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Physics Exam  >  Physics Tests  >  Topic wise Tests for IIT JAM Physics  >  Central Forces NAT Level – 1 - Physics MCQ

Central Forces NAT Level – 1 - Physics MCQ


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10 Questions MCQ Test Topic wise Tests for IIT JAM Physics - Central Forces NAT Level – 1

Central Forces NAT Level – 1 for Physics 2024 is part of Topic wise Tests for IIT JAM Physics preparation. The Central Forces NAT Level – 1 questions and answers have been prepared according to the Physics exam syllabus.The Central Forces NAT Level – 1 MCQs are made for Physics 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Central Forces NAT Level – 1 below.
Solutions of Central Forces NAT Level – 1 questions in English are available as part of our Topic wise Tests for IIT JAM Physics for Physics & Central Forces NAT Level – 1 solutions in Hindi for Topic wise Tests for IIT JAM Physics course. Download more important topics, notes, lectures and mock test series for Physics Exam by signing up for free. Attempt Central Forces NAT Level – 1 | 10 questions in 30 minutes | Mock test for Physics preparation | Free important questions MCQ to study Topic wise Tests for IIT JAM Physics for Physics Exam | Download free PDF with solutions
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Central Forces NAT Level – 1 - Question 1
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The change in the value of g at a height h above the surface of the earth is the same as at a depth d below that surface of earth. When both d and h are much smaller than the radius of earth, then, d = αh. Find the value of  α.


Detailed Solution for Central Forces NAT Level – 1 - Question 1

The gravitational field inside the earth is given by  where r is the distance from centre


The correct answer is: 2

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Central Forces NAT Level – 1 - Question 2
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Energy required to move a body of mass m  from an orbit of radius 2R  to 3R  is  Find the value of  α


Detailed Solution for Central Forces NAT Level – 1 - Question 2

The correct answer is: 12

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Central Forces NAT Level – 1 - Question 3
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A satellite in a circular orbit of radius r has time period of  4hrs. A satellite with orbital radius of 4r around the same planet will have a time period of in hours.


Detailed Solution for Central Forces NAT Level – 1 - Question 3

Radius of orbit of the first satellite

R1 = R

Time period of the first satellite T = 4 hrs. and radius of orbit of second satellite = 4r
The time period of satellite is given by


The correct answer is: 32

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Central Forces NAT Level – 1 - Question 4
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The minimum and maximum distances of a satellite from the centre of earth are 2R and 4R respectively, where R is the radius of earth and M is the mass of the earth. The radius of curvature at the point of minimum distance is λR.  Find the value of λ.

Detailed Solution for Central Forces NAT Level – 1 - Question 4

Applying conservation of angular momentum



From conservation of energy

Solving Eqs. (1) and (2), we get

If r is the radius of curvature at point A

The correct answer is: 2.667

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Central Forces NAT Level – 1 - Question 5
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Maximum height reached by a rocket fired with a speed equal to 50% of the escape velocity from Earth’s surface is R/α. Find the value of α.

Detailed Solution for Central Forces NAT Level – 1 - Question 5


Applying energy conservation


The correct answer is: 3

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Central Forces NAT Level – 1 - Question 6
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Two satellites S1 and S2 of equal masses revolves in the same sense around a heavy planet in coplanar circular orbit of radii R and 4R. Find the value of 

Detailed Solution for Central Forces NAT Level – 1 - Question 6

 V=√(GM/r)
⇒ V1/V2 = (4/1)1/2
⇒ V1/V2 = 2/1

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Central Forces NAT Level – 1 - Question 7
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Radius of the earth is R and the means density is ρ. Find out the gravitational potential at the earth’s surface απGρR2.  Find the value of  α.

Detailed Solution for Central Forces NAT Level – 1 - Question 7

The correct answer is: -1.333

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Central Forces NAT Level – 1 - Question 8
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A body which is initially at rest at a height R above the surface of the earth of radius R, falls freely towards the earth. Find out its velocity (in m/s) on reaching the surface of earth. 

Take g = 10m/s2 and R = 6400km.

Detailed Solution for Central Forces NAT Level – 1 - Question 8

Potential energy at ground surface 
Potential energy 

potential energy at a height of R is 
potential energy 
When a body comes to ground
Loss in potential energy = Gain in kinetic energy

The correct answer is: 8000

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Central Forces NAT Level – 1 - Question 9
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A particle is projected from the surface of earth with an initial speed of 4.0km/s. Find the maximum height (in kms) attained by the particle.

Detailed Solution for Central Forces NAT Level – 1 - Question 9

Radius of earth = 6400km and  the maximum height attained by the particle is,  and   g = 9.8 m/s2. 
Substituting the value, 


or h = 935km
The correct answer is: 935

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Central Forces NAT Level – 1 - Question 10
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The orbital velocity of an artificial satellite in a circular orbit just above the earth’s surface is V0. The value of orbital velocity for another satellite orbiting at an altitude of half of earth’s radius is  Find the value of  α.

Detailed Solution for Central Forces NAT Level – 1 - Question 10

For first satellite 

For second satellite 

The correct answer is: 0.667

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