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Civil Engineering (CE) Exam  >  Civil Engineering (CE) Test  >  APSC JE CE Mock Test Series 2026  >  APSC JE CE Paper 2 Mock Test - 9 - Civil Engineering (CE) MCQ

APSC JE CE Paper 2 Mock Test - 9 Free Online Test 2026


Full Mock Test & Solutions: APSC JE CE Paper 2 Mock Test - 9 (100 Questions)

You can boost your Civil Engineering (CE) 2026 exam preparation with this APSC JE CE Paper 2 Mock Test - 9 (available with detailed solutions).. This mock test has been designed with the analysis of important topics, recent trends of the exam, and previous year questions of the last 3-years. All the questions have been designed to mirror the official pattern of Civil Engineering (CE) 2026 exam, helping you build speed, accuracy as per the actual exam.

Mock Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 120 minutes
  • - Total Questions: 100
  • - Analysis: Detailed Solutions & Performance Insights

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APSC JE CE Paper 2 Mock Test - 9 - Question 1
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If the fineness modulus of sand is 2.7, it is geared as,

Detailed Solution: Question 1

If the fineness modulus of sand is 2.7, it is geared as medium sand.

Hence the correct answer is option C.

APSC JE CE Paper 2 Mock Test - 9 - Question 2
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For unstiffened webs of girders, the thickness of the web shall not be less than

Detailed Solution: Question 2

For unstiffened webs of girders, the thickness of the web shall not be less than D1/85.

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APSC JE CE Paper 2 Mock Test - 9 - Question 3
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The commonly used lime in whitewashing is:

Detailed Solution: Question 3

Fat lime is suitable for whitewashing and plastering.

Fat lime is also known as high calcium lime or pure lime or rich lime or white lime. It is popularly known as fat lime as it slakes vigorously, and its volume is increased to about 2 to 2.5 times that of quick lime. This lime is used for various purposes as whitewashing, plastering of walls, as lime mortar with sand for pointing in masonry work, as a lime mortar with turki for thick masonry walls, foundations, etc.

APSC JE CE Paper 2 Mock Test - 9 - Question 4
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An open-ended thin cylindrical shall subject to uniform internal pressure will be subjected to -

Detailed Solution: Question 4

An open-ended thin cylindrical shall, subject to uniform internal pressure, will be subjected to both hoop stress and longitudinal strain.

APSC JE CE Paper 2 Mock Test - 9 - Question 5
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The slenderness limit for simply supported or continuous beam to ensure lateral stability is:

Detailed Solution: Question 5

As per IS 456:2000, clause 23.3, A simply supported or continuous beam shall be so proportioned that the clear distance between the lateral restraints does not exceed 60b or 250b2/d whichever is less, where d is the effective depth of the beam and b is the breadth of the compression face midway between the lateral restraints.

APSC JE CE Paper 2 Mock Test - 9 - Question 6
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If a uniform bar is supported at one end in a vertical direction and loaded at the bottom end by a load equal to the weight of the bar, the strain by a load equal to the weight of the bar, the strain energy as compared to that due to self-weight will be-

Detailed Solution: Question 6

Strain energy (U)(=½(WΔ))

Now, axil deformation due to load W is given by (Δ1=WL/AE)axial deformation due to self-weight W is given by (Δ2=WL/2AE)

(NowΔ1=2Δ2)(and U∞Δ)

Hence strain energy due to load W is given by (U1=(1/2)WΔ1)

(U1=2U2)

Hence strain energy as compared to that due to self-weight will be double.

Hence the option C is correct.

APSC JE CE Paper 2 Mock Test - 9 - Question 7
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If the maximum bending moment of a simply supported slab is M kg-cm, the effective depth of the slab is-

Detailed Solution: Question 7

The effective depth of the slab

(=√M/100Q)

Hence the option D is correct.

APSC JE CE Paper 2 Mock Test - 9 - Question 8
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The length of the straight portion of a bar beyond the end of the hook should be at least-

Detailed Solution: Question 8

The length of the straight portion of a bar beyond the end of the hook curve should be at least four times the diameter.

Hence the option C is correct.

APSC JE CE Paper 2 Mock Test - 9 - Question 9
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Effective length of the fillet weld of length L and size S is given by -

Detailed Solution: Question 9

Effective length of the fillet weld of length L and size S is given by L – 2s.

Hence, the correct option is (b).

APSC JE CE Paper 2 Mock Test - 9 - Question 10
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The line drawn through the points of the same declination is called-

Detailed Solution: Question 10

Iso = equal, Gonic = declination, thus isogonic lines represent lines obtained from joining points of equal declination.

Hence the correct answer is option C.

APSC JE CE Paper 2 Mock Test - 9 - Question 11
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Thermal pollution can be controlled by

Detailed Solution: Question 11

Water from condensers is stored in ponds where natural evaporation cools the water, which can be recirculated or discharged in the nearby water body.

Hence the correct answer is option D.

APSC JE CE Paper 2 Mock Test - 9 - Question 12
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The ozonation in drinking water helps to remove

Detailed Solution: Question 12

Because of its excellent disinfection and oxidation qualities, ozone is widely used for drinking water treatment. Ozone can be added at several points throughout the treatment system, such as during pre-oxidation, intermediate oxidation, or final disinfection. Usually, it is recommended to use ozone for pre-oxidation before a sand filter or an active carbon filter (GAC). After ozonization, these filters can remove the remaining organic matter (important for final disinfection).

Hence the correct answer is option D.

APSC JE CE Paper 2 Mock Test - 9 - Question 13
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To estimate the 28-day crushing strength of concrete cubes from 7-day cube strength, we multiply the 7-day cube strength by

Detailed Solution: Question 13

To estimate the 28-day crushing strength of concrete cubes from 7-day cube strength, we multiply the 7-day cube strength by 1.5.

Hence the correct answer is option C.

APSC JE CE Paper 2 Mock Test - 9 - Question 14
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Low workability of concrete conforms to a slump of

Detailed Solution: Question 14

Low workability of concrete conforms to a slump of 25-75 mm.

Hence the correct answer is option A.

APSC JE CE Paper 2 Mock Test - 9 - Question 15
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The process by which a mass of saturated soil is caused by external forces to suddenly lose its shear strength and to behave as fluid is called-

Detailed Solution: Question 15

The phenomenon when the sand losses its shear strength due to oscillatory motion is known as liquefaction of sand—the structure resting on such soil sink.

APSC JE CE Paper 2 Mock Test - 9 - Question 16
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For completion of a project, the critical path of a network represents-

Detailed Solution: Question 16

In project management, a critical path is the sequence of project network activities that add up to the longest overall duration, regardless if that longest duration has float or not. This determines the shortest time possible to complete the project.

APSC JE CE Paper 2 Mock Test - 9 - Question 17
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For an irrigational flow, the velocity potential lines, and the streamlines are always-

Detailed Solution: Question 17

For an irrigational flow, the velocity potential lines and the streamlines are always orthogonal to each other.

APSC JE CE Paper 2 Mock Test - 9 - Question 18
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To avoid segregation, fresh concrete should be dropped from a height of-

Detailed Solution: Question 18

To avoid segregation, fresh concrete should be dropped from a height of Less than one meter.

APSC JE CE Paper 2 Mock Test - 9 - Question 19
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Knots in timber are-

Detailed Solution: Question 19

Knots are imperfections from branches that cause living wood grain to grow around them. These imperfections are just part of what makes wood a beautiful material with which to work but can also contribute to possible defects in structural strength for construction lumber.

APSC JE CE Paper 2 Mock Test - 9 - Question 20
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The enlarged head of the supporting column of a flat slab is called-

Detailed Solution: Question 20

Drop panels are rectangular, just supported above the Capital. Capital is the enlarged shape to support the drop panel.

APSC JE CE Paper 2 Mock Test - 9 - Question 21
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The bubble rube parallel to the telescope of a theodolite should be more sensitive since it controls :

APSC JE CE Paper 2 Mock Test - 9 - Question 22
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With storage, the strength of cement:

Detailed Solution: Question 22

  • Due to the hygroscopic nature of cement, it easily absorbs moisture from the atmosphere

  • This moisture or dampness is the main hazard for cement which makes it hard like stone and it converts it to a useless material not suitable for construction.

  • Storage of cement requires more care as strength of cement decreases with time

  • Storage of cement should be done in such a manner that it is not exposed to the atmosphere which can be done by packing in airtight bags.

Hence, the correct option is (B)

APSC JE CE Paper 2 Mock Test - 9 - Question 23
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Pick up the erroneous statement:

Detailed Solution: Question 23

Flemish bond is slightly economical as a number of bats can be used. This renders the use of possible broken bricks but requires more mortar for additional joints.

Hence, the correct option is (B)

APSC JE CE Paper 2 Mock Test - 9 - Question 24
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Which of the following chemical compounds can be used for de-chlorination of water?

Detailed Solution: Question 24

De-chlorination is the process of removing chlorine from water (e.g., disinfected wastewater) before discharging the water into the environment. De-chlorination is performed because chlorine can form deposits on the internal edges of industrial equipment, cause health issues (e.g., choking) or lead to corrosion.

De-chlorination can be achieved with sulphur dioxide, sodium bisulphite (NaHSO3) or sodium metabisulphite (Na2S2O5).

Hence, the correct option is (D)

APSC JE CE Paper 2 Mock Test - 9 - Question 25
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Surkhi is added to lime mortar to-

Detailed Solution: Question 25

Surkhi is added to lime mortar to Prevent shrinkage.

As Surkhi is an alternate of sand with some additional properties of strength and hydraulicity.

Hence, the correct option is (A)

APSC JE CE Paper 2 Mock Test - 9 - Question 26
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The moisture content of clayey soil is gradually reduced from a large value. The correct sequence of the occurrence of the limit is -

APSC JE CE Paper 2 Mock Test - 9 - Question 27
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Which one of the following is correct for impulse turbines?

Detailed Solution: Question 27

In the Impulse Turbine, the available hydraulic energy is first converted into kinetic energy by means of an efficient nozzle.

The high-velocity jet issuing from the nozzle then strikes a series of suitably shaped buckets fixed around the rim of a wheel.

The buckets change the direction of the jet without changing its pressure. The resulting change in momentum sets buckets and wheel into rotary motion and thus mechanical energy is made available at the turbine shaft.

Important impulse turbines are: Pelton wheel, Turgo - impulse wheel, Girad turbine, Banki turbine and Jonval turbine, etc., Pelton wheel is predominantly used at present.

Whereas In Reaction Turbine, a part of the total available hydraulic energy is transformed into kinetic energy before the water is taken to the turbine runner. A substantial part remains in the form of pressure energy.

APSC JE CE Paper 2 Mock Test - 9 - Question 28
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Compaction factor is defined as the ratio of:

Detailed Solution: Question 28

Compaction factor test is used to determine the workability of the fresh concrete mix. It is defined as the ratio of the weight of partially compacted concrete to fully compacted concrete.

For compaction factor = 0.65 – 0.7, the degree of workability is very low.

For compaction factor = 0.95 – 1, the degree of workability will be very high

APSC JE CE Paper 2 Mock Test - 9 - Question 29
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If W is the load in a circular slab of radius R, the maximum radial moment at the center of the slab is

Detailed Solution: Question 29

Radial moment at the centre of the Circular slab is

Where MR = Radial moment

R = radius of slab

μ = Poisson’s ratio

r = any section at a distance r from centre of the slab

W = load on circular slab

For the maximum radial moment at centre

r = 0 and μ = 0

Therefore,

APSC JE CE Paper 2 Mock Test - 9 - Question 30
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If Poisson’s ratio for material is 0.5, then the elastic modulus for the material is

Detailed Solution: Question 30

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About this Civil Engineering (CE) Mock Test

This mock test contains 100 questions designed to replicate the pattern, difficulty level and time pressure of the actual Civil Engineering (CE) exam. It is part of APSC JE CE Mock Test Series 2026 on EduRev, covering all the topics that are being asked as per the current Civil Engineering (CE) syllabus. Attempting this test under timed conditions will help you assess your exam readiness, identify subject-wise weak areas, and improve your speed and accuracy before the actual exam.

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