JEE Exam  >  JEE Tests  >  COMEDK Mock Test Series  >  COMEDK Mock Test - 5 - JEE MCQ

COMEDK Mock Test - 5 - JEE MCQ


Test Description

30 Questions MCQ Test COMEDK Mock Test Series - COMEDK Mock Test - 5

COMEDK Mock Test - 5 for JEE 2024 is part of COMEDK Mock Test Series preparation. The COMEDK Mock Test - 5 questions and answers have been prepared according to the JEE exam syllabus.The COMEDK Mock Test - 5 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for COMEDK Mock Test - 5 below.
Solutions of COMEDK Mock Test - 5 questions in English are available as part of our COMEDK Mock Test Series for JEE & COMEDK Mock Test - 5 solutions in Hindi for COMEDK Mock Test Series course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt COMEDK Mock Test - 5 | 180 questions in 180 minutes | Mock test for JEE preparation | Free important questions MCQ to study COMEDK Mock Test Series for JEE Exam | Download free PDF with solutions
COMEDK Mock Test - 5 - Question 1

The logic gate circuit shown in the figure realises which of the following functions?

Detailed Solution for COMEDK Mock Test - 5 - Question 1

This represents the XOR function.

COMEDK Mock Test - 5 - Question 2

Population of a town is reported as 157,900 . Which of the following statements correct?

Detailed Solution for COMEDK Mock Test - 5 - Question 2

157900  implies that the population is believed to be within the range of about 157850 to about 157950.

In other words, the population is 157900 ± 50. The “plus-or-minus 50” appended to this number means that we consider the absolute uncertainty of the population measurement to be 50 – (–50) = 100.

We can also say that the relative uncertainty is 100/157900, which we can also express as 1 part in 1579, or 1/1579 = 0.000633, or about 0.06 percent.

1 Crore+ students have signed up on EduRev. Have you? Download the App
COMEDK Mock Test - 5 - Question 3

During adiabatic change, specific heat is

Detailed Solution for COMEDK Mock Test - 5 - Question 3
In an adiabatic process, ΔH = 0

Hence, zero is the correct answer.

COMEDK Mock Test - 5 - Question 4

The de-Broglie wavelength associated with an electron and a proton were calculated by accelerating them through same potential of 100 V. What should nearly be the ratio of their wavelengths? (mp = 1.00727 u, me = 0.00055 u)

Detailed Solution for COMEDK Mock Test - 5 - Question 4

COMEDK Mock Test - 5 - Question 5

Three particles P, Q and R placed as per given figure. Masses of P, Q and R are √3 m, √3 m and m respectively. The gravitational force on a fourth particle ‘S’ of mass m is equal to

Detailed Solution for COMEDK Mock Test - 5 - Question 5

in horizontal direction  

in vertical direction

COMEDK Mock Test - 5 - Question 6

Let nr and nb be respectively the number of photons emitted by a red bulb and a blue bulb of equal power in a given time.

Detailed Solution for COMEDK Mock Test - 5 - Question 6

Since, Pr​=Pb​ 
r for red and b for blue.
Pr​=Pb​
or, nr​× (hc/λr)  ​=nb​× (hc​/λb)​
or,  ​(nr/nb)​​= λr​​/λb
Since, the wavelength of red bulb is greater than the wavelength of blue bulb.
or,  nr​>nb

COMEDK Mock Test - 5 - Question 7

A particle moving along x-axis has acceleration 'f' at time 't', given by , where 'f0' and 'T' are constants. The particle at 't' = 0 has zero velocity. In the time interval between 't' = 0 and the instant when 'f' = 0, the velocity (vx) of the particle is

Detailed Solution for COMEDK Mock Test - 5 - Question 7

Acceleration,

Acceleration will be zero when,

At t = 0, v = 0.

COMEDK Mock Test - 5 - Question 8

Two soap bubbles with radii   come in contact. Their common surface has a radius of curvature r. Then

Detailed Solution for COMEDK Mock Test - 5 - Question 8

Let p0 = atmospheric pressure,

p1 and p2 = pressures inside the two bubbles

Let r = radius of curvature of the common surface

COMEDK Mock Test - 5 - Question 9

If force  acts on a particle having position vector , then the torque about the origin will be:

Detailed Solution for COMEDK Mock Test - 5 - Question 9

COMEDK Mock Test - 5 - Question 10

Red light differs from blue light as they have:

Detailed Solution for COMEDK Mock Test - 5 - Question 10

Red light and blue light have different wavelengths and different frequencies. Blue light has shorter waves, with wavelengths between about 450 and 495 nanometres. Red light has longer waves, with wavelengths around 620 to 750 nanometres. Blue light has a higher frequency and carries more energy than red light.

COMEDK Mock Test - 5 - Question 11

Two light beams of intensities in the ratio of 9 : 4 are allowed to interfere. The ratio of the intensity of maxima and minima will be:

Detailed Solution for COMEDK Mock Test - 5 - Question 11

COMEDK Mock Test - 5 - Question 12

The length, breadth and thickness of a rectangular sheet of metal are 4.234 m, 1.005 m, and 2.01 cm respectively. Give the volume of the sheet to correct significant figures.

Detailed Solution for COMEDK Mock Test - 5 - Question 12

Length , l = 4,234 m
Breadth, b = 1.005 m
Thickness , t = 2.01 x 10-2 m
Volume = l x b x t
⇒ V = 4.234 x 1.005 x 0.0201 = 0.0855289 = 0.0855 m3 (significant figure = 3)

COMEDK Mock Test - 5 - Question 13

Among the lanthanide Eu, Tb, Er and Dy, which one readily forms stable divalent ions?

Detailed Solution for COMEDK Mock Test - 5 - Question 13

The electronic configurations of the given elements are -

Removal of two electrons from Eu gives it the configuration [Xe] 4f7 which is a stable half-filled configuration.

COMEDK Mock Test - 5 - Question 14

Which of the following is not a condensation polymer?

Detailed Solution for COMEDK Mock Test - 5 - Question 14

(a) Nylon−6,6 is the polymer of hexamethylene diamine and adipic acid. It is made by the condensation of given monomers.

(b) Nylon−6 os also a condensation polymer of caprolactum. It is a polymide.

(c) Dacron is also a condensation polymer of ethylene glycol and terephthalic acid. It is an example of polyester.

(d) Buna−S is an addition polymer of 1,3, butadiene and styrene.

Hence, only (4) is not a condensation polymer.

∴ (4) is the correct option.

COMEDK Mock Test - 5 - Question 15

If the ionisation potential of hydrogen atom is 2 x 10-18 J, then the frequency of Hβ line of Balmer series is
(Given: Plank's constant = 6.6 x 10-34 Js)

Detailed Solution for COMEDK Mock Test - 5 - Question 15

Hβ line is formed due to the transition of electrons from 4 to 2.

COMEDK Mock Test - 5 - Question 16

For the reaction 2H2 + O2  2H2O, H = -571 kJ, bond energy of H - H = 435 kJ/mol and that of O - O = 498 kJ/mol. Calculate the average bond energy (in kJ/mol) of O - H bond using this data.

Detailed Solution for COMEDK Mock Test - 5 - Question 16

COMEDK Mock Test - 5 - Question 17

Excess of iron is added to a 0.1 M Cd2+ solution and the system is allowed to attain equilibrium.

The concentration of Cd2+ ions, if Eo = 0.037 V, is

Detailed Solution for COMEDK Mock Test - 5 - Question 17

COMEDK Mock Test - 5 - Question 18

Directions: The following question has four choices out of which ONLY ONE is correct.
The heat of neutralisation of acetic acid by sodium hydroxide is −55.9 kJ/mol, and the heat of neutralisation of a strong acid by a strong base is −57.1 kJ/mol. What is the value of ΔH for the ionisation of CH3COOH?

Detailed Solution for COMEDK Mock Test - 5 - Question 18


 for a strong acid and a strong base = 
Let 
NaOH, CH3COONa are strong electrolytes and are fully dissociated in the aqueous solutions.
∴ -57.1 - x = -55.9
x = -1.2 kJ mol-1
Therefore, 

COMEDK Mock Test - 5 - Question 19

Consider the reaction:
P + 2Q → R
When concentration of Q alone was tripled, the half-life did not change. When the concentration of P alone was made four times, the rate increased two times. The unit of rate constant for this reaction would be

Detailed Solution for COMEDK Mock Test - 5 - Question 19

For the reaction: P + 2Q → R, when concentration of 'Q' is doubled, the half-life does not change, hence reaction is first-order with respect to 'Q'.
This is because for the first order reaction, rate constant is independent from initial concentration of the reactant.
When the concentration of 'P' is made four times, the rate of reaction becomes double. It means the reaction is half-order with respect to 'P'.
Hence, the rate law expression is:

Overall order = 1 + 1/2 = 3/2
Units of the rate constant = (mol L-1)(1 - n) s-1
So, unit of rate constant is L1/2 mol-1/2 s-1.

COMEDK Mock Test - 5 - Question 20

A solution has a 1 : 4 mole ratio of pentane to hexane. The vapour pressures of the pure hydrocarbons at 20oC are 440 mm of Hg for pentane, and 120 mm of Hg for hexane. The mole fraction of pentane in the vapour phase would be

Detailed Solution for COMEDK Mock Test - 5 - Question 20

Total vapour pressure (VP) of mixture = VP of pentane in mixture + VP of hexane in mixture
PT = (Mole fraction of pentane × VP of pentane) + (Mole fraction of hexane × VP of hexane)
PT = 
VP of pentane in mixture = VP of mixture × Mole fraction of pentane in vapour
88 = 184 x Mole fraction of pentane in vapour
Or, mole fraction of pentane in the vapour phase = 88/184 = 0.4782 

COMEDK Mock Test - 5 - Question 21

The term 'sorption' stands for

Detailed Solution for COMEDK Mock Test - 5 - Question 21

Sorption is the common term used for both absorption and adsorption. Absorption is the incorporation of a substance in one state into another of a different state (e.g., liquids being absorbed by a solid or gases being absorbed by water). Adsorption is the physical adherence or bonding of ions and molecules onto the surface of another molecule. The term 'sorption' is preferred when it is suspected that both processes are operative.

COMEDK Mock Test - 5 - Question 22

If 10 volume of H2O2 reacts completely with 100 ml of 2 N KMnO4, calculate the volume of H2O2 used in mL.

Detailed Solution for COMEDK Mock Test - 5 - Question 22

Volume strength of H2O2 = Normality × 5.6

According to law of equivalence.

N1V1(KMnO4) = N2V2(H2O2)

2 × 100 = 1.786 × V2

COMEDK Mock Test - 5 - Question 23

The mineral used in the isolation of radium is

Detailed Solution for COMEDK Mock Test - 5 - Question 23

Radium is an extremely rare element which was first discovered in 1898 by Pierre and Marie Curie. Marie Curie was awarded with a second Nobel Prize in 1911 for her discovery of radium: a Prize in chemistry, this time, making her the first woman to be awarded with a Nobel Prize in this particular field. The isotopes of radium are highly radioactive, with the most stable isotope being radium−226, which has a half-life of 1600 years and decays into radon gas.

On April 20, 1902, Marie and Pierre Curie successfully isolate radioactive radium salts from the mineral pitchblende in their laboratory in Paris. In 1898, the Curies discovered the existence of the element radium in their research of pitch blende.

COMEDK Mock Test - 5 - Question 24

For the redox reaction,

taking place in a cell, Ecell is 1.10 V. Ecell for the cell will be

Detailed Solution for COMEDK Mock Test - 5 - Question 24



= 1.10 - 0.0295
= 1.0705 V

COMEDK Mock Test - 5 - Question 25

If A is a non-singular, then adj A is

COMEDK Mock Test - 5 - Question 26

The equation of the parabola whose focus is (1,-1)and directrix is x + y + 7 = 0 is

COMEDK Mock Test - 5 - Question 27

The polar form of the complex number (i25 )3 is

COMEDK Mock Test - 5 - Question 28

COMEDK Mock Test - 5 - Question 29

Let A = { x ∈ R : x ≠ 0, − 4 ≤ x ≤ 4 } and f : A → R is defined by f (x)   = | x |/x for x ∈ A . Then the range of f is

COMEDK Mock Test - 5 - Question 30

The condition for the roots of the equation (c2-ab)x2-2(a2-bc)x+(b2-ac)=d are equal, is

View more questions
10 tests
Information about COMEDK Mock Test - 5 Page
In this test you can find the Exam questions for COMEDK Mock Test - 5 solved & explained in the simplest way possible. Besides giving Questions and answers for COMEDK Mock Test - 5, EduRev gives you an ample number of Online tests for practice

Top Courses for JEE

Download as PDF

Top Courses for JEE