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Digital Electronics NAT Level - 2 - Free MCQ Test with solutions for Physics


MCQ Practice Test & Solutions: Digital Electronics NAT Level - 2 (10 Questions)

You can prepare effectively for Physics Topic wise Tests for IIT JAM Physics with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Digital Electronics NAT Level - 2". These 10 questions have been designed by the experts with the latest curriculum of Physics 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 45 minutes
  • - Number of Questions: 10

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*Answer can only contain numeric values
Digital Electronics NAT Level - 2 - Question 1

The minimum number of NAND gates required to implement ?


Detailed Solution: Question 1


Hence, minimum number of NAND gates required to implement
 is zero.
The correct answer is: 0

*Answer can only contain numeric values
Digital Electronics NAT Level - 2 - Question 2

The output of the circuit in the figure is equal to.


Detailed Solution: Question 2


The correct answer is: 0

*Answer can only contain numeric values
Digital Electronics NAT Level - 2 - Question 3

What will be the output of the logic gate formed by the circuit drawn below for inputs 


Detailed Solution: Question 3

The above figure behaves as a NAND gate, hence for  and output = 0
The correct answer is: 0

*Answer can only contain numeric values
Digital Electronics NAT Level - 2 - Question 4

What is the output of the Boolean expression for the output of the logic circuit drawn below for A = B = C = 1


Detailed Solution: Question 4


The correct answer is: 1

*Answer can only contain numeric values
Digital Electronics NAT Level - 2 - Question 5

What is the output for X = 1, Y = 0 for the logic circuit drawn below :


Detailed Solution: Question 5

The truth table for the above circuit is.

Hence, for X = 1, Y = 0, output = 1
The correct answer is: 1 

*Answer can only contain numeric values
Digital Electronics NAT Level - 2 - Question 6

The Boolean expression   can be realized by how many minimum number of gates?


Detailed Solution: Question 6


Hence one two input AND gate is required.
∴ Minimum number of gate = 1.
The correct answer is: 1

*Answer can only contain numeric values
Digital Electronics NAT Level - 2 - Question 7

Find the output for A = 1, B = 0, C = 1.


Detailed Solution: Question 7



The correct answer is: 1

*Answer can only contain numeric values
Digital Electronics NAT Level - 2 - Question 8

Assuming that only the X and Y logic inputs are available and their complements and  are not available, what is the minimum number of two-input NAND gates require to implement 


Detailed Solution: Question 8


The correct answer is: 5

*Answer can only contain numeric values
Digital Electronics NAT Level - 2 - Question 9

Consider following gate network which of the following gate is redundant write the gate number____ ?


Detailed Solution: Question 9

Before gate Number 2 being remove, output

⇒ gate number 2 is redundant.
The correct answer is: 2

*Answer can only contain numeric values
Digital Electronics NAT Level - 2 - Question 10

The logic function is defined as:

f = [(x AND y) OR (z AND NOT x)] AND [NOT (x XOR z)]

Evaluate the output of the function for:

  • x = 1
  • y = 0
  • z = 1


Detailed Solution: Question 10

Solution:

  • Step 1: Simplify the first part:
    • (x AND y):
    • x = 1, y = 0 → (x AND y) = 1 AND 0 = 0.
    • (z AND NOT x):
    • z = 1, NOT x = 0 → (z AND NOT x) = 1 AND 0 = 0.
    • (x AND y) OR (z AND NOT x):
    • 0 OR 0 = 0.
  • Step 2: Simplify the second part:
    • (x XOR z):
    • x = 1, z = 1 → (x XOR z) = 0 (since XOR is true only if inputs are different).
    • NOT (x XOR z) = NOT 0 = 1.
  • Step 3: Combine both parts:
    • f = [(x AND y) OR (z AND NOT x)] AND [NOT (x XOR z)]
    • f = 0 AND 1 = 0.

Final Answer:

The value of f is 0.

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