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Bihar STET Paper 1 Mathematics Mock Test - 5 - Bihar PGT/TGT/PRT MCQ


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30 Questions MCQ Test Bihar STET Mock Test Series 2025 - Bihar STET Paper 1 Mathematics Mock Test - 5

Bihar STET Paper 1 Mathematics Mock Test - 5 for Bihar PGT/TGT/PRT 2025 is part of Bihar STET Mock Test Series 2025 preparation. The Bihar STET Paper 1 Mathematics Mock Test - 5 questions and answers have been prepared according to the Bihar PGT/TGT/PRT exam syllabus.The Bihar STET Paper 1 Mathematics Mock Test - 5 MCQs are made for Bihar PGT/TGT/PRT 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Bihar STET Paper 1 Mathematics Mock Test - 5 below.
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Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 1

Read the following text and answer the following questions on the basis of the same: Amit has a packet of Candies. It consists of 288 candies. He arranges the candies in a way that first row contains 3 candies, second row has 5 and third row has 7 and so on.

Q. How many rows are there?

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 1
The A.P. is 3, 5, 7, ................

⇒ 288 = n [3+(n−1)]

⇒ 288 = n2 + 2n

⇒ n2 + 2n − 288 = 0

⇒ n2 + 18n − 16n − 288 = 0

⇒ n(n + 18) − 16(n + 18) = 0

⇒ (n + 18)(n − 16) = 0

⇒ n = 16

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 2

The length of the wire is 66m. The number of circles of circumference 13.2cm can be made from the wire is

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 2

Given: Length of wire = 66 m = 6600 cm and Circumference = 13.2 cm

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 3

Ruhi’s mother is 26 years older than her. The product of their ages (in years) 3 years from now will be 360. Form a Quadratic equation so as to find Ruhi’s age​

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 3

Ruhi’s mother is 26 years older than her
So let Ruhi’s age is x
So mother’s age is x+26
The product of their ages 3 years from now will be 360
So After three years , Ruhi’s age will be x+3
Mother’s age will be x+26+3=x+29
Product of their ages =(x + 3)(x + 29)=360
x2+(3+29)x+87=360
x2+32x-273=0

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 4

The given figures show two congruent circles with centre O and O’. Arc AXB subtends an angle of 75o at the centre and arc A’YB’ subtends an angle of 25o at the centre O’. Then, the ratio of arcs AXB to A ‘YB’ is

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 4

Because the circles are congruent, therefore their radius are same

Length of arc AXB = [θ/(360°)] × 2πr = [(75°)/(360°)] × 2πr

Length of arc A’YB’ = [θ/(360°)] × 2πr = [(25°)/(360°)] × 2πr

Required Ratio = ([(75°)/(360°)] × 2πr) : ([(25°)/(360°)] × 2πr) = 3 : 1

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 5

The angle which is equal to 8 times its complement is :

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 5
Complement angle of 80 degree is 10 degree (90-80), which gives 80 degree when multlipied by 8.
Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 6

In the figure, O and O' are centres of two circles intersecting at B aand C. ACD is a straight line, find x.

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 6

In the figure, two circle with centers O and O' intersect each other at B and C.

ACD is a line, ∠AOB=130

Arc AB subtends ∠AOB at the centre O and ∠ACB at the remaining part of the circle.

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 7

From figure, identify the incorrect statement, given that l || m and t is transversal.

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 7

Angle 2 and 8 are a pair of alternate interior angles, and thus are equal. so they don't form a pair of supplementary angles.

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 8

Divide 16 into two parts such that twice the square of the larger part exceeds the square of the smaller part by 164.​

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 8

Let x and (16 - x) are two parts of 16 where (16 - x) is longer and x is smaller .
A/C to question,
2 × square of longer = square of smaller + 164
⇒ 2 × (16 - x)² = x² + 164
⇒ 2 × (256 + x² - 32x ) = x² + 164
⇒ 512 + 2x² - 64x = x² + 164
⇒ x² - 64x + 512 - 164 = 0
⇒ x² - 64x + 348 = 0
⇒x² - 58x - 6x + 348 = 0
⇒ x(x - 58) - 6(x - 58) = 0
⇒(x - 6)(x - 58) = 0
⇒ x = 6 and 58

But x ≠ 58 because x < 16
so, x = 6 and 16 - x = 10

Hence, answer is 6 and 10.

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 9

In the given figure, the value of x which makes POQ a straight line is :

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 9

For POQ=straight line →∠ POQ=180o

2x+30+4x=180

6x+30=180

6x=150

x=25o.

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 10

Three solid spherical beads of radii 3 cm, 4 cm and 5 cm are melted into a spherical bead. Its radius is :

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 10

Let three spheres are S1, S2 & S3
having radii r₁ = 3cm, r₂ = 4cm & r₃ = 5cm respectively.
Let the radius of new Big sphere S is R.
A/Q,
Volume of new Sphere  S = Sum of volumes three Spheres S1, S2 & S3

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 11

A sum of Rs.700 is to be used to award 7 prizes. If each prize is Rs.20 less than its preceding prize, then the value of the first prize is

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 11

Let the first prize be a.
The seven prizes form an AP with first term a and common difference d = −20
Now the sum of all seven prizes = Rs. 700

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 12

A box contains 3 blue balls, 2 white balls and 4 red balls. If a ball is drawn at random from the box, the probability of getting a white ball is

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 12

Number of outcomes = 2
Number of total outcomes = 3 + 2 + 4 = 9
∴ Required Probability = 2/9

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 13

Which of the following has two distinct roots?

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 13

In equation x2+x−5 = 0
a = 1,b = 1,c = −5
∴ b2−4ac = (1)2−4×1×(−5) = 1 + 20 = 21
Since b2−4ac > 0 therefore, x2+x−5 = 0 has two distict roots.

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 14

Read the following text and answer the following question on the basis of the same:

Authority wants to construct a slide in a city park for children. The slide was to be constructed for children below the age of 12 years. Authority prefers the top of the slide at a height of 4 m above the ground and inclined at an angle of 30° to the ground.

Q. The value of sin2 30° + cos2 60° is:

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 14
sin2 30° + cos2 60°

= (1 / 2)2 + (1 / 2)2

= 1 / 4 + 1 / 4

= 2 / 4 = 1 / 2

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 15

A square of side 7cmis inscribed in a circle. The area enclosed between the circle and the square is

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 15


Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 16

The angles of a quadrilateral are in the ratio 4: 5: 10: 11. The angles are

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 16

 Let x be the common angle among all the four angles of a quadrilateral.

As per angle sum property, we know:

4x+5x+10x+11x = 360°

30x = 360°

x = 12°

Hence, angles are

4x = 4 (12) = 48°

5x = 5 (12) = 60°

10x = 10 (12) = 120°

11x = 11 (12) = 132°

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 17

The angle formed by the line of sight with the horizontal, when the point being viewed is above the horizontal level is called:​

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 17

The term angle of elevation denotes the angle from the horizontal upward to an object.  An observer’s line of sight would be above the horizontal. And The term angle of depression denotes the angle from the horizontal downward to an object.  An observer’s line of sight would be below the horizontal. So The angle is called Angle of elevation.

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 18

Guddi was standing on a road near a mall. She was 1000m away from the mall and able to see the top of the mall from the road in such a way that top of the tree, which is in between her and the mall, was exactly in line of sight with the top of the mall. The tree height is 10m and it is 20m away from Guddi. How tall is the mall?

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 18

Angle of elevation for Guddi is same for the tree and the mall.

So, the ratio of object height to its shadow will be same for the both subjects.

Therefore by proportionality rule,

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 19

Which among the following statements is correct?

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 19

Teaching profession is a 'mission', rather than a job. A teacher may not find the affirmation of his/her career choice in salary, administrators or even the students whom he/she teaches, but he/she must believe in the uncanny ability of a good teacher to positively impact the future and to leave lasting, indelible marks on those who will one day be the leaders in all facets of society. It is this power in the hands of a teacher that translates to big responsibility. A teacher who realises these things is on a mission to empower, enable and to make a positive difference.

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 20

Assertion(A): Teacher and their students visits a zoological park and students can learn about animals more effectively by directly seeing them.
Reason(R): Children can learn more effectively by observational and direct interactional based learning.

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 20

Psychologist Albert Bandura is the researcher most often associated with learning through observation. He and others have demonstrated that we are naturally inclined to engage in observational learning.

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 21

Which of the following teaching aids is/are most effective in teaching primary level students?

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 21

Primary level students learn more by observing pictures and specimens. Thus, they are most effective in teaching primary level students. Pictures and specimens are important visual tools which facilitate learning.

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 22

It is said that a teacher is a friend, philosopher and guide because

  1. a teacher imparts high values to pupils
  2. a teacher spends a lot of time with the students
  3. a teacher is a reformer

Choose from the options given below:

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 22

It is said that a teacher is a friend, philosopher and guide because a teacher plays all these vital roles in respect of pupils. It is based on the intent and capacity that a teacher possesses, exposed to which, a student is influenced to make a positive difference in his own life as well as in the society and the world at large.

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 23

In an extempore speech, the principal of a school asked the students to focus more on vocabulary. He opined that they must adopt the habit of learning the correct use of words. What according to you is the intelligence that is associated with the ability of students to use words effectively?  

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 23

Linguistic Intelligence is associated with the ability of students to use words in a proper way. These students like reading, writing poetry, playing word games, etc. 

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 24

In order to develop rapport with pupils, a teacher should

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 24

Successful teachers are those who have the ability to maximise the learning potential of all students in their class. Developing positive relationships between a teacher and student is a fundamental aspect of quality teaching and student learning. In order to develop rapport with pupils, a teacher should behave with them in a democratic way, guide them, and he should have communicative ability.
Gillespie recognised that the inherent qualities of a student-teacher relationship (caring, knowing, trust and mutual respect) and a teacher's rapport with students results in a classroom environment where students are affirmed and supported to achieve their best.

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 25

A teacher finds that a particular class after giving several warnings behaves in an undisciplined manner. What method should he apply to maintain the discipline of the class?

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 25

In case a teacher notices any activity that causes indiscipline in the class, he should immediately find out the cause of that activity and try to handle the issue with resourcefulness. By identifying the students creating nuisance, the teacher can counsel them, and eliminate their concerns.

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 26

Effective teaching is by and large a function of teacher's

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 26

Liking for the profession not only in teaching but any other activity is foremost important to emerge out successfully. A teacher can effectively achieve this only if he has liking for his profession and he puts in all his efforts for the same.

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 27

In the class, a teacher should keep the pitch of his/her voice

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 27

A teacher needs to vary his/her pitch according to the situation. She may use a high or a low pitch. Intonation has been always considered an important aspect of communication. The positive intonation proved to have a dramatic effect on the learning rate of students. The students learn much faster when the vocal part of the message is positive than when it is neutral.

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 28

Recently, India surpassed which country to become the fourth-largest equity market globally?

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 28

India recently overtook Hong Kong as the world’s fourth-largest equity market, boasting a total market value of $4.33 trillion, surpassing Hong Kong’s $4.29 trillion. The leading global stock markets are currently the U.S., China, and Japan. This milestone underscores India’s rising prominence in the global financial arena, propelled by a robust GDP, political stability, foreign investments, and its appeal as an alternative to China. Meanwhile, Hong Kong grapples with challenges like COVID-19 restrictions, regulatory crackdowns, a property crisis, and geopolitical tensions, affecting its attractiveness to investors.

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 29

Two angles are supplementary and the ratio of the angels is 1:4. what is the value of smaller angle?

Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 29

As we know that the angles are supplementary so sum of angles will be 180 degree.
Let us assume that the ratio factor is r.
According to question,
Angles are supplementary and have a ratio of 1:4.
r + 4r = 180
⇒ 5r = 180
⇒ r = 180/5
⇒ r = 36

Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 30
Five years ago, father's age was 5 times that of his son and after 3 years he will be 3 times as old as his son. Find the present age of son.
Detailed Solution for Bihar STET Paper 1 Mathematics Mock Test - 5 - Question 30

Given:

Five years ago, father's age was 5 times that of his son

After 3 years father will be 3 times as old as his son

Calculation:

Let the present age of son be x years 

Present age of father be y years 

According to the question,

Five years ago, father's age was 5 times that of his son

(y - 5) = 5 (x - 5)

⇒ y - 5 = 5x - 25 

⇒ y - 5x + 20 = 0     ---- (i)

After 3 years father will be 3 times as old as his son

(y + 3) = 3(x + 3)

⇒ y + 3 = 3x + 9

⇒ y - 3x - 6 = 0      ---- (ii)

Solving equation (i) and (ii) we get,

x = 13

∴ Present age of son is 13 years

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