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AP EAMCET Mock Test - 9 - JEE MCQ


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30 Questions MCQ Test AP EAMCET Mock Test Series - AP EAMCET Mock Test - 9

AP EAMCET Mock Test - 9 for JEE 2024 is part of AP EAMCET Mock Test Series preparation. The AP EAMCET Mock Test - 9 questions and answers have been prepared according to the JEE exam syllabus.The AP EAMCET Mock Test - 9 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for AP EAMCET Mock Test - 9 below.
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AP EAMCET Mock Test - 9 - Question 1
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The magnetic dipole moment of a short magnetic dipole at a distant point along the equator of magnet has a magnitude of ‘X’ in SI units, tf the distance between the point and the magnet is halved then the magnitude of dipole moment win be

Detailed Solution for AP EAMCET Mock Test - 9 - Question 1
The magnetic dipole moment is the product of either of pole strength and the magnetic length of dipole. Thus, it is independent of the distance of point at which it is measured. So. it remains unchanged, if the distance between point and the magnet is halved.
AP EAMCET Mock Test - 9 - Question 2
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When the electron in the hydrogen atom jumps from the fourth Bohr orbit to the second Bohr orbit, one gets the

Detailed Solution for AP EAMCET Mock Test - 9 - Question 2

The wavelength of line in cased Baimer series is given by where n = 3,4,5 and R = Rydberg constant.

So, for the Balmer series, the transition takes from third orbit to second for first line spectrum, fourth orbit to second for second line spectrum, etc. Hence, the given transition represents the second line of the Balmer series.

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AP EAMCET Mock Test - 9 - Question 3
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An X-ray tube produces a continuous spectrum of radiation with its shortest wavelength of 45 × 10−2 Å. The maximum energy of a photon in the radiation in eV is (h =6.62 × 10−34J s, c = 3 × 108 m s−1)

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AP EAMCET Mock Test - 9 - Question 4
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Two cars A and B are traveling in the same direction with velocities v1 and v2 (v1 > v2), respectively. When the car A is at a distance d behind the car B, the driver of the car A applies the brakes, producing uniform retardation, a. There will be no collision, when
Detailed Solution for AP EAMCET Mock Test - 9 - Question 4

Their final relative velocity = 0
Relative velocity of A w.r.t B is u = v1 - v2
Relative acceleration = -a

AP EAMCET Mock Test - 9 - Question 5
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In a series LCR circuit, R = 200Ω and the voltage and frequency of the main supply are 220 V and 50 Hz, respectively. On taking out the capacitance from the circuit, the current lags behind the voltage by 30°. On taking out the inductor from the circuit, the current leads the voltage by 30°. The power dissipated in the LCR circuit is
Detailed Solution for AP EAMCET Mock Test - 9 - Question 5
Here, R = 200 Ω, Vrms = 220 V, v = 50 Hz

When only the capacitance is removed, the phase difference between the current and voltage is tan

When only the inductance is removed, the phase difference between current and voltage is

As XL = XC, therefore the given series LCR is in resonance.

Impedance of the circuit is Z = R = 200 Ω

The power dissipated in the circuit is

P = VrmsIrmscos ϕ

At resonance, power factor cos ϕ = 1

AP EAMCET Mock Test - 9 - Question 6
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In forced oscillation of a particle, the amplitude is maximum for a frequency  of the force while the energy is maximum for a frequency ω2 of the force. Then,
Detailed Solution for AP EAMCET Mock Test - 9 - Question 6

When the frequency of the driving force is equal to the natural frequency i.e. at resonance, the amplitude is maximum.
At resonance, average power absorbed by the forced oscillator is also maximum.
So, both ω1 and ω2 are same at resonant frequencies.

AP EAMCET Mock Test - 9 - Question 7
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If the pressure and absolute temperatre of 2 litres of CO₂ are doubles, the volume of CO₂ would become
AP EAMCET Mock Test - 9 - Question 8
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Which of the following element is responsible for oxidation of water to O₂ in biological processes?
AP EAMCET Mock Test - 9 - Question 9
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12 g of Mg (at. mass 24) on reacting completely with acid gives hydrogen gas, the volume of which at S.T.P would be
AP EAMCET Mock Test - 9 - Question 10
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Calculate the amount of change flowing in 2 minute in a wire of resistance 10 Ω when a potential difference of 20 V is applied
AP EAMCET Mock Test - 9 - Question 11
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Which of the following is antipyretic?
AP EAMCET Mock Test - 9 - Question 12
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Which of these is a hypnotic?
AP EAMCET Mock Test - 9 - Question 13
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How many monochlorobutanes will be obtained on chlorination of n-butane?
AP EAMCET Mock Test - 9 - Question 14
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The lines  intersect the curves xy = c2 and z = 0, if c is equal to
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AP EAMCET Mock Test - 9 - Question 15
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Let  Then, the system of linear equations 
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AP EAMCET Mock Test - 9 - Question 16
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If  |z| = 4 and arg z = 5π/6, then z is
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AP EAMCET Mock Test - 9 - Question 17
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Number of integers greater than 7000 and divisible by 5 that can be formed using only the digits 3,5,7,8 and 9, no digit being repeated, is 
Detailed Solution for AP EAMCET Mock Test - 9 - Question 17

Number should be greater than 7000 and divisible by 5.
Digits that has to be used are 3,5,7,8 &9,  no digit being repeated.

The number to be divisible by 5 it should end with 5 in this case.

Therefore, four-digit numbers =3⋅3⋅2⋅1=18

Five-digit numbers =4⋅3⋅2⋅1⋅1=24
Hence, the total required numbers are 42.

AP EAMCET Mock Test - 9 - Question 18
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For the given figure find 
Detailed Solution for AP EAMCET Mock Test - 9 - Question 18

We have, 
∠F = α + γ & ∠D = β + γ
Quadrilateral AFED is cyclic.
⇒ ∠F+∠D = 180° ⇒ α  + β + 2γ = 180°

⇒ k = 20° ⇒ k = 20°
⇒ α + β + γ = 7k = 140°

AP EAMCET Mock Test - 9 - Question 19
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If in the expansion of  the sum of coefficients of x5 and x10 is 0 , then the coefficient of the third term is
Detailed Solution for AP EAMCET Mock Test - 9 - Question 19

We have,

General term of the binomial expansion of

For coefficient of x5, put
3n − 5r = 5
⇒ 5r = 3n − 5
 And, for coefficient of x10, put
3n − 5r = 10
⇒ 5r = 3n − 10
Then,

AP EAMCET Mock Test - 9 - Question 20
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In how many ways can 45 men be allotted to 3 different districts, if the districts are to be covered by 10, 15 and 20 men?
Detailed Solution for AP EAMCET Mock Test - 9 - Question 20

The required number of ways is the same as the number of ways in which m + n + p things can be divided into three groups containing m, n and p things, which is 
∴ The required number of different allotments 

AP EAMCET Mock Test - 9 - Question 21
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The value of  is equal to
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AP EAMCET Mock Test - 9 - Question 22
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Consider the lines given by L1: x + 3y - 5 = 0, L2: 3x - ky - 1 = 0 and L3: 5x + 2y - 12 = 0. If one of L1, L2 and L3 is parallel to at least one of the other two, then
Detailed Solution for AP EAMCET Mock Test - 9 - Question 22

According to the question, L1 and L3 are not parallel.

So the required values of k are given by

or 5k2 + 51k + 54 = 0

AP EAMCET Mock Test - 9 - Question 23
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Evaluate
 .
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AP EAMCET Mock Test - 9 - Question 24
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General solution of the differential equation 
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AP EAMCET Mock Test - 9 - Question 25
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If P(x, y, z) is a point on the line segment joining Q(2, 2, 4) and R(3, 5, 6) such that the projections of  on the axes are 13/5 , 19/5, 26/5 respectively, then P divides QR in the ratio
Detailed Solution for AP EAMCET Mock Test - 9 - Question 25

Since  has projections  13/5 , 19/5 and 26/5 on the co-ordinate axes, therefore  we can  write

Now, let P divide the given line segment joining Q(2, 2, 4) and R(3, 5, 6) in the ratio λ∶1 internally.

So, the position vector of P can be expressed as,

But position vector of P is given by

Hence,

AP EAMCET Mock Test - 9 - Question 26
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The value of eccentricity for the hyperbola x2 - 2y2 - 2x + 8y - 1 = 0 is
Detailed Solution for AP EAMCET Mock Test - 9 - Question 26

Comparing it with the general equation of hyperbola, we get
a2 = 6 and b2 = 3

Eccentricity for hyperbola is given by

AP EAMCET Mock Test - 9 - Question 27
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If  then x belongs to the interval
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AP EAMCET Mock Test - 9 - Question 28
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Sum of maximum & minimum values of f(x)=x3+2x2+2x−1 in interval x∈[0,4] is
Detailed Solution for AP EAMCET Mock Test - 9 - Question 28

f(x) = x3 + 2x2 + 2x − 1
f′(x) = 3x2 + 4x + 2
D = (4)2−4(3)(2) < 0
⇒ f′(x) > 0 ∀x ∈ R
⇒ f(x) is increasing function in x∈[0,4]
⇒ Minimum of f(x) = f(0) = −1
& maximum of f(x) = f(4)
⇒ f(4) = 64 + 2(16) + 2(4) − 1
= 64 + 32 + 7
= 103
⇒ f(4) + f(0) = 102

AP EAMCET Mock Test - 9 - Question 29
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One ticket is selected at random from 100 tickets numbered 00, 01, 02, ….., 98 and 99. If X and Y denote the sum and the product of the digits on the tickets, respectively, then P(X = 9|Y = 0) is equal to
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AP EAMCET Mock Test - 9 - Question 30
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If equation  is true for atleast one positive x , then a belongs to
Detailed Solution for AP EAMCET Mock Test - 9 - Question 30

For positive values of x, minimum value of 

By wavy curve method, a∈(0,1)

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