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All questions of Functions for Software Development Exam
Which of the following statements is true about JavaScript functions?- a)A function is a set of statements that performs a specific task.
- b)A function is a built-in feature of JavaScript that cannot be modified.
- c)A function is a data type in JavaScript that represents a string value.
- d)A function is a reserved word in JavaScript that cannot be used as a variable name.
Correct answer is option 'A'. Can you explain this answer?
Which of the following statements is true about JavaScript functions?
a)
A function is a set of statements that performs a specific task.
b)
A function is a built-in feature of JavaScript that cannot be modified.
c)
A function is a data type in JavaScript that represents a string value.
d)
A function is a reserved word in JavaScript that cannot be used as a variable name.
|
Yogesh Dwivedi answered |
A function in JavaScript is a set of statements that performs a specific task.
What is a function in JavaScript?- a)A JavaScript variable
- b)A reusable block of code that performs a specific task
- c)A JavaScript keyword used for loops
- d)A data type in JavaScript
Correct answer is option 'B'. Can you explain this answer?
What is a function in JavaScript?
a)
A JavaScript variable
b)
A reusable block of code that performs a specific task
c)
A JavaScript keyword used for loops
d)
A data type in JavaScript
|
Hackers World answered |
A function in JavaScript is a reusable block of code that performs a specific task when called.
What will be the output of the following code?
var x = 10;function test() {
if (x === 10) {
var x = 20;
} console.log(x);
}test();- a)10
- b)undefined
- c)20
- d)Error
Correct answer is option 'B'. Can you explain this answer?
What will be the output of the following code?
var x = 10;
var x = 10;
function test() {
if (x === 10) {
var x = 20;
}
if (x === 10) {
var x = 20;
}
console.log(x);
}
}
test();
a)
10
b)
undefined
c)
20
d)
Error
|
Tech Era answered |
The 'var x = 20' declaration inside the 'if' statement creates a new variable 'x' with block scope. Since the 'console.log(x)' statement is outside the block, it refers to the outer variable 'x', which is undefined.
Consider the following JavaScript code:
function outer() {
var x = 10; function inner() {
console.log(x);
} return inner;
}var closureFn = outer();
closureFn();
What will be the output of the above code?- a)10
- b)0
- c)Undefined
- d)This code will produce an error
Correct answer is option 'A'. Can you explain this answer?
Consider the following JavaScript code:
function outer() {
var x = 10;
function outer() {
var x = 10;
function inner() {
console.log(x);
}
console.log(x);
}
return inner;
}
}
var closureFn = outer();
closureFn();
What will be the output of the above code?
closureFn();
What will be the output of the above code?
a)
10
b)
0
c)
Undefined
d)
This code will produce an error
|
Simar Sharma answered |
The code defines a function named "outer" that declares a variable "x" with the value 10. Inside "outer", there is a nested function named "inner" that logs the value of "x" to the console. Finally, the "inner" function is returned from "outer" and assigned to the variable "closureFn". Calling "closureFn()" executes the "inner" function, which accesses the value of "x" from its outer scope. Therefore, the output is 10.
Which of the following statements is true regarding JavaScript functions?- a)JavaScript functions can only be declared using the 'function' keyword
- b)JavaScript functions can be used before they are declared (hoisting)
- c)JavaScript functions cannot have default parameter values
- d)JavaScript functions cannot return a value
Correct answer is option 'B'. Can you explain this answer?
Which of the following statements is true regarding JavaScript functions?
a)
JavaScript functions can only be declared using the 'function' keyword
b)
JavaScript functions can be used before they are declared (hoisting)
c)
JavaScript functions cannot have default parameter values
d)
JavaScript functions cannot return a value
|
Diksha Sharma answered |
JavaScript functions can be used before they are declared due to hoisting, which moves function declarations to the top of the scope.
Consider the following JavaScript code:
var x = 5;function updateX() {
x = 10;
}setTimeout(updateX, 1000);console.log(x);
What will be the output of the above code?- a)5
- b)10
- c)Undefined
- d)This code will produce an error
Correct answer is option 'A'. Can you explain this answer?
Consider the following JavaScript code:
var x = 5;
var x = 5;
function updateX() {
x = 10;
}
x = 10;
}
setTimeout(updateX, 1000);
console.log(x);
What will be the output of the above code?
What will be the output of the above code?
a)
5
b)
10
c)
Undefined
d)
This code will produce an error
|
|
Simar Sharma answered |
The code declares a global variable "x" with the value 5. The function "updateX" modifies the global variable "x" by assigning it the value 10. However, the function "updateX" is called asynchronously using "setTimeout" with a delay of 1000 milliseconds. Therefore, the console log is executed before the "updateX" function has a chance to modify the value of "x". Hence, the output is 5.
What will be the output of the following JavaScript code?
function greet() {
console.log("Hello, World!");
}greet();- a)"Hello, World!"
- b)"Hello"
- c)"World"
- d)This code will produce an error
Correct answer is option 'A'. Can you explain this answer?
What will be the output of the following JavaScript code?
function greet() {
console.log("Hello, World!");
}
function greet() {
console.log("Hello, World!");
}
greet();
a)
"Hello, World!"
b)
"Hello"
c)
"World"
d)
This code will produce an error
|
Anu Ahuja answered |
Function greet() { console.log("Hello World!"); }
greet();
The output will be "Hello World!"
greet();
The output will be "Hello World!"
What will be the output of the following JavaScript code?
var x = 5;function updateX() {
var x = 10;
}updateX();
console.log(x);- a)5
- b)10
- c)Undefined
- d)This code will produce an error
Correct answer is option 'A'. Can you explain this answer?
What will be the output of the following JavaScript code?
var x = 5;
var x = 5;
function updateX() {
var x = 10;
}
var x = 10;
}
updateX();
console.log(x);
console.log(x);
a)
5
b)
10
c)
Undefined
d)
This code will produce an error
|
Gaurav Khanna answered |
Explanation:
Variable Scope:
- In the given code, there are two instances of the variable `x`.
- The first one is declared globally with a value of 5, and the second one is declared inside the `updateX` function with a value of 10.
- When `updateX` function is called, it creates a new local variable `x` with a value of 10, but it does not modify the global variable `x`.
Output:
- When `console.log(x)` is executed after calling the `updateX` function, it prints the value of the global variable `x`, which is 5.
- Therefore, the output of the code will be `5`.
Variable Scope:
- In the given code, there are two instances of the variable `x`.
- The first one is declared globally with a value of 5, and the second one is declared inside the `updateX` function with a value of 10.
- When `updateX` function is called, it creates a new local variable `x` with a value of 10, but it does not modify the global variable `x`.
Output:
- When `console.log(x)` is executed after calling the `updateX` function, it prints the value of the global variable `x`, which is 5.
- Therefore, the output of the code will be `5`.
Which of the following options correctly represents the syntax to define a function in JavaScript?- a)function = myFunction() {}
- b)function myFunction() {}
- c)function() = myFunction {}
- d)myFunction = function() {}
Correct answer is option 'B'. Can you explain this answer?
Which of the following options correctly represents the syntax to define a function in JavaScript?
a)
function = myFunction() {}
b)
function myFunction() {}
c)
function() = myFunction {}
d)
myFunction = function() {}
|
Tanuja Mishra answered |
The correct syntax to define a function in JavaScript is "function myFunction() {}".
Consider the following JavaScript code:
var calculate = function(a, b, operation) {
return operation(a, b);
};function add(a, b) {
return a + b;
}var result = calculate(3, 4, add);
console.log(result);
What will be the output of the above code?- a)3
- b)4
- c)7
- d)This code will produce an error
Correct answer is option 'C'. Can you explain this answer?
Consider the following JavaScript code:
var calculate = function(a, b, operation) {
return operation(a, b);
};
var calculate = function(a, b, operation) {
return operation(a, b);
};
function add(a, b) {
return a + b;
}
return a + b;
}
var result = calculate(3, 4, add);
console.log(result);
What will be the output of the above code?
console.log(result);
What will be the output of the above code?
a)
3
b)
4
c)
7
d)
This code will produce an error
|
Arka Banerjee answered |
Explanation:
- The given code defines a function called `calculate` which takes three parameters: `a`, `b`, and `operation`.
- The `calculate` function returns the result of calling the `operation` function with `a` and `b` as arguments.
- The code also defines a function called `add` which takes two parameters: `a` and `b`.
- The `add` function returns the sum of `a` and `b`.
- Lastly, the code calls the `calculate` function with the arguments `3`, `4`, and the `add` function.
- The result of this calculation is then printed to the console using `console.log`.
Execution:
1. The `calculate` function is called with the arguments `3`, `4`, and the `add` function.
2. Inside the `calculate` function, the `operation` function (in this case, `add`) is called with `a` and `b` as arguments.
3. The `add` function calculates the sum of `a` and `b`, which is `3 + 4 = 7`.
4. The `calculate` function returns the result of the `add` function, which is `7`.
5. The returned result is stored in the `result` variable.
6. The `console.log` function prints the value of the `result` variable to the console.
7. Therefore, the output of the code will be `7`.
Conclusion:
The output of the given JavaScript code will be `7`.
- The given code defines a function called `calculate` which takes three parameters: `a`, `b`, and `operation`.
- The `calculate` function returns the result of calling the `operation` function with `a` and `b` as arguments.
- The code also defines a function called `add` which takes two parameters: `a` and `b`.
- The `add` function returns the sum of `a` and `b`.
- Lastly, the code calls the `calculate` function with the arguments `3`, `4`, and the `add` function.
- The result of this calculation is then printed to the console using `console.log`.
Execution:
1. The `calculate` function is called with the arguments `3`, `4`, and the `add` function.
2. Inside the `calculate` function, the `operation` function (in this case, `add`) is called with `a` and `b` as arguments.
3. The `add` function calculates the sum of `a` and `b`, which is `3 + 4 = 7`.
4. The `calculate` function returns the result of the `add` function, which is `7`.
5. The returned result is stored in the `result` variable.
6. The `console.log` function prints the value of the `result` variable to the console.
7. Therefore, the output of the code will be `7`.
Conclusion:
The output of the given JavaScript code will be `7`.
What is the purpose of using parameters in JavaScript functions?- a)Parameters define the return value of a function.
- b)Parameters specify the number of times a function should be executed.
- c)Parameters allow us to pass values into a function for its operation.
- d)Parameters determine the scope of variables within a function.
Correct answer is option 'C'. Can you explain this answer?
What is the purpose of using parameters in JavaScript functions?
a)
Parameters define the return value of a function.
b)
Parameters specify the number of times a function should be executed.
c)
Parameters allow us to pass values into a function for its operation.
d)
Parameters determine the scope of variables within a function.
|
|
Yogesh Dwivedi answered |
Parameters allow us to pass values into a function for its operation.
What will be the output of the following JavaScript code?
var x = 5;function updateX() {
x = 10;
}updateX();
console.log(x);- a)5
- b)10
- c)Undefined
- d)This code will produce an error
Correct answer is option 'B'. Can you explain this answer?
What will be the output of the following JavaScript code?
var x = 5;
var x = 5;
function updateX() {
x = 10;
}
x = 10;
}
updateX();
console.log(x);
console.log(x);
a)
5
b)
10
c)
Undefined
d)
This code will produce an error
|
|
Gaurav Khanna answered |
Explanation:
Variable Declaration:
- The code declares a variable x and assigns it a value of 5.
Function Declaration:
- A function named updateX is declared which sets the value of x to 10.
Function Call:
- The updateX function is called.
Console Output:
- Finally, the value of x is logged to the console using console.log(x).
Output:
- The output of this code will be 10 because the updateX function is called which updates the value of x to 10.
Therefore, the correct answer is 10.
Variable Declaration:
- The code declares a variable x and assigns it a value of 5.
Function Declaration:
- A function named updateX is declared which sets the value of x to 10.
Function Call:
- The updateX function is called.
Console Output:
- Finally, the value of x is logged to the console using console.log(x).
Output:
- The output of this code will be 10 because the updateX function is called which updates the value of x to 10.
Therefore, the correct answer is 10.
What will be the output of the following code?
var x = 10;function outer() {
function inner() {
console.log(x);
} inner();
var x = 20;
}outer();- a)10
- b)20
- c)undefined
- d)Error
Correct answer is option 'C'. Can you explain this answer?
What will be the output of the following code?
var x = 10;
var x = 10;
function outer() {
function inner() {
console.log(x);
}
function inner() {
console.log(x);
}
inner();
var x = 20;
}
var x = 20;
}
outer();
a)
10
b)
20
c)
undefined
d)
Error
|
Ritesh Kumar Shivhare answered |
The 'inner' function is called before the 'x' variable is defined within the 'outer' function. Therefore, when 'console.log(x)' is executed, 'x' is undefined.
Consider the following JavaScript code:
function outer() {
var x = 10; function inner() {
console.log(x);
var x = 20;
} inner();
}outer();
What will be the output of the above code?- a)10
- b)20
- c)Undefined
- d)This code will produce an error
Correct answer is option 'C'. Can you explain this answer?
Consider the following JavaScript code:
function outer() {
var x = 10;
function outer() {
var x = 10;
function inner() {
console.log(x);
var x = 20;
}
console.log(x);
var x = 20;
}
inner();
}
}
outer();
What will be the output of the above code?
What will be the output of the above code?
a)
10
b)
20
c)
Undefined
d)
This code will produce an error
|
|
Simar Sharma answered |
The code defines a function named "outer" that declares a variable "x" with the value 10. Inside "outer", there is a nested function named "inner" that logs the value of "x" to the console. However, before the console log, there is a variable declaration "var x = 20". This declaration creates a new local variable "x" within the "inner" function's scope. Since JavaScript has function-level scope, the declaration of the local "x" variable shadows the outer "x" variable. Therefore, when the console log is executed, the value of the local "x" variable, which is undefined, is logged.
What will be the output of the following code?
function add(a, b) {
return a + b;
}function multiply(a, b) {
return a * b;
}var result = add(2, multiply(3, 4));
console.log(result);- a)14
- b)12
- c)10
- d)24
Correct answer is option 'D'. Can you explain this answer?
What will be the output of the following code?
function add(a, b) {
return a + b;
}
function add(a, b) {
return a + b;
}
function multiply(a, b) {
return a * b;
}
return a * b;
}
var result = add(2, multiply(3, 4));
console.log(result);
console.log(result);
a)
14
b)
12
c)
10
d)
24
|
|
Gaurav Joshi answered |
Explanation:
Function Definitions:
- The code defines two functions, add and multiply, which perform addition and multiplication operations respectively.
Calculation:
- The add function takes two parameters a and b and returns their sum.
- The multiply function takes two parameters a and b and returns their product.
- In the expression add(2, multiply(3, 4)), the multiply function is called first with arguments 3 and 4, resulting in the product 12.
- Then, the add function is called with arguments 2 and 12, resulting in the sum 14.
Output:
- The final value 14 is stored in the variable result.
- The code then prints the value of result using console.log.
- Therefore, the output of the code will be 24.
Function Definitions:
- The code defines two functions, add and multiply, which perform addition and multiplication operations respectively.
Calculation:
- The add function takes two parameters a and b and returns their sum.
- The multiply function takes two parameters a and b and returns their product.
- In the expression add(2, multiply(3, 4)), the multiply function is called first with arguments 3 and 4, resulting in the product 12.
- Then, the add function is called with arguments 2 and 12, resulting in the sum 14.
Output:
- The final value 14 is stored in the variable result.
- The code then prints the value of result using console.log.
- Therefore, the output of the code will be 24.
What will be the output of the following code?
function multiply(a, b = 2) {
return a * b;
}console.log(multiply(3));- a)5
- b)6
- c)3
- d)Error
Correct answer is option 'C'. Can you explain this answer?
What will be the output of the following code?
function multiply(a, b = 2) {
return a * b;
}
function multiply(a, b = 2) {
return a * b;
}
console.log(multiply(3));
a)
5
b)
6
c)
3
d)
Error
|
|
Tech Era answered |
The 'multiply' function accepts two parameters, 'a' and 'b', with 'b' having a default value of 2. When called with 'multiply(3)', it uses the default value of 'b' (2) and returns the product of 'a' (3) and 'b' (2), which is 6.
What will be the output of the following code?
function sum(a, b) {
return a + b;
}var result = sum(3, 4);
console.log(result);- a)7
- b)34
- c)12
- d)undefined
Correct answer is option 'A'. Can you explain this answer?
What will be the output of the following code?
function sum(a, b) {
return a + b;
}
function sum(a, b) {
return a + b;
}
var result = sum(3, 4);
console.log(result);
console.log(result);
a)
7
b)
34
c)
12
d)
undefined
|
Startup Central Classes answered |
The 'sum' function returns the sum of its two parameters. When called with 'sum(3, 4)', it returns 7, which is assigned to the 'result' variable and then printed.
What will be the output of the following code?
function greet() {
console.log("Hello!");
}console.log(typeof greet);- a)"Hello!"
- b)"function"
- c)"undefined"
- d)"object"
Correct answer is option 'B'. Can you explain this answer?
What will be the output of the following code?
function greet() {
console.log("Hello!");
}
function greet() {
console.log("Hello!");
}
console.log(typeof greet);
a)
"Hello!"
b)
"function"
c)
"undefined"
d)
"object"
|
|
Startup Central Classes answered |
The 'typeof' operator returns the type of the operand. In this case, it returns "function" because 'greet' is a function.
What does the term "function expression" mean in JavaScript?- a)It refers to a function that calculates mathematical expressions.
- b)It is a way to define a function as a value of a variable.
- c)It denotes a function that is only used for expression-based operations.
- d)It is a special type of function that can only be used within if statements.
Correct answer is option 'B'. Can you explain this answer?
What does the term "function expression" mean in JavaScript?
a)
It refers to a function that calculates mathematical expressions.
b)
It is a way to define a function as a value of a variable.
c)
It denotes a function that is only used for expression-based operations.
d)
It is a special type of function that can only be used within if statements.
|
|
Tanuja Mishra answered |
A function expression is a way to define a function as a value of a variable.
What will be the output of the following JavaScript code?
function sum(a, b) {
return a + b;
}var result = sum(3, 4);
console.log(result);- a)3
- b)4
- c)7
- d)This code will produce an error
Correct answer is option 'C'. Can you explain this answer?
What will be the output of the following JavaScript code?
function sum(a, b) {
return a + b;
}
function sum(a, b) {
return a + b;
}
var result = sum(3, 4);
console.log(result);
console.log(result);
a)
3
b)
4
c)
7
d)
This code will produce an error
|
Codebreakers answered |
The code defines a function named "sum" that takes two parameters and returns their sum. Calling "sum(3, 4)" passes the values 3 and 4 to the function, which returns the sum of 7. The result is then logged to the console.
What will be the output of the following code?
var x = 5;function test() {
console.log(x);
var x = 10;
}test();- a)5
- b)undefined
- c)10
- d)Error
Correct answer is option 'B'. Can you explain this answer?
What will be the output of the following code?
var x = 5;
var x = 5;
function test() {
console.log(x);
var x = 10;
}
console.log(x);
var x = 10;
}
test();
a)
5
b)
undefined
c)
10
d)
Error
|
|
Tanuja Mishra answered |
In the 'test' function, the 'console.log(x)' statement is executed before the 'var x = 10' line. At that point, 'x' is undefined, so it prints undefined.
What will be the output of the following code?
function greet(name) {
console.log("Hello, " + name + "!");
}greet();- a)"Hello, undefined!"
- b)"Hello, null!"
- c)"Hello, !"
- d)Error
Correct answer is option 'A'. Can you explain this answer?
What will be the output of the following code?
function greet(name) {
console.log("Hello, " + name + "!");
}
function greet(name) {
console.log("Hello, " + name + "!");
}
greet();
a)
"Hello, undefined!"
b)
"Hello, null!"
c)
"Hello, !"
d)
Error
|
|
Tech Era answered |
The 'greet' function expects a parameter 'name' to be passed when called. Since no argument is provided when calling 'greet()', the 'name' parameter is undefined, resulting in the output "Hello, undefined!".
What is the difference between function declarations and function expressions in JavaScript?- a)Function declarations are hoisted, while function expressions are not.
- b)Function declarations can have named parameters, while function expressions cannot.
- c)Function expressions can be used before they are declared, while function declarations cannot.
- d)Function expressions are more efficient in terms of memory usage compared to function declarations.
Correct answer is option 'A'. Can you explain this answer?
What is the difference between function declarations and function expressions in JavaScript?
a)
Function declarations are hoisted, while function expressions are not.
b)
Function declarations can have named parameters, while function expressions cannot.
c)
Function expressions can be used before they are declared, while function declarations cannot.
d)
Function expressions are more efficient in terms of memory usage compared to function declarations.
|
Qudrat Chauhan answered |
Function declarations are hoisted, while function expressions are not.
Consider the following JavaScript code:
function multiplyBy(factor) {
return function(number) {
return number * factor;
};
}var multiplyByTwo = multiplyBy(2);
var multiplyByFive = multiplyBy(5);console.log(multiplyByTwo(3));
console.log(multiplyByFive(4));
What will be the output of the above code?- a)3, 4
- b)6, 20
- c)5, 8
- d)This code will produce an error
Correct answer is option 'B'. Can you explain this answer?
Consider the following JavaScript code:
function multiplyBy(factor) {
return function(number) {
return number * factor;
};
}
function multiplyBy(factor) {
return function(number) {
return number * factor;
};
}
var multiplyByTwo = multiplyBy(2);
var multiplyByFive = multiplyBy(5);
var multiplyByFive = multiplyBy(5);
console.log(multiplyByTwo(3));
console.log(multiplyByFive(4));
What will be the output of the above code?
console.log(multiplyByFive(4));
What will be the output of the above code?
a)
3, 4
b)
6, 20
c)
5, 8
d)
This code will produce an error
|
|
Simar Sharma answered |
The code defines a function named "multiplyBy" that takes a parameter "factor" and returns an inner function. The inner function takes a parameter "number" and multiplies it by the "factor" value captured in its closure. By calling "multiplyBy(2)", we create a closure that multiplies any number by 2. Similarly, calling "multiplyBy(5)" creates a closure that multiplies any number by 5. Therefore, "multiplyByTwo(3)" returns 6, and "multiplyByFive(4)" returns 20.
Which keyword is used to call a function in JavaScript?- a)invoke
- b)exec
- c)call
- d)function
Correct answer is option 'C'. Can you explain this answer?
Which keyword is used to call a function in JavaScript?
a)
invoke
b)
exec
c)
call
d)
function
|
|
Diksha Sharma answered |
The 'call' keyword is used to call a function in JavaScript.
What will be the output of the following code?
function outer() {
var x = 10; function inner() {
console.log(x);
} x = 20;
return inner;
}var fn = outer();
fn();- a)10
- b)20
- c)undefined
- d)Error
Correct answer is option 'A'. Can you explain this answer?
What will be the output of the following code?
function outer() {
var x = 10;
function outer() {
var x = 10;
function inner() {
console.log(x);
}
console.log(x);
}
x = 20;
return inner;
}
return inner;
}
var fn = outer();
fn();
fn();
a)
10
b)
20
c)
undefined
d)
Error
|
|
Tech Era answered |
The 'inner' function is defined inside the 'outer' function and has access to the variables in its parent scope, including 'x'. When 'fn()' is called, it prints the value of 'x', which is 10.
What is the difference between parameters and arguments in JavaScript?- a)Parameters are variables defined in a function, while arguments are the values passed to the function
- b)Parameters and arguments are the same thing in JavaScript
- c)Parameters are used in arrow functions, while arguments are used in regular functions
- d)Parameters are optional in JavaScript, while arguments are required
Correct answer is option 'A'. Can you explain this answer?
What is the difference between parameters and arguments in JavaScript?
a)
Parameters are variables defined in a function, while arguments are the values passed to the function
b)
Parameters and arguments are the same thing in JavaScript
c)
Parameters are used in arrow functions, while arguments are used in regular functions
d)
Parameters are optional in JavaScript, while arguments are required
|
|
Diksha Sharma answered |
Parameters are the variables defined in a function's declaration, while arguments are the actual values passed to the function when it is called.
What will be the output of the following JavaScript code?
var multiply = function(a, b) {
return a * b;
};console.log(multiply(2, 5));- a)2
- b)5
- c)10
- d)This code will produce an error
Correct answer is option 'C'. Can you explain this answer?
What will be the output of the following JavaScript code?
var multiply = function(a, b) {
return a * b;
};
var multiply = function(a, b) {
return a * b;
};
console.log(multiply(2, 5));
a)
2
b)
5
c)
10
d)
This code will produce an error
|
|
Codebreakers answered |
The code defines a function expression named "multiply" that takes two parameters and returns their product. Calling "multiply(2, 5)" passes the values 2 and 5 to the function, which returns the product of 10. The result is then logged to the console.
What will be the output of the following code?
function outer() {
var x = 10; function inner() {
console.log(x);
} return inner;
}var fn = outer();
fn();- a)10
- b)undefined
- c)Error
- d)null
Correct answer is option 'A'. Can you explain this answer?
What will be the output of the following code?
function outer() {
var x = 10;
function outer() {
var x = 10;
function inner() {
console.log(x);
}
console.log(x);
}
return inner;
}
}
var fn = outer();
fn();
fn();
a)
10
b)
undefined
c)
Error
d)
null
|
Neeraj Singh Kushwah answered |
The 'inner' function is defined inside the 'outer' function and has access to the variables in its parent scope, including 'x'. When 'fn()' is called, it prints the value of 'x', which is 10.
What is the purpose of the 'return' statement in JavaScript functions?- a)To terminate the execution of a function
- b)To output a value from a function
- c)To assign a value to a variable
- d)To define the scope of a function
Correct answer is option 'B'. Can you explain this answer?
What is the purpose of the 'return' statement in JavaScript functions?
a)
To terminate the execution of a function
b)
To output a value from a function
c)
To assign a value to a variable
d)
To define the scope of a function
|
|
Diksha Sharma answered |
The 'return' statement is used to output a value from a function. It also terminates the execution of the function.
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JavaScript for Web Development
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