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All questions of Sets for Commerce Exam

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If A = {a, b, c} then the number of proper subsets of A are:
  • a)
    3
  • b)
    10
  • c)
    7
  • d)
    8
Correct answer is option 'C'. Can you explain this answer?

Pooja Nair answered
  • Number of proper subsets of a given set = 2m - 1, where m is the number of elements.
  • Here the number of elements is 3. So the number of proper subsets of A = 23 - 1 = 7.

 The Shaded region in the following figure illustrates
  • a)
    A ∩ ( B ∪ C)
  • b)
    A ∩ B ∩ C
  • c)
    A ∪ B ∪ C
  • d)
    (A ∩ B) ∪ (A ∩ C)
Correct answer is option 'D'. Can you explain this answer?

Naina Sharma answered
First which region is over which region Then We will see that A is on the B so A intersection B and after C is on the A so, A intersection C after that we have to take all intersection part so A intersection B is Union with A intersection C.
The shaded region represents (A ∩ B) ∪ (A ∩ C).

 If A = {3, 6, 9, 12} and B = {6, 8, 9} then intersection of A and B is
  • a)
    {3, 6}
  • b)
    {3, 12}
  • c)
    {6, 9}
  • d)
    {9, 12}
Correct answer is 'C'. Can you explain this answer?

Gaurav Saini answered
An intersection is the collection of all the elements that are common to all the sets under consideration.
Here element 6 & 9 are common in both the sets. So option C is correct . 

 Which of the following is not an empty set?
  • a)
    {x : x is a multiple of 7, x < 7, x ∈ N}
  • b)
    Set of common points of two parallel lines in a plane
  • c)
    {x : 6 + 2x > 5x + 3, x ∈ N}
  • d)
    Set of smallest whole number
Correct answer is option 'D'. Can you explain this answer?

Ayush Joshi answered
As, the set of Whole numbers is {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, ...};
So, according to the set of whole numbers above, the smallest whole number should be "0" and therefore the set of smallest whole number is not empty.

For the set of all natural numbers the universal set can be
  • a)
    Set of all odd numbers
  • b)
    Set of all even numbers
  • c)
    Set of all integers
  • d)
    Set of all prime numbers
Correct answer is option 'C'. Can you explain this answer?

Krishna Iyer answered
Integers contain all the natural numbers. So it can be a universal set for natural numbers. In other options, there are only some of the elements of natural numbers.

Can you explain the answer of this question below:

If A = {5, 10, 15}, B = ϕ, then B – A is

  • A:

    5

  • B:

    {5,10}

  • C:

    ϕ

  • D:

    {5,10, 15}

The answer is c.

Om Desai answered
If A = {5, 10, 15}, B = ϕ
B - A will have those elements which are in B but not in A.
B - A = ϕ

The set A = {1,4,9,16,25—} in set builder form is written as
  • a)
    A = {x:x is a prime number}
  • b)
    A ={x:x is the cube of a natural number}
  • c)
    A = {x:x is the square of a natural number}
  • d)
    A = {x:x is an even natural number}
Correct answer is 'C'. Can you explain this answer?

Krishna Iyer answered
  • We know that, 12 = 1, 22 = 4, 32 = 9, 42 = 16, 52 = 25
  • Therefore the set A = {1, 4, 9, 16, 25...} can be written in set builder form as: 
    A = {x: x is the square of a natural number}

Which of the following is a set ?
  • a)
    The collection of all the months of a year
  • b)
    The collection of all interesting novels
  • c)
    The collection of all rich persons of Delhi
  • d)
    A collection of 10 best writers of India
Correct answer is option 'A'. Can you explain this answer?

Neha Joshi answered
(a) The collection of all months of a year is a well-defined collection of objects because one can definitely identify a month that belongs to this collection. Hence, this collection is a set.
(b) A collection of novels is not a well-defined collection because one cannot identify a book that belongs to this collection. Hence, this collection is not a set.
(c) A collection of top rich persons can not be defined. Hence, this collection is not a set.
(d) The collection of the ten most talented writers of India is not a well-defined collection because the criteria for determining a writer's talent may vary from person to person. Hence, this collection is not a set.

If Q = {x : x = 1/y , where y ∈ N} , then
  • a)
    1 ∈ Q
  • b)
    0 ∈ Q
  • c)
    1/2 ∈ Q
  • d)
    2 ∈ Q
Correct answer is option 'B'. Can you explain this answer?

Pooja Shah answered
We know that
n(A∪B)=n(A)+n(B)−n(A∩B)......(i)
n(A∪B)=n(A)+n(B)-n(A∩B)......(i)
Case 1 From (i) , it is clear that n(A∪B)
n(A∪B) will be maximum when n(A∩B)=0
In that case, 
n(A∪B)=n(A)+n(B)=(3+6)=9
∴ Maximum number of elements in 
(A∪B)=9
Case 2 From (i) , it is clear that n(A∪B)
n(A∪B) will be minimum when n(A∩B)=0 maximum ,i.e, when 
n(A∩B)=3
In this case, 
n(A∪B)=n(A)+n(B)−n(A∩B)=(3+6−3)=6
∴ minimum number of elements in 
A∪B=6

 Choose the incorrect statement
  • a)
    If a set has only one element, we call it a singleton set.
  • b)
    Set of all even prime numbers is a subset of set of all natural numbers.
  • c)
    Φ is not a subset of any set.
  • d)
    Every set is a subset of itself.
Correct answer is option 'C'. Can you explain this answer?

Rohit Joshi answered
set A is a proper subset of a set B if A is a subset of B and there is at least one element of B that's not an element of A. Thus, the void set is a subset of all sets, and it's a proper subset of every set except itself

If n (P) = 5, n(Q) = 12 and n(P U Q) = 14 then n(P ∩ Q) =
  • a)
    3
  • b)
    4
  • c)
    5
  • d)
    7
Correct answer is option 'A'. Can you explain this answer?

Hansa Sharma answered
n (P) = 5, n(Q) = 12 and n(PUQ) = 14
n(PUQ) = n(P) + n(Q) - n(P∩Q) 
14 = 5 + 12 - n(P∩Q)
n(P∩Q) = 3

 If U= set of all whole numbers less than 12, A=set of all whole numbers less than 10, B= Set of all odd natural numbers less than 10, then what is (A∩B)’?
  • a)
    {3,5,7,9}
  • b)
    {0,1,3,5,7,9}
  • c)
    {0,2,4,6,8,10,11}
  • d)
    {1,3,5,7}
Correct answer is option 'A'. Can you explain this answer?

Hansa Sharma answered
U = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11}
A = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
B = {1, 3, 5, 7, 9}
A ∩ B = {1, 3, 5, 7, 9}
(A ∩ B)’ = U - (A ∩ B)
(A ∩ B)’ = {0, 2, 4, 6, 8, 10, 11}

From the sets given below, select equal sets :
A = { 2, 4, 8, 12}, B = { 1, 2, 3, 4},
C = { 4, 8, 12, 14}, D = { 3, 1, 4, 2}
  • a)
    A and C
  • b)
    A and B
  • c)
    B and D
  • d)
    B and C
Correct answer is option 'C'. Can you explain this answer?

Mansi Chopra answered
 The sets are equal, if they have the exact same elements in them. Since option B & D have exactly same number of elements in them So, B & D are equal sets. 

If A = {1,2,3,4} , B = {4,5,6,7} , then A - B =
  • a)
    {5,6,7}
  • b)
    {1,2,3,4}
  • c)
    {4}
  • d)
    {1,2,3}
Correct answer is option 'D'. Can you explain this answer?

Preeti Iyer answered
  • (A - B) is nothing but the elements which are present in set A but not present in set B.
  • In other words, it is elements of set A excluding the elements which are in set B.
  • Here A = {1, 2, 3, 4} and B = {4, 5, 6, 7}
    So, (A - B) = {1, 2, 3}

 The number of elements in the Power set P(S) of the set S = [ [ Φ] , 1, [ 2, 3 ]] is
  • a)
    2
  • b)
    4
  • c)
    8
  • d)
    None of these
Correct answer is option 'C'. Can you explain this answer?

Preeti Iyer answered
There’s a result in mathematics used for this. It says that a power set B of any set A is a set of all the subsets of A and the number of elements of B will be 2^n where n is the number of elements of A.
So taking your question as an example;
A = {1,2,3}
B : set of all subsets of A
List out all the subsets of A - {1},{2},{3},{1,2},{2,3},{1,3},{1,2,3},{empty set}
Number of elements in A (n) = 3 
so 23 = 8
So, B = {{1},{2},{3},{1,2},{2,3},{1,3},{1,2,3},{empty set}} 
and the number of elements are 8.

Let U = {1,2,3,4,5,6,7,8,9,10} , A = {1,2,5} , B = {6,7}. Then A∩B’ is :
  • a)
    A
  • b)
    B
  • c)
    B’
  • d)
    none
Correct answer is option 'A'. Can you explain this answer?

Pooja Shah answered
  • B' gives us all the elements in U other than 6 and 7 i.e., B' = {1, 2, 3, 4, 5, 8, 9, 10}
  • The intersection of this set with A will be the common elements in both of these (A and B') i.e., = {1, 2, 5} which is set A itself.

The set of intelligent students in a class is
  • a)
    a finite set
  • b)
    a null set
  • c)
    not a well defined collection
  • d)
    a singleton set
Correct answer is option 'C'. Can you explain this answer?

Saumya Datta answered
As the opinions of different person's is differentabout the intelligent student. So, we can't exactly have the same student's name in a set, hence it is not a well defined collection.

Consider the set A of all divisors of 30. How many subsets of A contains even divisors only?
  • a)
    2
  • b)
    16
  • c)
    28
  • d)
    4
Correct answer is 'B'. Can you explain this answer?

Himaja Ammu answered
Set of divisors of 30={1,2,3,6,10,15,30} in these the even divisors r={2,6,10,30} we know no.of subsets to any set=2^n so answer is 2^4=16

Which of the following has only one subset?
  • a)
    { }
  • b)
    {5}
  • c)
    {4,5}
  • d)
    {0}
Correct answer is option 'A'. Can you explain this answer?

Vijay Kumar answered
  • Every set has the empty set as a subset. So if a set has 1 element, like {0}, then it will have 2 subsets: itself and the empty set, which is denoted by { }.
  • So, if a set has only one subset, then this set must be the empty set.

If A, B and C are any three sets , then A∩ (B∪C) is equal to
  • a)
    (A ∩ B) ∪(A∩C)
  • b)
    (A∪B) ∩ (A∩C)
  • c)
    (A∪B) ∪ (A∪C)
  • d)
    (A – B) ∩ (A – C)
Correct answer is option 'A'. Can you explain this answer?

Lavanya Menon answered
In the problem statement we are taking union of B and C and then taking its intersection with A.
This means A∩(B∪C)will contain elements that are in A and are in either B or C.
∴ A∩(B∪C) is equivalent to taking intersection of A,B and A,C and then taking there union i.e. (A∩B)∪(A∩C)

Let A and B be two sets containing four and two elements respectively.Then the number of subsets of the set A×B,each having atleast three elements is:
  • a)
    219
  • b)
    256
  • c)
    275
  • d)
    510
Correct answer is option 'A'. Can you explain this answer?

Advait Singh answered
⇒ Number of elements in Set A = 4
⇒ Number of elements in Set B = 2
∴ Number of elements in set (A × B) = 8
∴ Total number of subsets of (A×B) = 28 = 256
⇒ Number of subsets having 0 elements = 8C0 = 1
⇒ Number of subsets having 1 element = 8C1 = 8
⇒ Number of subsets having 2 elements = 8C2 = 28
∴ Number of subsets having atleast 3 elements = 256 - 1 - 8 - 28 = 219

Chapter doubts & questions for Sets - Mathematics (Maths) Class 11 2024 is part of Commerce exam preparation. The chapters have been prepared according to the Commerce exam syllabus. The Chapter doubts & questions, notes, tests & MCQs are made for Commerce 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests here.

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