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All questions of Introduction to JS for Software Development Exam

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What is the output of the following JavaScript code?
var x = [1, 2, 3];
x.push(4);
console.log(x.length);
  • a)
    1
  • b)
    2
  • c)
    3
  • d)
    4
Correct answer is option 'D'. Can you explain this answer?

Tanuj Arora answered
The push() method is used to add elements to the end of an array. In this case, it adds the number 4 to the array, resulting in a length of 4.

What will be the output of the following code snippet?
let x = 1;
{
  let x = 2;
  {
    console.log(x);
    let x = 3;
  }
}
  • a)
    1
  • b)
    2
  • c)
    3
  • d)
    ReferenceError
Correct answer is option 'D'. Can you explain this answer?

KnowIT answered
The 'console.log(x)' line tries to access 'x' before it is declared inside the inner block. Since 'let' has block scope, the declaration of 'x' inside the inner block shadows the outer 'x' variable, and it is not accessible before its declaration.

What is the output of the following JavaScript code?
var x = 10;
var y = 5;
console.log(x += y);
  • a)
    10
  • b)
    15
  • c)
    5
  • d)
    Error
Correct answer is option 'B'. Can you explain this answer?

Tanuj Arora answered
The += operator is used for addition and assignment. It adds the value of y to x and assigns the result back to x, resulting in x being 15.

What will be the output of the following code snippet?
let x = 5;
(function() {
  console.log(x);
  let x = 10;
})();
  • a)
    5
  • b)
    10
  • c)
    undefined
  • d)
    ReferenceError
Correct answer is option 'D'. Can you explain this answer?

KnowIT answered
The variable 'x' is declared using 'let' inside the immediately-invoked function expression (IIFE). Since 'let' has block scope, the declaration of 'x' inside the function creates a new variable that is not accessible before the declaration.

What will be the output of the following code snippet?
let x = 1;
function foo() {
  console.log(x);
  let x = 2;
}
foo();
  • a)
    1
  • b)
    2
  • c)
    undefined
  • d)
    ReferenceError
Correct answer is option 'D'. Can you explain this answer?

Explanation:
The code snippet provided defines a variable `x` with the value of 1 and a function `foo`. When `foo` is called, it attempts to log the value of `x` to the console and then defines a new variable `x` with the value of 2.

Variable Hoisting:
In JavaScript, variable declarations using the `let` keyword are hoisted to the top of their scope, but they are not initialized. This means that the variable `x` is hoisted to the top of the `foo` function, but its value is not set until the line where it is defined.

Execution:
When the code is executed, the following steps occur:

1. The variable `x` is declared and initialized with the value of 1.
2. The `foo` function is defined.
3. The `foo` function is called.
4. Inside the `foo` function, the `console.log(x)` statement is executed.
- At this point, the variable `x` is hoisted to the top of the `foo` function, but its value is not set yet.
- Since the value of `x` is not set, it is undefined.
- Therefore, trying to log the value of `x` to the console will result in the output of `undefined`.
5. The variable `x` is defined with the value of 2.
- This line is never reached because the `console.log(x)` statement causes an error.

Error:
The error thrown is a ReferenceError because the variable `x` is referenced before it has been initialized with a value. This error occurs because the `let` keyword does not allow hoisting to the top of the scope, unlike the `var` keyword.

Therefore, the correct answer is option 'D) ReferenceError'.

What will be the output of the following code snippet?
console.log(2 + "2");
  • a)
    22
  • b)
    4
  • c)
    2 + "2"
  • d)
    2
Correct answer is option 'A'. Can you explain this answer?

The + operator, when one operand is a string, performs string concatenation. Therefore, "2" is treated as a string, and the result is "22".

What will be the output of the following code snippet?
let x = 10;
{
  console.log(x);
  let x = 20;
}
  • a)
    10
  • b)
    20
  • c)
    undefined
  • d)
    ReferenceError
Correct answer is option 'D'. Can you explain this answer?

Hridoy Ghoshal answered


Explanation:

Variable Scope:
- When a variable is declared using the `let` keyword, it is block-scoped.
- In the given code snippet, there is a variable `x` declared outside the block and another `x` declared inside the block.

Hoisting:
- Variables declared with `let` are hoisted to the top of their block but are not initialized.
- In the code snippet, the variable `x` inside the block is hoisted to the top of the block but not initialized.

Output:
- When the `console.log(x)` statement is executed, it refers to the `x` variable declared inside the block which is not initialized yet.
- This results in a `ReferenceError` because the `x` variable inside the block is in the temporal dead zone until it is initialized.

Therefore, the output of the given code snippet will be a ReferenceError.

How do you output a message to the console in JavaScript?
  • a)
    console.log()
  • b)
    print()
  • c)
    log()
  • d)
    e.log() b. print() c. log()
Correct answer is option 'A'. Can you explain this answer?

Nilotpal Jain answered
Explanation:

console.log() function:
- In JavaScript, the console.log() function is used to output a message to the console.
- It is a built-in function that is commonly used for debugging purposes, displaying variables, or general logging.
- The console.log() function takes one or more arguments, which can be strings, numbers, objects, or other data types.

Usage:
- To use the console.log() function, simply write console.log() followed by the message you want to output in parentheses.
- For example, console.log("Hello, World!"); will output "Hello, World!" to the console.

Benefits:
- The console.log() function is a powerful tool for developers to quickly check the output of their code and track the flow of their program.
- It helps in identifying errors, debugging issues, and understanding the behavior of the code during runtime.

Example:
javascript
console.log("Hello, World!");

Conclusion:
- In JavaScript, the console.log() function is the standard way to output messages to the console and is an essential tool for developers to effectively debug and monitor their code.

What is the output of the following JavaScript code?
 
var x = 5;
function update() {
  x = 10;
}
update();
console.log(x);
  • a)
    5
  • b)
    10
  • c)
    Error
  • d)
    Undefined
Correct answer is option 'B'. Can you explain this answer?

Tanuj Arora answered
The update() function modifies the global variable x by assigning it a new value of 10. The console.log() statement outputs the updated value.

What will be the output of the following code snippet?
var x = 10;
function foo() {
  console.log(x);
  var x = 20;
}
foo();
  • a)
    10
  • b)
    20
  • c)
    undefined
  • d)
    ReferenceError
Correct answer is option 'C'. Can you explain this answer?

Qudrat Chauhan answered
Variable hoisting causes the declaration of 'var x' inside the function to be hoisted to the top. However, it is initialized with the value 'undefined' before the assignment. Therefore, the output is 'undefined'.

What will be the output of the following code snippet?
for (let i = 0; i < 3; i++) {
  setTimeout(function() {
    console.log(i);
  }, 1000);
}
  • a)
    0, 1, 2
  • b)
    3, 3, 3
  • c)
    1, 2, 3
  • d)
    0, 0, 0
Correct answer is option 'D'. Can you explain this answer?

Qudrat Chauhan answered
The 'setTimeout' function is asynchronous. By the time the 'console.log(i)' is executed, the loop has already completed, and the value of 'i' is 3. Therefore, the output is 0, 1, 2.

What will be the output of the following code snippet?
var x = 10;
function foo() {
  console.log(x);
  if (false) {
    var x = 20;
  }
}
foo();
  • a)
    10
  • b)
    20
  • c)
    undefined
  • d)
    ReferenceError
Correct answer is option 'A'. Can you explain this answer?

Explanation:

The output of the code snippet will be 10.

Code Explanation:

1. The variable x is declared and assigned a value of 10.
2. The function foo() is defined, which logs the value of x to the console.
3. Inside the function, there is an if statement with a condition of false.
4. Inside the if statement, a new variable x is declared and assigned a value of 20.
5. Since the condition of the if statement is false, the code inside the if statement is not executed.
6. The function foo() is called, which logs the value of x to the console.
7. As there is no variable x declared inside the function foo(), it uses the variable x declared in the outer scope.
8. Thus, the value of x is 10 and it is logged to the console.

Key Points:

- The variable x is hoisted to the top of the function scope.
- Hoisting is a JavaScript behavior where variable and function declarations are moved to the top of their containing scope before code execution.
- Since the variable x is hoisted, the code inside the if statement is actually interpreted as:
```
var x;
if (false) {
x = 20;
}
```
- As the if statement is never executed, the value of x remains unchanged as 10.
- Therefore, when the function foo() is called, it logs the value of x as 10.

What is the output of the following JavaScript code?
var x = "Hello";
console.log(x.length);
  • a)
    5
  • b)
    6
  • c)
    1
  • d)
    Error
Correct answer is option 'A'. Can you explain this answer?

Tanuj Arora answered
The length property is used to determine the number of characters in a string. In this case, the string "Hello" has a length of 5.

What will be the output of the following code snippet?
console.log("2" - 1);
  • a)
    1
  • b)
    2
  • c)
    "2" - 1
  • d)
    "2" - "1"
Correct answer is option 'A'. Can you explain this answer?

The - operator performs arithmetic subtraction. In this case, the string "2" is converted to the number 2, and the result is 2 - 1 = 1.

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