EMRS Exam  >  EMRS Tests  >  EMRS PGT Mock Test Series 2024  >  EMRS PGT Mathematics Mock Test - 9 - EMRS MCQ

EMRS PGT Mathematics Mock Test - 9 - EMRS MCQ


Test Description

30 Questions MCQ Test EMRS PGT Mock Test Series 2024 - EMRS PGT Mathematics Mock Test - 9

EMRS PGT Mathematics Mock Test - 9 for EMRS 2024 is part of EMRS PGT Mock Test Series 2024 preparation. The EMRS PGT Mathematics Mock Test - 9 questions and answers have been prepared according to the EMRS exam syllabus.The EMRS PGT Mathematics Mock Test - 9 MCQs are made for EMRS 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for EMRS PGT Mathematics Mock Test - 9 below.
Solutions of EMRS PGT Mathematics Mock Test - 9 questions in English are available as part of our EMRS PGT Mock Test Series 2024 for EMRS & EMRS PGT Mathematics Mock Test - 9 solutions in Hindi for EMRS PGT Mock Test Series 2024 course. Download more important topics, notes, lectures and mock test series for EMRS Exam by signing up for free. Attempt EMRS PGT Mathematics Mock Test - 9 | 150 questions in 180 minutes | Mock test for EMRS preparation | Free important questions MCQ to study EMRS PGT Mock Test Series 2024 for EMRS Exam | Download free PDF with solutions
EMRS PGT Mathematics Mock Test - 9 - Question 1

Which planet is known as Blue Planet?

Detailed Solution for EMRS PGT Mathematics Mock Test - 9 - Question 1

The correct answer is Earth.

Key Points

  • From the sun, it is the third planet.
  • Life existed only on this planet.
  • Around 4.5 billion years ago, the earth was formed.
  • Inside the solar system, the earth is a rocky planet.
  • Earth moves around the sun due to the large mass of the sun.
  • In space, the earth also turns around.
  • At different times, a different part of the earth is faced by the sun.
  • A large amount of liquid water is found only on the earth.
  • Water covers around 74 percent area of the earth.
  • From different places, the earth's water came.
  • Of all the rocky planets, the earth is the largest.
  • As compared to Jupiter, it is very small.

Hence, the Earth is known as a blue planet.

EMRS PGT Mathematics Mock Test - 9 - Question 2

If ROSE is coded as 6821, CHAIR is coded as 73456 and PREACH is coded as 961473, then what will be the code for SEARCH?

Detailed Solution for EMRS PGT Mathematics Mock Test - 9 - Question 2

The logic followed is:

ROSE is coded as 6821

CHAIR is coded as 73456

PREACH is coded as 961473

Therefore SEARCH will be written as

Hence, the correct answer is "214673".

1 Crore+ students have signed up on EduRev. Have you? Download the App
EMRS PGT Mathematics Mock Test - 9 - Question 3

To qualify in Hockey and Football, minimum age required is 13 years and 15 years respectively, minimum weight required is 50 kgs and 56 kgs respectively, and maximum height allowed is 160 cms and 165 cms respectively. Vasudha is 13 years old, has a weight of 48 kgs, and has a height of 161 cms. For which of these games is she eligible?  

Detailed Solution for EMRS PGT Mathematics Mock Test - 9 - Question 3

The logic follows here is:

Now,

Vasudha is 13 years old, has a weight of 48 kgs and a height of 161 cms.

It is clearly mentioned in the criteria of Hockey and Football about the weight of the candidate. Vasudha has a weight of 48 kgs which is less than the criteria set for both games. Therefore, Vasudha neither qualifies for Hockey nor for Football.

Hence, the correct answer is "Neither Hockey nor Football".

EMRS PGT Mathematics Mock Test - 9 - Question 4

Find out which answer figures will exactly make up the question figure?

Detailed Solution for EMRS PGT Mathematics Mock Test - 9 - Question 4

EMRS PGT Mathematics Mock Test - 9 - Question 5

The first cell in Excel worksheet is labeled as:

Detailed Solution for EMRS PGT Mathematics Mock Test - 9 - Question 5

The first cell in EXCEL worksheet Is labeled as "A1"

EMRS PGT Mathematics Mock Test - 9 - Question 6

 1) A play queue is a ___________ song listing that allows you to easily select and sort sound tracks.

EMRS PGT Mathematics Mock Test - 9 - Question 7

Rohit is an above average intelligence student. He has always been praised by his teachers for his academic progress in the class. But, recently his achievement was not up to satisfaction. Which of the following could be a reason for his poor performance?

Detailed Solution for EMRS PGT Mathematics Mock Test - 9 - Question 7

The cause of Rohit's poor performance can be either physical problems, family disturbances or his maturation process.
Rohit may not be physically fit or may be suffering from some physical ailment, which might be affecting his studies and resulting in poor performance.
There may be some disturbances at home, which may be affecting his studies. A construction work at home or a fight amongst elders could be the reason behind his recent performance.
The mental capabilities of Rohit are maturing but maybe not up to the level that is required to understand the concepts taught in the class. Thus, he might be performing poorly.
Apart from this, the teacher might lack the required knowledge of modern educational and psychological theories. This can lead to students' poor academic performance. Several other factors also lead to poor academic achievement, such as social factors, economic factors and political conditions.

EMRS PGT Mathematics Mock Test - 9 - Question 8

Which of these is a method of evaluating the delivery of a course through the gathering of feedback from the learner on the level of the knowledge they acquired after the completion of the instruction?

Detailed Solution for EMRS PGT Mathematics Mock Test - 9 - Question 8

A knowledge survey is a method of evaluating the delivery of a course through the gathering of feedback from the learner on the level of the knowledge they acquired after the completion of the instruction. It usually consists of questions that cover the content of the course. The surveys evaluate student learning and content mastery at all levels: from basic knowledge and comprehension through higher levels of thinking. Knowledge surveys can serve as both formative and summative assessment tools.

EMRS PGT Mathematics Mock Test - 9 - Question 9

A teaching aid cannot

Detailed Solution for EMRS PGT Mathematics Mock Test - 9 - Question 9

A teaching aid cannot prevent behavioural problems. Proper psychological treatment is required to deal with behavioural problems. Teaching aid is a means used by teachers for facilitating learning among pupils. They reinforce learning and do not address any behavioural problems.

EMRS PGT Mathematics Mock Test - 9 - Question 10

If f : R → S, defined by

f (x) = sin x - √3 cosx+ 1, is onto, then the interval of S is

Detailed Solution for EMRS PGT Mathematics Mock Test - 9 - Question 10

f (x) is onto ∴ S = range of f (x)


EMRS PGT Mathematics Mock Test - 9 - Question 11

The value of  is:

Detailed Solution for EMRS PGT Mathematics Mock Test - 9 - Question 11

∫(-3 to 3) (x+1)dx

=  ∫(-3 to -1) (x+1)dx +  ∫(-1 to 3) (x+1) dx 

= [x2 + x](-3 to -1) + [x2 + x](-1 to 3)

= [½ - 1 - (9/2 - 3)] + [9/2 + 3 - (½ - 1)]

= -[-4 + 2] + [4 + 4]

= -[-2] + [8]

= 10

EMRS PGT Mathematics Mock Test - 9 - Question 12

A circle C and the circle x2 + y2 = 1 are orthogonal and have radical axis parallel to y-axis, then C can be  

Detailed Solution for EMRS PGT Mathematics Mock Test - 9 - Question 12

(A) The  radical axis of the circle x2 + y2 = 1 and the circle given in is x = -2, which is | | to y-axis 
(B) is y = 2, which is | | to x-axis
(C) is x = 0, which is y-axis 
The radical axis with circle in (A) | | to y-axis and the given circle intersect circle given in A orthogonally. 

EMRS PGT Mathematics Mock Test - 9 - Question 13

Detailed Solution for EMRS PGT Mathematics Mock Test - 9 - Question 13

Since g(x) and h(x) are integrals of the same function , therefore ; g(x) – h(x) is constant.

EMRS PGT Mathematics Mock Test - 9 - Question 14

The area enclosed by the parabola y2 = 2x and its tangents through the point (-2 , 0) is

Detailed Solution for EMRS PGT Mathematics Mock Test - 9 - Question 14


EMRS PGT Mathematics Mock Test - 9 - Question 15

The point from which the tangents to the circles x2 + y2 – 8x + 40 = 0,  5x2 + 5y2 – 25 x + 80 = 0, x2 + y2 – 8x + 16y + 160 = 0 are equal in length is

Detailed Solution for EMRS PGT Mathematics Mock Test - 9 - Question 15

The Required point is the radical centre of the three given circles. The radical axes of the three circles taken in pairs are 3x - 24 = 0,16y + 120 = 0 and - 3x + 16y + 80 = 0. On solving, the required point is (8, -15/2).

EMRS PGT Mathematics Mock Test - 9 - Question 16

If f (x)  then f (1) is equal to

Detailed Solution for EMRS PGT Mathematics Mock Test - 9 - Question 16

EMRS PGT Mathematics Mock Test - 9 - Question 17

The domain of the function f = {(1, 3), (3, 5), (2, 6)} is

Detailed Solution for EMRS PGT Mathematics Mock Test - 9 - Question 17

The domain in ordered pair (x,y) is represented by x-coordinate. Therefore, the domain of the given function is given by : {1, 3, 2}.

EMRS PGT Mathematics Mock Test - 9 - Question 18

The equation of the circle passing through (0, 0) and making intercepts a and b on the coordinate axes is:

Detailed Solution for EMRS PGT Mathematics Mock Test - 9 - Question 18

Let the equation of the required circle be (x – h)2 + (y – k)2 = r2.
Since the centre of the circle passes through (0, 0),
(0 – h)2 + (0 – k)2 = r2
⇒ h2 + k2 = r2
The equation of the circle now becomes (x – h)2 + (y – k)2 = h2 + k2.
It is given that the circle makes intercepts a and b on the coordinate axes. This means that the circle passes through points (a, 0) and (0, b). Therefore,
(a – h)2 + (0 – k)2 = h2 + k2 …………… (1)
(0 – h)2 + (b – k)2 = h2 + k2 ………… (2)
From equation (1), we obtain a2 – 2ah + h2 + k2 = h2 + k2
⇒ a2 – 2ah = 0
⇒ a(a – 2h) = 0
⇒ a = 0 or (a – 2h) = 0
However, a ≠ 0; hence, (a – 2h) = 0 ⇒ h =a/2.
From equation (2), we obtain h2 + b2 – 2bk + k2 = h2 + k2
⇒ b2 – 2bk = 0
⇒ b(b – 2k) = 0
⇒ b = 0 or(b – 2k) = 0
However, b ≠ 0; hence, (b – 2k) = 0 ⇒ k =b/2. Thus, the equation of the required circle is

EMRS PGT Mathematics Mock Test - 9 - Question 19

In which quadrant are sin, cos and tan positive?

Detailed Solution for EMRS PGT Mathematics Mock Test - 9 - Question 19
  • All three of them are positive in Quadrant I
  • Sine only is positive in Quadrant II
  • Tangent only is positive in Quadrant III
  • Cosine only is positive in Quadrant IV
  • trig ASTC is All,Sine,Tangent,Cosine
EMRS PGT Mathematics Mock Test - 9 - Question 20

The area bounded by the curves y = √x , 2y+3 = x and the x – axis in the first quadrant is

Detailed Solution for EMRS PGT Mathematics Mock Test - 9 - Question 20

Required area :

EMRS PGT Mathematics Mock Test - 9 - Question 21

The G.M. between 3/2 and 27/2 is

Detailed Solution for EMRS PGT Mathematics Mock Test - 9 - Question 21

b2 = ac
a = 3/2, c = 27/2
⇒ b2 = 3/2 * 27/2
⇒ b = (√81/4)
⇒ b = 9/2

EMRS PGT Mathematics Mock Test - 9 - Question 22

The amplitude of the function 3sin x

Detailed Solution for EMRS PGT Mathematics Mock Test - 9 - Question 22

The amplitude of y = 3sinx is 3.
graph{y=-3*sinx [-10, 10, -5, 5]}
Amplitude is the height of a periodic function, aka the distance from the center of the wave to it's highest point (or lowest point). You can also take the distance from the highest point to the lowest point of the graph and divide it by two.

EMRS PGT Mathematics Mock Test - 9 - Question 23

Out of 15 tickets marked 1, 2, 3, ... 15, three are drawn at random. The chance that numbers on them are in AP is

Detailed Solution for EMRS PGT Mathematics Mock Test - 9 - Question 23

Remember, if the total number of tickets is (2n + 1) and three (3) tickets are drawn at random; then the number of ways that numbers on the drawn tickets are in AP is n2.
Here 2n + 1 = 15
⇒ 2n = 14
⇒ n = 7

EMRS PGT Mathematics Mock Test - 9 - Question 24

Which of the following is incorrect:

Detailed Solution for EMRS PGT Mathematics Mock Test - 9 - Question 24

D is not a trigonometric identity.

EMRS PGT Mathematics Mock Test - 9 - Question 25

If ar > 0, r ∈ N and a1, a2 , a3 , .............a2n are A.P. then

Detailed Solution for EMRS PGT Mathematics Mock Test - 9 - Question 25

a1 + a2n = a2 + a2n-1 = an + an-1 = K(say)

EMRS PGT Mathematics Mock Test - 9 - Question 26

Kritika who does not talk much at home talks a lot at school. It shows that:

Detailed Solution for EMRS PGT Mathematics Mock Test - 9 - Question 26

The reason behind Kritika's this behaviour shows that her thoughts get acknowledged in schools. Sometimes it happens with children, if they feel that they are not being given importance or no one will praise them then they adopt such kind of behaviour that they talk only to those people who praise them gives due importance. Hence, the correct answer is, 'Her thoughts get acknowledged in schools.'

EMRS PGT Mathematics Mock Test - 9 - Question 27

The following questions consist of a single sentence with one blank only. You are given four words as answer choice and from the four choices, you have to pick up one correct answer, which will make the sentence meaningfully complete.
Q. Although Sarah started her company inside a small, rented apartment, her firm is now a ________ one in the international business community.

Detailed Solution for EMRS PGT Mathematics Mock Test - 9 - Question 27

The sentence indicates Sarah's massive success as a businessman; the company which was once small has now turned into an enormous one. Out of the given options, 'gargantuan' means enormous. The other words, 'gorgeous', 'tiny', and 'mendacious' respectively mean attractive, minuscule, deceitful and friendly. Hence, the correct answer is 3.

EMRS PGT Mathematics Mock Test - 9 - Question 28

In the following question, a sentence has been given in Active/Passive voice. Out of four alternatives suggested, select the one which best expresses the same sentence in Passive/Active voice.

Q. Why are they laughing at you?

Detailed Solution for EMRS PGT Mathematics Mock Test - 9 - Question 28

The given sentence is in the active voice. The correct conversion to passive voice is given in option 2. Options 1 and 4 change the meaning of the given sentence and option 3 gives an incomplete conversion. 

EMRS PGT Mathematics Mock Test - 9 - Question 29

निम्नलिखित प्रश्न में, चार विकल्पों में से उस विकल्प का चयन करें जो दिए गए वाक्य के भेद का सबसे अच्छा विकल्प हो ।

जुग जुग जिओ।

Detailed Solution for EMRS PGT Mathematics Mock Test - 9 - Question 29
जुग जुग जिओ मे वाक्य के भेद का सबसे अच्छा विकल्प इच्छावाचक है।
EMRS PGT Mathematics Mock Test - 9 - Question 30
राधा का भाई आने वाला है' - वाक्य है:
Detailed Solution for EMRS PGT Mathematics Mock Test - 9 - Question 30

राधा का भाई आने वाला है। ये विधानवाचक वाक्य है।

  • राधा का भाई आने वाला है - विधानवाचक वाक्य
  • विधानवाचक वाक्य - जिस वाक्य से किसी बात के होने का बोध होता है उसे विधानवाचक वाक्य कहते हैं।
    • वाक्य प्रयोग - निकित हमेशा आलस करती है।

Important Pointsअर्थ की दृष्टि से वाक्य के आठ भेद होते हैं -

View more questions
8 docs|45 tests
Information about EMRS PGT Mathematics Mock Test - 9 Page
In this test you can find the Exam questions for EMRS PGT Mathematics Mock Test - 9 solved & explained in the simplest way possible. Besides giving Questions and answers for EMRS PGT Mathematics Mock Test - 9, EduRev gives you an ample number of Online tests for practice

Top Courses for EMRS

Download as PDF

Top Courses for EMRS