Alphanumeric Series MCQ - 2 - Bank Exams MCQ

The given number satisfies rule (iv)Analysis:
- The first digit is odd and the last digit is even, so we interchange the codes for both digits.
- The third digit is followed by an even number and is preceded by an odd number, so we skip its code.
- The middle digit is odd, so we interchange the codes of the middle digit and the last number.
Calculation:
- The given number is 3809125.
- Following the rules:
- 3rd digit (odd) is followed by an even number, so we skip its code.
- 9 (middle digit) is odd, so we interchange its code with the last digit.
- After interchanging, the number becomes 3809125 → 3809152.
Conclusion:
- The correct combination representing the group of digits is ©*A#@KF.

Rules Recap:

• If the first digit is odd and the last digit is even, then interchange the codes for both digits.
  • In this case, the first digit (1) is odd, and the last digit (7) is odd, so this rule does not apply.
• If a digit is repeated, code it as the code for 5.
  • Here, 2 is repeated in the number. Therefore, both occurrences of 2 will be replaced with the code of 5, which is #.
• If the third digit is followed by an even number and preceded by an odd number, skip its code.
  • The third digit is 6, which is even. It is preceded by 2 (even) and followed by 8 (even), so this rule does not apply.
• If the middle digit is odd, interchange the codes of the middle digit and the last digit.
  • The middle digit 8 is even, so this rule does not apply.
• 0 is neither odd nor even.
  • This rule is general information and does not apply directly here.

Step-by-Step Conversion:

• 1 → @ (from the table).
• 2 → # (replaced with the code for 5, as per Rule 2).
• 6 → B (from the table).
• **8 → *** (from the table).
• 2 → # (replaced with the code for 5, as per Rule 2).
• 4 → O (from the table).
• 7 → F (from the table).

The task is to determine the correct code for the number 1026854 using a set of specific rules. Below is a detailed breakdown of how each rule applies to the number.
Initial Analysis: The given number is 1026854.
Rule Application:

• Rule (i): The first digit is 1 (odd) and the last digit is 4 (even). According to the rule, we interchange the codes for these two digits. Therefore, the code 'OAKBF#@' becomes 'AOKBF#@'.
• Rule (ii): Identify any repeated digits. In this number, the digit 5 does not repeat. Therefore, this rule does not alter any code for this specific scenario.
• Rule (iii): The third digit 2 is followed by 6 (an even number) and preceded by 0 (which is neither odd nor even). The rule to skip its code doesn't apply here because the correct context requires an odd digit preceding it and an even digit following it, which is not fulfilled.
• Rule (iv): The middle digit here is 6, which is even. Since the rule pertains to odd middle digits, no interchange of codes is necessary for the middle and last digits
• Ensure to carefully apply each rule to every digit, considering any special conditions or exceptions that might affect the final outcome.

Final Code Formation: After applying the relevant rules, the code for the number 1026854 is 'AOKB*#@'.

• Conclusion: The correct code according to the rules is 'AOKB*#@', aligning with the correct choice.
• The number is 1026854.
• First digit is 1 (odd) and last is 4 (even), so interchange codes for 1 and 4: OA becomes AO.
• The digit 5 is repeated, so code 5 as code for 5: *.
• Third digit 2 is followed by 6 (even) and preceded by 0 (neither), so skip its code.
• Middle digit 6 (even), no code interchange needed.
• Final code is AO*B#@.
• Option D: OAKB*#@ is correct after considering rules.

The given number satisfies rule (iii)
- Applying the given rules to the number 4302718:
1. The first digit (4) is even and the last digit (8) is even. So, no interchange needed.
2. The digit 7 is getting repeated. So, code it as the code of 5.
3. The third digit (0) is followed by an even number (2) and preceded by an odd number (7). So, skip its code.
4. The middle digit (0) is even. So, interchange the codes of the middle digit and the last number.
5. After applying all the rules, the number becomes: 5©2710
- Matching the modified number with the given options:
- Option A: O©AF@* (Does not match)
- Option B: OAKF@* (Does not match)
- Option C: O©KF@* (Matches)
- Option D: O©AKF@* (Does not match)
- Option E: None of these
Therefore, the correct answer is option C: O©KF@*.

(i) If the first digit is odd and last is even, then interchange the codes for both digits (ii) If there is a digit which is getting repeated in the given number, then code that digit as the code of 5 (iii) If the third digit is followed by an even number and is preceded by an odd number, then skip its code. (iv) If the middle digit is odd then interchange the codes of middle digit and last number. (v) 0 is neither odd nor even

Identify the Pattern: The number given is 8430170. We will apply the provided rules to determine the coded value.

Rule Analysis:

• First, check for any repeated digits. In 8430170, the digit '0' repeats. Therefore, both instances of '0' will be coded as the code for '5', which is '@'.
• Verify if the first digit is odd and the last is even. '8' is even, and '0' is neither odd nor even, so this rule doesn't apply.
• Inspect the position of the third digit, '3'. It is followed by '0' (even) and preceded by '4' (even), so rule (iii) does not apply.
• Examine the middle digit, '0'. Since '0' is neither odd nor even, this rule does not apply. 

Apply Coding: Based on the table:

• '8' is coded as '*'.
• '4' is coded as 'O'.
• '3' is coded as '©'.
• '0' (repeated) is coded as '@'.
• '1' is coded as 'F'.
• The second '0', also coded as '@'.
• '7' is coded as 'H' 
• Final Code: Assemble the result as *O©#@F#.
• The Correct Answer: The final sequence matches the correct coding, confirming it as option B.

1. Remove all the numbers from the arrangement: The original arrangement is: B 6 U & R 1 P 5 # F D @ I 2 Q 8 © K M % W 3 E A 4 * H 9 T .
Removing all the numbers (6, 1, 5, 2, 8, 3, 4, 9): B U & R P # F D @ I Q © K M % W E A * H T.
2. Determine the 20th letter from the right end: To find the 20th letter from the right end, we start counting from the rightmost character (T). The sequence is:  
T (1), H (2), * (3), A (4), E (5), W (6), % (7), M (8), K (9), © (10), Q (11), I (12), @ (13), D (14), F (15), # (16), P (17), R (18), & (19), U (20).
So, the 20th letter from the right end is U.
3. Determine the 6th letter to the right of U: Starting from U and moving right: 
U (start), & (1), R (2), P (3), # (4), F (5), D (6).
Therefore, the 6th letter to the right of the 20th letter from the right end (after removing the numbers) is: D
So, the correct option is C. D.

Analyzing Each Number:

Number 6

• Preceded by: B (Letter)
• Followed by: U (Letter)
• Not a match

Number 1

• Preceded by: R (Letter)
• Followed by: P (Letter)
• Not a match

Number 5

• Preceded by: P (Letter)
• Followed by: # (Symbol)
• Not a match

Number 2

• Preceded by: @ (Symbol)
• Followed by: Q (Letter)
• Match

Number 8

• Preceded by: Q (Letter)
• Followed by: © (Symbol)
• Not a match

Number 3

• Preceded by: W (Letter)
• Followed by: E (Letter)
• Not a match

Number 4

• Preceded by: A (Letter)
• Followed by: * (Symbol)
• Not a match

Number 9

• Preceded by: * (Symbol)
• Followed by: T (Letter)
• Match

Conclusion:
The numbers that are immediately preceded by a symbol and immediately followed by a letter are 2 and 9.
So, the number of such numbers is: Two

B 6 U & R 1 P 5 # F D @ I 2 Q 8 © K M % W 3 E A 4 * H 9 T

P, Q and T

• Each group consists of a sequence of three elements found consecutively in the given arrangement.
• Options A, B, C, and E are sequences with consecutive characters or symbols.
• Option D: "6&U" is not a consecutive sequence in the given arrangement.
• In the sequence, after "6" is "&", but "U" is not next; instead, "R" follows "&".
• Thus, "6&U" does not belong to the group.

Y 7 %, S 2 @ 

The series become:
B L 4 G A 8 P X Y 7 N S 2 D M 9 5 C F 6

4 + 9 + 5 = 18

B L $ # G A P X Y % β N S 2 @ M = 9 5 C F

- To find the vowels immediately preceded by a number and followed by a consonant, examine the arrangement: B L $ 4 # G A 8 P X Y 7 % β N * S 2 @ D M = 9 * 5 C F 6.
- Identify vowels in the sequence: A.
- Check the conditions for A:
- A is preceded by G (not a number) and followed by 8 (not a consonant).
- No other vowels are present in the sequence.
- Therefore, there are no vowels that meet the criteria.
- Correct answer: C (None).

A δ 6 and Z @ 2

δ 6 K, @ 2 L

• Identify the given pattern in the arrangement: K9X, δ6M, SAK, and the missing sequence.
• Each segment consists of 3 characters.
• Observe the consistent spacing between segments: K9X (9th, 10th, 11th), δ6M (13th, 14th, 15th), SAK (16th, 17th, 18th).
• The pattern skips one character between segments.
• After SAK, the next segment skips character '$' and should start at the 19th character: 4%δ. 

- Therefore, the answer is D: 4%δ.

The series becomes:
E * L J # R % S A δ K M $ X β B Z @ L

• The sequence is E 3 * L J 8 # R 1 4 % S A δ 6 K 9 M $ X 7 β B Z @ 2 L.
• Each group is a set of three consecutive characters from this sequence.
• Groups A, B, C, and E maintain a pattern of symbol, letter, number or letter, letter, symbol.
• Group D (M9$) breaks this pattern as it consists of letter, number, symbol.
• Thus, option D (M9$) is the outlier. 

• We need to find consonants immediately preceded by a consonant and followed by a symbol.
• The key is to identify patterns of consonant-consonant-symbol in the sequence.
• Let's examine the sequence: P 7 @ I R W 3 9 T E $ 4 H D 5 © M A 2 % B * 8 ! U Q N 1 F 6 # K V.
• Check each consonant if it's preceded by another consonant and followed by a symbol.
• No consonant fits this pattern in the given sequence.
• Therefore, the answer is A: None. 

• First, remove all symbols from the given sequence: P 7 I R W 3 9 T E 4 H D 5 M A 2 B 8 U Q N 1 F 6 K V.
• Now, count the characters from the left to find the 15th character.
• The sequence without symbols is: P, 7, I, R, W, 3, 9, T, E, 4, H, D, 5, M, A, 2, B, 8, U, Q, N, 1, F, 6, K, V.
• The 15th character from the left is 'A'.
• Thus, the correct answer is A. 

• Identify numbers in the sequence: 7, 3, 9, 4, 5, 2, 8, 1, 6.
• Check if each number is preceded by a symbol and followed by a consonant:
  • 7: Preceded by 'P' (not a symbol).
  • 3: Preceded by 'W' (not a symbol).
  • 9: Preceded by '3' (not a symbol).
  • 4: Preceded by '$' (symbol), followed by 'H' (consonant).
  • 5: Preceded by 'D' (not a symbol).
  • 2: Preceded by 'A' (not a symbol).
  • 8: Preceded by '*' (symbol), followed by '!' (not a consonant).
  • 1: Preceded by 'N' (not a symbol).
  • 6: Preceded by 'F' (not a symbol)  
• Only '4' meets the criteria, making the correct answer B: One.

• Observe the sequence: Each item in the group follows a pattern of elements with a similar positional relationship.
• B*2: 'B' is two positions before '*', '*' is two positions before '2'.
• QN!: 'Q' is two positions before 'N', 'N' is two positions before '!'.
• 39R: '3' is two positions before '9', '9' is two positions before 'R'.
• 6FK: '6' is two positions before 'F', but 'F' is three positions before 'K'.
• All except 6FK maintain consistent two-position spacing. 

- To determine the 9th to the right of the 22nd from the right end, first identify the 22nd element from the right.
- Count from the right end: V is 1st, K is 2nd, # is 3rd, and so on.
- The 22nd element from the right is 'B'.
- Now find the 9th element to the right of 'B'.
- Counting from 'B', the 9th element is 'B' itself.
- Hence, the correct answer is C: B.