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DSSSB PGT Physics Mock Test - 2 - DSSSB TGT/PGT/PRT MCQ


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30 Questions MCQ Test DSSSB PGT Mock Test Series 2024 - DSSSB PGT Physics Mock Test - 2

DSSSB PGT Physics Mock Test - 2 for DSSSB TGT/PGT/PRT 2024 is part of DSSSB PGT Mock Test Series 2024 preparation. The DSSSB PGT Physics Mock Test - 2 questions and answers have been prepared according to the DSSSB TGT/PGT/PRT exam syllabus.The DSSSB PGT Physics Mock Test - 2 MCQs are made for DSSSB TGT/PGT/PRT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for DSSSB PGT Physics Mock Test - 2 below.
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DSSSB PGT Physics Mock Test - 2 - Question 1

Physical quantities are:

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 1
  • A physical quantity is a physical property of a phenomenon, body, or substance, that can be quantified by measurement.
  • A physical quantity can be expressed as the combination of a magnitude expressed by a number – usually a real number – and a unit.
  • All these given above can be expressed as explained so these are physical quantity.
DSSSB PGT Physics Mock Test - 2 - Question 2

Vectors can be added by

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 2

Explanation:The sum of two or more vectors is called the resultant. The resultant of two vectors can be found using either the triangle method or the parallelogram method.

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DSSSB PGT Physics Mock Test - 2 - Question 3

The path of a projectile is 

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 3

Explanation:A particle with a vertical and horizontal velocity travelling in a gravitational field will trace out a parabola.

DSSSB PGT Physics Mock Test - 2 - Question 4

The reason why cyclists bank when taking a sharp turn is

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 4

Explanation:In order to take a safe turn, the cyclist has to bend a little from his vertical position. In this case, a component of the reaction provides the required centripetal force.If q is angle made by the cyclist with the vertical then

In actual practice, the value of q is slightly less because the force of friction also contributes towards the centripetal force.

DSSSB PGT Physics Mock Test - 2 - Question 5

A block rests on a rough inclined plane making an angle of 30° with the horizontal. The coefficient of static friction between the block and the plane is 0.8. If the frictional force on the block is 10 N, the mass of the block (in kg) is (g = 10 m/s2

[AIEEE 2004]

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 5

Let mass of the block be m.

Frictional force in rest position F = mg sin 300

[This is static frictional force and may be less than the limiting frictional force]

DSSSB PGT Physics Mock Test - 2 - Question 6

As per the given figure, two blocks each of mass 250 g are connected to a spring of spring constant 2 Nm-1. If both are given velocity v in opposite directions, then maximum elongation of the spring is:

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 6


Using energy conservation,

DSSSB PGT Physics Mock Test - 2 - Question 7

A body of mass 0.5 kg travels on a straight line path with velocity v = (3x2 + 4) m/s. The net work done by the force during its displacement from x = 0 to x = 2 m is:

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 7

Given,
Mass = 0.5 kg
At x = 0
vi = 3(02) + 4 = 4
At x = 2
vf = 3(2)2 + 4
= 16

DSSSB PGT Physics Mock Test - 2 - Question 8

A free electron of 2.6 eV energy collides with a H+ ion. This results in the formation of a hydrogen atom in the first excited state and a photon is released. Find the frequency of the emitted photon (h = 6.6 × 10-34 J s).

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 8

For every large distance, P.E. = 0
Total energy = 2.6 + 0 = 2.6 eV
Finally, in the first excited state of H atom, total energy = -3.4 eV
Loss in total energy = 2.6 - (-3.4) = 6 eV
It is emitted as photon.

= 1.45 × 109 MHz

DSSSB PGT Physics Mock Test - 2 - Question 9

When does the potential energy of a spring increase?

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 9

Potential energy of a spring is proportional to the square of the difference of the springs length and its original length, hence whether it is compressed or stretched the potential the potential energy will eventually increase only.

DSSSB PGT Physics Mock Test - 2 - Question 10

Two identical thin uniform rods of length L each are joined to form T shape as shown in the figure. The distance of centre of mass from D is  

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 10


On solving we get 3L/4
 

DSSSB PGT Physics Mock Test - 2 - Question 11

Two particles of equal masses have velocities    First particle has an acceleration    while the acceleration of the other particle is zero. The centre of mass of the two particles moves in a path of  

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 11



DSSSB PGT Physics Mock Test - 2 - Question 12

A body of mass m moving at a constant velocity v hits another body of the same mass moving with a velocity v/2 but in the opposite direction and sticks to it. The common velocity after collision is 

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 12


Hence v = v/4
 

DSSSB PGT Physics Mock Test - 2 - Question 13

What is the force required to produce an acceleration of 9.8 m/s2 on a body of weight 9.8N? Take g = 9.8 m/s2.

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 13

Acceleration (a) = 9.8 m/s2

Weight of the body = 9.8 N

Since, Weight of the body = mg

⇒ Mass = Weight/g = 9.8/9.8 = 1 kg

We know that,

F = m × a

⇒ F = 1 kg × 9.8 m/s2

⇒ F = 9.8 Newton

DSSSB PGT Physics Mock Test - 2 - Question 14

What pulls a ball back to earth?

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 14

The gravitational force of the earth acts on every object having mass. When a ball is thrown upwards the gravitational force of the earth acts against the velocity of the object and pulls the ball downwards, i.e, towards itself.

Thus, gravity pulls a ball back to earth.

DSSSB PGT Physics Mock Test - 2 - Question 15

The earth attracts the moon with a gravitational force of 1020 N. Then the moon attracts the earth with the gravitational force of  

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 15

The universal law of gravitation:

  • Sir Isaac Newton put forward the universal law of gravitation in 1687 and used it to explain the observed motions of the planets and moons.
  • The law states that every particle attracts every other particle in the universe with force directly proportional to the product of the masses and inversely proportional to the square of the distance between them.
  • Formula, Gravitational force,  where, F is the gravitational force between bodies, m1, and m2 are the masses of the bodies, d is the distance between the centers of two bodies, and G is the universal gravitational constant.
  • Here, universal gravitational constant, G = 6.67 × 10-11 Nm/kg2

  • The Universal Gravitational Law can explain almost anything, right from how an apple falls from a tree to why the moon revolves around the Earth.

Newton's third law of motion

  • It states that for every action, there is an equal and opposite reaction.
  • Action and reaction always act on two different bodies.

Explanation:

By Newton's Third Law and Newton's Law of Universal gravitation, the gravitational force the Earth exerts on the Moon is exactly the same as the force the Moon exerts on the Earth. 
F(Earth) = F(Moon)
Therefore, the moon attracts the earth with a gravitational force of 1020N.

DSSSB PGT Physics Mock Test - 2 - Question 16

Both earth and moon are subject to the gravitational force of the sun. As observed from the sun, the orbit of the moon

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 16

Concept:

Newton's law of gravitation: The force of attraction between any objects in the universe is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

  • The force acts along the line joining the two bodies.
  • The gravitational force is a central force that is It acts along the line joining the centers of two bodies.
  • It is a conservative force. This means that the work done by the gravitational force in displacing a body from one point to another is only dependent on the initial and final positions of the body and is independent of the path followed.


 

  • The moon revolves around the earth in a circular orbit (not perfectly circular). Sun exerts a gravitational force on both, the earth and moon. The major force acting on the moon is due to the gravitational force of attraction of the sun and earth and the moon is not always on the line joining the sun and earth. 
  • Two forces acting on the moon have different lines of action or the forces are not central, so it's motion will not be strictly elliptical.

Hence, option (2) is the correct answer.

DSSSB PGT Physics Mock Test - 2 - Question 17

As observed from earth, the sun appears to move in an approximate circular orbit. For the motion of another planet like mercury as observed from earth, this would

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 17

Concept:

Newton's law of gravitation: The force of attraction between any objects in the universe is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

  • The force acts along the line joining the two bodies.
  • The gravitational force is a central force that is It acts along the line joining the centers of two bodies.
  • It is a conservative force. This means that the work done by the gravitational force in displacing a body from one point to another is only dependent on the initial and final positions of the body and is independent of the path followed.

Explanation:

  • The gravitational force on mercury due to the sun is very large than that due to the earth.
  • As observed from the earth, the sun appears to move around the earth in a circular orbit though, in reality, the earth moves around the sun due to gravitational force between them
  • All planets move around the sun due to the huge gravitational force of the sun acting on them.
  • Since the gravitational force on mercury due to the earth is smaller as compared to that on it due to the sun therefore it revolves around the sun and not around the earth.

Hence, option (3) is the correct answer.

DSSSB PGT Physics Mock Test - 2 - Question 18

A 200-kg load is hung on a wire with a length of 4.00 m, a cross-sectional area of 0.200 × 10−4 m2, and a Young’s modulus of 8.00 × 1010N/ m2. What is its increase in length?

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 18

DSSSB PGT Physics Mock Test - 2 - Question 19

If a person studies about a fluid which is at rest, what will you call his domain of study?

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 19

Fluid Mechanics deals with the study of fluid at rest or in motion with or without the consideration of forces, Fluid Statics is the study of fluid at rest, Fluid Kinematics is the study of fluid in motion without consideration of forces and Fluid Dynamics is the study of fluid in motion considering the application forces.

DSSSB PGT Physics Mock Test - 2 - Question 20

According to the Stefan-Boltzmann law of thermal radiation for a perfect radiator, the rate of radiant energy per unit area is proportional to

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 20

The rate of loss of heat by a body is directly proportional to its excess temperature over that of the surroundings provided that this excess is small.

DSSSB PGT Physics Mock Test - 2 - Question 21

Suppose we have a box filled with gas and a piston is also attached at the top of the box.What are the ways of changing the state of gas (and hence its internal energy)?

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 21

As change of state depends on both temperature and pressure, so, either method A or C can be used. We can understand this by ideal gas equation PV = nRT

DSSSB PGT Physics Mock Test - 2 - Question 22

Kelvin- Planck statement states that

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 22

It works on the principle that no machine is 100% efficient. For instance if taking an ideal machine into consideration, work can be completely converted to heat. Now if the conditions are reversed, all heat cannot be converted to equal amount of work until and unless backed up by an external force.

DSSSB PGT Physics Mock Test - 2 - Question 23

Value of gas constant, R for one mole of a gas is independent of the

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 23

We know that PV=nRT also PM=dRT
So in the equation The value of R depends on P , V , n , T , d , M
except atomicity 
 so the ans is A

DSSSB PGT Physics Mock Test - 2 - Question 24

If Q =2 coloumb and force on it is F=100 newtons , Then the value of field intensity will be

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 24

Electric force on a charge q placed in a region o electric field intensity is E and it is given by F = qE.
In this case, F = 100 N and q = 2 C.
So, E=F/q​=100N/2C​=50 N/C.
Hence, the value of field intensity will be 50 N/C.

DSSSB PGT Physics Mock Test - 2 - Question 25

The electric field intensity at a point situated 4 meters from a point charge is 200 N/C. If the distance is reduced to 2 meters, the field intensity will be

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 25

Field intensity is proportional to the inverse of the square of the distance separating the point charges:

F = k*q1*q2/d^2

Since k, q1, and q2 are assumed to be constant, their product can be combined to form a single constant:

K = k*q1*q2, so

F = K/d^2 (and by algebraic manipulation we have K=F*d^2).

Therefore we know that

F(at d=4) = K/4^2, and

F(at d=2) = K/2^2.

Since K is a constant, we can equate K=F*d^2 for each case:

K=F(at d=4)*4^2 = F(at d=2)*2^2

so

F(at d=2) = (F(at d=4)*4^2)/2^2

F(at d=2) = 200N/C * (4^2)/(2^2) = 200N/C *16/4 = 800N/C.

DSSSB PGT Physics Mock Test - 2 - Question 26

Gauss Law can be used to compute which of the following?

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 26

Gauss law relates the electric flux density and the charge density. Thus it can be used to compute the radius of the Gaussian surface. Permittivity and permeability are constants for a particular material.

DSSSB PGT Physics Mock Test - 2 - Question 27

When number of identical cells, in parallel combination are increased, the voltage of the circuit will

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 27

The voltage developed by the cells in parallel connection cannot be increased by increasing the number of cells present in the circuit. It is because they do not have the same circular path. In parallel connection the connection provides power based on one cell.
The voltage will remain the same.

DSSSB PGT Physics Mock Test - 2 - Question 28

An infinitely long conductor PQR is bent to form a right angle as shown in Figure. A current I flows through PQR. The magnetic field due to this current at the point M is H1. Now, another infinitely long straight conductor QS is connected at Q so that current is I/2 in QR as well as in QS, the current in PQ remaining unchanged. The magnetic field at M is now H2. The ratio H1/H2 is given by

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 28

Case 1 : Magnetic field at M due to PQ and QR is

Case 2 : When wire QS is joined.
H2 = (Magnetic field at M due to PQ) + (magnetic field at M due to QR) + (Magnetic field at M due to QS)

NOTE : The magnetic field due to an infinitely long wire carrying current at a distance R from the end point is half that at a distance R from the middle point.

DSSSB PGT Physics Mock Test - 2 - Question 29

A coil having N turns is wound tightly in the form of a spiral with inner and outer radii a and b respectively. When a current I passes through the coil, the magnetic field at the center is

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 29

Let us consider a thickness dx of wire. Let it be at a distance x from the centre O.

Number of turns per unit length

∴ Number of turns in thickness dx =dx

Small amount of magnetic field is produced at O due to thickness dx of the wire.

On integrating, we get,

 

DSSSB PGT Physics Mock Test - 2 - Question 30

Which of the following statements about bar magnets is correct ?

Detailed Solution for DSSSB PGT Physics Mock Test - 2 - Question 30

Explanation:As magnetic monopole does not exist. If we split the bar magnet into two pieces  each part will have its own north and south pole.

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