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COMEDK Mock Test - 4 - JEE MCQ


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30 Questions MCQ Test COMEDK Mock Test Series - COMEDK Mock Test - 4

COMEDK Mock Test - 4 for JEE 2025 is part of COMEDK Mock Test Series preparation. The COMEDK Mock Test - 4 questions and answers have been prepared according to the JEE exam syllabus.The COMEDK Mock Test - 4 MCQs are made for JEE 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for COMEDK Mock Test - 4 below.
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COMEDK Mock Test - 4 - Question 1

A Carnot engine takes 5000 kcal of heat from a reservoir at 727°C and gives heat to a sink at 127°C. The work done by the engine is

Detailed Solution for COMEDK Mock Test - 4 - Question 1


⇒ W = 0.6Q = 3000 kcal = 12.6 × 106 J

COMEDK Mock Test - 4 - Question 2

Identify the pair of physical quantities that have same dimensions.

Detailed Solution for COMEDK Mock Test - 4 - Question 2


Decay constant λ has dimensions of [T-1] because of the relation dN/dt = -λN.
⇒ Velocity gradient and decay constant have same dimensions.

COMEDK Mock Test - 4 - Question 3

The stopping potential in the context of photoelectric effect depends on the following property of incident electromagnetic radiation:

Detailed Solution for COMEDK Mock Test - 4 - Question 3

Stopping potential changes linearly with frequency of the incident radiation.

COMEDK Mock Test - 4 - Question 4

A wall has two layers A and B ach made of different materials. Both layers have the same thickness. The thermal conductivity of the material of A is twice that of B. Under thermal equilibrium, the temperature difference across the wall is 36C. The temperature difference across the layer A is:

Detailed Solution for COMEDK Mock Test - 4 - Question 4

Consider two walls 'A' and 'B' of thickness 't' each, and thermal conductivity of ' 2K ' and 'K' respectively.
The temperatures at the left of A=Ta, The temperatures at the right of B=Tb, The temperature at the junction 
= T. 

Heat flow is a constant in steady state:

Equating heat flow for both walls we get:  

Which simplifies to:  

Also given that the temperature difference between the walls is 36º C

Combining the two equation in T,Ta,Tb and eliminating Tb

.

COMEDK Mock Test - 4 - Question 5

A body rolls down an inclined plane without slipping. The kinetic energy of rotation is 50% of its translational kinetic energy. The body is:

Detailed Solution for COMEDK Mock Test - 4 - Question 5

Krotational = 50% times Ktranslational

This is a case of pure rolling.
∴ v = ωR ... (ii)
From equations (i) and (ii),

This is the value of moment of inertia for a solid cylinder. Therefore, the body is a solid cylinder.

COMEDK Mock Test - 4 - Question 6

Directions: These questions consist of two statements, each printed as Assertion and Reason. While answering these questions, you are required to choose any one of the following four responses.

Assertion: The electric flux of the electric field ∮ E.dA is zero. The electric field is zero everywhere on the surface.

Reason: The charge inside the surface is zero.

Detailed Solution for COMEDK Mock Test - 4 - Question 6

By Gauss’s law:
∮ E ⋅ dA = Qenc / ε₀

If ∮ E ⋅ dA = 0, then Qenc = 0, so the reason is true. However, the assertion is false: zero flux does not imply E = 0 everywhere on the surface (e.g., a dipole with no net charge produces non-zero field).

Thus, both are not correct, and the correct answer is D: Assertion is false, Reason is true.

COMEDK Mock Test - 4 - Question 7

Amplitude modulated wave is represented by VAM = 10[1 + 0.4cos(2π × 104t)] cos(2π × 107 t). The total bandwidth of the amplitude modulated wave is:

Detailed Solution for COMEDK Mock Test - 4 - Question 7

Bandwidth = 2 fm
= 2 × 104 Hz
= 20 × 103 Hz
= 20 kHz

COMEDK Mock Test - 4 - Question 8

A deuteron and an alpha particle having equal kinetic energy enter perpendicular into a magnetic field. Let rd and rα  be their respective radii of circular path. The value of  is equal to

Detailed Solution for COMEDK Mock Test - 4 - Question 8

COMEDK Mock Test - 4 - Question 9

A cylinder of fixed capacity of 44.8 litres contains helium gas at standard temperature and pressure. The amount of heat needed to raise the temperature of gas in the cylinder by 20.0°C will be:
(Given: gas constant R = 8.3 JK-1 mol-1)

Detailed Solution for COMEDK Mock Test - 4 - Question 9

No. of moles = 44.8/22.4 = 2
The gas is monatomic, so CV = 3/2 R.
ΔQ = nCvΔT
= 2 × 3/2 R × 20
= 60R
= 60 × 8.3
= 498 J

COMEDK Mock Test - 4 - Question 10

If , then the relative error in Z will be:

Detailed Solution for COMEDK Mock Test - 4 - Question 10


In case of error,

COMEDK Mock Test - 4 - Question 11

A cylindrical tank has a hole of diameter 2r in its bottom. The hole is covered wooden cylindrical block of diameter 4r, height h and density ρ/3.

Situation I : Initially, the tank is filled with water of density ρ to a height such that the height of water above the top of the block is h1 (measured from the top of the block).

Situation II : The water is removed from the tank to a height h2 (measured from the bottom of the block), as shown in the figure.
The height h2 is smaller than h (height of the block) and thus the block is exposed to the atmosphere.

Q. Find the minimum value of height h1 (in situation 1), for which the block just starts to move up?    

Detailed Solution for COMEDK Mock Test - 4 - Question 11

Consider the equilibrium of wooden block.
Forces acting in the downward direction are

(a) Weight of wooden cylinder

(b) Force due to pressure (P1) created by liquid of height h1 above the wooden block is
= P1 × π (2r)2 = [P0 + h1rg] × π (2r)2
Force acting on the upward direction due to pressure P2 exerted from below the wooden block and atmospheric pressure is

At the verge of rising

COMEDK Mock Test - 4 - Question 12

The reaction in which sodium cyanide is used is

COMEDK Mock Test - 4 - Question 13

Molarity of liquid HCl with density equal to 1.17 g/cc is

COMEDK Mock Test - 4 - Question 14

Which one of the following proteins transports oxygen in the blood stream?

COMEDK Mock Test - 4 - Question 15

Orthophosphoric acid is

COMEDK Mock Test - 4 - Question 16

The equilibrium constant for the following reaction will be 3 A + 2 B → C

COMEDK Mock Test - 4 - Question 17

A system is said to be in thermodynamic equilibrium when it is in

COMEDK Mock Test - 4 - Question 18

If the truth values of statements p,q,r are True, True and False respectively

Statement-1: Statement ~(p∨q)∧(p∨~r)∧(~p∨~q) is false.

Statement-2: For given truth values ~(p∨q) is false, (p∨~r)  is true, (~p∨~q) is false.

Detailed Solution for COMEDK Mock Test - 4 - Question 18

We have,

Hence, statement − 1 is True, Statement −2 is True: Statement−2 is a correct explanation for Statement − 1.

COMEDK Mock Test - 4 - Question 19

Let f:(−∞,0]→[1,∞) be defined a  then f(x) is

Detailed Solution for COMEDK Mock Test - 4 - Question 19

Because of √-x, domain of the function is x ≤ 0.

It proves that the function is one-one. 

f(x) is one-one and range is same as co-domain.

So, the function is injective as well as surjective.

COMEDK Mock Test - 4 - Question 20

Tangents are drawn from the point (α,β) to the hyperbola 3x2−2y2=6 and are inclined at angles θ and ϕ to the X
-axis. If  tanθ⋅tanϕ=2, then β2−2α2=

Detailed Solution for COMEDK Mock Test - 4 - Question 20

Given hyperbola is 3x2−2y2=6

We know that, the tangent to the hyperbola with slope m is

Tangents passes through the point (α,β), hence, we have

The roots of this equation are m1 and m2
Hence, by using product of roots

COMEDK Mock Test - 4 - Question 21

If  then which of the following is not true

Detailed Solution for COMEDK Mock Test - 4 - Question 21

Given,

On differentiating the above function with respect to x we get,

f(x) has a point of maxima at x=0, because the sign of the function f′(x) changes from positive to negative.

⇒ f(x)=0 has a maxima at x=0.
Now, applying the second derivative test, 

We have taken x=0 already and x=3/4 is not true for [x2(3−4x),x<0]. Therefore, we have to take x=e−4.

Now,

f′′(x)=e4 is positive and by the definition of maxima-minima of a function, the minima is at x=e−4

Now, we want to check the continuity of the f(x) at x=0

Hence, the function is continuous at x=0 and therefore, continuous for x∈R.

Now, when

Therefore. f(x) takes all the values from −∞ to +∞. Hence, f(x) has range R.

COMEDK Mock Test - 4 - Question 22

The number of positive integral solutions of  is

Detailed Solution for COMEDK Mock Test - 4 - Question 22

Hence, positive integral solutions are 2,3,4.
So, three positive integral solutions are possible.

COMEDK Mock Test - 4 - Question 23

if  are non-coplanar unit vectors such that  are non-parallel, then the angle between  is

Detailed Solution for COMEDK Mock Test - 4 - Question 23

COMEDK Mock Test - 4 - Question 24

 is equal to

Detailed Solution for COMEDK Mock Test - 4 - Question 24

COMEDK Mock Test - 4 - Question 25

Assuming the sum and the products given below are defined, which of the following is false for matrices?

Detailed Solution for COMEDK Mock Test - 4 - Question 25

So, option (4) is correct.

COMEDK Mock Test - 4 - Question 26

The function f(x) = tan x/x for x ≠ 0 ; f (0) = 1 at x = 0 is

COMEDK Mock Test - 4 - Question 27

COMEDK Mock Test - 4 - Question 28

If f : R → R is defined by f x = 2 x + | x | then f (3x) − f (-x)   − 4 x =

COMEDK Mock Test - 4 - Question 29

If f(x)   = e -1/x2 , x ≠ 0, and f(0) = 0 then f ′(0)    is

Detailed Solution for COMEDK Mock Test - 4 - Question 29

COMEDK Mock Test - 4 - Question 30

∫[(1)/(4x2+9)]dx =

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