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CSIR NET Life Sciences Mock Test - 10 - UGC NET MCQ


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30 Questions MCQ Test CSIR NET Exam Mock Test Series 2025 - CSIR NET Life Sciences Mock Test - 10

CSIR NET Life Sciences Mock Test - 10 for UGC NET 2025 is part of CSIR NET Exam Mock Test Series 2025 preparation. The CSIR NET Life Sciences Mock Test - 10 questions and answers have been prepared according to the UGC NET exam syllabus.The CSIR NET Life Sciences Mock Test - 10 MCQs are made for UGC NET 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for CSIR NET Life Sciences Mock Test - 10 below.
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CSIR NET Life Sciences Mock Test - 10 - Question 1

Surendra divided some amount among his wife, son and daughter such that the amount received by his wife and his son in the ratio and his son and his daughter in the ratio . If his daughter received more than son, then what amount Surendra divided among them?

Detailed Solution for CSIR NET Life Sciences Mock Test - 10 - Question 1

Wife: Son

Son: Daughter

Wife: Son: Daughter

Let his Daughter received and his Son received

Difference

Total amount

Rs

CSIR NET Life Sciences Mock Test - 10 - Question 2

X and Y are the two alloys which were made by mixing Zinc and Copper in the ratio 1:3 and 2: 5 respectively. If 120 grams of alloy X ,91 grams of alloy Y and 34 gram pure Zinc are melted and mixed to form another alloy Z, what is the ratio of Zinc and Copper in the new alloy Z?

Detailed Solution for CSIR NET Life Sciences Mock Test - 10 - Question 2

Total Zink
Total Copper
Ratio

CSIR NET Life Sciences Mock Test - 10 - Question 3

Marks obtained by a student in 7 subjects are as follows 90, 66, 70, 82, 86, 78, 74 in these obtained marks 78 is:

Detailed Solution for CSIR NET Life Sciences Mock Test - 10 - Question 3

Given:

Marks in 7 subjects = 90, 66, 70, 82, 86, 78, 74

Mean

Median term when, n is odd

Median term term }, when n is even

Mode = The mode is the value that appears most frequently in a data set.

Arrange the given data in ascending order and then use the median formula.

Mean

Median th term = 78

∴ 78 is both median and mean.

CSIR NET Life Sciences Mock Test - 10 - Question 4

Everybody in a room shakehands with everybody else. The total number of hand shakes is 66. The total number of persons in the room is:

Detailed Solution for CSIR NET Life Sciences Mock Test - 10 - Question 4

Two people are required to shake hands.

The total number of handshakes is 66.

Suppose there are n people in the room

The total number of persons in the room is nC2 = 66

⇒ n (n - 1) = 132
⇒ n2 -  n - 132 = 0
⇒ (n - 12)(n + 11) = 0
⇒ n = 12 or n = - 11
Here n = - 11 is not possible as the number of persons can't be negative.
⇒ n = 12
∴ The number of people in the room is 12.

CSIR NET Life Sciences Mock Test - 10 - Question 5

In a code language, ‘SERVICE’ is written as ‘RESVECI’. How will ‘NAUGHTY’ be written as in that language?

Detailed Solution for CSIR NET Life Sciences Mock Test - 10 - Question 5

The logic followed here is as follows:

Similarly,


So, ‘NAUGHTY’ will be written as UANGYTH in that language.

CSIR NET Life Sciences Mock Test - 10 - Question 6

Which letter from the options will replace the question mark (?) in the following series?

D, H, M, Q, V, ?

Detailed Solution for CSIR NET Life Sciences Mock Test - 10 - Question 6

The pattern followed here is:

D + 4 = H

H + 5 = M

M + 4 = Q

Q + 5 = V

Similarly,

V + 4 = Z

Thus, "Z" is the next term of the series.

CSIR NET Life Sciences Mock Test - 10 - Question 7

If (10a+ 4b3) : (11a− 15b3) = 7:5, then (3a + 5b):(9a − 2b) = ?

Detailed Solution for CSIR NET Life Sciences Mock Test - 10 - Question 7

Given:

Putting the value of a and b

CSIR NET Life Sciences Mock Test - 10 - Question 8

A survey was conducted by a group of students as a part of their environment awareness programme, in which they collected the following data regarding the number of plants in  houses in a locality. Find the mean number of plants per house.

Detailed Solution for CSIR NET Life Sciences Mock Test - 10 - Question 8

The number of houses denoted by .

The mean can be found as given below:

Class mark for each interval is calculated as follows:

xi and can be calculated as follows:


From the table, it can be observed that

Substituting the value of fixi and xi in the formula of mean we get:
Mean number of plants per house  

Therefore, mean number of plants per house is 8.1.

CSIR NET Life Sciences Mock Test - 10 - Question 9

Which of the following barriers does not come under innate immunity?

Detailed Solution for CSIR NET Life Sciences Mock Test - 10 - Question 9

Complex barrier does not come under innate immunity.

Innate immunity includes Physical barrier, Physiological barrier, Cellular barrier and Cytokine barrier.

CSIR NET Life Sciences Mock Test - 10 - Question 10

The dye used in Gram staining is:

Detailed Solution for CSIR NET Life Sciences Mock Test - 10 - Question 10

The dye used in Gram staining is Crystal violet .

The gram stain utilizes crystal violet as the primary stain. This basic dye is positively charged and, therefore, adheres to the cell membranes of both gram negative and positive cells. After applying crystal violet and waiting 60 seconds the excess stain is rinsed off with water.

CSIR NET Life Sciences Mock Test - 10 - Question 11

Which statement best describes the pKa of amino groups in proteins?

Detailed Solution for CSIR NET Life Sciences Mock Test - 10 - Question 11

pKa of a - amino group is lower than the pKa of E - amino group describes the pKa of amino groups in proteins.

The pKa value given for the amino group on any amino acid specifically refers to the equilibrium between the protonated positive nitrogen and deprotonated neutral nitrogen.

CSIR NET Life Sciences Mock Test - 10 - Question 12

An intermediate of the citric acid cycle that undergoes reductive amination with glutamine as nitrogen donor is ____________?

Detailed Solution for CSIR NET Life Sciences Mock Test - 10 - Question 12

α-ketoglutarate is the intermediate of the citric acid cycle that undergoes reductive amination with glutamine as nitrogen donor. Its carboxylate, α-ketoglutarate also called 2-oxoglutarate, is an important biological compound. It is the keto acid produced by deamination of glutamate, and is an intermediate in the Krebs cycle.

CSIR NET Life Sciences Mock Test - 10 - Question 13

The angiosperms were developed in:

Detailed Solution for CSIR NET Life Sciences Mock Test - 10 - Question 13

The angiosperms were developed in Coenozoic era.

Geological time refers to that period of Earth's history which can be studied geologically from the rocks.

Geological time scale is how that timeframe is sub-divided like a calendar for our understanding.

The fossils that are found in the rock strata helps in establishing the timeline for appearance or disappearance of species. It also helps us in studying the timelines of biological evolution of different species. It is divided into eons, eras, periods and epochs.

CSIR NET Life Sciences Mock Test - 10 - Question 14

Mark the one, which is NOT the characteristics of the guard cell?

Detailed Solution for CSIR NET Life Sciences Mock Test - 10 - Question 14

The epidermal cells of the guard cell show chloroplast. They have a thin outer wall and thick inner wall and constitute an important functional element of the plant.

CSIR NET Life Sciences Mock Test - 10 - Question 15

The amino acid with pKa closest to physiological pH is:

Detailed Solution for CSIR NET Life Sciences Mock Test - 10 - Question 15

Histidine is the amino acid with pka closest to physiological pH. It has pka of 6.8 and that is why it is found at the active - site of enzymes.

Histidine is also basic, but the pKa of its conjugate acid is close to physiological pH; as a result, it exists at physiological pH as a mixture of its positively charged, protonated form and its neutrally charged, deprotonated form.

CSIR NET Life Sciences Mock Test - 10 - Question 16

Which of the following is not related to embryo culture?

Detailed Solution for CSIR NET Life Sciences Mock Test - 10 - Question 16

Embryo culture is the technique of taking out young/fragile/dormant embryos from developing seeds and their growth on a culture medium to form seedlings and then young plants. This technique is useful in the multiplication of some rare plants, e.g., Makapuno Nut.

CSIR NET Life Sciences Mock Test - 10 - Question 17

In the human female, the fertilized eggs get implanted in the uterus:

Detailed Solution for CSIR NET Life Sciences Mock Test - 10 - Question 17

In the human female, the fertilized eggs get implanted in the uterus after about 7 days of fertilization.

  • The fertilization of the egg takes place somewhat in the middle of the fallopian tube.
  • The formed zygote undergoes continuous division and starts to travel and reaches the uterus in 4-5 days and the zygote is referred to as the morula.
  • In the uterus, the morula becomes a blastocyst and then gets implanted into the uterine wall in 7-8 days.
  • After 3 weeks of fertilization, the zygote is about 0.1mm in length.
  • After one month of fertilization, formation of the amniotic sac occurs which helps in the growth of the embryo. There is also the development of the placenta.
  • After two months of fertilization, the embryo is about 4-5 inches long. At this stage, the basic heart beating and development of the circulatory system occur. The umbilical cord also develops.

CSIR NET Life Sciences Mock Test - 10 - Question 18

What would be the number of chromosomes of the aleurone cells of a plant with 42 chromosomes in its roots tip cells?

Detailed Solution for CSIR NET Life Sciences Mock Test - 10 - Question 18

The number of chromosomes in the diploid cell of the root tip as given is 42, which means one set is of 21 chromosomes. So the cells of the aleurone layer of the given plant will have 63 chromosomes. Option B: The aleurone cells of the plant having 42 chromosomes in the root tip cells will have 63 chromosomes.

CSIR NET Life Sciences Mock Test - 10 - Question 19
Hormonal regulation of cardiac activity involves the hormones ___ and ____ secreted by the ____.
Detailed Solution for CSIR NET Life Sciences Mock Test - 10 - Question 19

Hormonal regulation of cardiac activity involves the hormones epinephrine and norepinephrine secreted by the medulla of adrenal glands. 

The renal medulla secretes two similar hormones: adrenaline( epinephrine) and noradrenaline( norepinephrine) that have almost the same basic effect.

Role of epinephrine and norepinephrine- They whip up metabolism for preparing the animal to face special conditions created by physical stress such as fall in BP or blood sugar, anger, fear etc..All these conditions require more energy which is provided by increasing heart rate, blood pressure, sugar level of blood. 

CSIR NET Life Sciences Mock Test - 10 - Question 20
In the rainy season, doors get swelled up due to :
Detailed Solution for CSIR NET Life Sciences Mock Test - 10 - Question 20

In rainy season, door gets swelled due to the phenomenon of imbibition. It is the process of absorption of water without forming a solution.

CSIR NET Life Sciences Mock Test - 10 - Question 21

Under a given renaturing condition E. coli DNA reassociates with a Cot ½ of 4.0 and an unknown DNA sample with a Cot ½ of 283. The complexity of this unknown DNA will be

Detailed Solution for CSIR NET Life Sciences Mock Test - 10 - Question 21

Genome size of E.coli/Genome size of unknown=Cot ½ of E.coli/Cot½ of unknown
4 X 106 bp / x = 4/283
x = 4 X 106 bp X 283/ 4
x = 283 X 106 bp
x = 2.83 X 108 bp

CSIR NET Life Sciences Mock Test - 10 - Question 22

Science that deals with the relationships between living organisms with their physical environment and with each other is called:

Detailed Solution for CSIR NET Life Sciences Mock Test - 10 - Question 22

Science that deals with the relationships between living organisms with their physical environment and with each other is called Ecology.

  • Ecology is the science that deals with the relationships between living organisms with their physical environment and with each other.
  • The term “ecology” was coined by the German zoologist, Ernst Haeckel, in 1866 to describe the “economies” of living forms.
  • Ecology can be approached from the viewpoints of 
  1. The environment and the demands it places on the organisms in it or
  2. Organisms and how they adapt to their environmental conditions.
  • An ecosystem consists of an assembly of mutually interacting organisms and their environment in which materials are interchanged in a largely cyclical manner. 

CSIR NET Life Sciences Mock Test - 10 - Question 23

The epidermis and rootcap are produced by:

Detailed Solution for CSIR NET Life Sciences Mock Test - 10 - Question 23

The epidermis and root cap are produced by dermatogen. The protoderm forms periblem, plerom, and dermatogen.

CSIR NET Life Sciences Mock Test - 10 - Question 24

Which of the following is wrongly matched in the given table:

Detailed Solution for CSIR NET Life Sciences Mock Test - 10 - Question 24

Virus is a microscopic, infectious agent that can multiply only inside living cells. They are considered to be non-cellular biological entities as they lack cellular structures. The nucleic acid present in the virus can be either DNA or RNA.

Viruses can be categorized based on their nucleic acids:

  • ds-DNA virus - They contain double-stranded DNA as their nucleic acid component.
  • ss-DNA virus - They have single-stranded DNA.
  • ds-RNA virus - They have double-stranded RNA molecule.
  • ss-RNA virus - They contain single-stranded RNA.

The given viruses and their corresponding nucleic acids are:

  • Poxvirus - ds DNA
  • Myxovirus - ss RNA
  • TMV (Tobacco Mosaic Virus) - ss RNA
  • Adenovirus - ds DNA

CSIR NET Life Sciences Mock Test - 10 - Question 25

Bacteriophage was discovered by:

Detailed Solution for CSIR NET Life Sciences Mock Test - 10 - Question 25

Bacteriophage was discovered by F. W. Twort and Felix d'Herelle independently.

Virology started when two bacteriologists, Frederick William Twort in 1915 and Félix d'Hérelle in 1917, freely found the presence of bacteriophages (viruses that infect bacteria). Félix d'Hérelle had coined the word 'bacteriophage' which literally means "bacteria eater".

Bacteriophages, commonly known as phages, are viruses that infect and reproduce in bacterial cells. They are omnipresent within the environment and are recognized as the foremost inexhaustible organic specialist on soil. They are amazingly different in the size, morphology, and genomic organization.

CSIR NET Life Sciences Mock Test - 10 - Question 26

Anaerobic respiration occurs in the absence of ________.

Detailed Solution for CSIR NET Life Sciences Mock Test - 10 - Question 26

​Anaerobic respiration does not need oxygen. It is the release of a relatively small amount of energy in cells by the breakdown of food substances in the absence of oxygen. Anaerobic respiration happens in muscles during hard exercise.

Anaerobic respiration is the type of respiration through which cells can break down sugars to generate energy in the absence of oxygen. This is in contrast to the highly efficient process of aerobic respiration, which relies on oxygen to produce energy.

Aerobic respiration is the process by which organisms use oxygen to burn fuel, such as fats and sugars, into chemical energy. In contrast, anaerobic respiration does not use oxygen. Respiration is used by all cells to turn fuel into energy that can be used to power cellular processes.

CSIR NET Life Sciences Mock Test - 10 - Question 27

In the question given below, there are two statements marked as Assertion (A) and Reason (R). Mark your answer as per the codes provided below:

Assertion: The direction of movement of organic solutes in the phloem is bidirectional.

Reason: The transportation depends on variability of source-sink relationship.

Detailed Solution for CSIR NET Life Sciences Mock Test - 10 - Question 27

'Both Assertion and Reason are correct and Reason is the correct explanation for Assertion'.

Phloem transport is the long distance movement of organic substances from the source or supply end (region of manufacture or storage) to the region of utilisation or sink. But the source and sink may be reversed depending on the season or need of the plants. Sugar stored in roots may be mobilized to become a source of food in the early spring when the buds of trees act as sink and require energy for their growth and development. Since the source- sink relationship is variable, the direction of movement of organic solutes in phloem can be upwards or downwards i.e., bidirectional.

CSIR NET Life Sciences Mock Test - 10 - Question 28

Which pair/s is/are Uvr component molecules scanning the DNA during nucleotide excision repair?
1. UvrB, UvrC
2. UvrB, UvrA
3. UvrD, UvrA
4. UvrA, UvrB

Detailed Solution for CSIR NET Life Sciences Mock Test - 10 - Question 28

Only pair 4 is correct.
In nucleotide excision repair complex of two UvrA and UvrB molecules scan the DNA with two UvrA subunits being responsible for detecting the distortions to the helix. Upon encountering a distortion, UvrA exits the complex and create a single stranded bubble with UvrB.

CSIR NET Life Sciences Mock Test - 10 - Question 29
The backbone of DNA is made up of?
Detailed Solution for CSIR NET Life Sciences Mock Test - 10 - Question 29

DNA is polymer of deoxyribonucleotides; each of which is made up of sugar, nitrogenous base and phosphate moiety. Two successive nucleotides are joined by phosphodiester bond between 3' hydroxyl of one nucleotide and 5' phosphate of next nucleotide. The hydrophilic backbones of alternating sugar and phosphate groups are present on the outside of the double helix facing the surrounding water. 

CSIR NET Life Sciences Mock Test - 10 - Question 30

Which of the following is also known as the removal of one or more bases from the nucleotide chain?

Detailed Solution for CSIR NET Life Sciences Mock Test - 10 - Question 30

The removal of one or more bases from the nucleotide chain is also known as deletion. Deletion is a type of frame-shift mutation. If we add one or more bases in a nucleotide chain, then it is called insertion.

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