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DSSSB PGT Physics Mock Test - 3 - DSSSB TGT/PGT/PRT MCQ


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30 Questions MCQ Test DSSSB PGT Mock Test Series 2025 - DSSSB PGT Physics Mock Test - 3

DSSSB PGT Physics Mock Test - 3 for DSSSB TGT/PGT/PRT 2025 is part of DSSSB PGT Mock Test Series 2025 preparation. The DSSSB PGT Physics Mock Test - 3 questions and answers have been prepared according to the DSSSB TGT/PGT/PRT exam syllabus.The DSSSB PGT Physics Mock Test - 3 MCQs are made for DSSSB TGT/PGT/PRT 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for DSSSB PGT Physics Mock Test - 3 below.
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DSSSB PGT Physics Mock Test - 3 - Question 1

Which of the following statement is wrong ?

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 1

The incorrect statement is:

d) Unit of surface tension is Newton metre.

The correct unit of surface tension is Newton per metre (N/m), not Newton metre.

Here's a breakdown:

  • a) Unit of K.E. is Newton-metre: True, because kinetic energy is measured in joules, and 1 joule equals 1 Newton-metre.
  • b) Unit of viscosity is poise: True, poise is indeed a unit of dynamic viscosity.
  • c) Work and energy have the same dimensions: True, both work and energy have the same dimensions and are measured in joules.
  • d) Unit of surface tension is Newton metre: Incorrect, it should be Newton per metre (N/m).
DSSSB PGT Physics Mock Test - 3 - Question 2

 A ball is released from the top of a tower of height h meter. It takes T seconds to reach the ground. What is the position of the ball in T/3 seconds?   

[AIEEE 2004]

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 2

Second law of motion gives:

DSSSB PGT Physics Mock Test - 3 - Question 3

Two vectors are equal if

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 3

Explanation:Equal vectors are vectors that have the same magnitude and the same direction. Equal vectors may start at different positions.

DSSSB PGT Physics Mock Test - 3 - Question 4

Rain is falling vertically with the speed of 30 m/s. A man rides a bicycle with the speed of 10 m/s in east to west direction. What is the direction in which he should hold the umbrella?

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 4

When the man rides, he should put an umbrella in the opposite direction to which the drops are falling with respect to him.
Hence wrt man, the speed of rain drop is
at an angle of tan-1
Hence he would put umbrella to the direction of tan-1

DSSSB PGT Physics Mock Test - 3 - Question 5

A particle of mass 0.3 kg is subjected to a force F = - kx with k = 15 Nm-1. What will be its initial acceleration, if it is released from a point 20 cm away from the origin ?   

 [AIEEE 2005]

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 5

Given,

m= 0.3 kg, x = 20cm and k = 15N/m

F= -kx    ..(i)
and F = ma    ..(ii)
∴   ma = -kx

DSSSB PGT Physics Mock Test - 3 - Question 6

A block is kept on a frictionless inclined surface with angle of inclination a. The incline is given an acceleration a to keep the block stationary. Then a is equal to    

[AIEEE 2005]

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 6

In the frame of wedge, the force diagram of block is shown in figure. From free body diagram of wedge.

For block to remain stationary

ma cos α = mg sin α

or         a = g tan α

DSSSB PGT Physics Mock Test - 3 - Question 7

Which one belongs to a different class?

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 7

Concept:

Conservative force:

  • Work done due to conservative force in a loop is always zero.
  • Work done due to conservative force is only depending on the initial and final position.
  • E.g. Gravity force, spring force, Electrostatic force, Magnetic force.

Non-conservative force:

  • Work done due to non-conservative force on loop is not zero.
  • Work done due to non-conservative force is depending on the path.
  • E.g. Friction force, Viscous force.

Explanation:

  • The frictional force is not a conservative force.
  • Magnetic force, static electric force, and Gravitational force are the conservative forces.
  • Work done by Gravitational force depends upon the initial position and final position of the object while it is falling from a height. 
  • It doesn't matter it is falling through steps, frictionless inclined plane, or just through from height. 
  • This is not the case with frictional force. The work done by a fictional force depends upon the path taken.
  • So, the correct option is frictional force
DSSSB PGT Physics Mock Test - 3 - Question 8

A particle of mass 1 kg is hanging from a spring of force constant 100 Nm-1. The mass is pulled slightly downward and released, so that it executes free simple harmonic motion with time period T. The time when the kinetic energy and potential energy of the system will become equal is The value of x is _______. (in integers)

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 8

The time when the kinetic energy and potential energy of the system become equal can be determined as follows:

The condition for equal kinetic and potential energy is given by:
Kinetic Energy (KE) = Potential Energy (PE)

⇒  A2 = 2x2

The displacement X is given by: X = A sin(ωt)

Solving these equations, 

A2 = 2x2

X = A sinωt

x = 8 sec

DSSSB PGT Physics Mock Test - 3 - Question 9

Which physical quantity is conserved during both elastic and inelastic collision?

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 9

Momentum is conserved in all types of collision whether it is elastic or inelastic where as kinetic energy is lost in sound energy in the absence of external force in inelastic collision.

DSSSB PGT Physics Mock Test - 3 - Question 10

Which of the following force is non-conservative

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 10

Force between two stationary mass is gravitational force which is conservative. between two charge is electrostatic. muscular force is non conservative because we did work it lost or appear in form of heat and we need to eat food to gain energy for work done.

DSSSB PGT Physics Mock Test - 3 - Question 11

A body dropped from height H reaches the ground with a speed of showimage (1)

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 11

The forces acting on the body are the force of gravity and the air friction. By work energy theorem, the total work done on the body is
W=1/2m(1.2√gH)2−0=0.72mgH
The work done by the force of gravity is mgH.
. Hence, the work done by the air friction is,
=0.72mgH-mgH
=00.28mgH.
 

DSSSB PGT Physics Mock Test - 3 - Question 12

The height above surface of earth where the value of gravitational acceleration is one fourth of that at surface, will be

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 12

To find the height above the Earth's surface where the gravitational acceleration is one-fourth of its value at the surface, we can use the formula for gravitational acceleration:

Thus, the height at which the gravitational acceleration is one-fourth of that at the Earth's surface is Re

DSSSB PGT Physics Mock Test - 3 - Question 13

The value of escape velocity on earth when the body is thrown making an angle of 45o with the horizontal is

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 13

 Escape velocity does not depend on the angle of projection. Escape velocity will remain the same.
Hence, escape velocity is 11.2km/s .

DSSSB PGT Physics Mock Test - 3 - Question 14

When a solid is deformed,

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 14

Explanation:External force permanently distubed the equilibrium position of the interatomic ( or intermolecular ) forces between the particles of solid bodies.

DSSSB PGT Physics Mock Test - 3 - Question 15

Which of the following statement is true for a thermodynamical system where ∆U is the increase in internal energy and ∆W work done respectively?

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 15

∆ U = ∆ Q - ∆ W
In an adiabatic process ∆Q is zero, therefore
∆ U = - ∆ W

DSSSB PGT Physics Mock Test - 3 - Question 16

A carnot engine is taking 700 cal from source and is rejecting 500 cal to the sink in each cycle. What is the temperature of sink if the source temperature is 150° C .

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 16

Heat extracted from source Q1= 700 cal
Heat rejected to the sink Q2= 500 cal
Temperature of source T1= 150 +273= 423K
Temperature of sink T2 to be found:
 Q2/Q1 = T2/T1
So,
T2 = (Q2/Q1) x T1
= (500 x 423)/700
= 302.02 K
= 29.02 degree C.
 

DSSSB PGT Physics Mock Test - 3 - Question 17

Two particles executing SHM with same angular frequency and amplitude A and 2A same 
straight line with same position cross other in opposite direction at a distance A/3 from mean position. The phase difference between the two SHM’s is

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 17

Let particle (1) is moving towards right and particle (2) is moving towards left art this instant, 1 = 0 

DSSSB PGT Physics Mock Test - 3 - Question 18

The displacement of the motion of a particle is represented (in metre) by the equation  The motion of the particle is 

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 18

 

∴ Amplitude is 0.4 m and motion is SHM.

DSSSB PGT Physics Mock Test - 3 - Question 19

What should be the radius of an isolated spherical conductor so that it has a capacity of 2μF?​

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 19

Capacitance of an isolated spherical conductor =4π€R , where €=permittivity of vacuum
C=2×10-6F
C=4π€R
4×3.14×8.85×10-12×R=2×10-6
R=2×10-6/4×3.14×8.85×10-12
=1.8×104 m

DSSSB PGT Physics Mock Test - 3 - Question 20

A capacitor is charged using an exter nal batter y with a resistance x in series. The dashed line shows the variation of ln I with respect to time. If the resistance is changed to 2x, the new graph will be 

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 20

KEY CONCEPT : The current in RC circuit is given by I = I0e–t/RC

On comparing with y = mx + C

When R is changed to 2R then slope increases and current becomes less. New graph is Q.

DSSSB PGT Physics Mock Test - 3 - Question 21

Find out the value of current through 2Ω resistance for the given circuit.

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 21

The current in 2W resistor will be zero because it is not a part of any closed loop.

DSSSB PGT Physics Mock Test - 3 - Question 22

A thin flexible wire of length L is connected to two adjacent fixed points and carries a current I in the clockwise direction, as shown in the figure. When the system is put in a uniform magnetic field of strength B going into the plane of the paper, the wire takes the shape of a circle. The tension in the wire is

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 22

Let us consider an elemental length dl subtending an angle dθ at the centre of the circle. Let FB be the magnetic force acting on this length. Then

FB = BI (dl)  directed upwards as shown

= BI (Rdθ)              

Let T be the tension in the wire acting along both ends of the elemental length as shown. On resolving T, we find that the components. cancel out and
the components.  add up to balance FB.
At equilibrium  

 

 

 

 

DSSSB PGT Physics Mock Test - 3 - Question 23

Which among the following has a relative permeability much larger than 1?

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 23

The relative permeability of ferromagnetic materials is much larger than 1. Ferromagnetic substances are those, which when placed in a magnetic field are strongly magnetized in the direction of the magnetizing field, i.e., it is strongly attracted by a magnet.

DSSSB PGT Physics Mock Test - 3 - Question 24

A light bulb is rated at 50W for a 220 V supply. The resistance of the bulb, the peak voltage of the source and the rms current through the bulb are

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 24

Given    P=50W, Vrms​=220V,
by     P=Vrms2​​/R
or      R=Vrms2/P​​= 2202/50=968Ω
The peak voltage of the source is,
Erms=E0/√2
=>E0=Erms x √2=220√2=311.13V
Now, 
Irms​=Vrms​​/R
=220/968​
=0.227A
Hence option B is correct.

DSSSB PGT Physics Mock Test - 3 - Question 25

What is the natural frequency of an LC oscillator?

DSSSB PGT Physics Mock Test - 3 - Question 26

What is the average power consumed/cycle in ideal capacitor.​

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 26

Pav=(V0i0/2) cosθ
In ideal capacitor θ= -π2
Cosθ=Cosθ(-π/2)=0
Therefore
Pav=0

DSSSB PGT Physics Mock Test - 3 - Question 27

At resonance the impedance of RLC circuit is

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 27

Resonance is a condition in LCR circuit where the inductive reactance ( XL) and capacitive reactance (Xc) is equal.
Impedance at resonance is equal to the Resistance of the resistor because the other two cancel themselves off according to the below formula -
Z2=R2+(XL2-Xc2)
As XL = Xc ,
Z = R
 

DSSSB PGT Physics Mock Test - 3 - Question 28

Critical angle is

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 28

The Critical Angle
a light ray is in the more dense medium and approaching the less dense medium.
The angle of incidence for the light ray is greater than the so-called critical angle.
When the angle of incidence in water reaches a certain critical value, the refracted ray lies along the boundary, having an angle of refraction of 90-degrees. This angle of incidence is known as the critical angle; it is the largest angle of incidence for which refraction can still occur. For any angle of incidence greater than the critical angle, light will undergo total internal reflection.

DSSSB PGT Physics Mock Test - 3 - Question 29

The average power dissipation in a pure capacitor in AC circuit is

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 29
Why Power in pure Capacitive Circuit is Zero (0)
Pure inductive circuit, current is lagging by 90 degree from voltage ( in other words, Voltage is leading 90 Degree from current) i.e the pahse difference between current and voltage is 90 degree. 
So  If Current and Voltage are 90 Degree Out of Phase, Then The Power (P) will be zero. The reason is that,
We know that Power in AC Circuit
P= V I Cos φ
if angle between current and Voltage are 90 ( φ = 90) Degree. then
Power P = V I Cos ( 90) = 0
[ Note that Cos (90) = 0]So if you put Cos 90 = 0→Then Power will be Zero (In pure Inductive circuit)
DSSSB PGT Physics Mock Test - 3 - Question 30

Which of these mechanisms can be used to produce electromagnetic waves?

Detailed Solution for DSSSB PGT Physics Mock Test - 3 - Question 30

The electromagnetic waves are produced by vibration of an electric charge. This creates a wave which is both as electric and magnetic components. This way oscillates in perpendicular planes with respect to each other and in a phase.This creates all electromagnetic waves begin with an oscillating charged particle which creates an oscillating electric and magnetic field.

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