DSSSB PGT Chemistry Mock Test - 6 - DSSSB TGT/PGT/PRT MCQ

M-travels in car X
T-+Q as given in Y
J-no female, and travels in Z
R-car X(sequential)
D-car Y
W-female with Z
Q-X
hence correct option is C.

Numbers obtained in three throws are 5,3 and 6
Let the number obtained in fourth throw be x
Now, Sum > 20
5 + 3 + 6 + x > 20
14 + x > 20
x > 6(never wins)

x > 1 and x > -1
Take two points 1,-1 on number line
Therefore x > 1

In this type of problem, the formula is"

Here, H is replaced by the first interval of given time and t is spaces apart.
Given that H is 5.

 mins or 24 mins
Therefore, the hands will by 3 minutes apart at 336/11 minutes or 24 minutes past 5.

From the given conditions, A > B > C > D = F ≥ G < H.

1. G > C → C > D = F ≥ G, C > G → False.

2. B > F → B > C > D = F, B > F → True.

3. G > F → D = F ≥ G < H, F ≥ G → False.

4. D < G → D = F ≥ G, D ≥ G → False.

So, B > F is the correct inequality.

Answer: A. Ashoka wanted to control both the land and sea routes to south India, and any hostile power obstructing the route would have had to be conquered.

Explanation:
- The Kalinga war took place in 261 BCE when the Mauryan Emperor Ashoka invaded the kingdom of Kalinga, which lay along the eastern coast of India.
- There were multiple factors that contributed to the war, but the primary reason was Ashoka's ambition to control both the land and sea routes to south India.
- South India was a major source of wealth and resources for trade, and controlling these routes would enhance the prosperity and power of the Mauryan empire.
- Kalinga was a strategically important region as it lay between the Mauryan Empire and the southern kingdoms, and its control would ensure uninterrupted access to these trade routes.
- The hostile power of Kalinga obstructing the route made it necessary for Ashoka to conquer the region in order to secure the trade routes and further expand the Mauryan empire.
- Although other factors such as Kalinga's growing power, the piracy by the Nagas, and its potential threat to the Mauryan empire might have played a role, the primary cause of the war was Ashoka's ambition to control the land and sea routes to south India.

The Chola kingdom known as Cholamandalam, was situated to the northeast of the Pandya territory between Pennar and Velar Rivers. Sangam literature throws light on the fact that their center of political power was Uraiyur, an important center of cotton products and their most important port was Puhar or Kaveripattinam.

• It was in the news due to Nepalese constitution issues.

• The Northern plains can be divided into four regions - two are discussed here.

• After descending from the mountains, the rivers deposit pebbles in a narrow belt of about 8 to 16km in width lying parallel to the slopes of the Shivalik. It is known as bhabar.

• All the streams disappear in this bhabar belt. South of this belt, the streams and rivers re-emerge and create a wet, swampy and marshy region known as terai. This was a thickly forested region full of wildlife. The forests have been cleared to create agricultural land and to settle migrants from Pakistan after partition.

Let C = x.
Then, B = x + 5000 and A = x + 5000 + 4000 = x + 9000
So, x + x + 5000 + x + 9000 = 50000
⇒ 3x = 36000
⇒ x = 12000
A : B : C = 21000 : 17000 : 12000 = 21 : 17 : 12
So A's Share

Assume that a container contains x of liquid from which y units are taken out and replaced by water. After n operations, the quantity of pure liquid

Hence milk now contained by the container = 40

Let capacity of bucket P = x
Then capacity of bucket Q =  x/3
Given that it takes 80 turns for bucket P  to fill the empty drum
⇒ capacity of the drum = 80x
Number of turns required if both P and Q are used = 

"बेइंसाफी" में प्रयुक्त उपसर्ग "बे" है।
उपसर्ग, वह अव्यय है जो किसी शब्द के पहले लगकर शब्द का अर्थ परिवर्तित कर देता है।

जिस संज्ञा के शब्द से पुरुष जाति का ज्ञात होता है, उसे पुल्लिंग कहते हैं।
"भवानी" का पुल्लिंग "भव" हैं।

"अतिथि" का उचित पर्यायवाची शब्द "आगंतुक" है।
अतिथि के अन्य पर्यायवाची- पहुना, मेहमान, अभ्यागत।
एक ही अर्थ में प्रयुक्त होने वाले शब्द, जो बनावट में भले ही अलग हों, को पर्यायवाची शब्द कहते है। 
पर्यायवाची शब्द को समानार्थी शब्द भी कहा जाता है।

• एक-दूसरे के विपरीत अर्थ देने वाले शब्द, विलोम कहलाते है।
• बंधन का अर्थ- बँधने या बाँधने की अवस्था या भाव।
• मोक्ष का अर्थ- मुक्ति, छुटकारा।

गद्यांश के अनुसार-
"मुझे पता है कि यहाँ जो लोग जुटते हैं वे गरीब लोग होते हैं। अपने काम-धाम के बीच रोटी खाने चले आते हैं और खाकर चले जाते हैं। ये आमतौर पर बिहार से आए गरीब ईमानदार लोग हैं जो हमारे इस परिसर के स्थायी सदस्य हो गए हैं। ये उन अशिष्ट अमीरों से भिन्न हैं जो साधारण-सी बात पर भी हंगामा खड़ा कर देते हैं। लोगों के पास पैसा तो आ गया पर धनी होने का स्वर नहीं आया।"

"बहाव" शब्द में प्रयुक्त प्रत्यय "आव" है।
प्रत्यय, वह अव्यय है जो किसी शब्द के बाद लगकर शब्द का अर्थ परिवर्तित कर देता है।

• "चरण कमल बंदौ हरिराई" में रूपक अलंकार है।

जब गुण की अत्यंत समानता के कारण उपमेय को ही उपमान बता दिया जाए अर्थार्थ उपमेय ओर उपमान में अभिन्नता दर्शायी जाए तब वह रूपक अलंकार कहलाता है।

Sol.    = 1 p and  = 2 for d.

 Now Cr has configuration

1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁵ 4s¹

Hence there are 12, p-electrons and 5, d-electrons

Adsorption and absorption is commonly known as sorption.

The catalytic reaction that depends upon the structure of pores of the catalyst and the size of the reactant and product molecules is called shape/selective catalysis. Zeolites are good shape selective catalysts because of their honeycomb structure. 

The correct answer is Option D.
Electrophoresis movement of colloidal particles towards an electrode, when they are subjected to an electrical field.

Role of catalyst is to decrease the activation energy of reaction.

Oxidation Numbers in Oxygen Difluoride (OF₂) and Dioxygen Difluoride (O₂F₂)

Oxidation numbers are assigned to elements in compounds according to several rules. Here, we'll use the rule that states the oxidation number of fluorine (F) in a compound is always -1, and the rule that states the sum of oxidation numbers of all atoms in a compound is 0.

Oxidation Number in OF₂:

• In Oxygen Difluoride (OF₂), there are two fluorine atoms, each with an oxidation number of -1. So, the total oxidation number contributed by fluorine is -2.
• To mak e the total oxidation number 0, the oxygen atom must have an oxidation number of +2.

Oxidation Number in O₂F₂:

• In Dioxygen Difluoride (O₂F₂), there are two fluorine atoms, each with an oxidation number of -1. So, the total oxidation number contributed by fluorine is -2.
• There are also two oxygen atoms. To make the total oxidation number 0, the combined oxidation number of the two oxygen atoms must be +2.
• Therefore, the oxidation number of each oxygen atom in O₂F₂ is +1 (because +2 divided by 2 equals +1).

So, in OF₂ and O₂F₂, the oxygen is assigned an oxidation number of +2 and +1, respectively. Therefore, the correct answer is B: +2 and +1.

The correct answer is option D
The statement D is false.
Two sucrose solutions of the same molality prepared in different solvents will have different freezing point depression. This is because the molal depression in freezing point constant K_b​ is different for different solvents.
The freezing point depression = ΔT_f​=K_b​×m
Here, m is the molality of sucrose solution.

The correct answer is option D
For Na₂​SO₄ ​: −i = n
Na₂​SO₄ ​⟶ 2Na⁺ + SO₄²⁻​​
                         n=2
i=1−α+nα
i=1−α+2α
i=1+2α

pi-bond is always formed by sidewise overlapping of p – p orbitals in sidewise manner.

There are several ways to tell metals and nonmetals apart. Nonmetalsdon't have a metallic appearance. Unlike metals, they typically have lower melting and boiling points and tend not to conduct heat or electricity very well.

Ionic hydrides are commonly known as saline hydrides or pseudohalides. These compounds form between hydrogen and the most active metals, especially with the alkali and alkaline-earth metals of group one and two elements.

In this group, the hydrogen acts as the hydride ion (H−). They bond with more electropositive metal atoms. Ionic hydrides are usually binary compounds (i.e., only two elements in the compound) and are also insoluble in solutions. Now I hope you can form your own examples, but common examples are Sodium Hydride (NaH), Lithium hydride (LiH), Potassium hydride (KH) etc.