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DSSSB TGT Natural Science Mock Test - 9 - DSSSB TGT/PGT/PRT MCQ


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30 Questions MCQ Test DSSSB TGT Mock Test Series 2025 - DSSSB TGT Natural Science Mock Test - 9

DSSSB TGT Natural Science Mock Test - 9 for DSSSB TGT/PGT/PRT 2025 is part of DSSSB TGT Mock Test Series 2025 preparation. The DSSSB TGT Natural Science Mock Test - 9 questions and answers have been prepared according to the DSSSB TGT/PGT/PRT exam syllabus.The DSSSB TGT Natural Science Mock Test - 9 MCQs are made for DSSSB TGT/PGT/PRT 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for DSSSB TGT Natural Science Mock Test - 9 below.
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DSSSB TGT Natural Science Mock Test - 9 - Question 1

Members of the Legislative assembly (MLAs) elected by the

Detailed Solution for DSSSB TGT Natural Science Mock Test - 9 - Question 1

The correct option is Option B.
A Member of the Legislative Assembly (MLA) is a representative elected by the voters of an electoral district (constituency) to the legislature of the State government in the Indian system of government. From each constituency, the people elect one representative who then becomes a member of the Legislative Assembly (MLA).
 

DSSSB TGT Natural Science Mock Test - 9 - Question 2

Gandhiji started Satyagraha in 1919 to protest against the

DSSSB TGT Natural Science Mock Test - 9 - Question 3

Who was named as the Wisden Cricketer of the Year 1980?

Detailed Solution for DSSSB TGT Natural Science Mock Test - 9 - Question 3
Sunil Gavaskar played his last ODI in Mumbai in 1987 and then retired.
DSSSB TGT Natural Science Mock Test - 9 - Question 4

Gobar gas contains mainly –

Detailed Solution for DSSSB TGT Natural Science Mock Test - 9 - Question 4

Bio gas is a clean unpolluted and cheap source of energy in rural areas. It consists of 55-70% methane which is inflammable. Bio gas is produced from cattle dung in a bio gas plant commonly known as gobar gas plant through a process called digestion. It helps in reducing the deforestation as it arrests for cutting of trees for firewood. It also helps in maintaining ecological balance, in rural sanitation and it needs Lower capital cost and almost cost free maintenance.

DSSSB TGT Natural Science Mock Test - 9 - Question 5

According to 2011 Census, the State having maximum population is–

Detailed Solution for DSSSB TGT Natural Science Mock Test - 9 - Question 5

With total population of 19,98,12,341, Uttar Pradesh is the most heavily populated state of India as per the 2011 Census. It constitutes 16.51% of India's population. Maharashtra and Bihar come next with respective contributions of 9.28% and 8.60% to the national population.

DSSSB TGT Natural Science Mock Test - 9 - Question 6

As per Census of India, an Urban area with a population from 50,000 to 99,999 is named as –

Detailed Solution for DSSSB TGT Natural Science Mock Test - 9 - Question 6

The Census of India groups all towns and urban agglomerations into the following six classes according to population size:  
Class I: population of 100,000 and above
Class II: population of 50,000 to 99,999
Class III: population of 20,000 to 49,999
Class IV: population of 10,000 to 19,999
Class V: population of 5,000 to 9,999
Class VI: population less than 5,000

DSSSB TGT Natural Science Mock Test - 9 - Question 7

The Name of the Laccadive, Minicoy and Amindivi Islands was changed, to Lakshadweep by an act of parliament in -

Detailed Solution for DSSSB TGT Natural Science Mock Test - 9 - Question 7

In 1956, during the reorganization of Indian states, the Lakshadweep islands were organized into a separate union territory for administrative purposes. The name of this Union Territory was changed to Lakshadweep with effect from November 1, 1973.

DSSSB TGT Natural Science Mock Test - 9 - Question 8

The original founder of the Manuscripts and Editor of Kautilya's Athashastra was -

Detailed Solution for DSSSB TGT Natural Science Mock Test - 9 - Question 8

In 1905, R. Ramashashtry discovered and published the Arthashastra, an ancient Indian treatise on state craft. He transcribed, edited and published the Sanskrit edition in 1909. He proceeded to translate it into English, publishing it in 1915.

DSSSB TGT Natural Science Mock Test - 9 - Question 9

With reference to National Industrial Corridor Development Corporation (NICDC) Limited, consider the following statements.
1. It has been formed by renaming Delhi Mumbai Industrial Development Corporation Limited after the expansion of its mandate.
2. Government of India and Japan Bank for International Cooperation are its shareholders.
3. Its mandate is to develop and implement all industrial corridor projects in the country.

Which of the statements given above are correct?

Detailed Solution for DSSSB TGT Natural Science Mock Test - 9 - Question 9
  • National Industrial Corridor Development Programme is India's most ambitious infrastructure programme aiming to develop new industrial cities as "Smart Cities" and converging next generation technologies across infrastructure sectors.
  • Delhi Mumbai Industrial Corridor Development Corporation (DMICDC) Limited, a special purpose company, was incorporated to establish, promote and facilitate development of Delhi Mumbai Industrial Corridor Project.
  • Further, after announcement of other Industrial Corridor Projects, the mandate of DMICDC Ltd. has been expanded to develop and implement all Industrial Corridor Projects in the country and accordingly, the name has been changed to National Industrial Corridor Development Corporation (NICDC) Limited. Hence statement 1 and statement 3 are correct.
  • NICDC is mandated to undertake project development activities for Investment Regions/Industrial Areas/ Economic Regions / Industrial Nodes and Township etc.
  • The shareholding of NICDC is as follows:
    1. Govt of India – 49% o Japan Bank for International Cooperation – 26%
    2. Housing and Urban Development Corporation Ltd – 19.9%
    3. India Infrastructure Finance Company Ltd – 4.1%
    4. LIC – 1%

Hence statement 2 is correct.

DSSSB TGT Natural Science Mock Test - 9 - Question 10

Where was the three-day All-India Taekwondo Championship recently inaugurated?

Detailed Solution for DSSSB TGT Natural Science Mock Test - 9 - Question 10

The three-day All-India Taekwondo Championship was recently inaugurated in New Delhi.

DSSSB TGT Natural Science Mock Test - 9 - Question 11

Which country's Prime Minister Giorgia Meloni will be the chief guest at the 8th Raisina Dialogue?

Detailed Solution for DSSSB TGT Natural Science Mock Test - 9 - Question 11

Italian Prime Minister Giorgia Meloni will be the chief guest at the 8th Raisina Dialogue.

DSSSB TGT Natural Science Mock Test - 9 - Question 12

Which birth anniversary of Sant Sevalal Maharaj has been celebrated recently?

Detailed Solution for DSSSB TGT Natural Science Mock Test - 9 - Question 12

The 284th birth anniversary of Sant Sevalal Maharaj has been celebrated recently.

DSSSB TGT Natural Science Mock Test - 9 - Question 13

Manju is at a fixed point, from where she goes 20 metres towards West. From there she goes 10 metres towards Notrh. Then she goes 35 metres towards East and after this she goes 5 metres towards South and in the end she goes 15 metres towards West. How far is she from the fixed point?

Detailed Solution for DSSSB TGT Natural Science Mock Test - 9 - Question 13

Let's analyze Manju's movements step by step:
Initial position:

- Manju is at a fixed point (let's call this point A).
First Movement:
- She goes 20 meters towards West.
- Let's call this point B.
Second Movement:
- From point B, she goes 10 meters towards North.
- Let's call this point C.
Third Movement:
- From point C, she goes 35 meters towards East.
- Let's call this point D.
Fourth Movement:
- From point D, she goes 5 meters towards South.
- Let's call this point E.
Fifth Movement:
- From point E, she goes 15 meters towards West.
- Let's call this point F.
Now, we need to find the distance between point A and point F.
- Since Manju initially moved 20 meters West and then moved an additional 15 meters West in her last movement, she is a total of 35 meters West from her starting point A.
- However, she also moved 35 meters East from point C to point D, which brings her back to the same vertical line as her starting point A.
- Considering her North and South movements, she moved a total of 10 meters North and 5 meters South, resulting in a net movement of 5 meters North from point A.
Now, we can use the Pythagorean theorem to find the distance between points A and F:
AF = √((Horizontal Distance)² + (Vertical Distance)²)
AF = √((0 meters)² + (5 meters)²)
AF = √(25)
AF = 5 meters
So, Manju is 5 meters away from her initial fixed point.
Answer: **A: 5 km** (Note: It should be "5 meters" instead of "5 km" in the options)

DSSSB TGT Natural Science Mock Test - 9 - Question 14

Directions to Solve

In each of the following questions two statements are given. Which are followed by four conclusions (1), (2), (3) and (4). Choose the conclusions which logically follow from the given statements.

Question -

Statements: All men are vertebrates. Some mammals are vertebrates.

Conclusions:

  1. All men are mammals.
  2. All mammals are men.
  3. Some vertebrates are mammals.
  4. All vertebrates are men.
Detailed Solution for DSSSB TGT Natural Science Mock Test - 9 - Question 14

DSSSB TGT Natural Science Mock Test - 9 - Question 15

Directions to Solve

In each of the following questions two statements are given. Which are followed by four conclusions (1), (2), (3) and (4). Choose the conclusions which logically follow from the given statements.

Question -

Statements: All the phones are scales. All the scales are calculators.

Conclusions:

  1. All the calculators are scales.
  2. All the phones are calculators
  3. All the scales are phones.
  4. Some calculators are phones.
Detailed Solution for DSSSB TGT Natural Science Mock Test - 9 - Question 15

DSSSB TGT Natural Science Mock Test - 9 - Question 16

If P $ Q means P is the brother of Q; P # Q means P is the mother of Q; P * Q means P is the daughter of Q in A # B $ C * D, who is the father?

Detailed Solution for DSSSB TGT Natural Science Mock Test - 9 - Question 16

A is the mother of B, B is the brother of C and C is the daughter of D. Hence, D is the father.

DSSSB TGT Natural Science Mock Test - 9 - Question 17

Directions to Solve

Five girls are sitting on a bench to be photographed. Seema is to the left of Rani and to the right of Bindu. Mary is to the right of Rani. Reeta is between Rani and Mary.

Question - Who is in the middle of the photograph?

Detailed Solution for DSSSB TGT Natural Science Mock Test - 9 - Question 17

Rani is in the middle of the photograph.

DSSSB TGT Natural Science Mock Test - 9 - Question 18

If A = 2, M = 26, Z = 52, then BET = ?

Detailed Solution for DSSSB TGT Natural Science Mock Test - 9 - Question 18

Clearly, each letter is assigned a numerical value which is twice the numeral denoting its position in the English alphabet.
B, E and T are 2nd, 5th and 20th letters respectively.
So, BET = B + E + T = (2 × 2) + (5 × 2) + (20 × 2) = 54.

DSSSB TGT Natural Science Mock Test - 9 - Question 19

In a certain code, the word DEAL is coded as 4 – 5 – 1 – 12. Following the same rule of coding, what should e the code for the word LADY?

Detailed Solution for DSSSB TGT Natural Science Mock Test - 9 - Question 19

Clearly, each letter is coded by the numeral denoting its position in the English alphabet,
Thus, A is coded as 1, B as 2, C as 3, D as 4,…………, I, as 12, M as 13……., Y as 25, Z as 26. So, the code for LADY is 12 – 1 – 4 – 25.

DSSSB TGT Natural Science Mock Test - 9 - Question 20

Directions: Study the following information carefully and answer the question given below.
Eight people O, H, U, V, I, D, B and G are sitting around a circular table facing the centre. 
O is sitting second to the left of U and third to right of H. D and I are immediate neighbors of  each other and one of them is an immediate neighbor of O. V is sitting second to the right of B. G is sitting second to the left of D.

Q. Starting from B’s position, if all the eight were arranged in alphabetical order in clockwise direction the seating position of how many members (excluding B) does not change?

Detailed Solution for DSSSB TGT Natural Science Mock Test - 9 - Question 20

Following the final seating arrangement, we can say position of none of the members remains the same if we arrange all alphabetically as given in the question. 
Hence, the correct answer is option A.

Common Explanation:
Reference:
O is sitting second to the left of U and third to right of H.

Inference:
 
Reference:
D and I are immediate neighbors of  each other but one of them is an immediate neighbor of O. 
V is sitting second to the right of B.

Inference:
Here, we can place D and I as follows:

Reference:
G is sitting second to the left of D.
 
Inference:
To fix these two positions, we will have to place D to the immediate right of H. Thus, we get the final arrangement as:

DSSSB TGT Natural Science Mock Test - 9 - Question 21

The following line graph gives the percent profit earned by two Companies X and Y during the period 1996 - 2001.

Percentage profit earned by Two Companies X and Y over the Given Years

Q.
If the expenditures of Company X and Y in 1996 were equal and the total income of the two Companies in 1996 was Rs. 342   crores, what was the total profit of the two Companies together in 1996? (Profit = Income - Expenditure)

Detailed Solution for DSSSB TGT Natural Science Mock Test - 9 - Question 21

The correct answer is D as ,
Total Income = 342 cr
Income in percentage = 140+145=285%
Expenditure per year= 200×342/285 = 240 cr
So total profit in 1996 = 342 - 240 = 102 cr.

DSSSB TGT Natural Science Mock Test - 9 - Question 22

A sum of money placed at compound interest doubles itself in 3 years. In how many years will it amount to 8 times itself?

Detailed Solution for DSSSB TGT Natural Science Mock Test - 9 - Question 22

If it doubles in 3 years, it would become 4 times in 6 year and 8 times in 9 years.

DSSSB TGT Natural Science Mock Test - 9 - Question 23

Solve the following

Detailed Solution for DSSSB TGT Natural Science Mock Test - 9 - Question 23

Let the unknown number be x

On squaring both sides, we get
12 + 15 + 11x = 49   (444/37 = 12)
11x + 27 = 49
x = 2

So Option C is correct

DSSSB TGT Natural Science Mock Test - 9 - Question 24

In a college all the students are made to stand in four rows. 4 rows contains 12, 8, 22, 30 students respectively. Find the least number of students in the college?

Detailed Solution for DSSSB TGT Natural Science Mock Test - 9 - Question 24

LCM (12, 8, 22, 30) = 3960

DSSSB TGT Natural Science Mock Test - 9 - Question 25

A is thrice as good a work man as B and takes 10 days less to do a piece of work than B takes. The number of days taken by B to finish the work is:

Detailed Solution for DSSSB TGT Natural Science Mock Test - 9 - Question 25


(Since number of days are inversely proportional to the efficiency)
Now if A requires x days, so B requires 3x days.
∴ Difference of required days = (3x - x) = 2x = 10
    ► ⇒ x = 5
Hence the number of days required by
   ► B = 3x = 3 x 5 = 15 days

DSSSB TGT Natural Science Mock Test - 9 - Question 26

Ajit is 3 times as efficient as Bablu, then the ratio of number of days required by each to work alone, completely?

Detailed Solution for DSSSB TGT Natural Science Mock Test - 9 - Question 26

DSSSB TGT Natural Science Mock Test - 9 - Question 27

P and Q are two different mouth fresheners, prepared by mixing Supari and Saunf in the ratios 9 : 4 and 9 : 17, respectively. If equal quantities of the P and Q mouth fresheners are mixed to form a third kind of mouth freshener R, find the ratio of Saunf and Supari in R.

Detailed Solution for DSSSB TGT Natural Science Mock Test - 9 - Question 27

In P, quantity of Supari = 9/13
And quantity of Saunf = 4/13
In Q, quantity of Supari = 9/26
And quantity of Saunf = 17/26
When we add these two
mouth fresheners:
Total quantity of Supari = 
Total quantity of Saunf = 
So, ratio of Saunf and Supari in R = 25 : 27

DSSSB TGT Natural Science Mock Test - 9 - Question 28

A and B invested the same amount of money in shares. After one month, A and B both sold their shares. A got P% loss, whereas B got P% profit. With this amount of money, they again purchased shares and sold them after one month. But this time, A got P% profit, whereas B got P% loss. Finally, who has more money?

Detailed Solution for DSSSB TGT Natural Science Mock Test - 9 - Question 28

If A and B invest Rs. 100 each and assuming the profit to be Rs. 10, after one month, A has Rs. 90 and B has Rs. 110. The next month A has Rs. 99 and B also has Rs. 99.

DSSSB TGT Natural Science Mock Test - 9 - Question 29

Increasing the height of a cone by 9 units increases its volume by x cubic units. Increasing its radius by 6 units also increases its volume by x cubic units. If the original height is 3 units, then the original radius is _____.

Detailed Solution for DSSSB TGT Natural Science Mock Test - 9 - Question 29

Let the initial volume of the cone be

After increasing the radius by 6 units, new volume 


After increasing the height by 9 units, new volume


By putting the value of x in equation (i), we get:

9r2 = h[36 + 12r]

By putting the value of h in above equation, we get: 
9r2 = 3[36 + 12r]
3r2 - 12r - 36 = 0
r2 - 4r - 12 = 0
r2 - 6r + 2r - 12 = 0
r = 6 units

DSSSB TGT Natural Science Mock Test - 9 - Question 30

A sealed bottle, which contains water, has been constructed by attaching a cylinder of radius 1 cm to a cylinder of radius 3 cm, as shown in Figure A. When the bottle is upright, the height of the water is 20 cm, as shown in the cross section of the bottle in Figure B. When the bottle is upside down, the height of the liquid is 28 cm, as shown in Figure C. What is the total height (in cm) of the bottle?

Detailed Solution for DSSSB TGT Natural Science Mock Test - 9 - Question 30

We'll start by denoting the height of the large cylinder by h1 and the height of the small cylinder by h2. For simplicity, we'll suppose x = h1 + h2.
If the bottom cylinder is completely filled and the top cylinder is only partially filled, the top cylinder will have a cylindrical space that is not filled. This cylindrical space will have a height equal to x - 20 and a volume equal to π(1)2(x - 20).
Similarly, if we turn the bottle upside down, there will be cylindrical space unfilled that will have a height equal to x - 28 and a volume equal to π(3)2(x - 28).
Since these two unoccupied spaces must be equal, we can write:
π(1)2(x - 20) = π(3)2(x - 28)
x - 20 = 9x - 252
8x = 232
x = 29
Therefore, the total height is 29 cm.

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