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31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - NEET MCQ


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30 Questions MCQ Test Chemistry Class 11 - 31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2

31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 for NEET 2024 is part of Chemistry Class 11 preparation. The 31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 questions and answers have been prepared according to the NEET exam syllabus.The 31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for 31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 below.
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31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 1

The correct order of the O–O bond length in O2, H2O2 and O3 is [1995, 2005]

Detailed Solution for 31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 1

The bond length of  O – O in O2 is 1.21 Å, in H2O2 it is 1.48 Å and in O3 it is 1.28 Å.
∴ correct order of bond length is H2O2 > O3 > O2.

31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 2

The ground state electronic configuration of valence shell electrons in nitrogen molecule (N2) is written as KK Bond order in nitrogen molecule is [1995]

Detailed Solution for 31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 2

In this configuration, there are four completely filled bonding molecular orbitals and one completely filled antibonding molecular orbital. So that Nb = 8 and
Na = 2 .

∴ Bond order =

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31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 3

The correct order of N–O bond lengths in NO, NO2, NO3and N2O4 is [1996]

Detailed Solution for 31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 3

 

31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 4

Which of the following compounds has a 3-centre bond?[1996]

Detailed Solution for 31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 4

The bond represented by dots form the 3-centred electron pair bond. The idea of three centred electron pair bond B–H–B bridges is necessitated because diborane does not have sufficient electrons to  form normal covalent bonds. It has only 12 electrons instead of 14 required to give simple ethane like structure for diborane.

31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 5

The low density of ice compared to water is due to[1997]

Detailed Solution for 31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 5

We know that due to polar nature, water molecules are held together by intermolecular hydrogen bonds. The structure of ice is open with large number of vacant spaces, therfore the density of ice is less than water.

31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 6

The cylindrical shape of an alkyne is due to the fact that it has [1997]

Detailed Solution for 31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 6

In alkynes the hybridisation is sp i.e each carbon atom undergoes sp hybridisation to form two sp-hybrid orbitals. The two 2porbitals remain unhybridised. Hybrid orbitals form one sigma and two unhybridised orbitals form π-bonds.

Hence two π bond and one sigma bond between C — C lead to cylindrical shape.

31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 7

N2 and O2 are converted into monocations, N2+ and O2+ respectively. Which of the following statements is wrong ? [1997]

Detailed Solution for 31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 7

For N2; 
σ1s2 < σ*1s2 < σ2s2 < σ*2s2 < П2px = 2py4 <σ2pz2 < П*2px = 2py < σ*2pz
For O2;
σ1s2  < σ*1s2 < σ2s2 < σ*2s2 <σ2pz2 < П2px = 2py4  <П*2px = 2py2 < σ*2pz  
a) In N2+,the electron is removed from bonding molecular orbital.Hence bond order decreases and  N-N bond weakens.
b) In O2+ , the electron is removed from anti bonding molecular orbital.Hence O-O bond order increases.
c) In O2+, the no of unpaired electrons decreases and hence paramagnetism decreases.
d) In N2+, there is one unpaired electron.It is paramagnetic. This statement is wrong.

31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 8

The AsF5 molecule is trigonal bipyramidal. The hybrid orbitals used by the As atom for bonding are          [1997]

Detailed Solution for 31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 8

The electronic configuration of As is

sp3 d hybridisation

Thus the hybridisation involved in the AsF5 molecule is trigonal bipyramidal. So, the hybrid orbitals used are s, px, py, pz, dz2.

31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 9

The number of anti-bonding electron pairs in O2-2 molecular ion on the basis of molecular orbital theory is, (Atomic number of O is 8) [1998]

Detailed Solution for 31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 9

Total no. of electrons in O22- = 16 + 2 = 18

Distribution of electrons in molecular orbital

Anti bonding electron = 8 (4 pairs)

31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 10

Among the following which one is not paramagnetic? [Atomic numbers : Be = 4, Ne = 10, As = 33, Cl = 17] [1998]

Detailed Solution for 31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 10

Paramagnetic character is based upon presence of unpaired electron

Hence only Cl do not have unpaired electrons.

31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 11

In PO43– ion, the formal charge on each oxygen atom and P—O bond order respectively are

Detailed Solution for 31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 11

Bond order between P – O

or Formal charge on oxygen = 

(Formal charge = No. of electrons in valance

31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 12

Which of the following molecules is planar?

Detailed Solution for 31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 12

XeF4 hybridisation is = 

hence V = 8 (no. of valence e) X = 4 (no of monovalent atom)

C = 0 charge on cation A = 0 (charge on anion). The shape is

  Square planar   shape.

31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 13

The dipole moments of diatomic molecules AB and CD are 10.41D and 10.27 D, respectively while their bond distances are 2.82 and 2.67 Å, respectively. This  indicates that [1999]

Detailed Solution for 31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 13

As dipole moment = electric charge × bond length D. M. of AB molecules = 4.8 x 10 -10 x 2.82 x10 -8 = 13.53D
D.M. of CD molecules = 4.8 x10-10 x 2.67 x10-10 = 12.81D
now% ionic character

then % ionic character  in

% ionic character in

31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 14

Which one of the following arrangements represents the increasing bond orders of the given species? [1999]

Detailed Solution for 31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 14

Bond order of NO+ =

Similarly, Bond order of NO =  

Bond order of NO 

Bon d order of  

By above calculation, we get Decreasing bond order NO+ > NO > NO > O-2

31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 15

Which one of the following has the pyramidal shape?[1999]

Detailed Solution for 31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 15

PF3 has pyramidal shape
Phosphorus exist in sp3 hybridiation state hence it exist in tetrahedral shape. But due to presence of lone pair its shape is pyramidal.
F—H-----F—H-----F—H-----F

31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 16

Which one of the following molecules will form a linear polymeric structure due to hydrogen bonding? [2000]

Detailed Solution for 31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 16

In the case of HCl we can see that hydrogen is bonded to chlorine atoms so it will not show hydrogen bonding.

HF: 
Here we can see that  HF show a linear polymeric structure due to hydrogen bonding.

Here we can see that though  H2O show polymerisation due to hydrogen bonding it is not linear polymerisation.

NH3

Here we can see that though  NH3  show polymerisation due to hydrogen bonding it is not linear polymerisation.

Thus, the correct option is (B)  HF.

31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 17

Among the following  the electron deficient compound is : [2000]

Detailed Solution for 31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 17

In BCl3​ the valence electrons for boron are 6 (3 of boron and 3 of chlorine), so there are two electrons deficient for the octet configuration. Thus, electron deficient molecule is BCl3​.

31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 18

The relationship between the dissociation energy of N2 and N2+ is : [2000]

Detailed Solution for 31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 18

Dissociation energy of any molecules depends upon bond order. Bond order in N2 molecule is 3 while bond order in N+2 is 2.5.
Further we know that more the Bond order, more is the stability and more is the BDE.

31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 19

Cation and anion combines in a crystal to form following type of compound. [2000]

Detailed Solution for 31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 19

We know that the electr ostatic force that binds the oppositely charged ions which are formed by transfer of electron from one atom to another is called ionic bond. We also know that cation and anion are oppositely charged particles therefore they form ionic bond in crystal.

31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 20

Among the following ions the pπ–dπ overlap could be present in [2000]

Detailed Solution for 31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 20

In P–O bond, π bond is formed by the sidewise overlapping of d-orbital of P and p-orbital of oxygen. Hence it is formed by pπ and dπ overlapping.

31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 21

 In which of the following the bond angle is maximum? [2001]

Detailed Solution for 31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 21

We know that bond angles of  NH3 = 107º, 4+ = 109.5º,  PCl3 = 100º. Therefore bond angle of NH4+ is maximum.

31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 22

Which of the following two are isostructural?

Detailed Solution for 31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 22

In XeF2 and IF2. Both XeF2 and IF2 are sp3d hybridized and have planar shape.

31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 23

Main axis of a diatomic molecule is z, molecular orbital px and py overlap to form which of the following orbital? [2001]

Detailed Solution for 31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 23

px and Py orbitals do not have proper orientation to overlap and hence no bond is formed.

31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 24

In X — H --- Y, X and Y both are electronegative elements

Detailed Solution for 31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 24

In X — H - - - Y, X an d Y both are electronegative elements (i.e attracts the electron pair) then electron density on X will increase and on H will decrease.

31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 25

Which of the following has pπ – dπ bonding?

Detailed Solution for 31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 25

In SO3-2

S is sp3 hybridised, so

In 'S' unhybride d- orbit is present, which is involved in π bond formation

n oxygen two unpaired p- orbital is present in these one is involved in σ bond formation while other is used in π bond formation Thus in orbitals ar e involved for pπ - dπbonding.

31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 26

In NO3 ion number of bond pair and lone pair of electrons on nitrogen atom respectively are

[2002]

Detailed Solution for 31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 26

To form NO3- , nitrogen uses one p-electron for π-bond formation two p-electrons for σ-bond formation. 2s electrons are used for coordinate bond formation. Thus there is no lone pair on nitrogen but four bond pairs

31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 27

Which of the following statements is not correct for sigma and pi-bonds formed between two carbon atoms? [2003]

Detailed Solution for 31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 27

As sigma bond is stronger than the π(pi) bond, so it must be having higher bond energy than π (pi) bond.

31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 28

Among the following the pair in which the two species are not isostructural is [2004]

Detailed Solution for 31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 28

Shape (structure ) of a species can be ascertained on the basis of hybridisation of its central atom, which in turn can be known by determining the number of hybrid bonds

(H). Thus 

For SiF4

(Tetrahedral structure)

For SiF4

(See saw structure)

Hence the two compounds have different structures

31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 29

In a regular octahedral molecule, MX6 the number of X - M - X bonds at 180° is [2004]

Detailed Solution for 31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 29

Thus here  bond angles between X4 - M - X2 = 180°
X1 - M - X3 = 180°
X5 - M - X6 = 180°

31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 30

H2O is polar, whereas BeF2 is not. It is because [2004]

Detailed Solution for 31 Year NEET Previous Year Questions: Chemical Bonding & Molecular Structure - 2 - Question 30

In a linear symmetrical molecule like BeF2, the bond angle between three atoms is 180°, hence the polarity due to one bond is cancelled by the equal polarity due to other bond, while it is not so in angular molecules, like H2O

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