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Bihar PGT Physics Mock Test - 10 - Bihar PGT/TGT/PRT MCQ


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30 Questions MCQ Test Bihar PGT Exam Mock Test Series 2025 - Bihar PGT Physics Mock Test - 10

Bihar PGT Physics Mock Test - 10 for Bihar PGT/TGT/PRT 2025 is part of Bihar PGT Exam Mock Test Series 2025 preparation. The Bihar PGT Physics Mock Test - 10 questions and answers have been prepared according to the Bihar PGT/TGT/PRT exam syllabus.The Bihar PGT Physics Mock Test - 10 MCQs are made for Bihar PGT/TGT/PRT 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Bihar PGT Physics Mock Test - 10 below.
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Bihar PGT Physics Mock Test - 10 - Question 1

Improve the bracketed part of the sentence with the parts given below.

Q. He retired from service (on his own wish).

Detailed Solution for Bihar PGT Physics Mock Test - 10 - Question 1

'Voluntarily' means to do something out of self-will and not under force.
Example- He voluntarily gave up all his possessions and left for a spiritual life.

Bihar PGT Physics Mock Test - 10 - Question 2

'अध्‍यात्मिक रंग के चश्‍में आजकल बहुत सस्‍ते हो गये है।' आचार्य रामचन्द्र शुक्ल ने यह टिप्‍पणी किस कवि के सन्‍दर्भ में की है?

Detailed Solution for Bihar PGT Physics Mock Test - 10 - Question 2

यह टिप्पणी विद्यापति के संदर्भ में आचार्य रामचन्द्र शुक्ल ने अपनी पुस्तक हिंदी साहित्य का इतिहास में लिखी है। विद्यापति हिंदी साहित्य के आदिकाल के कवि हैं। श्रृंगार रस के प्रमुख कवि हैं। मैथिली, संस्कृत, अवहट्ट इनकी रचना हैं I हिन्दी साहित्य में कृष्णगीति परम्परा के प्रवर्तक हैं।

Bihar PGT Physics Mock Test - 10 - Question 3

2019 का साहित्य अकादमी पुरस्कार किस रचनाकर को दिया गया?

Detailed Solution for Bihar PGT Physics Mock Test - 10 - Question 3

2019 का साहित्य अकादमी पुरस्कार ‘नंदकिशोर आचार्य’ को दिया गया था। यह पुरस्कार उनकी रचना ‘छिलते हुए अपने को’ कविता को मिला है।

Bihar PGT Physics Mock Test - 10 - Question 4

‘बहुत दिनों के बाद’ कविता किस युग की कविता है?

Detailed Solution for Bihar PGT Physics Mock Test - 10 - Question 4

एक साहित्यिक आंदोलन के रूप में प्रगतिवाद का समय 1936 ई. से लेकर 1956 ई. तक है। जिसके प्रमुख कवि हैं- केदारनाथ अग्रवाल, नागार्जुन, राम विलास शर्मा, रांगेय राघव, शिव मंगल सिंह 'सुमन', त्रिलोचन आदि। 'बहुत दिनों के बाद' घुमक्कड़ कवि नागार्जुन की देशज प्रकृति और घरेलू संवेदना का एक दुलर्भ साक्ष्य प्रस्तुत करती है। यह प्रगतिवादी कविता है।

Bihar PGT Physics Mock Test - 10 - Question 5

'नाच्यो बहुत गोपाल' किसका उपन्यास है?

Detailed Solution for Bihar PGT Physics Mock Test - 10 - Question 5

'नाच्यो बहुत गोपाल' अमृतलाल नागर का प्रसिद्ध उपन्यास है।

अमृतलाल नागर के उपन्यासों को रामविलास शर्मा ने 'हिंदी के गैर मानक रूपों का पिटारा' कहा है। अमृतलाल नागर प्रेमचंदोत्तर युग के उपन्यासकार हैं।

अमृतलाल नागर के अन्य प्रमुख उपन्यास हैं - सुहाग के नूपुर, अमृत और विष, अग्निगर्भा, खंजन नयन, महाकाल आदि।

Bihar PGT Physics Mock Test - 10 - Question 6

“कहते हुए यों उत्तरा के नेत्र जल से भर गए। 
हिम के कणों से पूर्ण मानो हो गए पंकज नए।। 

इन पंक्तियों में प्रयुक्त छंद का नाम बताइये?

Detailed Solution for Bihar PGT Physics Mock Test - 10 - Question 6

उक्त पँक्तियों में गीतिका छन्द का प्रयोग किया गया है।

प्रत्येक चरण में 14 और12 की यति से 26 मात्राएँ होती हैं 

प्रत्येक चरण के अंत में लघु और गुरु होता है।  

Bihar PGT Physics Mock Test - 10 - Question 7

निम्नलिखित में से कौन विसर्ग संधि है?

Detailed Solution for Bihar PGT Physics Mock Test - 10 - Question 7

निरन्तर में विसर्ग सन्धि का प्रयोग हुआ है।

इसका सन्धि विच्छेद नि: + अंतर है।

Bihar PGT Physics Mock Test - 10 - Question 8
Money Bill is introduced in
Detailed Solution for Bihar PGT Physics Mock Test - 10 - Question 8

The correct answer is Lok Sabha.

Key Points

  • Money Bill:
    • A money bill is defined by Article 110 of the Constitution, as a draft law that contains only provisions that deal with all or any of the matters listed therein.
    • These comprise a set of seven features, broadly including items such as the imposition or regulation of a tax; the regulation of the borrowing of money by the Government of India; the withdrawal of money from the Consolidated Fund of India; and so forth.
    • In the event proposed legislation contains other features, ones that are not merely incidental to the items specifically outlined, such a draft law cannot be classified as a money bill.
    • Article 110 further clarifies that in cases where a dispute arises over whether a bill is a money bill or not, the Lok Sabha Speaker’s decision on the issue shall be considered final.

Additional Information

  • According to Article 110 of the Indian Constitution, a bill is deemed to be a money bill if it contains ‘only’ provisions dealing with all or any of the following matters:
    • The imposition, abolition, remission, alteration, or regulation of any tax.
    • The regulation of the borrowing of money by the Union government.
    • The custody of the Consolidated Fund of India or the contingency fund of India, the payment of amounts of money into or the withdrawal of money from any such fund.
    • The appropriation of money out of the Consolidated Fund of India.
    • Declaration of any expenditure charged on the Consolidated Fund of India or increasing the amount of any such expenditure.
    • The receipt of money on account of the Consolidated Fund of India or the public account of India or the custody or issue of such money, or the audit of the accounts of the Union or of a state.
  • According to Article 109 clause 5 of the Indian Constitution, if a Money Bill passed by the House of the People and transmitted to the Council of States for its recommendations is not returned to the House of the People within the said period of 14 days, it shall be deemed to have been passed by both Houses at the expiration of the said period in the form in which it was passed by the House of the People
Bihar PGT Physics Mock Test - 10 - Question 9
Which of the following is not among the six major controls of the climate in India?
Detailed Solution for Bihar PGT Physics Mock Test - 10 - Question 9

The correct answer is option 4 i.e. Population.

  • Climate refers to the sum total of weather conditions and variations over a large area for a long period of time (more than thirty years).
  • Weather refers to the state of the atmosphere over an area at any point of time.
  • There are six major controls of the climate of any place as explained below: 
  • Latitude
    • Due to the curvature of the earth, the amount of solar energy received varies according to latitude.
    • As a result, air temperature generally decreases from the equator towards the poles.
  • Altitude
    • As one goes from the surface of the earth to higher altitudes, the atmosphere becomes less dense and temperature decreases.
    • The hills are therefore cooler during summers.
  • Pressure and Wind System 
    • The pressure and wind system of any area depend on the latitude and altitude of the place.
    • Thus it influences the temperature and rainfall pattern.
  • Distance from the sea (continentality)
    • The sea exerts a moderating influence on climate: As the distance from the sea increases, its moderating influence decreases and the people experience extreme weather conditions.
    • This condition is known as continentality (i.e. very hot during summers and very cold during winters).
  • Ocean currents
    • Ocean currents along with onshore winds affect the climate of the coastal areas.
    •  For example, any coastal area with warm or cold currents flowing past it, will be warmed or cooled if the winds are onshore. 
  • Relief features 
    • Finally, relief too plays a major role in determining the climate of a place.
    • High mountains act as barriers for cold or hot winds; they may also cause precipitation if they are high enough and lie in the path of rain-bearing winds.
    • The leeward side of mountains remains relatively dry.
Bihar PGT Physics Mock Test - 10 - Question 10

Which of the following organ is not a part of the human excretory system?

Detailed Solution for Bihar PGT Physics Mock Test - 10 - Question 10

The Correct Answer is Option (2) i.e Pancreas.

Key Points

  • In humans, the kidney is one of the main organs of the excretory system.
  • The kidney's function is the filtration of the blood and removing waste(toxic) products.
  • Waste products and excess fluid are removed through the urine.
  • If the kidney fails person needs to undergo dialysis.
  • Dialysis is a treatment that filters and purifies the blood using a machine
  • The human excretory system includes certain organs that eliminate the wastes such as salts, carbon dioxide, urea, uric acid and water produced by the body.
  • The path of the urine in the human excretory system is -
  • After filtering from the kidney → The urine through Ureter → Stored in the Urinary bladder → Exits through the urethra.

Important Points

  • The Pancreas is an organ located in the abdomen. It is not a part of the human excretory system.
  • The Pancreas plays an important role in converting the food we eat into fuel for the body's cell.
  • It helps in the process of digestion. It also regulates blood sugar.
  • The body system that removes metabolic wastes from the body is known as the 'Excretory System'.

Bihar PGT Physics Mock Test - 10 - Question 11
The headquarters of South Asian Association for Regional Co-operation (SAARC) is
Detailed Solution for Bihar PGT Physics Mock Test - 10 - Question 11

The correct answer is Kathmandu (Nepal)

Key Points

  • SAARC is South Asian Association for Regional Cooperation, which is a regional intergovernmental organisation.
  • It was founded on 8 December 1985 in Dhaka.
  • It aims to promote the development of economic and regional integration.
  • It is headquartered in Kathmandu, Nepal.
  • The South Asian Free Trade Area was launched on 1st January 2006 to create a free trade zone between its members.
  • As of March 2020 Esala Ruwan Weerakoon is the Secretary-General. He assumed office on 1st March 2020.

Additional Information

  • Given below is the list of all members of SAARC:
    • Afghanistan
    • Bangladesh
    • Bhutan
    • India
    • Maldives
    • Nepal
    • Pakistan
    • Sri Lanka
Bihar PGT Physics Mock Test - 10 - Question 12

Ravi goes 40 km to North, then turns right and walks 50 km then again turns right and walks 30 km, then again turns right and walks 50 km. Now how many km away is he from his original position ? 

Detailed Solution for Bihar PGT Physics Mock Test - 10 - Question 12

According to the information given in the question, we can draw the following diagram.

AC = 40 km
BC = 30 km
AB = AC - BC
AB = 40 - 30
AB = 10 km
Ravi is 10 km away from his starting point.
Hence, the correct answer is "10 km".

Bihar PGT Physics Mock Test - 10 - Question 13
Which among the following is a fat-soluble vitamin?
Detailed Solution for Bihar PGT Physics Mock Test - 10 - Question 13

The correct answer is Vitamin D.

Key Points

  • Vitamin is an organic non-protein substance that is required by an organism for normal metabolic function but cannot be synthesized in sufficient quantity by that organism.
  • These can be divided into two categories: fat-soluble and water-soluble.

Fat-Soluble vitamins

  • Fat-soluble vitamins are soluble in fats.
  • They are absorbed by fat globules that travel through the small intestines and into the general blood circulation within the body.
  • Unlike water-soluble vitamins, fat-soluble vitamins are stored in the body when they are not in use.
  • Vitamin A, D, and E K are fat-soluble.

Water-soluble vitamins

  • Water-soluble vitamins dissolve in water, which means these vitamins and nutrients dissolve quickly in the body.
  • Unlike fat-soluble vitamins, water-soluble vitamins are carried to the body’s tissues, but the body cannot store them.
  • Any excess amounts of water-soluble vitamins simply pass through the body
  • Vitamin B and Vitamin C are water-soluble.​

Additional Information

Bihar PGT Physics Mock Test - 10 - Question 14

Vectors can be added by

Detailed Solution for Bihar PGT Physics Mock Test - 10 - Question 14

Explanation:Vector addition is the operation of adding two or more vectors together into a vector sum. The so-called parallelogram law gives the rule for vector addition of two or more vectors. For two vectors, the vector sum is obtained by placing them head to tail and drawing the vector from the free tail to the free head.

Bihar PGT Physics Mock Test - 10 - Question 15

A force of 20 N is applied on a body of mass 4 kg kept on a rough surface having coefficient of friction 0.1. Find acceleration of body. Take g = 10 m/s2

Detailed Solution for Bihar PGT Physics Mock Test - 10 - Question 15

 

Bihar PGT Physics Mock Test - 10 - Question 16

What is the main source of energy of the sun?

Detailed Solution for Bihar PGT Physics Mock Test - 10 - Question 16

Like most stars, the sun is made up mostly of hydrogen and helium atoms in a plasma state. The sun generates energy from a process called nuclear fusion. During nuclear fusion, the high pressure and temperature in the sun's core cause nuclei to separate from their electrons.

Bihar PGT Physics Mock Test - 10 - Question 17

The average kinetic energy of a molecule in an ideal gas is

Detailed Solution for Bihar PGT Physics Mock Test - 10 - Question 17

KE = f/2 KT

Bihar PGT Physics Mock Test - 10 - Question 18

The quantity which remains unchanged during the flight of an oblique projectile is

Detailed Solution for Bihar PGT Physics Mock Test - 10 - Question 18

As there is no horizontal acceleration is present in oblique projection horizontal component of velocity is constant

Bihar PGT Physics Mock Test - 10 - Question 19

At any point on an electric field line 

Detailed Solution for Bihar PGT Physics Mock Test - 10 - Question 19

When a tangent is drawn at any point on field line then that tangent gives the direction of electric field at that point

Bihar PGT Physics Mock Test - 10 - Question 20

Consider the situation shown in fig. The resistanceless wire AB is slid on the fixed rails with a constant velocity. If the wire AB is replaced by a resistanceless semicircular wire, the magnitude of the induced current will

Detailed Solution for Bihar PGT Physics Mock Test - 10 - Question 20

Rate of change of area with remain same even if wire is replaced by semi-circular wire, 
∴ induced current will be same as earlier one as I = (e/R) & e i.e. induced emf is function of area because
e = – N (dɸ/dt) = – N (d/dt) (ABcoswt).
 

Bihar PGT Physics Mock Test - 10 - Question 21

A coil of 100 turns is pulled in 0.04 sec. between the poles of a magnet, if its flux changes from 40 x 10-6 Wb per turn to 10-5 Wb per turn, then the average emf induced in the coil is​

Detailed Solution for Bihar PGT Physics Mock Test - 10 - Question 21

Emf = - N(∆magnetic flux)/∆t
N=100turns
∆magnetic flux= -30×10-6Wb
∆t = 0.04sec
Emf = -(100turns)(-30×10-6)/(0.04sec)
Emf = 0.075V
 

Bihar PGT Physics Mock Test - 10 - Question 22

The physical properties of electromagnetic waves are decided by their

Detailed Solution for Bihar PGT Physics Mock Test - 10 - Question 22

Electromagnetic waves vary in wavelength and frequency. Longer wavelength electromagnetic waves have lower frequencies, and shorter wavelength waves have higher frequencies. Higher frequency waves have more energy.

Bihar PGT Physics Mock Test - 10 - Question 23

A short bar magnet placed in a horizontal plane has its axis aligned along the magnetic north-south direction. Null points are found on the axis of the magnet at 14 cm from the centre of the magnet. The earth’s magnetic field at the place is 0.36 G and the angle of dip is zero. What is the total magnetic field on the normal bisector of the magnet at the same distance as the null–point (i.e., 14 cm) from the centre of the magnet? (At null points, field due to a magnet is equal and opposite to the horizontal component of earth’s magnetic field.)

Detailed Solution for Bihar PGT Physics Mock Test - 10 - Question 23

At null point (and along the axis), earth's magnetic field and bar's magnetic field are opposite in direction.
On the equatorial line, the bar's magnetic field is opposite in direction to its field on the axis. Hence, on the equatorial line, the two fields add up.
As the null points are on the axis of the bar magnet, therefore,
B1= (μ0/4π)(2M/d3)=H
On the equatorial line of magnet at same distance(d), field due to the magnet is 
B2= (μ0/4π)(M/d3)=B1/2=H/2
Therefore, total magnetic field at this point on equatorial line is 
B=B2+H=3H/2=3×0.36G/2=0.54G
 

Bihar PGT Physics Mock Test - 10 - Question 24

In a Young’s double-slit experiment, the slits are separated by 0.28 mm and the screen is placed 1.4 m away. The distance between the central bright fringe and the fourth bright fringe is measured to be 1.2 cm. Determine the wavelength of light used in the experiment

Detailed Solution for Bihar PGT Physics Mock Test - 10 - Question 24

Distance between the slits, d=0.28×10−3 m

Distance between the slits and the screen, D=1.4m

Distance between the central fringe and the fourth (n=4) fringe, 

u=1.2×10−2 m

In case of a constructive interference, we have the relation for the distance between the two fringes as:

u=nλD/d

⇒λ=ud/nD=6×10−7m=600nm

Bihar PGT Physics Mock Test - 10 - Question 25

If the light is completely polarized by reflection, then angle between the reflected and refracted light is

Detailed Solution for Bihar PGT Physics Mock Test - 10 - Question 25

The polarization angle (also called Brewster's angle)is defined as the angle of incidence at which light with a particular polarization is perfectly transmitted through a transparent dielectric surface, with no reflection.
Brewster's Law states that the tangent of the angle of polarization is numerically equal to the refractive index of the medium.
μ = tan i ...................... (1)
From Snell's law:
μ = sinr sini​ ....................(2)
Comparing (1) and (2)
cos i = sin r = cos (2π​ - r)
i.e. i = (2π​ - r)
So, i + r = 2π​
So, as seen from the diagram, if i + r = 90o Then the angle between reflected ray and refracted ray will be 180o - 90o = 90o

Bihar PGT Physics Mock Test - 10 - Question 26

A particle of mass m moves in the potential energy U shown in the figure. The particle of the motion, if the total energy of the particle is Eo , is

Detailed Solution for Bihar PGT Physics Mock Test - 10 - Question 26

For x<0
F = −dU/dx = −kx
ma = −kx
or a = −kx/m
−ω21x = −kx/m
ω1 = (√k/m)
T1 = 2π(√m/k)
For x>0 U = mgx
F = −dv/dx = −mg
But E = 1/2mv20
v0 = (√2E/m)
It is speed at lowest point
T2 = 2v0/g
= 2/g(√2E/m)
T = T1/2 + T2
= π(√m/k) + 2/g(√2E/m)

Bihar PGT Physics Mock Test - 10 - Question 27

Light of wavelength 500 nm is incident on a slit of width 0.1 mm. The width of the central bright line on the screen is 2m. What is the distance of the screen?​

Detailed Solution for Bihar PGT Physics Mock Test - 10 - Question 27

Beta(central Maxima) = 2 * lambda * D(distance of the screen) / d(distance between slits)
beta = 2 m, wavelength = 500nm = 5 ×10-7m & d = 0.1mm = 1×10-4m
► 2 = 2 × 5 × 10-7 * D/10-4
► 1 = 5 × 10-3
► D = 1000/5
► D = 200m

Bihar PGT Physics Mock Test - 10 - Question 28

The slope of velocity-time graph for motion with uniform velocity is equal to:

Detailed Solution for Bihar PGT Physics Mock Test - 10 - Question 28

When velocity is uniform, velocity-time graph is straight line parallel to time axis. So, the slope is zero.

Bihar PGT Physics Mock Test - 10 - Question 29

An electric dipole is placed at an angle of 30° with an electric field intensity 2 × 105 N/C. It experiences a torque equal to 4 N m. The charge on the dipole, if the dipole length is 2 cm, is

Detailed Solution for Bihar PGT Physics Mock Test - 10 - Question 29

Torque on a dipole kept in external electric field is given by the expression,

Bihar PGT Physics Mock Test - 10 - Question 30

The mutual inductance has unit of-

Detailed Solution for Bihar PGT Physics Mock Test - 10 - Question 30

The unit of inductance in the SI system is the henry (H), named after American scientist Joseph Henry, which is the amount of inductance which generates a voltage of one volt when the current is changing at a rate of one ampere per second.

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