AWES TGT Physics Mock Test - 1 - AWES TGT/PGT MCQ

The Indian Institute of Technology (IIT Kanpur) Kanpur signed an MoU with Conlis Global for licensing an innovative bone healing technology based on Nano Hydroxyapatite-based Porous Composite Scaffolds. This collaboration aims to promote bone healing and regeneration in orthopaedic and dental applications, among others.

Russia's nuclear energy corporation Rosatom has set a record by installing a research reactor pressure vessel in Mountain Meteor at an altitude of about 4,000 meters above sea level in El Alto, Bolivia.

The correct answer is Akbar.

Key Points

•  Akbar(1556-1605):
  • Akbar was born on 15th October 1542. His full name was Abu'l-Fath Jalal ud-din Muhammad Akbar.
  • Akbar succeeded his father Humayun at the age of thirteen on 14th February 1556 as the third Mughal Emperor of India.
  • Akbar made major reforms in the war techniques especially in the use of firearms.
  • He reigned from 1556 to 1605 and extended Mughal power over most of the Indian subcontinent.
  • To preserve the unity of his empire, Akbar adopted programs that won the loyalty of the non-Muslim populations of his realm.

Additional Information

• Jahangir:
  • The fourth Mughal ruler, Jahangir, was succeeded by the famous Akbar the Great.
  • Jahangir was known for his ambivalent stance on religion and his love for art.
  • Like most Mughal rulers, Jahangir has given India a few of the most iconic structures that have lasted the centuries without losing their glory.
• Shahjahan:
  • Shah Jahan was an able military commander.
  • While still a prince, he was able to obtain the submission of the Rajput state of Mewar which Akbar had not been able to defeat.
  • Mewar then became a vassal of the Mughal Empire.
  • On becoming the emperor, Shah Jahan executed many of his former rivals including his own brother Shahryar, imprisoned many more, and consolidated his power.
  • The Mughal rules of succession do not follow primogeniture, i.e., the eldest son succeeding the father; there is always a fight for power by brothers in the Mughal courts upon the death of a ruler.
• Babur:
  • Babur was the founder of the Mughal empire in the Indian subcontinent
  • He ruled the Mughal dynasty from 1526 to 1530.
  • Babur came to India from Ferghana.
  • Babur succeeded to the throne of Ferghana in 1494 when he was only 12 years old.
  • He was forced to leave his ancestral throne due to the invasion of the Uzbeks(Mongol group).
  • He was a descendant of Timur from his father's side and a descendant of Chengiz Khan from his mother's side.
  • He defeated Ibrahim Lodi at Panipat and captured Delhi and Agra in 1526.
  • He defeated Rana Sanga of Mewar at Khanwa in 1527
  • He defeated the Rajputs at Chanderi in 1528.
  • Baburnama or Tuzuk-e-Baburi is the autobiography of Babur.
  • He died at Agra in 1530.

A gifted child is one whose IQ is above 130. He/she derives many creative ideas, explores many possible solutions for a single problem, thinks in a divergent way. always have a curiosity to know about new things, always brings something unusual and entertaining beyond the level of thinking at the same age children. All these qualities are found in gifted children. 
Hence, the correct answer is, 'Fighting with others.'

Socialisation of a child can be measured by social welfare method. 

Dyslexia is a type of learning disorder that involves difficulty in reading or recalling a sequence of letters in words (decoding) due to problems like speech sounds. It has an impact on areas of the brain that process language. It is also known as a reading disability.
Hence, this is the correct answer.

The magnetic field from the centre of wire of radius R is given by
B = ((μ₀I)/(2R²))r (r < R) ⇒ B ∝ r
and B = μ₀I/2πr (r > R) ⇒ B ∝ 1/r
From this descriptions, we can say that the graph (b) is a correct representation.

Microwaves are electromagnetic waves with wavelengths longer than those of terahertz (THz) wavelengths, but relatively short for radio waves. Microwaves have wavelengths approximately in the range of about one meter to one millimeter; with frequencies between 300 MHz (1 m) and 300 GHz (1 mm).

If the axes are parallel, we use the formula:
Io = Icm + md²
For the first body the distance between the axis and the axis passing through C.O.M is 0 
Therefore, Io = Icm + m(0)² = lcm since it is mentioned in question
Whereas for the second body it is not passing through the C.O.M therefore, there is some distance between the axes, say 'd'
So, Io = Icm + md²

Q-factor: In LCR Circuit, the ratio of resonance frequency to the difference of its neighbouring frequencies so that their corresponding current is 1/√2​ times of the peak value, is called Q-factor of the circuit.
Formula: Q=(1/R)​ √(L/C)​​
So, Q ∝1/R
Conditions for the large value of Q factor:
(i) Value of CL​ should be large.
(ii) Value of R should be less.
 

In stationary position, spring balance reading  => mg = 49

Concept:

1. Momentum: momentum is the product of the mass and velocity of an object. It is a vector quantity, possessing a magnitude and a direction.
2. The unit of momentum (P) is kg m/s.
3. Dimension: [MLT-1]
4. Law of conservation of Momentum: A conservation law stating that the total linear momentum of a closed system remains constant through time, regardless of other possible changes within the system.
5. P₁ = P₂
6. m₁ v₁ = m₂ v₂
7. Where, P₁ = initial momentum of system, P₂ = final momentum of system, m₁ = mass of first object, v₁ = velocity of first object, m₂ = mass of second object and v₂ = velocity of second object.

Calculation:
Given:  m₁ = m kg,  m₂ = m kg,  u₁ = v m/s,  u₂ ​=  -v m/s

Let the common velocity of the combined body be V m/s

Mass of combined body      M = m + m = 2m

Applying conservation of momentum:          

m₁ v₁ + m₂ v₂ = M V

mv + (-mv) = 2mV

0 = 2mV

V = 0 m/s
Hence the correct answer will be zero (0) m/s.

As the two identical coaxial circular loops carry a current i each circulating in the same direction, their flux add each other. When the two are brought closer, the total flux linkage increases. By Lenz's law a current will be induced in both the loops such that it opposes this change in flux. As the flux increases, the current in each loop will decrease so as to decrease the increasing flux.

In the direction of electric field the electric potential decreases. This is because electric potential is the work done against the direction of the electric field.

Let’s keep this simple and to the point. We know that:
1.in a series circuit the same current flows through each component
2.the voltage across an ideal inductor L is 90˚ ahead of an AC current through it
3.the voltage across an ideal capacitor C is 90˚ behind an AC current through it
So putting these facts together we can conclude that given an AC series current the voltages across any L and C must have a phase difference of 180˚

According to Gauss’s Law, the electric field outside a closed surface will be only because of the total charge enclosed inside the surface. In this case, there are two positive and negative charges of the same magnitude inside the surface. Therefore the net charge inside the surface is zero. Therefore, the electric field outside the surface will also be zero. There will be no effect of the second charge q₂

We know that the electric field and area both are vector quantity and the electric flux is expressed as E.s (taking dot product). But if the angle between the two vectors is θ then the formula becomes E^-.s^-.cosθ. Cosθ will be maximum if theta is zero, in all other cases, the value of Cosθ is less than 1. Therefore flux will be the maximum if the angle is 0 degrees.

peak value E_m=2E₀/π
so 2/π value is 0.637
therefore,
E_m=-0.637 E₀

'u' should be the least distance of distinct vision.
U=-25cm
V=-50
(1/f)=(1/v)-(1/u)
=(-1/50) + (1/25)
=1/50
F=50cm
Hence a convex lens of focal length 50cm should be used.
 

Since the charges are unlike, the force will be attractive. Thus the force directs from 1C to -4C.

Magnification in microscope is  m=− lD/f₀​​f_e
where, l is length of tube and D is least distance for clear vision
f_0​ is focal length of objective
fe​ is the focal length of the eyepiece.
So, as l increases m increases.
Hence, the magnifying power of a microscope increases with increase in tube length.
 

There is a condition of weightlessness in a satellite.
Therefore, mg=0
Due to electrostatic force of repulsion between the balls, the string would become horizontal.
Therefore, angle between the string =180
 

Power = energy / time.
energy = power × time.
energy = watt × hour
= 1watt × 1hour
= 1 × (60×60)
= 3600
= 3.6 × 10³ joule

Quantities with different dimensions cant be added or subtracted. Also the dimension of the product of the quantities in power is always one. But when two quantities are multiplied the dimension of the product is the product of the dimensions of the initial quantities.

Rate of change of area with remain same even if wire is replaced by semi-circular wire, 
∴ induced current will be same as earlier one as I = (e/R) & e i.e. induced emf is function of area because
e = – N (dɸ/dt) = – N (d/dt) (ABcoswt).
 

The resolving power of a telescope is given by RP∝2μsinθ​/122λ
Further, sinθ ∝ tanθ ∝ diameter of the objective.
So, the resolving power of a telescope depends on the diameter of the objective lens.