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Bihar PGT Physics Mock Test - 6 - Bihar PGT/TGT/PRT MCQ


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30 Questions MCQ Test Bihar PGT Exam Mock Test Series 2025 - Bihar PGT Physics Mock Test - 6

Bihar PGT Physics Mock Test - 6 for Bihar PGT/TGT/PRT 2025 is part of Bihar PGT Exam Mock Test Series 2025 preparation. The Bihar PGT Physics Mock Test - 6 questions and answers have been prepared according to the Bihar PGT/TGT/PRT exam syllabus.The Bihar PGT Physics Mock Test - 6 MCQs are made for Bihar PGT/TGT/PRT 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Bihar PGT Physics Mock Test - 6 below.
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Bihar PGT Physics Mock Test - 6 - Question 1

Improve the bracketed part of the sentence with the parts given below.

Q. The police referred to him as (a complete cheat).

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 1

Let's look at the meaning of all the given options.
A prankster is a person fond of playing tricks.
A hooligan is used for someone who is a troublemaker.
A charlatan is a fraud.
Spunk means courage and determination.
Hence, the correct answer is option 3. 

Bihar PGT Physics Mock Test - 6 - Question 2

कालिदास का खण्डकाव्य कौन सा है?

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 2

कालिदास संस्कृत भाषा के महान कवि ओर नाटककार थे। उन्होंने भारत की पौराणिक कथाओं को आधार बनाकर रचनाएं की, जिसमें भारतीय जीवन और दर्शन के विविध रूप और मूल तत्त्व निरूपित हैं। कालिदास अपनी इन्हीं विशेषताओं के कारण राष्ट्र की समग्र राष्ट्रीय चेतना को स्वर देने वाले कवि माने जाते हैं संसृत साहित्य में ही नहीं अपितु समग्र साहित्यिक संसार में उन्हें कविकुलश्रेष्ठ तथा कविशिरोमणि माना जाता है।

प्रस्तुत विकल्पों में से 'मेघदूतम्' यह कालिदास का खण्डकाव्य है।

Bihar PGT Physics Mock Test - 6 - Question 3

'अभिनव जयदेव' के नाम से विभूषित कवि है:-

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 3

"विद्यापति" को "अभिनव जयदेव" की उपाधि दी गई है। कीर्तिलता, कीर्तिपताका से राजा शिवसिंह ने बहुत प्रसत्र होकर विद्यापति को "अभिनव जयदेव" की उपाधि और "विसपी" नामक ग्राम उपहार में दिया।

Bihar PGT Physics Mock Test - 6 - Question 4

कबीर दास जी के गुरु का नाम निम्नलिखित में से है:-

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 4

कबीर दास जी के गुरु का नाम "रामानंद" है। कबीरदास की भाषा को पंचमेल खिचड़ी, सधुक्कडी आदि नाम से अभिहित किया जाता है। कबीर की वाणी का संग्रह उनके शिष्य धर्मदास में बीजक नाम से सन 1464 में किया है।

Bihar PGT Physics Mock Test - 6 - Question 5

पद्मावत में राजा रत्नसेन किसका प्रतीक है-

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 5

मन यहाँ उचित विकल्प है। राजा रत्नसेन मन का प्रतीक है। "पद्गावत" ,"जायसी" की रचना है। मलिक मुहम्मद जायसी (1467-1542) हिन्दी साहित्य के भक्ति काल की निर्गुण प्रेमाश्रयी धारा के कवि थे। उनकी 21 रचनाओं के उल्लेख मिलते हैं।

Bihar PGT Physics Mock Test - 6 - Question 6
Which of the following does not describe Indian Economy?
Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 6

The correct answer is option 1, i.e., Fixed Exchange rate

Key Points

  • Fixed Exchange rate: A fixed exchange rate is a regime applied by a government or central bank ties the country's currency official exchange rate to another country's currency or the price of gold. The purpose of a fixed exchange rate system is to keep a currency's value within a narrow band.

Additional Information

  • Managed exchange rate: Under the managed exchange rate system, the exchange rate is predominantly determined in the foreign exchange market by the supply of and demand for a currency. The government intervenes only occasionally to influence the exchange rate when it considers it to be necessary.
  • Mixed Economy: A mixed economic system is a system that combines aspects of both capitalism and socialism. A mixed economic system protects private property and allows a level of economic freedom in the use of capital, but also allows for governments to interfere in economic activities in order to achieve social aims. According to neoclassical theory, mixed economies are less efficient than pure free markets, but proponents of government interventions argue that the base conditions required for efficiency in free markets, such as equal information and rational market participants, cannot be achieved in practical application. 
Bihar PGT Physics Mock Test - 6 - Question 7
In which part of our body RBC formed?
Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 7

The correct answer is Bone-marrow.

Key Points

Red blood cell:

  • Red blood cells (RBCs) are the most common type of blood cell and the vertebrate's principal means of delivering oxygen to the body tissues via blood flow through the circulatory system.
  • RBC is formed in Bone Marrow.
  • RBCs take up oxygen in the lungs, or in fish the gills, and release it into tissues while squeezing through the body's capillaries.
  • The cytoplasm of erythrocytes is rich in hemoglobin, an iron-containing biomolecule that can bind oxygen and is responsible for the red color of the cells and the blood.
  • Each human red blood cell contains approximately 270 million of these hemoglobin molecules.
  • The cell membrane is composed of proteins and lipids, and this structure provides properties essential for physiological cell function such as deformability and stability while traversing the circulatory system and specifically the capillary network.

Additional Information

  • Red blood cells are thus much more common than the other blood particles: there are about 4,000–11,000 white blood cells and about 150,000 - 400,000 platelets per microliter.
  • Human red blood cells take on average 60 seconds to complete one cycle of circulation.
  • The blood's red color is due to the spectral properties of the hemic iron ions in hemoglobin.
  • Each hemoglobin molecule carries four heme groups; hemoglobin constitutes about a third of the total cell volume.
  • The normal pH range of blood is between 7.35 to 7.45. This means that blood is naturally slightly alkaline or basic.
Bihar PGT Physics Mock Test - 6 - Question 8
The Brahmo Samaj was founded by:
Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 8

The Brahmo Samaj was founded by Raja Rammohan Roy.

Key Points

  • It was founded in Calcutta in 1828 by Ram Mohan Roy as Brahmo Sabha.
  • The Brahmo Samaj was a monotheistic sect of Hinduism
  • The samaj was dedicated to the "worship and adoration of the Eternal, the Unsearchable, the Immutable Being, who is the Author and Preserver of the Universe".
  • The Samaj was open to all without distinction of color, creed, caste, nation, or religion.
  • It denounced polytheism, image worship, and the caste system.
  • It also discarded meaningless Hindu rituals.
  • Raja Rammohun Roy is also called the father of the Indian renaissance.
Bihar PGT Physics Mock Test - 6 - Question 9

Find the wrong term in the given series?

50, 25, 15, 6.25, 3.125

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 9

The pattern followed here is;

15 is the wrong term that doesn't follow the pattern here.

There should be 12.5 in place of 15.

Hence, "15" is the correct answer.

Bihar PGT Physics Mock Test - 6 - Question 10
Article 19 of the Indian Constitution includes which of the following right?
Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 10

The correct answer is the Right to freedom of speech and expression.

  • Article 19 of the Indian Constitution includes the Right to freedom of speech and expression.

Key Points

  • Article 19 deals with the six Fundamental Rights. They are:
    • Right to freedom of speech and expression.
    • Right to assemble peacefully and without arms.
    • Right to form association or unions or co-operatives.
    • Right to move freely throughout the territory of India.
    • Right to reside and settle in any part of the territory of India.
    • Right to practice any profession or to carry on any occupation, trade or business.
  • Fundamental Rights:
    • The Fundamental Rights have been described in Articles 12-35, Part III of the Indian Constitution.
    • The Right to Property (Article 31) was deleted from the list of Fundamental Rights.
      • By the 44th Amendment Act, 1978, it is made a normal constitutional right under Act 300A in Part XII of the Constitution

Additional Information

  • Right to Constitutional Remedies is enumerated in Articles 32-35.
  • Right against exploitation is enumerated in Articles 23 and 24.
  • The right to freedom of Religion is enumerated in Articles 25-28.
  • Fundamental Rights that are available to citizens only and not to foreigners: Article 15,16, 19, 29 and 30.
Bihar PGT Physics Mock Test - 6 - Question 11
 In September 1940, a Tripartite Pact was signed between which of the following countries?
Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 11
  • Tripartite Pact, the agreement concluded by Germany, Italy, and Japan on September 27, 1940, one year after the start of World War II.
  • It created a defense alliance between the countries and was largely intended to deter the United States from entering the conflict.
  • Hungary, Romania, Slovakia, Bulgaria, Yugoslavia, and Croatia were later signatories to the pact.
  • On October 25, 1936, Germany and Italy completed the Rome-Berlin Axis, a cooperation deal. A month later Japan joined the so-called Axis powers by signing (with Germany) the Anti-Comintern Pact, an anti-communist agreement that was primarily directed against the Soviet Union; Italy signed in 1937.

  • However, that compact was broken with the German-Soviet Non-aggression Pact of August 23, 1939, which paved the way for Germany to invade Poland the following week, thus starting World War II.

  • Against this backdrop, officials from Germany, Italy, and Japan met in Berlin in September 1940 to devise the Tripartite Pact.

  • It notably called on signees “to assist one another with all political, economic and military means” when any one of them was attacked by “a Power at present not involved in the European War or in the Sino-Japanese Conflict.”

  • Such wording notably excluded the Soviet Union, which was already involved in both wars, and was thus seen as a warning to the United States against entering World War II.

  • The pact was signed by Joachim von Ribbentrop (Germany), Galeazzo Ciano (Italy), and Kurusu Saburo (Japan). Several other European countries—some of which had been coerced—were later signatories.

Bihar PGT Physics Mock Test - 6 - Question 12
When is National Youth Day celebrated in India?
Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 12

The correct answer is 12 January.

  • On 12 January, National Youth Day is celebrated in India.

Key Points

  • National Youth Day is celebrated on 12 January and is also known as Rashtriya Yuva Diwas.
    • The day is observed to commemorate the birth anniversary of Swami Vivekananda, one of the greatest philosophers and spiritual leaders.
    • In 1984, the Indian Government first declared to celebrate the birthday of Swami Vivekananda i.e. 12 January as National Youth Day. Since then the day has been celebrated as National Youth Day all over the country.
    • The main aim of the Government is to make a better future for the country by motivating the youths through the way of their life and ideas of the Swami Vivekananda.

Additional Information

  • Swami Vivekananda was born on 12 January 1863 was an Indian Hindu monk. He was a chief disciple of the 19th-century Indian mystic Ramakrishna
    • When Swami Ji became a monk from Narendra, his name was Swami Vividishanand, but before moving to Chicago, he changed his name to Vivekananda.
    • Swami Vivekananda books are:
      • Karma Yoga (1896).
      • Raj Yoga (1896).
      • Vedanta Shastra (1896).
      • Speeches from Colombo to Almora (1897).
Bihar PGT Physics Mock Test - 6 - Question 13
The resources of water on the earth are:
Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 13

The correct answer is option 4, i.e. Ocean, snow and rain, underground water.

  • Water resources available on earth are :
    • Freshwater: Glaciers, ice caps, and snow
    • Groundwater
    • Oceans, seas, streams, rivers, lakes, ponds
    • Wetlands- lagoons, swamps, and marshes
    • Precipitation- Rain, snow, and dew

Hence, from the above points, we can clearly infer that the resources of water on the earth are ocean, snow and rain, underground water.

Bihar PGT Physics Mock Test - 6 - Question 14

A is father of C and D is son of B. E is brother of A. If C is sister of D, then how is B related to E?

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 14

The family chart is as follows:

i) A is father of C and D is son of B.

ii) E is brother of A.

iii) If C is sister of D

Drawing the family tree as per the given information:

Thus we can see B is the wife of A.

E is the brother of A.

Thus we can conclude B is the sister-in-law of E.

Hence, the correct answer is "Sister-in-law".

*Multiple options can be correct
Bihar PGT Physics Mock Test - 6 - Question 15

A block of mass m slides down a plane inclined at an angle q. Which of the following will NOT increase the energy lost by the block due to friction ?

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 15

Bihar PGT Physics Mock Test - 6 - Question 16

An electric hair dryer is rated at 1500 W (the average power) at 120 V (the rms voltage). Calculate (a) the resistance, (b) the rms current, and (c) the maximum instantaneous power. Assume that the dryer is a pure resistor.

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 16

Given,
Pavg=1200W
Vrms=120 Volts
A,
The resistance is,
R=Vrms2/Pavg
So,R=1202/1500=9.6ohm
B,
The rms current is,
Irms=Vrms/R
So, Irms=120/9.6
=>Irms=12.5A
C,
The maximum instantaneous power is,
Pm=2Pavg
So,Pm=2(1500)
=>Pm=3000W.
Hence option D is the correct answer.
 

Bihar PGT Physics Mock Test - 6 - Question 17

A resistance of 5 ohm and an inductance of 50 mH are connected in series with an a. c. I = 100 sin (100 t). What is the phase difference between the instantaneous current and voltage?​

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 17

Cosφ=R/Z=R/√R2/ ω2L2=5/√(25+(50)2x (0.1)2)
=5/√(25+25)=1/√2
⇒φ=π/4

Bihar PGT Physics Mock Test - 6 - Question 18

A sinusoidal voltage of peak value 283 V and frequency 50 Hz is applied to a series LCR circuit in which R = 3 Ω, L = 25.48 mH, and C = 796 μF. Power dissipated in the circuit; and the power factor are

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 18

Angular frequency of the ac signal w=2πν
∴ w=2π(50)=100π
Capacitive reactance Xc​=1/wC​
∴ Xc​=1/(100π×786×10−6)​=4Ω
Inductive reactance XL​=wL
∴ XL​=100π×(25.48×10−3)=8Ω
Impedance of the circuit Z=√[R2+(XL​−Xc​)2​]
∴ Z=√[32+(8−4)2​]=5Ω
 Phase difference ϕ=tan−1[(XL​−Xc​​)R]
Or ϕ=tan−1((8−4​)/3)=tan−1(4/3​)
⟹ ϕ=53.13o
Power factor cosϕ=cos53.13o=0.6
Power dissipated in the circuit
P=Iv2R
Now, Iv=I0/√2=E0/√2Z=283/(1.414×5)=40A
∴P=Iv2R=(40)2×3=4800 watt

Bihar PGT Physics Mock Test - 6 - Question 19

A 7 kg disc is free to rotate about a horizontal axis passing through its centre O (see figure).  The radius of the disc is 10 cm and spring constant of both the spring is 600 Nm-1 There is  no slipping between the disc and the string. The time period of small oscillations of the disc is

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 19

When the angular displacement of the disc is θ the deformation (elongation and compression) in each  spring is x = Rθ .

Bihar PGT Physics Mock Test - 6 - Question 20

If the voltage across the electrodes of a cathode ray tube is 500 volts then energy gained by the electrons is

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 20

Voltage across the electrodes of a cathode ray gun, V=500V
Charge of the electron=1.6x10-19
Energy=eV
E= 1.6x10-19 x 500
E=800 x 10-19 J
E=8 x 10-17 J

Bihar PGT Physics Mock Test - 6 - Question 21

Electric potential is a -

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 21

Electric potential is a pure Scalar quantity, The reason is as follows.
The Electric Potential is defined as the amount of work-done per unit positive charge to bring from infinity to that point under the influence of the primary charge only.
U=W/q
And work done is defined as the dot product of force and displacement which is a scalar quantity.
W=F.S
Thus Electric potential is a scalar quantity.

Bihar PGT Physics Mock Test - 6 - Question 22

How much work is done by a man weighing 80 kgf in raising a stone of weight 20 kgf to the top of a building of height 40 m? (g = 9.8 m/s2)

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 22

Total mass=80+20=100
w=mgh(where m=100, g=9.8, h=40m)
w=100×9.8×40
w=39200J
work done by man weighing 80 kg raising a stone of 20kgf to the top of building of Height is 40m is 39,200J

Bihar PGT Physics Mock Test - 6 - Question 23

Zener diodes are used as

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 23

Zener Diodes can be used to produce a stabilised voltage output with low ripple under varying load current conditions. By passing a small current through the diode from a voltage source, via a suitable current limiting resistor (RS), the zener diode will conduct sufficient current to maintain a voltage drop of Vout.

Bihar PGT Physics Mock Test - 6 - Question 24

Pure sound notes from two sources make the molecules of air at a location vibrate simple harmonically in accordance with the equations:
y1 = 0.008 sin (604πt) and
y2 = 0.007 sin (610πt) respectively.
The number of beats heard by a person at the location will be:

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 24

Given the two sound waves:
y1 = 0.008 sin (604πt)
y2 = 0.007 sin (610πt)
The general form y = A sin (2πft) shows that the term multiplied with t inside the sine gives 2πf, so the frequency f1 = 604/2 = 302 Hz and f2 = 610/2 = 305 Hz.
The number of beats heard per second (beat frequency) is the absolute difference of the two frequencies:
Beat frequency = |f2 - f1| = |305 - 302| = 3 Hz.
However, since the argument in the sine is 604πt, frequency is 604/2 = 302 Hz, not 604 Hz. The same logic applies for the second wave.
Therefore, the beat frequency is 3 Hz, so the number of beats heard per second is 3.
But reviewing the options, and based on the form of the equations, the number of beats heard per second is 3 (option a). However, if the question expects the number of maxima (beats) heard per second, it is 3.
Therefore, the correct answer is a) 3.

Bihar PGT Physics Mock Test - 6 - Question 25

In an n-p-n transistor, the emitter current is

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 25

In the transistor circuit, the current flows from emitter to collector via base.
Ie​=Ib​+Ic​ where variables have their usual meanings.
Hence, emitter current is slightly more than the collector current.

Bihar PGT Physics Mock Test - 6 - Question 26

Which wall would allow the flow of thermal energy between systems A and B to achieve thermal equilibrium?

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 26

Wall that permits *heat" to flow through them,such as engine block is called diathermic wall.
wall Perfectly insulating ball that doesn't allow the flow heat to them are called adiabatic walls.

Bihar PGT Physics Mock Test - 6 - Question 27

In a pure, or intrinsic, semiconductor, valence band holes and conduction-band electrons are always present

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 27

Explanation:An intrinsic semiconductor, also called an undoped semiconductor or i-type semiconductor, is a pure semiconductor without any significant dopant species present. The number of charge carriers is therefore determined by the properties of the material itself instead of the amount of impurities. In intrinsic semiconductors the number of excited electrons and the number of holes are equal: n = p.

Bihar PGT Physics Mock Test - 6 - Question 28

 The value of G = 6.67 × 10_11 N m2 (kg)_2. Its numerical value in CGS system will be :

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 28

G = 6.67 × 10−11 N m2 kg−2

To convert G from SI units to CGS units, we use:
1 N = 105 dynes
1 m = 100 cm
1 kg = 1000 g

So,
G = 6.67 × 10−11 N m2 kg−2

= 6.67 × 10−11 × [ (105 dynes) × (102 cm)2 ] / (103 g)2

= 6.67 × 10−11 × (105 × 104) / 106

= 6.67 × 10−11 × 109 / 106

= 6.67 × 10−8 dyne cm2 g−2

So, the correct value of G in the CGS system is 6.67 × 10−8.

Bihar PGT Physics Mock Test - 6 - Question 29

A rotating calcite crystal is placed over an ink dot. On seeing through the crystal one finds:

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 29

In calcite crystal there is a phenomenon of double refraction. So, we see one dot as a stationary object whereas the other being refracted at a little displaced position seems to be rotating about the first dot.

Bihar PGT Physics Mock Test - 6 - Question 30

The moment of inertia of a particle of mass m kept at point (a, b) on the x-y plane about the x-axis is

Detailed Solution for Bihar PGT Physics Mock Test - 6 - Question 30

Moment of inertia:

  • Moment of inertia of a rigid body about a fixed axis is defined as the sum of the product of the masses of the particles constituting the body and the square of their respective distances from the axis of the rotation.
  • The moment of inertia of a particle  is

⇒ I = mr2

Where r = the perpendicular distance of the particle from the rotational axis.

  • Moment of inertia of a body made up of a number of particles (discrete distribution)

⇒ I = m1r12 + m2r22 + m3r32 + m4r42 + -------

EXPLANATION:

Given: mass of the particle = m, distance from x-axis = b.

The moment of inertia for the particle of mass m from an axis at a distance b is,

⇒ I = mb2

Therefore option 3 is correct.

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