[0]);
int target = 7; int index = linearSearch(arr, size, target); cout << "Element found at index: " << index; return 0;
}- a)Element found at index: 3
- b)Element found at index: 1
- c)Element found at index: 4
- d)Element found at index: -1
Correct answer is option 'A'. Can you explain this answer?
What will be the output of the following code snippet?
#include <iostream>
using namespace std;
#include <iostream>
using namespace std;
int linearSearch(int arr[], int size, int target) {
for (int i = 0; i < size; i++) {
if (arr[i] == target) {
return i;
}
}
return -1;
}
for (int i = 0; i < size; i++) {
if (arr[i] == target) {
return i;
}
}
return -1;
}
int main() {
int arr[] = {4, 9, 2, 7, 5};
int size = sizeof(arr) / sizeof(arr[0]);
int target = 7;
int arr[] = {4, 9, 2, 7, 5};
int size = sizeof(arr) / sizeof(arr[0]);
int target = 7;
int index = linearSearch(arr, size, target);
cout << "Element found at index: " << index;
return 0;
}
}
a)
Element found at index: 3
b)
Element found at index: 1
c)
Element found at index: 4
d)
Element found at index: -1
|
|
Vikram Singh Baghel answered |
The code implements the linear search algorithm to find the target element in the given array. The target element 7 is found at index 3.
Which of the following sorting algorithms has the best average-case time complexity?- a)Selection sort
- b)Bubble sort
- c)Quick sort
- d)Insertion sort
Correct answer is option 'C'. Can you explain this answer?
Which of the following sorting algorithms has the best average-case time complexity?
a)
Selection sort
b)
Bubble sort
c)
Quick sort
d)
Insertion sort
|
|
Anil Kumar answered |
Quick sort has an average-case time complexity of O(n log n), which is better than the average-case time complexity of selection sort, bubble sort, and insertion sort (O(n^2)).
Which sorting algorithm is an example of an in-place and stable sorting algorithm?- a)Merge sort
- b)Quick sort
- c)Insertion sort
- d)Heap sort
Correct answer is option 'A'. Can you explain this answer?
Which sorting algorithm is an example of an in-place and stable sorting algorithm?
a)
Merge sort
b)
Quick sort
c)
Insertion sort
d)
Heap sort
|
Tanuja Mishra answered |
Merge sort is an in-place and stable sorting algorithm. It operates by dividing the input array into smaller subarrays, sorting them, and then merging the sorted subarrays to obtain the final sorted array.
What will be the output of the following code snippet?
#include <iostream>
using namespace std;void selectionSort(int arr[], int size) {
for (int i = 0; i < size - 1; i++) {
int minIndex = i;
for (int j = i + 1; j < size; j++) {
if (arr[j] < arr[minIndex]) {
minIndex = j;
}
}
swap(arr[i], arr[minIndex]);
}
}int main() {
int arr[] = {5, 2, 9, 1, 7};
int size = sizeof(arr) / sizeof(arr[0]); selectionSort(arr, size); for (int i = 0; i < size; i++) {
cout << arr[i] << " ";
}
return 0;
}- a)1 2 5 7 9
- b)1 2 9 5 7
- c)9 7 5 2 1
- d)5 2 9 1 7
Correct answer is option 'A'. Can you explain this answer?
What will be the output of the following code snippet?
#include <iostream>
using namespace std;
#include <iostream>
using namespace std;
void selectionSort(int arr[], int size) {
for (int i = 0; i < size - 1; i++) {
int minIndex = i;
for (int j = i + 1; j < size; j++) {
if (arr[j] < arr[minIndex]) {
minIndex = j;
}
}
swap(arr[i], arr[minIndex]);
}
}
for (int i = 0; i < size - 1; i++) {
int minIndex = i;
for (int j = i + 1; j < size; j++) {
if (arr[j] < arr[minIndex]) {
minIndex = j;
}
}
swap(arr[i], arr[minIndex]);
}
}
int main() {
int arr[] = {5, 2, 9, 1, 7};
int size = sizeof(arr) / sizeof(arr[0]);
int arr[] = {5, 2, 9, 1, 7};
int size = sizeof(arr) / sizeof(arr[0]);
selectionSort(arr, size);
for (int i = 0; i < size; i++) {
cout << arr[i] << " ";
}
return 0;
}
cout << arr[i] << " ";
}
return 0;
}
a)
1 2 5 7 9
b)
1 2 9 5 7
c)
9 7 5 2 1
d)
5 2 9 1 7
|
Yogesh Dwivedi answered |
The code implements the selection sort algorithm to sort the given array. The sorted array will be {1, 2, 5, 7, 9}.
What will be the output of the following code snippet?
#include <iostream>
using namespace std;void bubbleSort(int arr[], int size) {
for (int i = 0; i < size - 1; i++) {
for (int j = 0; j < size - i - 1; j++) {
if (arr[j] > arr[j + 1]) {
swap(arr[j], arr[j + 1]);
}
}
}
}int main() {
int arr[] = {3, 8, 1, 6, 4};
int size = sizeof(arr) / sizeof(arr[0]); bubbleSort(arr, size); for (int i = 0; i < size; i++) {
cout << arr[i] << " ";
}
return 0;
}- a)1 3 4 6 8
- b)8 6 4 3 1
- c)3 8 1 6 4
- d)1 4 6 8 3
Correct answer is option 'A'. Can you explain this answer?
What will be the output of the following code snippet?
#include <iostream>
using namespace std;
#include <iostream>
using namespace std;
void bubbleSort(int arr[], int size) {
for (int i = 0; i < size - 1; i++) {
for (int j = 0; j < size - i - 1; j++) {
if (arr[j] > arr[j + 1]) {
swap(arr[j], arr[j + 1]);
}
}
}
}
for (int i = 0; i < size - 1; i++) {
for (int j = 0; j < size - i - 1; j++) {
if (arr[j] > arr[j + 1]) {
swap(arr[j], arr[j + 1]);
}
}
}
}
int main() {
int arr[] = {3, 8, 1, 6, 4};
int size = sizeof(arr) / sizeof(arr[0]);
int arr[] = {3, 8, 1, 6, 4};
int size = sizeof(arr) / sizeof(arr[0]);
bubbleSort(arr, size);
for (int i = 0; i < size; i++) {
cout << arr[i] << " ";
}
return 0;
}
cout << arr[i] << " ";
}
return 0;
}
a)
1 3 4 6 8
b)
8 6 4 3 1
c)
3 8 1 6 4
d)
1 4 6 8 3
|
|
Yogesh Dwivedi answered |
The code implements the bubble sort algorithm to sort the given array. The sorted array will be {1, 3, 4, 6, 8}.
What is the time complexity of merge sort in the worst case scenario?- a)O(n)
- b)O(n log n)
- c)O(n2)
- d)O(1)
Correct answer is option 'B'. Can you explain this answer?
What is the time complexity of merge sort in the worst case scenario?
a)
O(n)
b)
O(n log n)
c)
O(n2)
d)
O(1)
|
|
Codebreakers answered |
Merge sort has a time complexity of O(n log n) in the worst-case scenario. It divides the array into halves recursively and then merges them, resulting in a logarithmic time complexity.
Which sorting algorithm is known for its in-place sorting property?- a)Merge sort
- b)Quick sort
- c)Insertion sort
- d)Radix sort
Correct answer is option 'B'. Can you explain this answer?
Which sorting algorithm is known for its in-place sorting property?
a)
Merge sort
b)
Quick sort
c)
Insertion sort
d)
Radix sort
|
|
Neeraj Singh Kushwah answered |
Quick sort is an in-place sorting algorithm as it sorts the array by partitioning it into smaller subarrays and sorting them in-place. It avoids the need for additional memory.
Which of the following search algorithms require the input to be sorted in ascending order?- a)Linear search
- b)Binary search
- c)Selection sort
- d)Bubble sort
Correct answer is option 'B'. Can you explain this answer?
Which of the following search algorithms require the input to be sorted in ascending order?
a)
Linear search
b)
Binary search
c)
Selection sort
d)
Bubble sort
|
KnowIT answered |
Binary search is an efficient search algorithm that requires the input to be sorted in ascending order. It follows a divide-and-conquer approach to find the target element by repeatedly dividing the search space in half.
Which sorting algorithm has the worst-case time complexity of O(n2)?- a)Bubble sort
- b)Insertion sort
- c)Merge sort
- d)Quick sort
Correct answer is option 'A'. Can you explain this answer?
Which sorting algorithm has the worst-case time complexity of O(n2)?
a)
Bubble sort
b)
Insertion sort
c)
Merge sort
d)
Quick sort
|
|
Codebreakers answered |
Bubble sort has a worst-case time complexity of O(n2), where n is the number of elements in the array. It occurs when the array is in reverse order.
Which of the following is an example of an unstable sorting algorithm?- a)Merge sort
- b)Quick sort
- c)Bubble sort
- d)Insertion sort
Correct answer is option 'C'. Can you explain this answer?
Which of the following is an example of an unstable sorting algorithm?
a)
Merge sort
b)
Quick sort
c)
Bubble sort
d)
Insertion sort
|
|
Codebreakers answered |
Bubble sort is an example of an unstable sorting algorithm. Unstable sorting algorithms may change the relative order of equal elements during the sorting process, while stable sorting algorithms preserve the order.
Which of the following is true about binary search?- a)It requires the input to be sorted in descending order.
- b)It has a time complexity of O(n).
- c)It can be applied on a linked list.
- d)It is a linear search algorithm.
Correct answer is option 'C'. Can you explain this answer?
Which of the following is true about binary search?
a)
It requires the input to be sorted in descending order.
b)
It has a time complexity of O(n).
c)
It can be applied on a linked list.
d)
It is a linear search algorithm.
|
Tech Era answered |
Binary search can be applied to search for an element in a sorted linked list by using the divide-and-conquer approach. However, it requires random access to elements, which is not efficiently supported by a singly linked list.
Which of the following is a stable sorting algorithm?- a)Quick sort
- b)Heap sort
- c)Bubble sort
- d)Shell sort
Correct answer is option 'C'. Can you explain this answer?
Which of the following is a stable sorting algorithm?
a)
Quick sort
b)
Heap sort
c)
Bubble sort
d)
Shell sort
|
|
KnowIT answered |
Bubble sort is a stable sorting algorithm as it compares adjacent elements and swaps them if they are in the wrong order. It maintains the relative order of elements with equal values.
Chapter doubts & questions for Searching and Sorting - DSA in C++ 2024 is part of Software Development exam preparation. The chapters have been prepared according to the Software Development exam syllabus. The Chapter doubts & questions, notes, tests & MCQs are made for Software Development 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests here.
Chapter doubts & questions of Searching and Sorting - DSA in C++ in English & Hindi are available as part of Software Development exam.
Download more important topics, notes, lectures and mock test series for Software Development Exam by signing up for free.
DSA in C++
153 videos|115 docs|24 tests
|
Signup to see your scores go up within 7 days!
Study with 1000+ FREE Docs, Videos & Tests
10M+ students study on EduRev
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup