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BEL Trainee Engineer Electronics Mock Test - 3 - Electronics and Communication Engineering (ECE) MCQ


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30 Questions MCQ Test BEL Trainee Engineer Electronics Mock Test Series 2024 - BEL Trainee Engineer Electronics Mock Test - 3

BEL Trainee Engineer Electronics Mock Test - 3 for Electronics and Communication Engineering (ECE) 2024 is part of BEL Trainee Engineer Electronics Mock Test Series 2024 preparation. The BEL Trainee Engineer Electronics Mock Test - 3 questions and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus.The BEL Trainee Engineer Electronics Mock Test - 3 MCQs are made for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for BEL Trainee Engineer Electronics Mock Test - 3 below.
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BEL Trainee Engineer Electronics Mock Test - 3 - Question 1

A series RL circuit has a resistance of 5 kΩ and inductive reactance of 5 kΩ. What is the magnitude and phase angle of the effective impedance?

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 3 - Question 1

Concept:

For a series RLC circuit, the net/effective impedance is given by:

XL = Inductive reactance 

XC = Capacitive reactance

The magnitude of the effective/net impedance is given by:

Also, the phase angle of the effective impedance is given by:

Calculation:

For a series RL circuit, XC = 0 Ω

Given, R = 5 kΩ and XL = 5 kΩ

The magnitude of the net/effective impedance will be:

Putting on the respective values, we get:

Z = 5√2 = 7.07 kΩ

The phase angle of the effective impedance will be:

ϕ = 45° 

BEL Trainee Engineer Electronics Mock Test - 3 - Question 2

Which of the following instrument is used in an airplane to measure its height above the ground?

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 3 - Question 2
  • The radar altimeter measures absolute altitude, i.e. the altitude that the aircraft is above the ground (Above ground level)
  • The radar altimeter system sends out a radio wave, and that radio wave bounces off the ground and is received.
  • AGL is computed by taking the speed of the radio wave and the amount of time for it to return.
  • Unlike radar, the signal is not pulsed, but is Frequency modulated and is transmitted at 4300 MHz at 350 milliwatts.
  • Radar Altimeters operate between - 20 and 2500 feet.

          

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BEL Trainee Engineer Electronics Mock Test - 3 - Question 3

The figure of merit (FOM) of a logic family is given by the product of

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 3 - Question 3

FOM of a logic Family is defined as the product of the propagation delay (tpd) and the power dissipation (PDavg), i.e.

FOM = tpd × PD(avg)

For the best IC operation, FOM should be as small as possible.

Units: ns × mW

= pJ (pico Joule)

Propagation delay (tpd­):

tPHL = delay time in going form High to low logic

tPLH = Delay time in going from low to High logic

Power dissipation (PD):

PD(avg) = Icc × Vcc

VCC = power supply

ICC = avg collector current calculated as the average of the High and low current, i.e.

BEL Trainee Engineer Electronics Mock Test - 3 - Question 4

The solid angle subtended by the sun as viewed from the earth is Ω = 4 × 10-5 steradian. A microwave antenna designed to be used for studying the microwave radiation from the sun has a very narrow beam whose equivalent solid angle is approximately equal to that subtended by the sun. What is the approximate directivity, D?

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 3 - Question 4

Calculation:

The given situation can be visualized as shown:-

The approximate directivity is given by:

BEL Trainee Engineer Electronics Mock Test - 3 - Question 5

The relationship between fT, fβ and hfe in a high frequency model is given by:

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 3 - Question 5

The correct answer is option 4): (fT = fβhfe)

Concept:

In BJT, at the high–frequency end, there are two factors that define the – 3dB cutoff point:

The network capacitance ( parasitic and introduced) and the frequency dependence of hfe (β )

The frequency at which |hfe|dB = 0 dB is indicated by fT.

fT = fβhfe

The hybrid π model for high-frequency analysis is given as

BEL Trainee Engineer Electronics Mock Test - 3 - Question 6

The range of frequency generated by VHF oscillator is -

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 3 - Question 6

Explanation:

Very High Frequency:

It has a range of  30 MHz to 300 MHz and are used in television broadcast.

Some ultra high frequencies are also used in television broadcasting.

Additional Information

The frequency spectrum for the complete range is:


Hence option (3) is the correct answer.

BEL Trainee Engineer Electronics Mock Test - 3 - Question 7

​Calculate the value of Norton's current and Norton's equivalent resistance for the given circuit across the terminal AB.

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 3 - Question 7

Norton's Theorem :

Any linear bilateral network consisting of multiple resistances and sources can be replaced by a resistor Rin parallel of Current source IN .

Calculation:

RN : 

Disable all independent sources and find equivalent resistance.

R= ( 20 || 10 ) + 20 = 26.6 ohm

I:

Short circuited current

Let node voltage of 10 ohm is V

Apply nodal analysis

V = 2.5V

IN = V /20 = 125 mA

BEL Trainee Engineer Electronics Mock Test - 3 - Question 8
Which of the following statements about TCP/IP are incorrect?
Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 3 - Question 8

The correct answer is Data packets sent over TCP/IP are private.

Key Points

  • Transmission Control Protocol (TCP) is a communications standard that enables application programs and computing devices to exchange messages over a network.
  • It is designed to send packets across the internet and ensure the successful delivery of data and messages over networks. 
  • TCP guarantees the integrity of the data being communicated over a network. Before it transmits data, TCP establishes a connection between a source and its destination, which it ensures remains live until communication begins.
    • It then breaks large amounts of data into smaller packets, while ensuring data integrity is in place throughout the process.
  • Data packets sent over TCP/IP are not private, which means they can be seen or intercepted. Hence option 2 is correct.
  • So, it is recommended to avoid using public Wi-Fi networks to send private data and ensure information is encrypted. One way to encrypt data being shared through TCP/IP is through a virtual private network (VPN).
  • TCP/IP communications provide end-to-end error checking of data transmission for reliable and sequential exchange of data, guarantees the sequential delivery of data packets and so it comes with high latency.

Additional Information

  • Error control in TCP is mainly done through the use of three simple techniques: Checksum, Acknowledgement and Retransmission.
    • Every segment contains a checksum field which is used to find corrupted segments. If the segment is corrupted, then that segment is discarded by the destination TCP and is considered lost.
    • In acknowledgement affirm that the data segments have been delivered. Control segments that contain no data but have sequence numbers will be acknowledged as well but ACK segments are not acknowledged.
    • In retransmission, when a segment is missing, delayed in delivering to a receiver or corrupted when it is checked by the receiver then that segment is retransmitted again. 
    • Segments are retransmitted only during two events: when the sender receives three duplicate acknowledgements (ACK) or when a retransmission timer expires.
  •  High-level protocols that need to transmit data like File Transfer Protocol (FTP), Secure Shell (SSH), and Telnet use TCP Protocol.  
BEL Trainee Engineer Electronics Mock Test - 3 - Question 9

A LTI system is described by the difference equation 3y[n] = 2y [n - 2] – 2x[n] + x[n - 1]

The system is

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 3 - Question 9

Since output of system for any value of n is only depends on values of input at n or previous values the system, it is causal system

3y[n] = 2y [n - 2] – 2x[n] + x [n - 1]

Taking z – transform

3y[z] = 2y (z) z - 2 – 2x[z] + x (z) z - 1

It has poles at

Since poles lie in unit circle |zp| < 1 the system is stable

BEL Trainee Engineer Electronics Mock Test - 3 - Question 10
What is an operating system?
Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 3 - Question 10

The Correct Answer is Option (1) i.e A program.

  • An operating system is a software or a program that manages computer hardware, software resources, and provides common services for computer programs.
  • An operating system is an interface between the computer user and computer hardware.
  • The dominant desktop operating system is Microsoft Windows with a market of around 82.74%, followed by macOS by Apple Inc.
  • Some popular operating system include Linux operating system, Windows operating system, VMS, OS/400, macOS, etc.
  • Some of the important functions of an operating system are :
    • Memory Management
    • Processor Management
    • Device Management
    • File Management
    • Security
    • Job Accounting
    • Co-ordination between other software and users.
BEL Trainee Engineer Electronics Mock Test - 3 - Question 11

Transport layer can be

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 3 - Question 11

The transport layer can be either connectionless or connection oriented. A connectionless transport layer treats each segment as an independent packet and delivers it to the transport layer at the destination machine. A connection oriented transport layer makes a connection with the transport layer at the destination machine first before delivering the packets. After all the data are transferred, the connection is terminated.

BEL Trainee Engineer Electronics Mock Test - 3 - Question 12

Power dissipation is negligibly small in:

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 3 - Question 12
  • Complementary Metal-oxide-semiconductor (CMOS) uses complementary & symmetrical pair of P-type & n-type MOSFETS.

        

  • The two important characteristics of CMOS devices are high noise immunity and low power dissipation.
  • CMOS devices dissipate less power than NMOS devices because the CMOS dissipates power only when switching (“dynamic power), whereas N channel MOSFET dissipates power whenever the transistor is on because there is a current path from Vdd to Vss.
  • In a CMOS, only one MOSFET is switched on at a time. Thus, there is no path from voltage source to ground so that a current can flow. Current flows in a MOSFET only during switching.
  • Thus, compared to N-channel MOSFET has the advantage of lower drain current from the power supply, thereby causing less power dissipation.
BEL Trainee Engineer Electronics Mock Test - 3 - Question 13
Consider a test signal m(t) defined by a hyperbolic tangent function m(t) = A tanh(βt), Where A and B are constant. Determine the minimum step side Δ for delta modulation of this signal which is required to avoid slope overload:
Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 3 - Question 13

Concept:

To avoid slope overload, we require

Calculations:

Given,

m(t) = A tanh(βt)

To avoid slope overload

Since,

It follows the maximum value of sec h(βt) is 1, which occurs at time t = 0.

Hence |sec h(βt)|max = 1

∴ 

Δ ≥ Aβ Ts.

Hence option (1) is correct.

BEL Trainee Engineer Electronics Mock Test - 3 - Question 14

The phenomenon of pulse spreading in optical fibre is known as:

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 3 - Question 14

Scattering:

  • Scattering is the loss of signal caused by the diffusion of a light beam, where the diffusion itself is caused by microscopic variations in the transmission medium
  • Scattering typically happens when a light signal hits an impurity in the fibre

Dispersion:

  • Dispersion is defined as pulse spreading in an optical fibre
  • As a pulse of light propagates through a fibre, elements such as numerical aperture, core diameter, refractive index profile, wavelength, and laser linewidth cause the pulse to broaden

Attenuation:

  • The attenuation of an optical fibre measures the amount of light lost between input and output
  • Total attenuation is the sum of all losses
  • For a given fibre, these losses are wavelength-dependent

Inter-symbol Interference:

  • This is the effect of dispersion on optical fibre
  • Intersymbol interference occurs when the pulse spreading caused by dispersion causes the output pulses of a system to overlap

 

BEL Trainee Engineer Electronics Mock Test - 3 - Question 15

The deflecting torque of a moving iron instrument is

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 3 - Question 15

Moving Iron Instruments are the most common type of ammeter and voltmeter used at power frequencies in laboratories.

These instruments are very accurate, cheap, and rugged as compared to other AC instruments.

Working Principle of Moving Iron Instruments:

In Moving Iron Instruments, a plate or van of soft iron or of high permeability steel forms the moving element of the system.

The iron van is so situated that it can move in the magnetic field produced by a stationary coil.

The below figure shows a simple moving iron instrument.

The stationary coil is excited by the current or voltage under measurement.

When the coil is excited, it becomes an electromagnet, and the iron van moves in direction of offering a low reluctance path.

Thus the force of attraction is always produced in a direction to increase the inductance of the coil.

Mind that as the van follows the low reluctance path, the net flux in the air gap will increase which means increased flux linkage of the coil, and hence inductance of coil will increase.

It shall also be noticed that the inductance of the coil is variable and depends on the position of the iron van.

Torque Equation of Moving Iron Instruments:

Deflecting torque in Moving iron Instruments is given as

Td =  (1/2)I2(dL/dƟ)

In moving iron instruments, the controlling torque is provided by spring. Controlling torque due to spring is given as

Tc = KƟ

Where K = Spring constant

Ɵ = Deflection in the needle

In equilibrium state, deflecting and controlling torque shall be equal as below.

Deflecting Torque = Controlling Torque

⇒ Td = Tc

⇒ (1/2)I2(dL/dƟ) = KƟ

 Ɵ = (1/2)(I2/K)(dL/dƟ)

BEL Trainee Engineer Electronics Mock Test - 3 - Question 16

In which modulation technique does the phase of the carrier signal is changed by varying the sine and cosine inputs at a particular time.

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 3 - Question 16

PSK(Phase Shift Keying):

In PSK (phase shift keying), binary 1 is represented with a carrier signal and binary 0 is represented with 180° phase shift of a carrier, i.e. the phase of the carrier signal is changed by varying the sine and cosine inputs at a particular time.

For binary ‘1’ → S1 (A) = Acos 2π fCt

For binary ‘0’ → S2 (t) = A cos (2πfCt + 180°) = - A cos 2π fCt

The Constellation Diagram Representation is as shown:

Important Point

ASK, PSK and FSK are signaling schemes used to transmit binary sequences through free space. In these schemes, bit-by-bit transmission through free space occurs.

FSK (Frequency Shift Keying):

In FSK (Frequency Shift Keying) binary 1 is represented with a high-frequency carrier signal and binary 0 is represented with a low-frequency carrier, i.e. In FSK, the carrier frequency is switched between 2 extremes.

For binary ‘1’ → S1 (A) = Acos 2π fHt

For binary ‘0’ → S2 (t) = A cos 2π fLt . The constellation diagram is as shown:

ASK(Amplitude Shift Keying):

In ASK (Amplitude shift keying) binary ‘1’ is represented with the presence of a carrier and binary ‘0’ is represented with the absence of a carrier:

For binary ‘1’ → S1 (t) = Acos 2π fct

For binary ‘0’ → S2 (t) = 0

The Constellation Diagram Representation is as shown:

 

where ‘I’ is the in-phase Component and ‘Q’ is the Quadrature phase.

BEL Trainee Engineer Electronics Mock Test - 3 - Question 17

Direction: A word in capital letters is followed by four words. Choose the word that is most nearly opposite in meaning to the word given in capital letters.

NEBULOUS

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 3 - Question 17

As we can say that ,
Nebulous is indistinct something that does not have a clear outline, Concrete is solid and of definite shape.
Hence , Concrete is antonym ( opposite ) of Nebulous . 

BEL Trainee Engineer Electronics Mock Test - 3 - Question 18

A line printer
(i) prints an entire line at a time
(ii) is a non-impact printer
(iii) allows multiple copies to be taken at a time
(iv) prints one character at a time 

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 3 - Question 18

The correct answer is option B: i and iii.
Explanation:
- A line printer prints an entire line at a time, which means it prints all the characters in a line simultaneously.
- It allows multiple copies to be taken at a time, which means it can print multiple copies of the same line without having to print each copy separately.
- However, a line printer is an impact printer, not a non-impact printer. Impact printers use a mechanism that physically strikes an inked ribbon against the paper to create an image, whereas non-impact printers use methods like heat or lasers to transfer the image onto the paper.
- Lastly, a line printer does not print one character at a time. It prints an entire line, not individual characters.
To summarize, a line printer prints an entire line at a time and allows multiple copies to be taken at once. Therefore, the correct answer is option B: i and iii.
BEL Trainee Engineer Electronics Mock Test - 3 - Question 19
One gigabyte (GB) is equal to ________ megabytes (MB) (in binary format).
Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 3 - Question 19

The correct answer is 1024.

Key Points

  • One gigabyte in the memory context of data storage comprises 1024 MB (megabyte) or 1 million bytes.
  • In SI units, it is written as 109. This is the most commonly used unit of storage in modern times.

Additional Information

  •  Unit Conversion Table:
    • 4 bit = 1 Nibble
    • 8 bit = 1 byte
    • 1 KB (kilobyte) = 1024 byte
    • 1 MB (megabyte) = 1024 KB
    • 1 GB (gigabyte) = 1024 MB
    • 1 TB (terabyte) = 1024 GB
    • 1 PB (petabyte) = 1024 TB
    • 1 XB (Exabyte) = 1024 PB
    • 1 ZB (zettabyte) = 1024 XB
    • 1 YB (yottabyte) = 1024 ZB
BEL Trainee Engineer Electronics Mock Test - 3 - Question 20

_____ is not a part of CPU.

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 3 - Question 20

The correct answer is ​Program Unit.

  • program unit is a sequence of one or more lines, organized as statements, comments, and directives. A subprogram is either a function or a subroutine and is either an internal, external, or module subprogram.
  • program unit is usually a sequence of statements that define the data environment and the steps necessary to perform calculations; it is terminated by an END statement.

Additional Information 

  • A Fortran program consists of one or more program units.
  • Alternately referred to as a processorcentral processor, or microprocessor, the CPU (pronounced sea-pea-you) is the central processing unit of the computer.
  • A computer's CPU handles all instructions it receives from hardware and software running on the computer. It is often referred to as the brain of the computer.
  • Components of CPU:
    • ALU (arithmetic logic unit) - performs mathematical, logical, and decision operations.
    • CU (control unit) - directs all the processor's operations.
    • Storage Unit.
BEL Trainee Engineer Electronics Mock Test - 3 - Question 21

______ are very effective because a mode switch is not required to switch from one thread to another.

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 3 - Question 21
User-level threads

User-level threads are very effective because a mode switch is not required to switch from one thread to another. Here is a detailed explanation:



  • Definition: User-level threads are managed by the application without the intervention of the operating system. They are created and scheduled by the application itself.

  • Advantages: User-level threads offer several advantages, including:


    • No mode switch: User-level threads do not require a mode switch from user mode to kernel mode when switching between threads. This makes the context switch faster and more efficient.

    • Thread management control: The application has full control over thread management, including scheduling, synchronization, and resource allocation.

    • Portability: User-level threads can be easily ported across different operating systems, as they are independent of the underlying kernel.


  • Disadvantages: User-level threads also have some limitations:


    • Blocking system calls: If a user-level thread performs a blocking system call, it will block the entire process, as the kernel is unaware of the individual threads.

    • Limited parallelism: User-level threads may not fully utilize the available hardware resources, as the operating system schedules threads at the process level rather than at the thread level.



In conclusion, user-level threads are very effective because they eliminate the need for a mode switch and provide greater control over thread management. However, they also have some limitations that need to be considered in certain scenarios.

BEL Trainee Engineer Electronics Mock Test - 3 - Question 22

The word 'Internet' is a composition of:

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 3 - Question 22

Internet:

  1. The Internet (or internet) is the global system of interconnected computer networks that uses the Internet protocol suite (TCP/IP) to communicate between networks and devices.
  2. It is a network of networks that consists of private, public, academic, business, and government networks of local to global scope, linked by a broad array of electronic, wireless, and optical networking technologies.
  3. The Internet carries a vast range of information resources and services, such as the inter-linked hypertext documents and applications of the World Wide Web (WWW), electronic mail, telephony, and file sharing.

Therefore, The word 'Internet' is a composition of Inter-connection and Network.

Confusion Points 

Internet is an interconnected computer network. That's why it is Inter-connection and Network. 

BEL Trainee Engineer Electronics Mock Test - 3 - Question 23

Which is not the requirement of the internet?

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 3 - Question 23
Explanation:
The correct answer is B:

Dos

. DOS (Disk Operating System) is not a requirement of the internet. Here is a detailed explanation of why each of the other options is a requirement:
A: Operating System
- An operating system is required to run the necessary software and manage hardware resources on a computer. It provides the foundation for running internet-related applications and services.
C: Web browser
- A web browser is essential for accessing and viewing websites on the internet. It interprets HTML, CSS, and JavaScript code to display web pages and allows users to navigate through different websites.
D: Modem
- A modem is used to connect a computer or other device to the internet. It converts digital data from the computer into analog signals that can be transmitted over telephone lines or other communication channels. The modem at the receiving end then converts the analog signals back into digital data.
In summary, while an operating system, web browser, and modem are all requirements for accessing and using the internet, DOS is not necessary for internet connectivity.
BEL Trainee Engineer Electronics Mock Test - 3 - Question 24

 Which of the following keyboard shortcuts can be used in MS PowerPoint 365 to open the Transitions tab and add transitions between slides? 

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 3 - Question 24

The correct option is (4) Alt + K

Key Points

  • Add transitions between slides by opening the Transitions tab. tap Alt+K.
  • Choose the slide to which you wish to apply the transition. Choose a transition from the Transitions tab. To get a preview, choose a transition.
  • The keyboard shortcut Alt+R is frequently used to open the Review tab in the Ribbon of Office products.
  • To open the slide show settings in PowerPoint, use Alt+S on the keyboard.

Additional Information

Slide transitions are a great way to liven up your presentation.

  • Choose the slide to which you wish to apply the transition.
  • Choose a transition from the Transitions tab.
  • To determine the kind and direction of the transition, select Effect Options.
  • To get a preview of the transition, select Preview.
BEL Trainee Engineer Electronics Mock Test - 3 - Question 25

Direction: Read the following information carefully and answer the questions that follow.
A blacksmith has five iron articles A, B, C, D and E each having a different weight.
I. A weight is twice as much as of B.
II. B weight is four and half times as much as of C.
III. C weight is half times as much as of D.
IV. D weight is half as much as of E.
V. E weight is less than A but more than C.

Q. Which of the following is the heaviest in weight?

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 3 - Question 25

According to question,
A's weight is twice as much as of B.
1. A = 2B.
B's weight is four and half times as much as of C.
2. B = 4.5C
C's weight is half times as much as of D.
3. C = D/2.
D's weight is half as much as of E.
4. D = E/2.
E weight is less than A but more than C.
5. A > E > C
from 1 and 2
6. A = 2B = 9C
from 6 and 3
7. A = 2B = 9C = 4.5D
from 7 and 4
8. A = 2B = 9C = 4.5D = 2.25E
so from 8 and 5
A > B > E > D > C

So A is the heaviest in the weight.

BEL Trainee Engineer Electronics Mock Test - 3 - Question 26

In a group of students, each one knows either Hindi or English. If 100 know Hindi, 50 know English and 30 know both, how many students are there in group?

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 3 - Question 26

The logic followed is:

Therefore, the number of students in the group are 20 + 30 + 70 = 120

The number of students = 120

Hence, the correct answer is "120".

BEL Trainee Engineer Electronics Mock Test - 3 - Question 27

Pointing to a woman, a man said, "Her father is the only son of my father." How is the man related to the woman?

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 3 - Question 27

Logic: We have to make a family tree as per the above conditions.

Consider the below symbols.

The family tree for the given problem is as follows:

In the question, Her father is the only son of my father means woman's father and the man's father's only son is the same person means he is talking about himself. 

As the man is the father of that woman.

Therefore, the correct answer should be "Option 1: Father".  

BEL Trainee Engineer Electronics Mock Test - 3 - Question 28

If a Paper (Transparent Sheet ) is folded in a manner and a design or pattern is drawn. When unfolded this paper appears as given below in the answer figure. Choose the correct answer figure given below.

A piece of paper is folded and cut as shown below in the question figures. From the given answer figures, indicate how it will appear when opened?

Question Figure

Answer Figure

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 3 - Question 28

BEL Trainee Engineer Electronics Mock Test - 3 - Question 29

In the following question number of triangle are

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 3 - Question 29

 

The main triangle shown is in the given figure and this the total no. of triangle is 15. remaing triangle we can find out in the drawing the triangle in the image.

BEL Trainee Engineer Electronics Mock Test - 3 - Question 30

Direction: Study the following information and answer the given questions carefully.
There are 8 persons, P, Q, R, S, T, U, V and W sitting around a rectangular table in such a way that four of them sit at four corners of the table while four sit in the middle of each of four sides. Persons who sit at the corners face outside the centre while those who sit in the middle of the side face inside.
Q sits second to the right of P. R sits third to the left of W. R faces inside. T sits third to the left of U. V sits second to the left of U. R is not an immediate neighbor of P.
Q. Who among the following sits exactly opposite to U?

Detailed Solution for BEL Trainee Engineer Electronics Mock Test - 3 - Question 30

From the final arrangement, we get S sits exactly opposite to U.
Hence, Option D is correct.
References:
Q sits second to the right of P.
Inferences:
From the above reference, we get two different cases:
In case 1, P sits at the corner or in the middle of the side of the table.

References:
R is not an immediate neighbor of P.
R faces inside.
R sits third to the left of W.
Inferences:
From the above references, we get different cases for R, in case 1(a) in which R faces P and in case 1(b) R faces Q.

References:
T sits third to the left of U.
V sits second to the left of U.
Inferences:
So, from this case 1(b) and case 2 will be eliminated as there is no possible place for V in these cases after placing U and T. Hence, we get our final arrangement in which S sits on the immediate left of P and V sits on the immediate right of R.
Final arrangement:

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